All these years, I haven't seen anyone explain arrow functions any better

let input1 = Math.abs(5); let input2 = Math.abs(-7); let sum = (num1,num2) => num1 + num2; let result = sum(input1,input2); console.log(result);

This was easy for me because I saw your Java Lambda videos some time ago. You did a great job explaining how an anonymoys class can be converted into a lambda expression.

i took paid course from other but i cant understood arrow functions there , so i came here 😂😂😂,,, atlast we all have to come to 'mentors of all mentors'

Sir you are the inspiration and you are the one of the best guide. Keep going sir we all supports you.

Enjoying your course a lot! It's great to be a part of your alienArmy👽 Here's my solution for the assignment question: let func = (num1, num2) => (num1>=0 && num2>=0)?num1+num2:"positive numbers only";

time stamp: 5:10 // Assignment => let addition = function(num1, num2) { if (num1 > -1 && num2>-1){ console.log(num1 + num2); } else{ console.log("One of those number is negative"); } } addition(1400, 56); Output -- 1456

let add = (num1, num2) => (num1

We can use Math.abs(num1) + Math.abs(num2) for converting negative to positive.

great use of comments in the lower half of the screen. Nice pace. Not too long. I have watched a lot of bad videos trying to teach fat arrow functions and this is the best Thank you. @Telusko

Thanks, I was a bit confused with arrow functions which you made it so simple to understand.

const add = (num1, num2) => { const condition1 = Math.sign(num1); const condition2 = Math.sign(num2); if ((condition1 && condition2) === 1) return num1+num2 else return ('given num is zero or negative') } let result = add(1,9); console.log(result);

I made the 1000th like. Thanks Navin. Having concepts simple and crisp makes it easy for daily learning.

let a1 = Math.abs(5); let a2 = Math.abs(-7); let sum = (num1,num2) => num1 + num2; let result = sum(a1,a2); console.log(result);

let add=(n1,n2)=> { let n3=Math.abs(n1); let n4=Math.abs(n2); return n3+n4; } sum=add(4,-9); console.log(sum);

let add = (num1,num2) => Math.abs(num1) + Math.abs(num2); let result = add(-5,-6) console.log(result)

Solution to question at 5:30 let n1=6,n2=-4 let add=(n1,n2)=>{ if (n1

5:07 Answer: let add = (a,b) => { if(a

As usual - very well explained

After all this time, I can say I understand what the hell a arrow function is now!!!! Dude thanks :)

let add = (num1,num2) => num1+num2; let a=Math.abs(5); let b=Math.abs(-7); let result = add(a,b); console.log(result);

let add = function(num1, num2) { num1 = (num1 < 0) ? num1 * -1 : num1; num2 = (num2 < 0) ? num2 * -1 : num2; return num1 + num2; } let result = add(5, -6); console.log(result); is that right or wrong?

let sum =(a,b)=>{ if (a

he didn't mention one of the main features of the arrow functions. Arrow functions do not bind their own "this", instead, they inherit the one from the parent scope

I challenged myself to use Ternary Operator: (it is not a best practice to use nested ternary operators) let addNeg = (num1, num2) =>{ return num1

let t = (n1, n2) => (n1

let add = (a,b) => { if (a

So useful, i always use this. Just love it 💕

let a=4;let b=* Math.abs(-6);let add=(num1,num2)=>num1+num2;let output=add(a,b);console.log(output);

let sum=(num1,num2)=>{ result=num1+num2; if (result>0){ console.log(`value is ${result} +ve`); }else{ console.log('enter correct value'); } } sum(5,6)

// Assignment // const add = (num1, num2) => { if(num1>0 && num2>0) { return num1 + num2 } else { return "negative number" } } let result = add(2,-3) console.log(result);

let add = (num1,num2)=> (Math.abs(num1)+Math.abs(num2)) ; let result=add(5,-6); console.log(result);

Whats the benefit in this case using an arrow function instead of function expression? For now, I see the difference is that you can save the brackets if its only 1 statement and you can remove the return keyword.

Great tutorials man!

let n1=+prompt("enter first num"); let n2=+prompt("enter second num"); let sum =add(n1,n2); let add = (n1,n2)=>Math.abs(n1)+Math.abs(n2); console.log(sum);

this is amazing thank you so much

let sum = function (n1, n2) { var result = n1 + n2; if (result > 0) { console.log("+VE"); } else if (result < 0) { console.log("-VE"); } }; sum(5, -6); //MuraliVelyudam//

GREAT explanation! Thank you!

5:10 let add = function(num1,num2) { if (num2 < 0) { let positive_coverter = -1; num2 = positive_coverter*num2; return num1+num2; } else return num1+num2; } let result = add(3,-8) console.log(result);

Nice of you to make a video to help others. Though you seem to understand how to write an arrow function, I don’t think you understand the purpose of it. Use a Class in combination with .this That’ll help your audience understand the purpose of the code and then why you write it will make sense. And dude, don’t say things like “I know it doesn’t make sense but…” You can say that about an advanced topic you’ll cover in the future but you can’t say that about the core topic you’re teaching. Hope this helps. Good luck mate.

var add = (num1,num2) => Math.abs(num1) + Math.abs(num2) var result = add(-10,-10) console.log(result) // it will print 20 .

Such a good explanation

let add=(a,b)=>{ if(a>=0&&b>=0) return a+b else console.log("one of the input is negative") } let result=add(2,-3) console.log(result)

Very easy questions for me because I have learned data structure and algorithms But I have learned my first programming language from you🥰🥰

let add = (num1,num2) => num1 + num2; console.log(add(5,6));//it will also work

we can do different way- 1st way without inbuiled func:- let add=(num1,num2) => num1+(num2*-1); let result=add(5,-6) console.log(result) 2nd let add=(num1,num2) => num1+(-num2); let result=add(5,-6) console.log(result) 3rd way with inbuiled let add=(num1,num2) => num1+num2; let num1=Math.abs(5) let num2=Math.abs(-6) let result=add(num1,num2) console.log(result)

last question answer: let add=(num1,num2)=>{ if (num1>0 && num2>0) return num1+num2 else return "Only positive numbers are allowed as input" } let result=add(3,-4) console.log(result)

NICE SUPER EXCELLENT MOTIVATED

wow so much cleaner . thank you

function add(num1,num2) { return num1 +num2; } num1 =10; num2 =-17; let result= add(10,-17) if (num1

My answer of the exercise at 5:06: //By @iamsanbarb let add = (num1, num2) => num1 + num2; let result = add(Math.abs(5),Math.abs(-6)); console.log(result);

let add=(n1,n2)=>n1+n2 let rslt=add(-9,-6) console.log(rslt*-1)

7:31 let add = (num1, num2)=> { if (num1 > 0 && num2 >0) return num1 + num2 ; else console.log("Please add positive numbers only"); // return undefined; } let result = add (5,-6); console.log(result);

let add = (num1, num2) => num1 && num2 > 0 ? num1 + num2 : "unvalid positive num"; console.log(add(5, 8))

let doit = function(num1,num2){ if(num1>=0&&num2>=0){ console.log(num1+num2) } else{ console.log(num1) } } doit(50,-5)

This video is very useful and understandable thanks

great explanation

const add = (a,b) => Math.abs(a) + Math.abs(b) console.log(add(-2,-5))

let add = (n1, n2) => { if(n1 / (n1 * (-1)) == -1 || n2 / (n2 * (-1)) == -1) { return "-ve number alert" }else{ return n1+n2; } }; console.log(add(5,6)); this will give you the always positive output.

so can you use a arrow function with more than one statement ? and if so do you still have to include the curly brackets?

Bro I easily understood 😮😮

you got a new subscriber🥳🥳

I enjoyed this Video.

let add = (num1, num2) => num2

let ans = (a,b) => { let num1 = Math.abs(a) let num2 = Math.abs(b) return num1 + num2; } console.log(ans(-78,22)); // 100 is the output

great guide

The code for the assignment is: let add = (num1, num2) => { if (num1 > 0 && num2 > 0) return num1 + num2; else return "Can't add negative numbers"; } const prompt = require("prompt-sync") ({sigint: true}); let num1 = Number.parseInt (prompt ("Enter the first number: ")); let num2 = Number.parseInt (prompt ("Enter the second number: ")); let ans = add (num1, num2); console.log (ans);

Thanks for your efforts 🙏

SIR IS MACBOOK PREFERED FOR PROGRAMMING OVER WINDOWS?

Great video!

Nice explanation.

let hbd = (num1,num2) => num1 + num2 ; let ver = hbd(Math.abs(5) , Math.abs(-6)); console.log(ver)

assignment ..... let user = (a,b) => a + b a= 1 b= 2 let result = user(a,b) if(b

good explanation

i understood in a sec tysm🙏

let n1=Math.abs(3) let n2=Math.abs(-4) let add=(n1,n2)=>n1+n2; let R=add(n1,n2) console.log(R)

so simple thank u

let add = (num1, num2) => { if (num1

let add = (num1,num2) => Math.abs(num1)+Math.abs(num2) console.log(add(6,-5))

let addsum = (num1,num2,num3=1) => { //arrow function return num1 + num2 + num3 } let sak = addsum(15,Math.abs(-6)); console.log(sak)

let sum = (num1,num2) => (num1 >= 0 && num2 >=0) ? num1 + num2 : (num1 >=0 ? num1 : num2); is this the answer? my logic is- only add nos if both are non negative. else return any no which is non negative

let a = Math.abs(6) let b = Math.abs(-7) let sum = (num1,num2)=> (num1+num2) let result = sum (a,b) console.log(result);

Assignment Question: let addPos = (a,b) => Math.abs(a)+Math.abs(b) console.log(addPos(-6,-3))

Plz Uplaod Daily Maybe Not 2-3 videos but only 1 video daily

Easy to understand

Isn't it the same as lambda function from python

Hi Naveen, please make videos on reactJS it would be helpful.

let add = (a,b) => { if (a+b < 0){ return "the number will be less than 0" } return a+b } console.log(add(2,3));

let add = (num1, num2) => { return convertToPositive(num1) + convertToPositive(num2); } let convertToPositive = (num) => { return num > 0 ? num : num * -1; } let sum = add(10, -5); console.log(sum);

Can i do hoisting using arrow functions have a doubt sir waiting for your reply

How to use scanner in javascript or ex: how ask a user to enter num1 and num 2

is there any multiline commenting in javascript??

let addition = (num1,num2) => { if (num1 < 0 || num2 < 0) { return "Negative Numbers not accepted"; } return num1 + num2; } console.log(addition(3,-2));

let sum = (a,b) => { a = Math.abs(a) b = Math.abs(b) return(a + b) } console.log(sum(10,-20));

let exe = (num1,num2) => { if (num1< 0 || num2 < 0) console.log("negatives we can't add") else console.log(num1+num2) } exe(4,-5) //negatives we can't add

i reallly dont know about arrow funtion before, i just search for arrow function in JS and got yours , I am completely understood now thanks @telusko

let add=(num1,num2)=>{ if(num2

let add = (num1,num2) => { if(num1 < 0 || num2 < 0){ console.log(`Negative Number detected!`) } else{ let result = Number(num1) + Number(num2) console.log(`The result is ${result}`) } } let num1 = prompt("Enter first number:") let num2 = prompt("Enter second number:") add(num1,num2)

sir can you make videos on react js it would be helpful

let nnum = (a,b) => (a