15.7 Complex Splitting | Organic Chemistry

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15.7 Complex Splitting | Organic Chemistry

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Chad's Prep

Күн бұрын

Пікірлер: 67

@OhJynxHD 4 жыл бұрын

Wow! On my second semester of orgo and so for these videos have been extremely helpful. I cannot thank you enough, definitely deserve way more recognition.

@ChadsPrep 4 жыл бұрын

Glad you've found them helpful Juan!

@imtehcumseh 2 жыл бұрын

same

@26d8 3 жыл бұрын

I learned this topic now!!! he explains all the details very well, thank you very much :)

@ChadsPrep 3 жыл бұрын

Awesome Samira! 🙂

@aarongaynes4654 5 жыл бұрын

very good! Im always in need of a refresher for more complicated splitting. Good video!

@jamiestickelmaier5384 3 жыл бұрын

this is it. this is the video. thank you my guy

@ChadsPrep 3 жыл бұрын

Awesome Jamie! Glad you found this helpful!

@Unterhosegotti 3 жыл бұрын

Best video in this topic out there and way better than my professors, thanks

@ChadsPrep 3 жыл бұрын

You're very welcome Unterhosegotti! I'll actually be re-filming this lesson using a white board in the Spring semester and hope to actually improve on it so we'll see! Happy Studying!

@Unterhosegotti 3 жыл бұрын

@@ChadsPrep im pumped

@alenajarro7240 3 жыл бұрын

thanks omg I was having a meltdown before my final

@ChadsPrep 3 жыл бұрын

You are welcome, Ale - good luck on your final!

@juliasterbenz2996 2 жыл бұрын

This is really helpful. It makes so much sense now!

@ChadsPrep 2 жыл бұрын

Glad to hear it, Julia!

@relleumal 6 күн бұрын

For the second example (with Z-1-chloroprop-1-ene), why would the peaks of the quartet of doublets all be the same height? Wouldn’t the peaks in the center be higher?

@grodspott 2 жыл бұрын

This was incredibly helpful, thank you

@ChadsPrep 2 жыл бұрын

Glad to hear it, grodspott!

@eternalsunshineofspotlessi715 Жыл бұрын

Thanks chad

@ChadsPrep Жыл бұрын

You're welcome - Happy Studying!

@sarahlasterAPChemistry 3 жыл бұрын

Thank you for the video! I'm in a graduate program in a class for Molecular Spectroscopy and this was helpful. I have one question though: Does it matter which Hydrogen you observe? If so, how do you know which one to look at to determine how many peaks?

@grodspott 2 жыл бұрын

Hi, maybe I'm too late but perhaps someone else is wondering the same thing. The way I'm learning to do it is that all of the unique protons show up in the spectrum. To clarify, you observe all of them, each one has its own individual peak/cluster of peaks. Unless you are referring to which one as in which of the 3 hydrogens on, for example, a CH3 group, then the answer to your question is that they share the same environment so they will just show up as a single peak/cluster of peaks. If I misunderstood or am being wrong here someone please correct me.

@nastiachan9310 2 жыл бұрын

Super helpful. Thank you!

@ChadsPrep 2 жыл бұрын

You're welcome, Nastia!

@user-pg3mi2mi2t 2 жыл бұрын

Thanks a lot for the last example :)

@ChadsPrep 2 жыл бұрын

You're welcome!

@chemistryrussell 3 жыл бұрын

Excellent presentation.

@ChadsPrep 3 жыл бұрын

Thanks Chemistryrussell! Love the name!

@chemistryrussell 3 жыл бұрын

@@ChadsPrep I used this video for my organic II class. They got it!

@ChadsPrep 3 жыл бұрын

Nice! And OOOHHH you teach?! I just checked out your channel. Loved your intro to Ochem..."And then God created carbon"😆 Fantastic! I wish you and your students the best!

@chemistryrussell 3 жыл бұрын

@@ChadsPrep thanks! That means a lot. Same to you and yours!

@joshuachan7761 4 жыл бұрын

Super helpful, thank you so much!

@ChadsPrep 4 жыл бұрын

Glad you found it helpful Joshua! Happy studying!😊

@plamenpenchev262 2 жыл бұрын

6:42 qd are not with equal intensity!!! 1:1:3:3:3:3:1:1

@xCrash57x 3 жыл бұрын

This video really helped my understanding! For the last example where there are the two equivalent red hydrogens, would there be any change in the NMR spectrum if there was only one hydrogen? I would imagine both hydrogens are split the same way as they are equivalent so would this double the intensity on the proton NMR spectrum?

@ChadsPrep 3 жыл бұрын

The only change for this signal would be in its intensity as you suspected. With the signal representing half as many hydrogens it would have half as much area under the peak (i.e. half the integration). Hope this helps!

@karamellfunnyla 4 жыл бұрын

thank you very much for this video. It has helped me very much :)

@ChadsPrep 4 жыл бұрын

Awesome Paula!🙂

@yendavarunkumar6824 3 жыл бұрын

Thank you sir, from India

@ChadsPrep 3 жыл бұрын

You are welcome - thanks for watching!

@ChadsPrep 3 жыл бұрын

And one more thing...lots of prayers going up on behalf of your country. God bless.

@josepheyiolowope9176 Жыл бұрын

Amazing Video !!!!!!!!!!!

@ChadsPrep Жыл бұрын

Thank You!

@Pillipilli8 3 жыл бұрын

Hi! For the sextet example, could you call it a quartet of triplets in addition to a sextet? Or no?

@nuhafaridz2131 3 жыл бұрын

I want to know about this too T_T

@filipilic2451 4 жыл бұрын

Very Good explication would be cool also to do for benzene substituent and other cyclic compound

@jackvyletel3405 3 жыл бұрын

Is example 1 incorrect? If you split by 16 and then by 8 the two middle peaks would end up overlapping and make a triplet.

@ChadsPrep 3 жыл бұрын

You're exactly right! It would technically still be a doublet of doublets that just "looked like" a triplet. Also note that the J value for cis splitting is 6-12Hz and the J value for trans splitting is 12-18Hz. In the video I chose a value in each range and just happened to choose 8Hz and 16Hz. But had I chose any values within these ranges that were not in a 2:1 ratio then we would definitely see the doublet of doublets properly. I really should have chosen better representative numbers within those ranges to have avoided this. I'm remaking the whole playlist using a whiteboard and when I get to this lesson I will remember not to repeat this error! Thanks!