3 Techniques of Retinoscopy

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smart optometry

smart optometry

Күн бұрын

#optometry #optometrylectures #smartoptometry #Retinoscopy
✓Updated Video link: • Updated- Retinoscopy j...
•Note: In this video Horizontal meridian is mentioned as Vertical & Vertical meridian is mentioned as Horizontal meridian. But the procedure is right. If you find it difficult to understand watch the updated video in the above link.
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Пікірлер: 26
@ashishgupta-rf8kg
@ashishgupta-rf8kg Жыл бұрын
How to difine to axis 90 or 180 if movement is seasor movement
@sharadahire614
@sharadahire614 Жыл бұрын
Thanku sir now my doubts are clear 😊
@optometry-with-samir
@optometry-with-samir Жыл бұрын
Stay with us and share with your friends. Don't forget to download our app "Optometry Notes & MCQs". It's available in Google Play Store. Thank You, Samir Sutradhar.
@anush_a__anu_
@anush_a__anu_ Жыл бұрын
Thank you ... ❤
@optometry-with-samir
@optometry-with-samir Жыл бұрын
▪️Stay with us and share with your friends. ▪️Don't forget to download our App "Optometry Notes and MCQs ". It's available in Play Store. Thank you, Samir Sutradhar.
@ShivShankar-zz8hl
@ShivShankar-zz8hl Жыл бұрын
Nice video
@optometry-with-samir
@optometry-with-samir Жыл бұрын
Thank you Shiv
@user-xi1ot3tp6v
@user-xi1ot3tp6v Жыл бұрын
Why did we keep the cyl trial lens at 90° only in the 1st method?? Pls explain
@optometry-with-samir
@optometry-with-samir Жыл бұрын
You can take any meridian as cylindrical meridian. I took horizontal meridian as cylindrical meridian that's why I put cylinder axis at 90°. There is no specific rule that we have to keep cylinder 90° axis only. Watch updated version of this video here: kzfaq.info/get/bejne/bJiCp9Kcnb_HgIE.html
@nikhilmote9013
@nikhilmote9013 Жыл бұрын
Nice
@optometry-with-samir
@optometry-with-samir Жыл бұрын
Stay with us and share with your friends. Don't forget to download our app "Optometry Notes & MCQs". It's available in Google Play Store. Thank You, Samir Sutradhar.
@manavaiboys
@manavaiboys Жыл бұрын
In 2 spherical method Usually we take the sph value from least Power Meridian in optical cross then why took largest value for sphere . it's confusing
@optometry-with-samir
@optometry-with-samir Жыл бұрын
Least or largest power meridian formula will come after knowing the mechanism. As an optometrist you have to know everything then follow the specific rule. There is no such rules that we can't take larger power meridian as Spherical meridian. You can take any meridian as Spherical.
@priyankachandran3722
@priyankachandran3722 Жыл бұрын
If the reflex is oblique how can neutrilized
@optometry-with-samir
@optometry-with-samir Жыл бұрын
You have to rotate the retinoscopic slit to align with oblique axis. Then neutralize the meridian with any of the one technique. Watch this video few times. By imagine, you can't learn retinoscopy. Start practicing in patient.
@shivanipal7846
@shivanipal7846 Жыл бұрын
Sir Hindi language mei thoda define kr diya kriye pls sir
@otaigbeiyere3406
@otaigbeiyere3406 Жыл бұрын
Pls u are missing up axis and meridian,wen u scope up and down with the light at horizontal,u are scoping on the vertical meridian and horizontal axis,pls don't mistake meridian from axis
@optometry-with-samir
@optometry-with-samir Жыл бұрын
You are right..... The procedure or method is correct but there are some mismatching/misrecording between the axis and meridian. Soon we will upload updated version of this video..... Thank you, Team Smart Optometry.
@optometry-with-samir
@optometry-with-samir Жыл бұрын
✓Updated Video link: kzfaq.info/get/bejne/bJiCp9Kcnb_HgIE.html •Note: In this video Horizontal meridian is mentioned as Vertical & Vertical meridian is mentioned as Horizontal meridian. But the procedure is right. If you find it difficult to understand watch the updated video in the above link.
@sabafarooq6521
@sabafarooq6521 Жыл бұрын
Clear my confusion. In 1st technique, You 1st neutralized verticle axis, with sphere. And then you neutralized horizontal axis with cyl. You did a mistake there, in axis identification.
@optometry-with-samir
@optometry-with-samir Жыл бұрын
There is no mistake. First technique is "Neutralize one meridian with Spherical trial lens (Spherical meridian) and other meridian with Cylinder trial lens (Cylinder meridian). Watch this technique few times more, distribute the power in optical cross then converted into prescription from, try in real patient. This is the easiest technique.
@anush_a__anu_
@anush_a__anu_ Жыл бұрын
Yeh i' m also confused 🙄
@optometry-with-samir
@optometry-with-samir Жыл бұрын
✓Updated Video link: kzfaq.info/get/bejne/bJiCp9Kcnb_HgIE.html •Note: In this video Horizontal meridian is mentioned as Vertical & Vertical meridian is mentioned as Horizontal meridian. But the procedure is right. If you find it difficult to understand watch the updated video in the above link.
@skhan-Utube
@skhan-Utube Жыл бұрын
Your description is causing a bit confusion between Meridian and Axis . Meridian is determined by the direction of Streak movement , to and fro . If Streak is moving horizontally , then you are scanning Horizontal meridian. So The result will be written for Horizontal Meridian on the Horizontal side of cross, and vice versa. where as Streak direction or orientation indicates Axis in Angle . If Streak is vertically oriented then axis is near 90 , and vice versa.
@optometry-with-samir
@optometry-with-samir Жыл бұрын
You are right..... The procedure or method is correct but there are some mismatching/misrecording between the axis and meridian. Soon we will upload updated version of this video..... Thank you, Team Smart Optometry.
@optometry-with-samir
@optometry-with-samir Жыл бұрын
✓Updated Video link: kzfaq.info/get/bejne/bJiCp9Kcnb_HgIE.html •Note: In this video Horizontal meridian is mentioned as Vertical & Vertical meridian is mentioned as Horizontal meridian. But the procedure is right. If you find it difficult to understand watch the updated video in the above link.
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