97% Students Answer This Trigonometry Question Wrongly !

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BHANNAT MATHS

Күн бұрын

Пікірлер: 354

@jamilbarbhuiya813 10 ай бұрын

This question deserves to be the most hated problem of trigonometry

@itsmeadi...2006 9 ай бұрын

Phir sir ne kya bola wahi to bola hai 🙄

@aakritkatyal9135 8 ай бұрын

4 step mein hogaya 😂

@shoyo_Ishida 8 ай бұрын

Naa!!

@aakritkatyal9135 8 ай бұрын

@@shoyo_Ishida solution chaiye

@shoyo_Ishida 8 ай бұрын

@@aakritkatyal9135 noop!!

@user-ym4ci4rv5z 10 ай бұрын

Long but predictable method: sin (kpi/m), k=1..n are roots of equation sin(mx) = 0. So we expand sin(mx) in powers of sin(x) to get a polynomial equation in sin(x) of degree m. For m = 7 we get: sin(7x) = -64sin^7(x) +112 sin^4(x) -56 sin^2(x) + 7sin(x) =0. We can eliminate sin(x)=0 as solution, so the products of the remaining 6 roots is 7/64. This product is square of the required quantity.

@MyOneFiftiethOfADollar 8 ай бұрын

Did you "predict" the method prior to looking at the solution?

@Aditya_196 8 ай бұрын

Yeah bro same 😂 I once was curious and derived sin5x , 7x 9x 11x and those r some neet results if u want an interesting question check this .. what is the coefficient of last 3rd term of sin101x given that it's expansion is organised on the basis of descending order of powers of sinx ... Sayd question smjh me aagya hoga kya bol rha .... Actually mein general term ka coefficient khoj rha tha nahi mila but kuchh terms me pattern mila

@marrythebun-bun2501 7 ай бұрын

Hey please tell which theorem or Formula you have used, please tell the name 😢

@user-wd7yy2fm7g 5 ай бұрын

We can use complex numbers where w = cos(2pi/n) where w is nth root of unity

@cofanavay2235 9 ай бұрын

I have created formula see here for n=7 x=√7/8=} x^2 = 7/(8^2) And for n x^2=n/(2^[n-1]) ...😊

@Ayush-yj5qv 5 ай бұрын

Yeah easiest method

@ADARSHYODHA 9 ай бұрын

As a student of 10th class, I think trigonometry is used more in making questions harder , instead of finding length of a building.😂😂😂 Edit:Oh my god mai toh famous ho gya.

@prabaln4752 9 ай бұрын

Yes you thinks😂 correct

@skies_anuj 8 ай бұрын

Bilkul shi pakdo ho munna

@nirmalsurendranmenon7049 8 ай бұрын

😂😂😂😂😂

@heemensu 8 ай бұрын

it will make your analytical and critical thinking stronger... which are basics of logic development

@BeastModeWorkout24 8 ай бұрын

No, we use trigonometry in physics at an advanced level, therefore these difficult problems help us in that way.

@_elusivex_ 10 ай бұрын

Sir, i saw your video on the same problem and the next morning when i was searching for the video, i didn't find it anywhere, not even in my history, but then i thought that you might have deleted the video. Thanks for re uploading the problem.

@nishantpatriot3297 10 ай бұрын

Same with me😅

@benYaakov 10 ай бұрын

In general , it can be proved using complex numbers that: multiplication of 'N' terms of sines where each acute angle is in A.P. such that the first term is equal to common difference and last term is just less than π , is equal to (N+1))/2^(N). In the question in this video , let the value to be determined be X . Then , X²= sin(π/7)sin(π/7)sin(2π/7)sin(2π/7)sin(3π/7)sin(3π/7) Now using sin(x) = sin(π-x) , we have , X^2 = sin(π/7)sin(2π/7)sin(3π/7)sin(4π/7)sin(5π/7)sin(6π/7) The last equation follows the formula above , hence , X^2 = 7/2^6 = 7/64 . Take square root and you get your answer.

@vansh61595 10 ай бұрын

What should I put in the value of N

@benYaakov 10 ай бұрын

@@vansh61595 As written above , N is the number of terms.

@vansh61595 10 ай бұрын

Acha , thik h

@shlokpatel2472 10 ай бұрын

Hello :) I wanted to know how you came to know about this identity, because I am halfway through my 11th std., starting the chapter 'Circles' tomorrow, and I never came across such an identity while studying the two trigonometry chapters in the past. Thanks.

@aryannagariya6027 10 ай бұрын

Thank you for this trick

@user-kv6qx6rz7f 10 ай бұрын

As a matter of fact sir , I have solved this problem during my JEE days and have come to IIT BHU after qualifying JEE23 . Thank you sir for bringing out such problems

@mananluthra6831 9 ай бұрын

Hey did you solve this by this method only ?

@itsshubh3430 9 ай бұрын

Sale flex maar. Rha h tu

@susmitadutta1029 9 ай бұрын

@@itsshubh3430 If he really did this tough problem all on his own he can flex and deserves the honour,kudos to the guy👏👏

@rajcr877 8 ай бұрын

Congrats bro❤

@mayurgaming347 8 ай бұрын

Q@@😊@😊

@nicogehren6566 10 ай бұрын

very well explained and nice approach. thank you!

@shyamaldevdarshan 10 ай бұрын

Well explained sir!! I appreciate your effort 😊👍 But sir ,,i have an another excellent approach,,which is luckily a brilliant and time saver approach for this particular question!! We have a formula ,,,sinπ/n .sin 2π/n .sin3π/n ... .sin (n-1)π/n = n/{2^(n-1)}. In this particular problem we have value for sinπ/7 sin2 π/7 ...sin6π/7 = 7/(2^6).. Now we let us assume sin π/7...sin3π/7 =X .then the next three terms can be transformed in terms of Series of X.as eg:-sin4π/7 =sin 3π/7..now the series become X^2 in LHS...now apply root both side .we get value as √7/8.. Its so simple,,can be done within 4-5 lines😊😎🔥🤘 Lets have a look to my approach! Hope u like it !!. Thankyou! Radhe radhe🙏

@shauryagupta3644 10 ай бұрын

Could you pls share with me a link for the proof of this formula, or just hint me the approach to prove it? Thanks

@shyamaldevdarshan 10 ай бұрын

@@shauryagupta3644i appreciate your curiosity 😊!! And thankyou for read my approach 😊 . To be honest ,,this formula is not related to intermediate level directly!! And the proof is so lengthy ,you have to use eulers identity ,concept of limit ,and little bit use of complex no. Yeah iam also an iit jee aspirant right now😊 so ,no doubt you can understand the whole proof almost ! But this will worthless for u right now !! The result is important ,,so plz try to keep that result in mind ! Remember,,you cant use this formula in every situation,,the major condition is the coefficient of π in last term is 1 less than the denominator !!and the product should be continuous!! Further modification in this formula led to the result of "Riemann integral ". But still you want to know the proof ,,i have done an effort in searching the video you need to get the proof . Iam providing you link ,,you can chek it out!😊👇 kzfaq.info/get/bejne/nrdlZpWEz8jcfqM.htmlsi=auUbzdDu8AipVGw_ This contain the proof u want,,and given by any university professor !!👍. Once again ,i say ,,result is important!! Thankyou to love my approach!!😊👍 Radhe radhe 🙏

@timewalkwalker 10 ай бұрын

@@shyamaldevdarshan thanks I applied without knowing proof definately gonna learn proof after my complex number course.

@shyamaldevdarshan 10 ай бұрын

@@timewalkwalker welcome! Yeah sure! You can learn😊👍 Radhe radhe🙏

@atharvsalunke878 10 ай бұрын

Yes

@shreyashsinha7255 10 ай бұрын

Nice Explanation Sir. but I have another approach for this question as we know that CONTINUED PRODUCT(k=1 to n-1) sin(kpi/n)=n/(2^(n-1) HERE S= sin(pi/7) x sin(2pi/7)x sin(3pi/7) S=sin(6pi/7)sin(5pi/7)sin(4pi/7) =>S^2 =CONTINUED PRODUCT(k=1 to 6) sin(kpi/7)=7/2^6 =>S= sqrt(7)/8 HOPE U LIKE IT!! THANK YOU

@benYaakov 10 ай бұрын

Yes. It's a general formula which can be easily proved using complex numbers and a little bit algebraic manipulations.

@harashisharora1521 10 ай бұрын

This is exactly what i thought when I saw this.

@user-dd6cu2zw9c 10 ай бұрын

Can we get in touch please I think u can help me in mathematics.

@Player_is_I 9 ай бұрын

Your solution seems to be based on an interesting topic can you tell me more about that and for me there are some things that are unclear in your solution like how is s is equals to 2 products which are different I mean can you elaborate your solution

@benYaakov 9 ай бұрын

@@Player_is_I First, it's S^2 . Note that after squaring, each terms on RHS appear twice so that now we have a pair of each term which was present in S. Now , take exactly one term of each pair and use the identity sin(x) = sin(π-x) to get the desired product.

@bhaumikbhandari4001 29 күн бұрын

Sir this question can be easily solved Let y = π/7 x = sin y × sin 2y × siny 3y x = (sin y × sin 2y × sin 3y × sin 4y × sin 5y × sin 6y)/ x [ because sin 4y = sin 3y , sin 5y = sin 2y and sin 6y = sin y] By using Π( multiplication of series) sin rπ/N = N /2^(N-1) x = 7/[(2^6) × x] x² = 7/2^6 x = √7 / 2³ = √7 / 8 Sir please reply to my method

@hretz 10 ай бұрын

There's one more method ∏^n−1k=1sin(kπ/n)=n/[2^(n−1)] we need to find sinpi/7.sin2pi/7.sin3pi/7 but to use the formula Given above we need to have 6 terms as k goes from 1 to 6 we also know that sin(pi-pi/7)=sin(6pi/7), sin(pi-2pi/7)=sin(5pi/7), sin(pi-3pi/7)=4pi/7 so we can say that [sin(pi/7).sin(2pi/7).sin(3pi/7)]^2 = ∏^6 k=1sin(kπ/7)=7/[2^(6)] so now we can take root on both the sides and get our answer as root 7/ 8

@MathsStar-qo1fn 10 ай бұрын

Awesome ❤

@dexroner 10 ай бұрын

Ans the proof of that formulae comes from complex numbers

@slimshadyff7848 10 ай бұрын

Can you please explain that to me 😅

@hretz 10 ай бұрын

@@slimshadyff7848 explain what? We only need to use the formula for this method, but the problem is most of us aren't aware of this formula. To calculate answer using the formula we need to make sure that we've 6 terms as the formula requires us to use from k=1 to k=(n-1) here n is 7 so k will be 6. Rest is basic, sin(pi-x) = sin x as second quadrant sinx is positive

@ad59986 10 ай бұрын

@@hretzbro pls can you give name of the formula so that i can learn it .

@MikeHenry0001 10 ай бұрын

Maza aa gaya sir, Definitely looking up for more such videos❤

@yxsh5033 8 ай бұрын

When we got 8xy=x, why can't we do this to find x 👇 8xy-x=0 x(8y-1)=0 x=0, y=1/8 It would've been much faster

@adarshsubramanian9560 8 ай бұрын

wrong if y=1/8 x can be any value

@yxsh5033 8 ай бұрын

@@adarshsubramanian9560 bro xy = x/8 wat are you talking about

@adarshsubramanian9560 8 ай бұрын

@@yxsh5033 For example if y=1/8 then if u take x value as 1 then also equation is satisfied

@avtar0079 4 ай бұрын

because x is not equal to zero

@bijender6511 10 ай бұрын

Sir please derive formula . I always mug up and can't understand relationship between the formula . √( s . S- a . S- b. S- c)

@mamtamittal3051 10 ай бұрын

Just search for derivation of Heron’s formula

@neerajprajapati3852 10 ай бұрын

It's easy you can find so many videos on it in English and may be in Hindi too

@UGC1810BC Ай бұрын

Good explanation sir 👏🏻.. but we can also solve this by following method Cosπ/7.Cos2π/7.Cos(π-4π/7) = Cosπ/7.cos2π/7.cos4π/7 =Sun(2.4π/7)/2³.sin(π/7) =Sin(π+π/7)/8sinπ/7 =Sinπ/7/8sinπ/7 =1/8 Thankyou!!!!

@mrstrange15yp 26 күн бұрын

Buddy don't u think ki tumhare method se answer -1/8 aaega because cos(180 - x ) is -cos(x) 🤔

@Enstine.cricketer 10 ай бұрын

Appriciate for those student who solved. This question 😮

@MehtabHussain-vh3bl 10 ай бұрын

Bruh it's a basic question 🤖

@nikhildhanotiya5312 10 ай бұрын

@@MehtabHussain-vh3bljee also ask basic question

@sohambaviskar22 Ай бұрын

sir!! PW kyu chhoda ??

@thewickedphenol006 10 ай бұрын

Req to you sir..pls start PYQ solving of last 3-4 years Maths

@Rishi_Ji 10 ай бұрын

Bekar Sin ko cos me covert karo aur CosA cos2A cos4A....= sin2n/2nsina

@yash3449 10 ай бұрын

"BHANNAAAAT IS A ICONIC WORD" LOVE YOU SIR❤❤❤

@videepreddyjalapally6924 4 ай бұрын

sir have very fast solution for this with complex no there is a trig identity of sin(pi/n) *sin(2pi/n) .... *sin((n-1)pi/n) = n/2^n-1 now keep n = 7 and now sin 4pi/7 is same as 3pi/7 and so on therefore ans = sqroot(n/2^n-1)

@twinopedia7652 10 ай бұрын

power of aman sir- only 525 views and 106 likes❤‍🔥❤‍🔥❤‍🔥❤‍🔥🔥🔥🔥l

@subhadraprasad7676 10 ай бұрын

ध्यान से देखो😂

@wipergaming1448 10 ай бұрын

5:20 x zero nahi ho sakhta aapne kaise judge kiya sir? Plz batadijiye.

@neerajprajapati3852 10 ай бұрын

Kyunki sin. 0 180 360 me hi zero hota hai baki jagah nahi

@wipergaming1448 10 ай бұрын

@@neerajprajapati3852 bhai lekin x toh multiplication of sin fn hai toh vo zero bhi ho sakhte hai.

@neerajprajapati3852 10 ай бұрын

@@wipergaming1448 dekho anuj yahan sin p/7 sin2p/7 sin3p/7 ki bat hai aur ye teeno non zero hain aur teen non zero quantity ka product bhi non zero hi hoga

@navisleegaming7453 Ай бұрын

Kaisa hai @@wipergaming1448

@sarthaksheregar2663 13 күн бұрын

Hum is problem ko 2 to 3 lines mein bhi solve kar sakthe hein.. Sin pie/7 sin 2pie/7 sin 3pie/7 ko square kare tho sin(2n pie/2n+1) ka format ayega tho uska answer ayega 7/64 tho uska square root lelenge tho Aya root7/8

@satyam9267 9 ай бұрын

x aur y me jo sin aur cos ke values diye hai na usme cos ke aur sin ke angles same hai toh hame ye a,b,c vale chakkar me fasne ki jarurat hi nhi hai let y= cos(p)=1/8 then x=sinp=√(8²-1²)/8=√7/8 Sir pin kardo dil khush hogaya hoga aapka ye mera comment padhke

@youcandoit2911 Ай бұрын

Ye questions agar adv mein kiya toh mera IIT jayengaa....😂

@yugantar01 10 ай бұрын

Sir sin(2pie/7)=sin(5pie/7) As we take 7@=(2n-1)pie We can make sin4@=sin3@ Expanded to °4cos@(1-2sin²@)=3-4sin²@(because sin@=0 is rejected) °then squaring both sides 16(1-sin²@)(1-2sin²@)²=(3-4sin²@)² °-64sin⁶@+128sin⁴@-80sin²@=9+16sin⁴@-24sin²@ °64sin⁶@-112sin⁴@+56sin²@-7=0 (is the equation in which if we take roots in form of sin²@, roots are sin²(pie/7),sin²(3pie/7) and sin²(5pie/7)) Lets comment on the values for all three angle sin give positive value ) From equation produts of roots in form of sin²@: sin²(pie/7)sin²(3pie/7)sin²(5pie/7)=7/64 Then sin(pie/7)sin(3pie/7)sin(5pie/7)=square root (7) /8 Sir I did this please see this one time sir .

@bhagatsingh9101 8 ай бұрын

Iska easy answer batau,?? =Sinπ/7. Sin2π/7.sin 3π/7 =Sin180/7. Sin360/7.sin 540/7 =Sin180/7.sin0/7 . Sin540/7 =Sin180/7. 0.Sin540/7 =0 Easy, why respected sir make a video of 14 minutes 17 seconds And i already did it in just one minute without google

@sarthakgupta2463 2 ай бұрын

Nice one

@ManiramBasumatary-yj6ym Ай бұрын

u can't use sin(360/7)=0 it's sin(360/7) and not sin(360)

@manaspratimsarma4994 20 күн бұрын

You are really a great teacher who can turn the most hated question to most loveliest one.

@Bheemki_chaddi 10 ай бұрын

Re-upload 😊

@30rahulukey42 10 ай бұрын

Toh last time the answer was wrong as he forgot to multiply by 8

@ratandassarkar6682 10 ай бұрын

5[1.96-sin^2{(cos^-1 (0.02)}° ] find the value of it . Challenge to you sir 😊😊😊.

@user-eb8fw3df2t 10 ай бұрын

Good evening sir.Sir pyq solving videos please

@16melsterjesujegan5 8 ай бұрын

Sir you can solve using π/7 property 4π/7=π -3π/7 It will give ans in 2 steps Sinπ/7 sin2π/7 sin4π/7 multiply divide by 2cosπ/7 and it will give ans 1/8

@MAYANK.BRAHMAN958 14 күн бұрын

I am also getting same

@soumyasharma5318 9 ай бұрын

If I get this question, thsn I will focus on other problems than this one. IIT JEE failed person (rank 2k in 2004) this side..lol Probably justifies why I didn't qualify for IIT but doing better than 50% IITians by knowing how the world money flows.

@sleha4106 9 ай бұрын

So how exactly does money flow

@amitmahato5278 27 күн бұрын

Maturity is when you use calculator and get something different from √7/8 😂

@umeshguddad8427 8 ай бұрын

I learnt trigonometry in the early 70s.Now a retired banker. You said that the problem is with the approach, and not with formulae. Right? My question is why does my approach gets to be wrong. It was incorrect 50 years back and is incorrect even now.

@dixitkumarkumar6205 10 ай бұрын

Kya sir apply formula of trigonmetric series😮

@arnavsingh7580 10 ай бұрын

Bro there is only formula for continued product of cosine series and not of Sine series

@gaussiit4855 8 ай бұрын

Complex numbers se kijiye alag swaad aayega. (use 7th root of unity)

@UttamSingh-i1x 15 күн бұрын

Bro kaise

@UttamSingh-i1x 15 күн бұрын

Kaise Bhai thoda hint batao

@VishnuGupta-pb5pe 9 ай бұрын

Different approach - for series that is in product and is in form of sin theta we can use √2n+1/ 2^n . N - no of terms

@user-rf6ly9lk3s 9 ай бұрын

Use of complex no

@biriyanilover5596 6 ай бұрын

Abe chup gawar

@jeetverma3977 4 ай бұрын

"Maths approach ka game hai " 🔥🔥

@Ayushsrivastava-nn6qg 2 ай бұрын

भाई मुझे तो पता ही नहीं था l Thanks for telling .

@hardikkumar8630 8 ай бұрын

Another good and easy solution - Take theta = pie/7 Then, taking sin both the sides we have - Sin 7theta = Sin pie Sin 7theta = 0 Sin (4 theta + 3 theta) = 0 Sin4theta.cos3theta + cos4theta.sin3theta = 0 By multiplication rule - ½[sin(7theta) + sin theta]+ ½[sin(7theta) + sin theta] = 0 Then, Sin7theta + sin theta = 0 Sin7theta = 0 (as from upper portion) Sin(theta) = 0 Hence sin(pie/7) = 0 Hence if one term is zero then all are 0 Then correct answer is 0 Thanks for reading this solution till here. Please hit that like button 😅

@hardikkumar8630 8 ай бұрын

I know answer is wrong butt find any mistake 🙃

@Benzene42 8 ай бұрын

You born with mistake

@primeeditor8164 8 ай бұрын

Wrong

@primeeditor8164 8 ай бұрын

You used wrong formula in by multiplication rule

@primeeditor8164 8 ай бұрын

Also you idiot how is sin(pie/7) =0

@ABHIGAMING-yo9my 9 ай бұрын

Let T=sin(pi/7)sin(2pi/7)sin(3pi/7) T=sin(6pi/7)sin(5pi/7)sin(4pi/7) Multiply both equations T^2=sinpi/7)....sin(6pi/7) Then put formula sin(pi/n)sin(2pi/n)....sin((n-1)pi/n)= n/2^{n-1)

@Errorless-Math 9 ай бұрын

As this is a IMO problem.............So This should be one of the hardest problem....

@KrakenZYT 3 ай бұрын

Actually, this question is from a book named A das gupta

@syedmdabid7191 8 ай бұрын

Sin m^n=? ( No expansion, should be FINITE SERIES.)

@tanveer7969 10 ай бұрын

Sir ... is it the only solution for this question..... if any solution is there please tell

@shaatirop8901 10 ай бұрын

Apply direct formula for product series

@shyamaldevdarshan 10 ай бұрын

Check my comment 😊👍

@syed3344 9 ай бұрын

@@shaatirop8901WHAT??WHICH FORMULA

@maniratnamray3888 10 ай бұрын

why video was deleted and reuploaded sir?

@user-ku6fh6le3j 10 ай бұрын

Super explanation sir 👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻🥳🥳🥳🥳

@gaurav3794 8 ай бұрын

Wow! nobody will mind even if you also declare it as the most hated question in JEE level.

@hard8021 10 ай бұрын

Good qustion sir jeee namste🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

@theimp162 8 ай бұрын

My whole high school life ended learning this sin-π cos-π but still i dont know where to use this math formulas in my daily life.

@SaketRaman-jh6fw Ай бұрын

This level of complex math is obviously not made for the average person. Its required to get into IITs and other colleges depending on the performance, the better you do, the better your placement, that's the system, there is NO application for it in your daily life.

@ptksax 8 ай бұрын

apart from hard this seems to be quite a pointless problem in trigonometry, as both engineering and scientific point of view it has no significance, just few stupid formulas to learn to screw the lives of students and solve a pointless problem, how on earth would any student will logically come to the next step of getting the answer, this is mug up the solution kind of problem

@pankajsinha4280 8 ай бұрын

Very nice sir. Quite inspirational solution

@SoloManpower03 18 сағат бұрын

it can be easily done by complex number tried and tested

@ANDROIDPOSTMORTEM 8 ай бұрын

Solved it...!... Loved the problem... I tried straight for two days for it 😂

@The._boss8998 Ай бұрын

Khatarnak question

@omsahani844 10 ай бұрын

Sahi bola sir, formula hai sara yaad pr question nhi bn pata mere yaar

@adityasart2644 10 ай бұрын

This can be solved Put pi/7 = @ Now 2pi/7 , pi/7 , 3pi/7 will staisfy it We have pi = 7@ Pi - 4@ = 3@ Take sin on both sides Sin4@ = sin3@ Now apply their formula make a polynomial and its roots will be Sin pi/7 , sin 2pi/7 , sin 3pi/7 Just apply product of roots u will get answer

@vineetsadarangani564 Ай бұрын

why are we not considering the negetive counterpart of x?

@nimbu9356 10 ай бұрын

Reupload?

@Pika_quest 10 ай бұрын

You are the best guruji, thanks for the question practices ❤❤

@udayrathorevloging Ай бұрын

Let me do it Sin 22/7 /7 will take common then(2*3) Sin22*6 Sin132 😅

@gamingtips2941 10 ай бұрын

Legends ->> repload

@rahulpratap3459 5 ай бұрын

Can u please solve this question using quadratic equations/polynomials?

@user-rf6ly9lk3s 9 ай бұрын

Very easy question of complex no.

@sandy_2112 16 күн бұрын

Need aa gyi dekhte dekhte😮

@RajeshYadav-qc3oo 4 ай бұрын

I am read in class 6 th but I love seening this video l can understand this video 😊😊 and I am not joking😊mane apne maths wale sir se ye swal pucha tha but unohe ne 22÷7 man liya fir pura galt kar diya 😊 and i am preparing for Jee advanced and my some friend jeolus me and ma kabhi bhi 1st nhi aaya hu and i am watching this video 2024 😂 and mera result 5 aprail ko aayenga 😊❤and hare Krishna

@RajeshYadav-qc3oo 4 ай бұрын

Radhe Radhe hare Krishna ❤❤❤

@RajeshYadav-qc3oo 4 ай бұрын

Vo wahar lal nehru scool❤

@Kush11 3 ай бұрын

Lol

@MaheshKumar-lx1ku 2 ай бұрын

😂😂😂😂 learn counting from 1 to 100 properly. Edit. Thanks for 2k likes.

@vedant9127 10 ай бұрын

Can also be done by complex no

@chandranisahanone 10 ай бұрын

U teach so well that MATHEMATICIANS will try to learn from uuu❤❤❤...

@Amaan_khan334 10 ай бұрын

Sir please solve jee main 2023 1st feb shift 2 sequence and series question 🥺🥺🥺

@pyazkachori123 8 ай бұрын

You should also prove why you took the positive part

@MrMarshallAC 8 ай бұрын

The basic orthogonalality of sine waves is demonstrated here.

@rockerstudio432 4 ай бұрын

Maza aagaya sir but itna time kidhar hai solve karne ke liye ek question ko

@sidharthsuna3862 2 ай бұрын

2 ko 4 time multiply karne se 8 kaise hoga sir.

@nakulmanchanda8129 10 ай бұрын

For such ques....Complex no. God

@melancholystar6141 5 ай бұрын

Arjuna 1.0 adv lecture tarun sir ne iske 3 methods bataye the 7 months pehle 😂

@vinodjoc1752 4 ай бұрын

Pr sir na ak method se solve krdiya it's talent😂

@Devansh_6655 Ай бұрын

Mt sir ne 10 Saal phele💀💀

@nijwm1916 Ай бұрын

@@Devansh_6655 mt sir ka lecture?

@jyotikabuchha6360 9 ай бұрын

Sir ne bhot bade tarike se karvaya hai

@sunnysharma00632 10 ай бұрын

We love you sir❤

@MPC-JEE 8 ай бұрын

Assumption ka game hai...

@indiandefencelover7600 10 ай бұрын

Sir please NDA ka batch start kr do yt pe please sir😢😢😢😢🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼

@Halamadrid06-y7q 7 ай бұрын

Can also be done by complex no.

@shanthamanir3060 10 ай бұрын

Bio students attendance please 👇

@astikkar7978 10 ай бұрын

Sir wbjee k liye kuch class hota to acha hota

@Dhanika112 Ай бұрын

Loved it ❤

@jec_ecart 8 ай бұрын

Biggest question is that is trigonometry useful? Mostly no.

@rudrayadav_2_00_5 10 ай бұрын

Kya sir ne yeh video doobara post kra hai isse pehle yeh video sir ne kya post Kiya tha jo delete kr diya tha koi batao

@PEACE.54 10 ай бұрын

Don't do this long bro, we know that sin(π/n)sin(2π/n)....sin[(n-1)π/n]=n/[2^(n-1)] In this question put n=7, multiply divide by sin(π/7)sin(2π/7)sin(3π/7) and assume it T T = (7/2^6)/T T=√7/8 👍🏻 Easy

@Parth_tiwari_ 10 ай бұрын

Ye bhi issi se aya hai

@PEACE.54 10 ай бұрын

@@Parth_tiwari_ ?

@CBSEGamerYt786 10 ай бұрын

Is this a formula bruh??

@PEACE.54 10 ай бұрын

@@CBSEGamerYt786 yes