This is great Channel

you could add a gift to keep him helping us.

I feel the same way. It’s a blessing!

🤫 shhhhh lol

It's a blessing ❤

Thank you so much! Jason, MathAndScience.com

AGREE

What the name for the next video thank you so much

@@parada542 look up AC circuit analysis vol 6-3 in the playlists

Agree. Excellent teacher. Thank you (I wish I could draw as neatly as Jason too - when I present it's a total spider party!)

sm1 pls help.idk y i cant understand smthin. i expect the current to slow down after it passes thru the resistor but its the same thoughout the whole circuit.My brrain cant comprehend😭

How’d the 955 go? I’m taking it soon, just wondering.

Good teacher

Thankyou gues iam stadeyok

So... your English isn't bad

@@eng560 a a

ayyy moroccan gang

Indeed this is the greatest teacher ,,,,i love the explaination because it is very clear

I wish I could have met E = mc2. I’d like to spend the day with this guy too.

I’m doing my PPL theory and have the same issue . Agree with you entirely. Did you ever find that book?🙏

@@ajscain500 so I’ve never found a book for “dummy’s” so to speak, however as I’ve progressed in my career here are a few things I could say to someone starting out in aviation. As a pilot it’s important to know what you can affect from the cockpit. While knowing your aircraft in and out will make you a more complete aviator keeping it simple to begin with will create the base you need to dive further. Start with your emergency procedures that deal with either alternator or generator issues. Be sure you can conduct the steps in the cockpit even if you don’t understand what’s happening behind them. As you progress, go through the operators manual and find the section that deals with the electrical system and components. From here identify what does what. Like “what does an alternator do?” Then what does an alternator do for my aircraft when it’s running then when it’s not. Keep in the operators manual page by page and look up things you don’t understand within the electrical system. Like a short circuit or a bad ground. Take it slow and you’ll be able to electricity in time, and most importantly how it affects you when something fails. I also highly recommend becoming your own mechanic. I started working on my trucks about 6 years ago and it helped me understand lycomings and eventually turbine engine operations. Good luck!

What does god have to do with the current change in your life?

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Thank you. I was getting a bit confused.

why??? the resister ABSORB it..so whatever is left over. You know....like a dimmer knob or POT...which is just a variable RESISTOR..You know....when the knob is at Zero...it has crapload of RISISTANCE..when it's on 5....it has you know 2 ohm . When you crank it all the way up on 10...it has Zero ohm. Different ACTIVE components has different voltage requirements...You basically use resistors to adjust to different component input...such as an LED is only 3v .if you had a 6v source...you'll need to drop it to 3v into the LED.......but the motor is still using 6v. or lets say..you had 8-12V esc for a motor...made in china. People say the fan keeps crappy out becuase it cant handle the 12V...becuase there's only a 1v-9v cooling fan. You can install a resistor to the fans input to drop it's into voltage to below 9V...instead of disconnecting the fan to save the fan ( which will kill your esc..lmao)

Thank you so much! Jason, MathAndScience.com

I was wondering the same thing but i think these examples are perfect scenarios in which the battery never runs out of charge (through heat - like u said) I imagine resistance as running through the street normally, struggling through sand, then back to the street. At the end you still ate 2500 calories but you burned maybe about 60 in a small circuit. And now your left with (2440 calories) btw Calories = HEAT (related to "calor" or heat in spanish)

Resistor acts as a filter in a way, it filters energy out of the circuit (and dissipates it, it is warm/hot to the touch as it does it). As the law of energy preservation states, if work is performed the energy of the system (circuit) decreases (to paraphrase it), the work being "fighting that resistance" + heat. That means the available energy for pushing the current AFTER the resistor is less (ie voltage drop). Power is P = V * I (don't confuse with Ohm's law), energy is P * t (time).

@@doctorluzbubs258 Current is constant in a series circuit. Voltage is constant across parallel circuits.

@@vyarovoy that makes a lot of sense. i guess the fact that the current remains constant throughout the entire series circuit is due to the affect of ALL the resistance.

I know that's weird to me too but after googling i understand it: Forget ohm law in this case Current is constant in a series circuit. Example current is the same after R1 R2 R3 Voltage is constant across parallel circuits. www.electronics-tutorials.ws/resistor/res_3.html

go back to the video and start at the 17:00 minute mark. Hope this helps...

Candice Jones no mate purely because it was a simple circuit with 1 resistor I.e a 1 load ( could be anything) which is basically neutral you probably know if you measure between live and neutral you will get 240v in the UK So that's basically why .ohms law is pretty easy to understand really it's only a it bit of algebra . But when you start getting in to micro circuits and and pcb builds it's a different ball game diodes, capacitors, transistors,Inductors,that's what he was getting towards on the other circuit he drew . But the maths is always the same ✌✌✌

Candice Jones When you put a voltmeter across the 1st resistor, you are measuring the voltage drop. Try putting a positive probe at the bottom of R2 and put a negative probe to ground, you will get 0 volt because the bottom of R2 is basically connected to the negative of the supply voltage.

Candice Jones The split second current hits the resistor, no voltage drop occurs. But when the current has 100% finished going through the resistor then. The voltage drop occurs.

Had R1 being 2 ohms and R2 also 2 ohms, the value of V1 is 8. I am wondering what would the value of V2 be? By using Ohms law, we get V2= 8 (that is, 4 *2). If we add V1 and V2, we get 16 = (8+8) whereas the original voltage was only 12. What am I getting wrong? For instance, shouldn't the current flow between R1 and R2 reduce to 2 or something like that.

Johnny Minter Go to MathTutorDVD's playlist and it's under the "Engineering Circuits - Vol1"

Thank you so much!

Finish this, you are graduate .

Yes absolutely. I believe we are all capable of learning anything!

Welcome!

Keep your opinion to yourself ding dong 💣