Thanks for that! I really appreciate the motivation :)

Glad to help mate! :)

Haha! Thanks..

I'm glad you did!

Thanks so much!

Very glad that it helped! Thanks for checking it out!

Thanks so much! I'm glad you enjoyed the way it's presented. I try to make it as intuitive as possible. It might not always be evident if something is intuitive or not, as people have differing depths to their knowledge

You're welcome mate!

You're welcome mate! Thanks for checking it out..

Glad it was helpful!

Haha..thank you! I'm glad you approve!

You're welcome! Thanks for checking it out

Cheers!

So, let's split the question up. The computer doesn't know anything about pressure. Pressure is a quantity that only exists in the physical world. In analog devices, like microphones, the pressure of the physical medium is converted into changes in voltage. In a computer, these changes in voltage are represented as binary data. All the computer knows is what the maximum value of this data can be, and minimum value it can take. For example, if you have a 16 bit recording (signed PCM -32768 and +32767), each audio sample can theoretically have a maximum level of 32768, and a minimum level of 0. So in a computer, since each sample is represented by a fixed size, you cannot have any levels above or below this. Now, going back to your first question, why is it 0dBFS in DAWs. That's a choice that computer engineers have made. They have chosen the reference level to be the maximum possible value that an audio sample can hold. So dBFS calculations for 16 bit audio are made like this: 20log(value/32768) So if you apply this formula for the highest sample value (32768), you get 20log(1) = 0dBFS Any values above this are clipped. The lowest value would be -96dBFS, below that, it's just silence. There is no relation between dBSPL (pressure) and dBFS (full scale amplitude in computers). Though they may have the same term "decibels" associated with it, they don't share any relationship.

Glad you stumbled upon it!

Thank you!

Thanks mate! :)

Cheers!

Thanks very much! Yea, the 10 or 20 multiplier is covered in the next video in the series, that should give you a good understanding as to why a certain multiplier is used. It's got to do with whether the quantity is a power quantity or a field quantity.

Thanks for the support!

Cheers mate..!

Please let me know , about animation tools?

Oh is that what you wanted to know? I record the audio for the explanation first. And then I animate the sequences using Adobe After Effects. That's pretty much it.

@@akashmurthy ohh , got the answer I wanted 👍👍thank you ji

Cheers mate! I use After Effects

@@akashmurthy I hope you don't lose your passion. This channel is severely underrated!

Hey! Thanks for checking it out. Your statement about doubling sound pressure is a common cause for confusion. We can calculate it right now! We just need to find out what happens when pressure p is doubled. We can calculate dbSPL as: dbSPL = 20 log (2p/p) = 20 log(2) = 20 * 0.301 = 6.02 So doubling pressure gets you +6dbSPL. The +3db increase that you might've heard about elsewhere applies to power quantities, like Sound Intensity. Sound Intensity(SIL) can be calculated as: dbSIL = 10 log (2I/2) = 3.01 So doubling intensity gets you +3dbSIL. Does that make sense?

@@akashmurthy Ah I understand. If you want to double the sound pressure, you have increase dBspl with +6dB and if you want to double the sound intensity, you have to increase dBsil with +3dB. And the reason for this is that sound intensity includes the direction of sound, making the distance an exponential factor where sound pressure and distance is a linear relationship. Do I understand it correctly? Regarding perception, "sound intensity" sort of implies that this is how we perceive loudness. Would a doubling in dBsil be perceived as a doubling in loudness? Again man, thanks so much for these video's. Just checked 2 more and they are absolutely brilliant.

@@martijnbos9873 Well the reason for the difference is because of the physical relationship between pressure and intensity. In physics, Intensity is proportional to the square of the pressure. That's the defining factor, not distance. Squaring on the linear scale is multiplicative on the logarithmic scale (decibel scale). Don't worry about this statement if you don't get it. And we perceive sound as pressure, not intensity. I mention this on the 5th video in the series! Doubling pressure is equivalent to increasing by +6dbspl, does that mean loudness is doubled as well? Maybe, maybe not. Loudness is very subjective and is also dependent on frequency of the source material. You can say that increasing pressure anywhere between 6 to 10 dbspl could result in a perceived doubling of loudness.

@@akashmurthy Thanks for the explanation!