2023 g12 maths paper 2 question 3 equation of the curve and geometric progression

Рет қаралды 23,541

4 ай бұрын

Get ready to master 2023 G12 Maths Paper 2 Question 3 in this mind-blowing video! 📚🔢 Dive into the Equation of the curve and unlock the secrets of Geometric Progression like never before. 🧠💡 Whether you're a seasoned math pro or just looking to ace your exam, this tutorial has got you covered! Join us as we break down the complexities of Question 3, step by step, to boost your skills and confidence. 📊✏️ Don't miss out on this educational journey that will change the way you approach math problems forever! 🌟🔥 #2023G12MathsPaper2Question3 #EquationOfTheCurve #geometricprogression .
Get ready to master 2023 G12 maths paper 2 question 3 with this in-depth video walkthrough! Dive into the Equation of the curve and Geometric Progression as we break down every step to help you ace this challenging question. Our expert analysis will guarantee you crack the code on this complex math problem. Don't miss out on the ultimate study resource to ensure your success in the upcoming exams. Tune in now to level up your math skills and conquer 2023 G12 Maths paper 2 question 3 like a pro!
Unleash your math wizardry with this in-depth tutorial! Dive into the intricacies of finding the equation of a curve using the derivative dy/dx, as showcased in the challenging 2023 G12 maths paper 2 question 3. Get ready to crack the code on Geometric Progression problems including terms of a GP, sum of a GP, and the grand finale - sum to infinity. Equip yourself with the tools to conquer these complex concepts step by step. Elevate your math skills and prepare to ace any challenge coming your way. Watch now and level up your math game like never before!
Unlock the secrets of mathematical prowess with this comprehensive guide on finding the equation of a curve and mastering geometric progression problems. Dive into the intricate world of math as we solve the challenging 2023 G12 maths paper 2 question 3, unveiling the equation of the curve based on the derivative dy/dx. Learn to navigate the complexities of Geometric Progression effortlessly, understanding terms of a GP, sum of a GP, and the elusive sum to infinity. Prepare to elevate your math skills and conquer any curve or progression thrown your way. Stay tuned and transform into a math wizard!
Are you ready to ace your 2023 G12 Maths Paper 2 Question 3? In this tutorial, we dive deep into finding the equation of a curve when given the derivative dy/dx and unraveling the secrets of mastering Geometric Progression problems. Learn how to effortlessly uncover the equation of the curve and tackle GP sequences like a pro. From terms of a GP to summing a GP and even exploring the sum to infinity, this video is your ultimate guide to mathematical success. Get ready to elevate your math skills and conquer the toughest problems with confidence. Watch now and amplify your mathematical prowess!

Пікірлер: 69

@GSCEMathematicsZone12 4 ай бұрын

You can also watch: 1. 2023 G12 maths paper 2 question 1 kzfaq.info/get/bejne/d9pjnc5-3LW7dp8.htmlsi=kYcKXQXcJPyWhXDO 2. 2023 G12 maths paper 2 question 2 kzfaq.info/get/bejne/d7eZe7l92tuqhmw.htmlsi=vtn9LtAuT67Wo7Ek Remember to subscribe, comment, like and share!!

@SarahNakiberu 4 сағат бұрын

Thanks

@GSCEMathematicsZone12 4 сағат бұрын

You're welcome

@HarrietNambeya-js2gc 2 ай бұрын

Thanks sir it's helping

@GSCEMathematicsZone12 2 ай бұрын

You are welcome. Kindly watch more videos on this channel and remember to like, comment and share.

@LenardTembo-xl4zi 2 ай бұрын

Thanks sir

@GSCEMathematicsZone12 2 ай бұрын

You are welcome. I'm glad you are enjoying. Kindly watch more of our videos on this channel and remember to like, comment and share.

@user-fm8su3pq5t 2 ай бұрын

Good going sir

@GSCEMathematicsZone12 2 ай бұрын

Thank you very much for the positive feedback. Kindly watch more videos on this channel, remember to subscribe, comment, like and share.

@EsauSiyunda 2 ай бұрын

Thanks sir for helping

@GSCEMathematicsZone12 2 ай бұрын

Always welcome. Watch how to calculate standard deviation of ungrounded data by clicking the link below and remember to comment, like and share: kzfaq.info/get/bejne/bJ-DprZ6tbqcqaM.htmlsi=ARHPi-KOdVduIdOi Look out to the 2023 Linear programming for internal candidates.

@Canaanmwitwa 23 күн бұрын

Well done sir, thank you so much .

@GSCEMathematicsZone12 23 күн бұрын

You are welcome. Keep watching more videos on this channel, and remember to like, comment, and share.

@GSCEMathematicsZone12 23 күн бұрын

You are welcome. Keep watching more videos on this channel, and remember to like, comment, and share.

@LutaKyandamali-yx4qp 2 ай бұрын

I'm enjoying your teaching sir

@GSCEMathematicsZone12 2 ай бұрын

Keep watching, thank you.

@BoydMunonka-ky7yl 2 ай бұрын

Wonderful teaching

@GSCEMathematicsZone12 2 ай бұрын

Thank you very much and am glad you are enjoying. Feel free to join us every time we post a video and whenever we are live. You can also watch the 2023 G12 Maths Internal play list by clicking on the link below and remember to like, comment and share. kzfaq.info/sun/PLDIAIX5z4ETmY6x5Dv80mbgBybBCsNSxw&si=3wAc4BwCZwU_rNdV

@MosesMwalakanya Күн бұрын

Sir thank for teaching me God bless you because have get enough

@GSCEMathematicsZone12 Күн бұрын

Thank you very much. Keep watching.

@MUKESILILO 5 күн бұрын

Well done sir 👏

@GSCEMathematicsZone12 5 күн бұрын

Thank you very much. Keep watching more videos on this channel, and remember to like, comment, and share.

@user-gw1xl1uq7p Ай бұрын

Thank you very much sir But sir which formula can be used when r is greater than 1

@GSCEMathematicsZone12 Ай бұрын

You are welcome. For the sum of a geometric progression when r >1, use the formula, Sn = a(1 - r^n)/(1 - r) where r is the common ratio, a is the first term, n is the number of terms and S is the sum.

@user-gw1xl1uq7p Ай бұрын

@@GSCEMathematicsZone12 Thank you very much sir

@GSCEMathematicsZone12 Ай бұрын

@user-gw1xl1uq7p you are always welcome 🙏

@mkworldwide2 23 күн бұрын

This is amazing thankyou sir

@GSCEMathematicsZone12 23 күн бұрын

Thank you very much. Keep watching more videos on this channel, and remember to like, comment, and share.

@emmanuelkachunga-we5ls 2 ай бұрын

Wonderful

@GSCEMathematicsZone12 2 ай бұрын

Thank you very much. We are glad to help. Kindly watch more videos on this channel and remember to like, comment and share.

@NabifoAnna 2 ай бұрын

Sir am happy for that

@GSCEMathematicsZone12 2 ай бұрын

I'm glad to help ☺️

@MariaNgoma-qi5hh Ай бұрын

Very nice teaching sir

@GSCEMathematicsZone12 Ай бұрын

Thank you very much. I'm glad you are benefiting from our videos. Keep watching more videos on this channel and remember to like, comment and share.

@Kay-ti7su 2 ай бұрын

This was great Sir can you also tell me of a principal of accounts teacher please I've got u in math and am looking for a teacher of accounts

@GSCEMathematicsZone12 2 ай бұрын

Thank you very much for your positive feedback. We are really glad to help. For Principles of account, you can subscribe and watch videos of the channel in the link below kzfaq.info/get/bejne/nr-beNqop53YZ40.htmlsi=_taJYhbh0P1rAB0H

@Kay-ti7su 2 ай бұрын

@@GSCEMathematicsZone12 so Sir u mean that u also do grade 10, 11, 12 principal of accounts if u do please I want to be good in accounts before I go in grade 12 🥺🥺

@GSCEMathematicsZone12 2 ай бұрын

@Kay-ti7su not really. I don't do principles of accounts, I just recommended a channel to you that does that.

@user-fw3fz7hx1k Ай бұрын

That is good sir continue

@GSCEMathematicsZone12 Ай бұрын

Thanks a million. Keep watching more videos on this channel. Remember to like, comment and share.

@monicahchivunga-dy3fq Ай бұрын

sir after negative 2 closed The equal sine y didn't it change to positive?

@GSCEMathematicsZone12 Ай бұрын

Kindly be specific, where exactly? I'm happy to explain and help.

@GSCEMathematicsZone12 Ай бұрын

Kindly be more specific, which part of the question is that? I'm happy to help 😊

@monicahchivunga-dy3fq Ай бұрын

there ...where you have put negative 2...it was already ...negative...but when it closed the equal sine..you maintained negative sine..again..y didn't it change..to positive...sine

@Trafalgarlaw299 Ай бұрын

@@monicahchivunga-dy3fqThe 2 didn't Cross the equal sine sir just put it in a way that instead of it being - 2 =C he just put it C=-2 so that C becomes the subject

@NabifoAnna 2 ай бұрын

Ooh teacher thanks for da help🎉🎉

@GSCEMathematicsZone12 2 ай бұрын

You're welcome 😊kindly watch more of Maths videos on this channel. Please remember to like, comment and share.

@BalukuMonic721 2 ай бұрын

Thanks sir can I join u always

@GSCEMathematicsZone12 2 ай бұрын

You are always welcome and am glad you are enjoying. Feel free to join us every time we post a video and whenever we are live. You can also watch the 2023 G12 Maths Internal play list by clicking on the link below and remember to like, comment and share. kzfaq.info/sun/PLDIAIX5z4ETmY6x5Dv80mbgBybBCsNSxw&si=3wAc4BwCZwU_rNdV

@jeniphermwenya7370 2 ай бұрын

I'm understand 🎉🎉

@GSCEMathematicsZone12 2 ай бұрын

Great 👍 I'm glad to help.

@AgeaJoshua 24 күн бұрын

Master tnx we are enjoying

@GSCEMathematicsZone12 24 күн бұрын

You are welcome. Glad to hear that.

@GSCEMathematicsZone12 24 күн бұрын

Glad to hear that.

@Trafalgarlaw299 Ай бұрын

Sir in a GP the common ratio isnt it 2nd term Divide by First term so wasnt the common ratio just 2

@GSCEMathematicsZone12 Ай бұрын

You're right when you say, the common ratio is the next term divided by the previous term. Please be careful on that, the next term should always be the numerator while the previous term should always be the denominator. Hopeful this is now helpful.

@richardmake817 Ай бұрын

Sir you would have shown the formula on first question for calculus ❤❤ this is powerful and C= 2 if c crosses to the other side of the left it becomes -c=-2 So for us to kill negative we will divide both sides with -1 so that -2 becomes positive 2.

@GSCEMathematicsZone12 Ай бұрын

Thanks for your comment. We really appreciate it.

@richardmake817 Ай бұрын

You are most welcome