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#56 Dynamic Method Dispatch in Java
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in this video we are discussing method dispatch
-- in previous lecture we had discussed what is polymorphism
-- in this lecture we are further talking about run time polymorphism
-- suppose we have some class A , B and C
-- class B and C extends A
-- in All three class we have show() method
-- main() method of Demo we create object of A, B and C but we create only reference of A which can hold
object of A, B and C .
class A{
public void show(){
Systeem.out.println("in show A");
}
}
class B extends A{
public void show(){
Systeem.out.println("in show B");
}
}
class C extends A{
public void show(){
Systeem.out.println("in show C");
}
}
public class Demo{
public static void main(String []args){
A obj =new A();
obj.show(); //Output: in show A
obj =new B(); //reference is A (we can use reference of parents) and create object of B and assign to parents reference variable.
obj.show(); //Output: in show B
obj =new B(); //reference is A (we can use reference of parents) and create object of C and assign to parents reference variable.
obj.show(); //Output: in show C
}
}
Note: during compile time we donot which show() method is called from which class.
-- we can know during run time which show method is called this is known as run time polymorphism.
-- all this concept is class dynamic method dispatch
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@user-mk6um6rh1j 11 ай бұрын
Really you deserve a Dhrona Charya award sir. I've learn a looooooooot from you than I had learnt from my college.
@BLG120 5 ай бұрын
Dont flex too much. It ll be a loooooooooooot of problem for u in future
@thangutabbycat 4 ай бұрын
That's too over bro 😂
@magxbeats 10 күн бұрын
@@BLG120bro be humble
@vijankaush7308 Жыл бұрын
The best JAVA tutorial series ever
@MohamedWasim-gh6eh 7 ай бұрын
Sir you have God gifted knowledge no one can explain this clear thank you.
@kilvish25 2 ай бұрын
You said we don't know at the compile time which method will be called, But we know right, the method inside the class whose object is actually created, will be executed. So how exactly is this run time polymorphism.
@shishirbagalkot3404 21 күн бұрын
I think maybe he meant compiler does not know
@yeshwanthreddy6014 6 ай бұрын
Great place to learn or brush up java. Keep doing this great work sir.
@RealRameshBabu 4 күн бұрын
Practical and precise explanation
@raghav9721 6 ай бұрын
As am a Java Trainee Trainer Telusko videos are 💎
@onlysubscriptions2152 29 күн бұрын
Dynamic method dispatch is the mechanism by which the call to an overridden method is resolved at runtime rather than compile-time. This occurs when a superclass reference variable is used to refer to a subclass object, and the overridden method is called on that reference. The method to be executed is determined based on the actual object's type, not the reference variable's type.
@bhabagrahibarik1239 4 ай бұрын
The best explaination ever in few minutes. Thanku sir for the best explanation.
@user-ir2vf2nw6d Жыл бұрын
easy to understand! you are my saver!!
@mackensonreginaldmichel399 Жыл бұрын
Very interesting. Thank you very much. I'd like to know now: what element is polymorphic now: the variable obj? The method show()? The type? The Object?
@meenakshiviswanathan8409 Жыл бұрын
The concept of dynamic method dispatch makes the show() method to be polymorphic. Ie. Polymorphism is one interface multiple method .. By providing same method name in all child classes we are making it as an single interface which can operate as multiple method based on instances of class Real time scenario : If we have new implementation (new classes that implements super classes) for some old existing classes we can migrate it smoothly without having to break the code (ie. If we had used superclass reference variable to refer to the object, we can still pass the object of new implementation without need to worry about code breaking)
@janardhanreddyboyalla2941 Жыл бұрын
Great Explanation
@vasanthv4233 Жыл бұрын
superb explanation Sir thank you!
@avichiii 4 ай бұрын
that was an beautiful explanation. you earned a sub
@PraveenKumar-sk5sd 6 ай бұрын
Very Clear Understanding For Me...
@shreedharmakr2523 Жыл бұрын
Lets say there is a class A and class B (without inheritance), so to create objects we say { A obj = new A(); B obj2 = new B() }, now obj and obj2 are variables referring to objects (but what it actually holds is an address location), does it mean different classes have different type of address location?
@maryamgull1536 11 ай бұрын
yes
@k.kanimation4436 3 ай бұрын
Thanks a lot sir for ez understanding series💖
@sreeramv1579 Ай бұрын
Then what is the difference between function overriding and polymorphism sir?
@chakkers Жыл бұрын
Sir will this work if B extends A and C extends B. Is it possible to call show method of class A from C
@shaikmadani1898 9 күн бұрын
yes its possible
@user-ke1fj9eo6v 6 ай бұрын
When i give method name as show1() in class B and method name as show2() in class C and when I create object for B and and try to access the particular methods of particular classes it is not working. but it is working only when all the method names in all classes is show(). this is how i called method in B class obj=new B(); obj.show1(); @Telusko Please give me clarity on this, I was bit confused
@VarunGowda-ho2rm 3 ай бұрын
This video works only with method overriding. When you create an object of child class with reference of parent class You can use only parent class methods
@user-sw1mg8ni6l 4 ай бұрын
The example of laptop and computer is best.
@sinekad5132 11 ай бұрын
Thank you sir❤
@agariogg172 Жыл бұрын
Excellent explanation, I just noticed you look a little bit like Nacho from Better Call Saul :)
@funoverflow 5 ай бұрын
3:16 this is a heterogeneous object creation right?
@shaiknagurbasha9657 5 ай бұрын
Is it mandatory to define a main method with in show method of class A i got bit confusing y i should call main method in class A rather then we call main method in our demo class is it acceptable Give me the valid ans any one.....
@gujjushanmukhasaipavankuma8983 Жыл бұрын
Runtime polymorphism or Dynamic Method Dispatch
@neerajgarg9096 11 ай бұрын
is it different to C++ because in C++, if we create a pointer of base class and pointed it to derived class object then if we run any function using that pointer it will run function of base class and not of derived class , completely opposite to this tutorial is i am right?
@mrigankadhar8204 6 ай бұрын
Yes you are correct. I was looking a comment which had the same query. Finally found one guy !! cheers
@ehteerk Жыл бұрын
I thought my doubt would finally resolve but no class A{ public void show(){} } class B extends A{ Public void hi(){} } if we create a ref of parents to obj of child is there any way i can access child class methods A obj= new B(); obj.hi(); //thissss
@sonujhariya 10 ай бұрын
that's exactly how you do.
@radheambhure2112 Жыл бұрын
Yogiji : Aj se tumhara naam taklusko
@varuntanwar6746 Жыл бұрын
once we have gone through*
@rooparoy7775 Жыл бұрын
Where are u from sir?
@karanvirsagar1998 Жыл бұрын
It's working fine like: Vehicle c = new Vehicle(); c.showName(); c = new Car(); c.showName(); But shows an error: Type mismatch: cannot convert from Vehicle to CarJava(16777233) Car c = new Car(); c.showName(); c = new Vehicle(); c.showName(); --------------------------------------------------- Vehicle is the parent class....
@neerajgarg9096 11 ай бұрын
we can create reference of parent class and points it to object of child class like what u do in 1st case but we can't do opposite like we create reference of child class and points it to parent class that's why give an error in 2nd case class Phone{ public void name() { System.out.Println("I am phone"); } } Class SmartPhone extends Phone{ public void name() { System.out.Println("I am Smartphone"); } } public demo{ public static void main(string[] args){ Phone obj = new SmartPhone(); // this is correct we can call any smarphone as a phone (Phone obj ) is reference of parent class and new SmartPhone() is object of child class and this can be done but SmartPhone obj = new Phone(); //this is incorrect because we can't say any phone as smartphone as (SmartPhone obj ) is reference of child class and new Phone() is object of parent class and this will throw an error } }
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