#190

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w2aew

w2aew

9 жыл бұрын

This video is a back-to-basics tutorial on transistor current sources - what they are, some applications for them, and some circuit examples. The basic characteristics of current sources and sinks are presented and demonstrated, including the measurement of the output impedance of these simple current sources. Here is a link to the note pages used in this video:
www.qsl.net/w2aew/youtube/tran...
Viewer +BersekViking pointed out a problem with my test setup. Can you guess what it is? Here is a link to my followup video:
• #191: Beware of test e...

Пікірлер: 241
@johnwest7993
@johnwest7993 2 жыл бұрын
Yours are the best electronics instructional videos on the internet. If I magically had access to these videos back when I was a kid I'd be a retired physicist by now with a 60 year hobby in amateur radio. But better late than never. You're filling in many of the gaps in my Swiss cheese of electronics knowledge. Thank you.
@warrenking1815
@warrenking1815 10 ай бұрын
It still nice to see the old analog Simpson meter. Still in use . Good video well explained!
@TheDradge
@TheDradge Жыл бұрын
When I left college as an electronic engineer I built thyristors and breakover diodes in a semiconductor plant. Your videos and explanations are reminiscent of the Forrest Mims books back in the day. Excellent and well put together videos!
@w2aew
@w2aew Жыл бұрын
I learned a lot from the Forrest Mims books!
@TheDradge
@TheDradge Жыл бұрын
@@w2aew I still have the books! Bought from Radio Shack in the 70s and diligently studied. I remember my interview at the semiconductor plant in 1982. My boss to be gave me a sketch pad and asked me random questions like "draw me a single transistor class A amplifier circuit with example biasing resistor values." That "back of the envelope" method helped to get me the job and I hope your videos help get new kids coming through a grip on electronics. Breaking things down into smaller parts helps to get a handle on the common techniques.
@TheDradge
@TheDradge Жыл бұрын
@@w2aew books by R.M. Marston were also essential reading.
@PavelLarsson
@PavelLarsson Ай бұрын
This channel is fantastic! The explanations of important fundamentals are clear and the practical applications are always mentioned. I follow along and experiment with each topic covered. Thank you so much for your effort and I wish you all the best!
@1DR31N
@1DR31N 3 жыл бұрын
The best explanation about electronics I've seen. Wished I had a teacher like you. I wish all the success you deserve.
@aatifshah8476
@aatifshah8476 3 жыл бұрын
same
@norm1124
@norm1124 2 ай бұрын
Love this video, looking to understand transistors since ~1 year and making slooooowly progress.
@josevasquez4335
@josevasquez4335 Жыл бұрын
Professor, so much thankful for your videos. I never never have had the opportunity of learning with such a perfectly explanations. THANKS.
@W1RMD
@W1RMD 3 жыл бұрын
Valued info! Thanks! I love how the majority of your projects involve less than a $5 of a handful of parts.
@francescolucarno6214
@francescolucarno6214 6 жыл бұрын
The HP RPN calculator is a really nice touch. I am still using my trusty HP35s.
@CodeJeffo
@CodeJeffo 2 жыл бұрын
Best practical electronics & education channel out there. Hands down.
@maxfarr4142
@maxfarr4142 4 жыл бұрын
I've been a student of EE for 25 years and your style is the most impressive I've seen so far! I love the simply laid out notes and common themes. I'm on the binge and I want a vid specifically detailing the inside of an opamp from you. All the others I watch aren't cutting it!
@doncoltrane3565
@doncoltrane3565 9 жыл бұрын
I recently retired and now have time to learn about electronics. You are a good teacher, and I appreciate your videos. Thanks for all your hard work. 73!
@Tiky.8192
@Tiky.8192 9 жыл бұрын
I really like your back to basics videos, I always learn something new. Very well done too!
@tonybell1597
@tonybell1597 9 жыл бұрын
Cheers Alan, simple, straightforward, and very useful! Back to my bench!
@das250250
@das250250 7 жыл бұрын
One of the best channels to refresh and learn electronics ... As always , Excellent work W2
@tiagomello
@tiagomello Жыл бұрын
Time really flies when watching your videos. Thanks for the great explanation.
@malgailany
@malgailany 9 жыл бұрын
As usual, clear and informative video. Thank you.
@paultyson5145
@paultyson5145 Жыл бұрын
Brilliant. Thanks for explaining these mysterious little circuit blocks!! Now I see how they help increase the gain in audio stuff.
@Linksimpson
@Linksimpson 9 жыл бұрын
Really clearly explained, again! Thank you, love to see this continue on into a diff amp too.
@dougfarrell5091
@dougfarrell5091 2 жыл бұрын
Fantastic presentation Allen. I really enjoy your presentations and get allot of inside from them.
@Infinitesap
@Infinitesap 8 жыл бұрын
really love these back to basics videos.
@BersekViking
@BersekViking 9 жыл бұрын
Your VOM is in parallel with the current source and this causes a reading error. I guess it is a 20kohm/V meter, so in the 10V range it has an impedance to 200k, that matches the impedance you calculated.
@w2aew
@w2aew 9 жыл бұрын
Yikes!! You are absolutely right!! Although I grew up using analog meters like the 260, how quickly we can forget about the meter's impedance after getting spoiled by the 10Mohm input impedance of modern DMMs. Ugh, what a bonehead error! I'll have to do a follow up video (with egg on my face). Thank you for keeping me honest!
@shadowwolf225
@shadowwolf225 9 жыл бұрын
As a subscriber of w2aew's videos I'd like to say kudos for the sharp eye and a professional and polite comment on what was done wrong. You are the antithesis of stereotypical youtube comments. Thank you.
@shadowwolf225
@shadowwolf225 9 жыл бұрын
***** This is good stuff! You, one of the gods of youtube electronics, made a simple to overlook mistake and from just a comment made a whole video explaining the error and give credit to the one who found it. I'm impressed at the level of sportsmanship/professionalism here. Thanks for this. This type of discourse is REAL education.
@w2aew
@w2aew 9 жыл бұрын
Agreed!
@1959Berre
@1959Berre 5 жыл бұрын
When real professionals meet they usually behave like gentlemen. But you are right, this kind of chivalry is becoming the exception in YT comments.
@RinaldiMeteoric
@RinaldiMeteoric 7 жыл бұрын
Gosh I wish you were my electronics teacher on my graduation. Thank you for the excellent videos.
@HenriTroberg
@HenriTroberg 9 жыл бұрын
Another really great back to basics video, thanks! Also liked the HP 15C calculator.
@wk2w168
@wk2w168 8 жыл бұрын
Thanks for another great, thorough explanation.
@mouseyou12
@mouseyou12 9 жыл бұрын
Thank you hit the nail on the head I was looking for something on current I like the way you present your vid's.
@ThingsWhichArentWork
@ThingsWhichArentWork 9 жыл бұрын
Thanks Alan - a good tutorial on a subject I'm a bit fuzzy on. I'm going to have to watch this again. Cheers!!
@geneglondo
@geneglondo 9 жыл бұрын
...and finally I understand current sources. Awesome video. Thank you :)
@MrKaizen75
@MrKaizen75 9 жыл бұрын
Chapeau Maestro! Very clear and well explained...
@DAVET38
@DAVET38 9 жыл бұрын
Another good (and useful) video Alan. Thank you for prparing it.
@gregorymccoy6797
@gregorymccoy6797 3 жыл бұрын
I very much enjoyed this. These have always been a little fuzzy for me but this cleared it up nicely.
@CoolDudeClem
@CoolDudeClem 9 жыл бұрын
Nicely explained, although I'll have to replay it a few times for my mind to take it all in!
@monodipsarkar9805
@monodipsarkar9805 Жыл бұрын
Wow!! Great explanation
@zedlepplin9450
@zedlepplin9450 4 жыл бұрын
the slope of the IV characteristics is 1/R @ 6 min. So for a ideal constant current source, output impedance is infinite (1/infinite is 0 which means flat line).
@quantomic1106
@quantomic1106 9 жыл бұрын
Thanks Alan! You're the man!
@hardrocklobsterroll395
@hardrocklobsterroll395 8 жыл бұрын
another extremely informative video. thank you
@dwDragon88
@dwDragon88 9 жыл бұрын
Great video. Earlier today I built most of the circuits you showed, my favorite was the voltage divider biased BJT with two diodes in place of R2 in the divider. This circuit was remarkably stable, even when I changed the supply voltage or dropped in transistors with different betas. One configuration I tested, a 500 uA sink, showed less than 10 uA change with a 100% swing on the supply voltage. Remarkable.
@w2aew
@w2aew 9 жыл бұрын
Yes, this is exactly what you'd expect - nice job. Note that I made a mistake with my use of the old Simpson 260. It's input impedance was too low to be used to measure the voltage on the current source output. See my next video for details...
@BrendaEM
@BrendaEM 2 жыл бұрын
Thanks for the video. (My Fluke 87vMax multimeter is back for a safety recall, if I ever see my meter again, if they repair it. Check yours?) This setup gave me some issues because I was down to my intrepid Cen-Tech P37772 meter with the patent infringment yellow bumper, and worn selector switch, which also doesn't do microamps. So I needed to scale the current up the setup. I also used two power supplies to keep my bias divider in one place, but that might be cheating. What I found: I was displeased with the linearity (low input-impedence) Why I found it: likely because I was against the compliance voltage for my altered setup. What made recovered the fun: I replaced R2, with a diode, which brought up the bias voltage, and linearized the setup better. Also, placing 1 though 5 LEDs in the current source with very little change in apparent brightness made it fun, once again, all the way past 12 volts. They didn't smoke at 15. What opportunity I found: By watching the LED brightness when changing the voltage, I could see the limits of the voltage compliance. Oddly, the 2n222 handled the current quite well. Apparently, some have a max continous current of 600mA, others 800mA (likely with some kind of clip-on heatsink.) What opportunity I missed: while I practiced calculating the input impedance a few the circuit, I should have for this setup, but didn't. Thanks, again for the videos.
@Taran72
@Taran72 4 жыл бұрын
WOW! Amazing video! thank you very much for the detailed explanation and for showing the actual use of a current generator. A question I've been asking myself for a long time was "what are current sources used for?"
@TheDansana
@TheDansana 9 жыл бұрын
I'm enjoying your show - especially the b.e.e. stuff.
@SomeGuyInSandy
@SomeGuyInSandy 4 жыл бұрын
This is really good stuff, thanks!
@starlight8260
@starlight8260 6 жыл бұрын
Well done, excellent video!
@moonlightshadow5107
@moonlightshadow5107 8 жыл бұрын
Thanks,very very nice and simple tutorial, i hope you go forwards and waiting for more basics videos
@w2aew
@w2aew 8 жыл бұрын
+Moon Light Shadow Please let me know what topics you'd like to see in future "basics" videos!
@min2oly
@min2oly 9 жыл бұрын
This is very helpful for some working I'm doing on pulse magnet motors and what to do with the excess energy output.
@min2oly
@min2oly 9 жыл бұрын
I just noticed you also provide a pdf of the ckts - SWEET! thanks!
@wagsman9999
@wagsman9999 Жыл бұрын
very clear explanation, thank you
@frantisekvrabec7258
@frantisekvrabec7258 Жыл бұрын
Thank you very much for this video.
@alexeykokh8240
@alexeykokh8240 8 жыл бұрын
Thanks for the video, it is very helpful.
@1inDnile
@1inDnile 6 жыл бұрын
calmly taught, thank you.
@user-ur1ny8wt3c
@user-ur1ny8wt3c 6 ай бұрын
Great video about current soutces.
@TMuel1123
@TMuel1123 9 жыл бұрын
Thank you for that awesome video. I love these back to basics videos. You have mentioned that the gain of an amplifier could be massively increased with a current source. It would be great if you could do a video about that topic to show how that works.
@w2aew
@w2aew 9 жыл бұрын
I plan on doing something on this topic soon.
@billigerfusel
@billigerfusel 9 жыл бұрын
Very cool videos, thanks man.
@micpax1
@micpax1 9 жыл бұрын
Fantastic video! Thanks
@simonyoungglostog
@simonyoungglostog Жыл бұрын
Excellent, i can see that I was the last person to comment. I'm understanding more now and noticed the ring of two as an example of a current source. It would be great to see you do a video on that.
@judo-rob5197
@judo-rob5197 3 жыл бұрын
Thanks for the tutorial.
@benthere8051
@benthere8051 Жыл бұрын
Current sources are very useful. THANKS
@jospicant
@jospicant 9 жыл бұрын
It's a wonderfull video. I hope to see another video about current mirrors using Mosfet, wilson,wildar, wildson modificate, active cascode.... thanks for yours videos
@w2aew
@w2aew 9 жыл бұрын
I'm glad you liked it. I'll keep these topics in mind.
@simonyoungglostog
@simonyoungglostog Жыл бұрын
Super video. Thank you.
@pertileluca
@pertileluca 9 жыл бұрын
Very nice video!
@yaghiyahbrenner8902
@yaghiyahbrenner8902 9 жыл бұрын
Great Video, Good Presentation.
@blacklightning7227
@blacklightning7227 Жыл бұрын
awesome vid ! 🔥
@Infinitesap
@Infinitesap 6 жыл бұрын
Simply awsome video. Im getting there :-) Thanks for great stuff :-)
@aminemo93
@aminemo93 9 жыл бұрын
Absolutely awesome!!!
@Jose4416
@Jose4416 7 жыл бұрын
great video thank you
@hammershigh
@hammershigh 7 жыл бұрын
Excellent!
@AJSquirrel53
@AJSquirrel53 13 сағат бұрын
So awesome! Thank you!
@444guns
@444guns 3 жыл бұрын
awesome, thanks alot for this video
@Infinitesap
@Infinitesap 8 жыл бұрын
really awsome video.
@klave8511
@klave8511 4 жыл бұрын
Great lesson on current sources for tabletop circuits. My area of application is industrial and automotive where temperatures change from -20C to 70C at best. My designs have to cope with -40C to 80C. These basic current controllers won’t be useable without temperature compensation. Just consider the 0.6v Vbe reference voltage these circuits use, over a small 50C temperature range the voltage will change by 2mV per degree, that’s 100mV change for a 600mV reference! Even the self heating can render the current out of range. Throw in todays trend to run everything from a single battery or a USB voltage and you suddenly have a much more interesting design. I consider any circuit design to be incomplete if it doesn’t have some temperature compensation or a good reason not to use it. I’m sure you have a few design options for temperature correction, perhaps an update video one day.
@mouseyou12
@mouseyou12 9 жыл бұрын
Thank you for the pdf love your vid's.
@w2aew
@w2aew 9 жыл бұрын
You're welcome - I've had a lot of requests over the years, so I try to do it for each video now.
@armandine2
@armandine2 Ай бұрын
Just been building your second "sink" circuit - 0.6V across a 120 ohm emitter Resistor with a view to create a 5mA constant sink. That particular circuit was in an exam paper , GCE A level - June 1981 AEB Electronic Systems Paper 1. Testing the sink current in an actual circuit I'm getting about 10mA. The paper also asks for graphs of collector current and output voltage when you charge a 1000uF capacitor.
@w2aew
@w2aew Ай бұрын
Well, something sounds "off" if you're measuring 0.6V cross that emitter resistor, but also seeing 10mA current.
@armandine2
@armandine2 Ай бұрын
@@w2aew I thought it could be my "random" silicon npn transistor - I used a C4881 (TO-220) which measured 171 beta on my Peak tester. It appears to have survived being soldered on to a strip-board. The bias config is 2 diodes in series with a 300-ohm 1-watt resistor - dropping 15V - 1.2V.
@armandine2
@armandine2 Ай бұрын
I will measure again - with a load
@w2aew
@w2aew Ай бұрын
@@armandine2 Always a good idea to backup your measurements with a second method. For example, if you're measuring 10mA collector current, double check that by measuring the voltage across the emitter resistor, as well as the resistor value - all should lead to the same conclusion - if not, then something is wrong.
@w2aew
@w2aew Ай бұрын
@@armandine2 Make sure that load doesn't saturate the transistor.
@kevinnguyen5011
@kevinnguyen5011 3 жыл бұрын
Great video. Just correction on current changed is in milliamp, but Allen kept say Microamp.
@bobdoritique7347
@bobdoritique7347 6 ай бұрын
Thank a lot, very interesting.
@robr8554
@robr8554 Жыл бұрын
Is there a way to temperature compensate a current mirror used as to measure high side current? The current mirror I am using had a pnp and npn matched pair. The issue i see is the offset and slope changes as a function of temperature. Is there a way to compensate it?
@robinharris4706
@robinharris4706 3 жыл бұрын
Brilliant video with much for me to learn...including from the comments! I'm working through building these circuits to solidify my learning but am not sure how to set up a floating power supply. Would you be able to provide a brief explanation on how you set that up please?
@2326TOM
@2326TOM 8 жыл бұрын
Thank you very much
@10812059
@10812059 5 жыл бұрын
So, without the VOM it is actually a higher impedance. Great! It would be nice to see the same video with the VOM in parallel to the voltage source.
@w2aew
@w2aew 5 жыл бұрын
Yes - in fact I made a followup video that points out this error in measurement technique... kzfaq.info/get/bejne/gMhzfJd92NTVmKM.html
@waynegram8907
@waynegram8907 3 жыл бұрын
When looking at a schematic of a passive network or active network, how can you tell if the passive network or active circuit is a current source or voltage source? Can passive LCR or LR or LC networks be a current source or voltage source how can you tell?
@RexxSchneider
@RexxSchneider 11 ай бұрын
It's interesting to see that the output impedance of the 2N2222A of 190K across the range 2V to 10V when sinking around 0.5mA as calculated at 11:34 is almost the same as the output impedance of 192K across the range 5V to 10V, which is given by 5V/(419-396)μA. That's useful because some devices have a "knee" at lower collector voltages where the incremental output impedance drops off. It's also worth noting that the 2N2222A datasheet gives a wide range of output impedances at Ic=1mA and Vce=10V of between 30K and 200K. At Ic=10mA, Vce=10V, that falls to between 5K and 40K, meaning that the 2N2222A is not so useful as a constant current supply at higher currents.
@w2aew
@w2aew 11 ай бұрын
Hah! There's actually a mistake in this video when it comes to measuring and calculating the output impedance! It was discovered after the fact, and I posted a followup video. Note that the output impedance is much higher.... kzfaq.info/get/bejne/gMhzfJd92NTVmKM.html
@RexxSchneider
@RexxSchneider 11 ай бұрын
@@w2aew I noticed the discrepancy between the apparent emitter current of 384μA and the 419μA collector current, but I just surmised that the 1K emitter resistor was high by about 8%. The actual value of that resistor would have been the first thing I'd measure. It's been so long since I used an analogue meter, its loading wouldn't have occurred to me. So, the interesting point now is that the 2N2222A seemed to have an output impedance far in excess of the values in its datasheet, but I then realised that the emitter resistor effectively provides negative feedback in a common base configuration, stabilising the collector current against variations due to changes in Vce. Something to explore.
@AB-yu2tj
@AB-yu2tj 3 жыл бұрын
Thank you
@miketoreno4969
@miketoreno4969 4 жыл бұрын
Thank you.
@fredfabris7187
@fredfabris7187 6 жыл бұрын
You do an incredible job of walking a dumbo like me through this subject. One question........ you said a couple of times that the constant current source can improve the gain of a transistor, the reason isn’t so obvious to me.
@alanwolke6253
@alanwolke6253 6 жыл бұрын
A current source is a very high impedance - so when it is used as the load in the collector of an amplifier (instead of RC), the gain will be very high (since gain is gm*RC)
@cuchulainkailen
@cuchulainkailen 3 жыл бұрын
11:33 .... re: Using the current sink as a load for an amplifier. Dumb question: Is this a good strategy for a LNA block that must amplify very low-V (uV) raw sensor output (assuming the opamp ckt is well designed for noise)?
@dennisqwertyuiop
@dennisqwertyuiop 9 жыл бұрын
thank you for the great video
@bwack
@bwack 8 жыл бұрын
I love these fundamental electronics videos. Can I ask you how to match transistors used in a current mirror? Is it ok to compare the measured Hfe? Or are there other parameters needed.. (like thermal coefficients..) ? Thanks in advance.
@w2aew
@w2aew 8 жыл бұрын
Most important would be to match Vbe, and then beta.
@bwack
@bwack 8 жыл бұрын
Thanks. Makes sense though if the bases are connected together in the current mirror circuit, the Vbe should be close.
@zafariqbal7570
@zafariqbal7570 4 жыл бұрын
What is the purpise of mirror circuit in power amp circuit?
@nova0302
@nova0302 8 жыл бұрын
Great video!, Thanks a lot! I really enjoy your videos. Can i ask you a question? In the video at 7:44, what do you mean by "floating power supply"?
@w2aew
@w2aew 8 жыл бұрын
A floating or isolated power supply is one that generates the desired voltage between its positive and negative terminals, but neither of these terminals is connected to ground.
@cohof
@cohof 4 жыл бұрын
Could you possibly consider a video on different types of oscillator.Specifically why most designs don't oscillate as expected,or work every time in a simulation program but when constructed never do ?
@magdalenoarellano1841
@magdalenoarellano1841 9 жыл бұрын
gran video como todos los que usted hace mister gracias.
@paulp1204
@paulp1204 2 жыл бұрын
@ 12:00 mark, I am interested to know why using the current sink with an impedance of 190k is an advantage over simply using a 190k resistor in the amplifier application you mention.
@w2aew
@w2aew 2 жыл бұрын
Because, in order to use a 190k resistor, the collector current would have to be very low in order to not saturate the transistor. The low collector current will lower the transconductance (gm), and therefore lower the gain...
@duffyb11
@duffyb11 9 жыл бұрын
Would it be possible to demonstrate dependent voltage/current sources? Also, are you planning on doing a BJT differential amplifier with a current source?
@w2aew
@w2aew 9 жыл бұрын
I do plan on a diff amp, and show how current sources can be used...
@rapsod1911
@rapsod1911 9 жыл бұрын
I am curious about something you told about slew rate. Value of current inside op amp current mirrors limit slew rate.
@jospicant
@jospicant 9 жыл бұрын
slew rate is function of Capacity and Current if and opamp use a bigger current of polarization (this current normaly is obtained of a current mirror) you will improve the slew rate.
@billwilliams6338
@billwilliams6338 4 жыл бұрын
W2aew, Current source circuits were mostly used for headphone amplifiers cause there was no standard output impedance for headphones? A Constant current source amplifier circuit "can drive any load" impedance that is why they used them for headphones?
@robbowman8770
@robbowman8770 9 жыл бұрын
Nice video - I always forget how useful these are outside of ICs. Have you done a video on the "long tailed pair" before? Would make a good follow up ,,,
@w2aew
@w2aew 9 жыл бұрын
Yeah, I was thinking of a video on a diff pair, then maybe even using some current source active loads to make a crude discrete op amp.
@robbowman8770
@robbowman8770 9 жыл бұрын
***** Sounds great - diff amps are important, and also fun!
@fouadnano
@fouadnano Жыл бұрын
Thanks شكرا
@tezlallc2900
@tezlallc2900 Жыл бұрын
Really well done videos! I do have a question....At about 16:06 in the video you say that you take the first current source output and tie it to the PNP current mirror input. This happens to be the emitter on the PNP....my question is : What did you tie the collectors of the PNP mirror to?
@w2aew
@w2aew Жыл бұрын
Take a careful look at the schematic at 15:47 - the input of the PNP current mirror is the base-collection junction labeled 'IN". The emitters are tied to the positive power supply.
@tezlallc2900
@tezlallc2900 Жыл бұрын
@@w2aew ...my apologies......In prior video you always had a number (ie +10V, etc) labeled and I didn't recognize the 'circle' without the label....my bad....thanks
@hichamtassi1753
@hichamtassi1753 2 жыл бұрын
Hello, nice video ! how to do to have a constant 1amp 14V power supply to charge a battery. WIth classical PSUs, when the battery reaches 13.5v, it takes ages to go to 14v because it draws very few current. Pushing 1Amp all the way will make it charge better and faster. Thanks.
@w2aew
@w2aew 2 жыл бұрын
Different battery chemistries have different charge circuit requirements. Lead acid batteries need a constant voltage float charger, while NiCad generally use a constant current charge. Lithium and LiFePO have other requirements. Using the proper charger circuit for your particular battery chemistry will give you the best results, and safest results.
@lalitverma8385
@lalitverma8385 5 жыл бұрын
hi Alan great video but i have a question. i didn't get why you put a 470 ohm resistance in parallel with supply. will you please shed some light on that
@w2aew
@w2aew 5 жыл бұрын
Because the power supply can't "sink" current. The 470 ohm resistor ensures that it is always "sourcing" current.
@pirateman1966
@pirateman1966 5 жыл бұрын
I came across your video while searching for a solution to my problem. I built a circuit exactly like what you have on top right hand side of frame, you're pointing at it at 4:53 I've selected 5V as supply voltage. The resistor is 50 Ohms. I plan on charging a 20Ah NiMH cell connected to the output (via a schottky diode to prevent back flow when the source is off). It provides about 310mA, but quickly runs up and gets into a thermal run away. The current increases until the output transistor is destroyed. I've tried with 2x 2N2222, then went beefy, and used 2x TIP42C NPN transistors. Same effect. Both transistors are matched. Tried a resistor as load instead of battery. Same result. Then I installed a heat sink on the output transistor, and it works fine now! Why is this happening on only 300mA draw? How can I stabilize it? Would a MOSFET with its negative temp coefficient stop the thermal runaway? Do they even make current mirrors using MOSFETs?
@JohnSmith-he5xg
@JohnSmith-he5xg 6 жыл бұрын
Do you have a video you'd recommend for the variable, floating power supply? I'm confused by how its set up. 1) I normally see supplies hooked up with the negative to the ground. 2) It seems to be putting its positive out on the +10V rail. In my mind that would cause a short between the variable supply's voltage (assuming its any value other than 10V) and the 10V rail. But this must not be the case here. Thanks for any insight
@w2aew
@w2aew 6 жыл бұрын
Please see this video, it might help to clear this up for you: kzfaq.info/get/bejne/o7B8ZJSGq5fFooU.html
@JohnSmith-he5xg
@JohnSmith-he5xg 6 жыл бұрын
Thanks, that helps with the floating aspect. So the last thing I'm struggling with may just be me not understanding notation. At 8:07 you are talking about the variable supply. When I looked at the diagram I assumed + terminal of the variable is going in opposition to the + rail. Does the symbol not represent the direction of the voltage? (By which I mean the - variable terminal is at 10V and the variable + terminal goes down toward the ammeter)
@w2aew
@w2aew 6 жыл бұрын
The variable power supply basically sets the voltage that is generated between the + and - terminals of the supply. Since the + end of the supply is connected to the +10V supply rail, the - end of the supply is XX volts below +10V. For example, if the variable supply is set to 3V, then the - end of the supply will be at 7V in this circuit (10-3).
@claude77573
@claude77573 2 жыл бұрын
Can you explain why it was necessary to put a 470 ohm resistor across the outputs of the power supply to keep it sourcing current? Since a bench power supply typically has readouts for volts and current, I suppose one could "adjust" those readings to compensate for the resistor, correct?
@w2aew
@w2aew 2 жыл бұрын
In this setup, the power-supply would have to "sink" current (current flowing into the + terminal), and linear power supplies like this can't sink current. So, by placing a small resistor across the supply, the output will always "source" current and force the set voltage across the resistor. There is no adjustment to any readings necessary since we're not measuring the output current of the supply.
@claude77573
@claude77573 2 жыл бұрын
@@w2aew Thank you for your quick reply! I have a switching power supply. Can I ask a follow-up question? Do switching power supplies sink current into the + terminal? I am only a hobbyist, so it would take a great deal of research to try to figure this out, and the odds are good I would come up with the wrong answer!
@w2aew
@w2aew 2 жыл бұрын
@@claude77573 It likely can not sink current. Also, if you're going to replicate this experiment, you'll have to check the specs on your supply to see if the outputs are truly floating from ground.
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