This question deserves to be the most hated problem of trigonometry
@itsmeadi...20069 ай бұрын
Phir sir ne kya bola wahi to bola hai 🙄
@aakritkatyal91358 ай бұрын
4 step mein hogaya 😂
@shoyo_Ishida8 ай бұрын
Naa!!
@aakritkatyal91358 ай бұрын
@@shoyo_Ishida solution chaiye
@shoyo_Ishida8 ай бұрын
@@aakritkatyal9135 noop!!
@user-ym4ci4rv5z10 ай бұрын
Long but predictable method: sin (kpi/m), k=1..n are roots of equation sin(mx) = 0. So we expand sin(mx) in powers of sin(x) to get a polynomial equation in sin(x) of degree m. For m = 7 we get: sin(7x) = -64sin^7(x) +112 sin^4(x) -56 sin^2(x) + 7sin(x) =0. We can eliminate sin(x)=0 as solution, so the products of the remaining 6 roots is 7/64. This product is square of the required quantity.
@MyOneFiftiethOfADollar8 ай бұрын
Did you "predict" the method prior to looking at the solution?
@Aditya_1968 ай бұрын
Yeah bro same 😂 I once was curious and derived sin5x , 7x 9x 11x and those r some neet results if u want an interesting question check this .. what is the coefficient of last 3rd term of sin101x given that it's expansion is organised on the basis of descending order of powers of sinx ... Sayd question smjh me aagya hoga kya bol rha .... Actually mein general term ka coefficient khoj rha tha nahi mila but kuchh terms me pattern mila
@marrythebun-bun25017 ай бұрын
Hey please tell which theorem or Formula you have used, please tell the name 😢
@user-wd7yy2fm7g5 ай бұрын
We can use complex numbers where w = cos(2pi/n) where w is nth root of unity
@cofanavay22359 ай бұрын
I have created formula see here for n=7 x=√7/8=} x^2 = 7/(8^2) And for n x^2=n/(2^[n-1]) ...😊
@Ayush-yj5qv5 ай бұрын
Yeah easiest method
@ADARSHYODHA9 ай бұрын
As a student of 10th class, I think trigonometry is used more in making questions harder , instead of finding length of a building.😂😂😂 Edit:Oh my god mai toh famous ho gya.
@prabaln47529 ай бұрын
Yes you thinks😂 correct
@skies_anuj8 ай бұрын
Bilkul shi pakdo ho munna
@nirmalsurendranmenon70498 ай бұрын
😂😂😂😂😂
@heemensu8 ай бұрын
it will make your analytical and critical thinking stronger... which are basics of logic development
@BeastModeWorkout248 ай бұрын
No, we use trigonometry in physics at an advanced level, therefore these difficult problems help us in that way.
@_elusivex_10 ай бұрын
Sir, i saw your video on the same problem and the next morning when i was searching for the video, i didn't find it anywhere, not even in my history, but then i thought that you might have deleted the video. Thanks for re uploading the problem.
@nishantpatriot329710 ай бұрын
Same with me😅
@benYaakov10 ай бұрын
In general , it can be proved using complex numbers that: multiplication of 'N' terms of sines where each acute angle is in A.P. such that the first term is equal to common difference and last term is just less than π , is equal to (N+1))/2^(N). In the question in this video , let the value to be determined be X . Then , X²= sin(π/7)sin(π/7)sin(2π/7)sin(2π/7)sin(3π/7)sin(3π/7) Now using sin(x) = sin(π-x) , we have , X^2 = sin(π/7)sin(2π/7)sin(3π/7)sin(4π/7)sin(5π/7)sin(6π/7) The last equation follows the formula above , hence , X^2 = 7/2^6 = 7/64 . Take square root and you get your answer.
@vansh6159510 ай бұрын
What should I put in the value of N
@benYaakov10 ай бұрын
@@vansh61595 As written above , N is the number of terms.
@vansh6159510 ай бұрын
Acha , thik h
@shlokpatel247210 ай бұрын
Hello :) I wanted to know how you came to know about this identity, because I am halfway through my 11th std., starting the chapter 'Circles' tomorrow, and I never came across such an identity while studying the two trigonometry chapters in the past. Thanks.
@aryannagariya602710 ай бұрын
Thank you for this trick
@user-kv6qx6rz7f10 ай бұрын
As a matter of fact sir , I have solved this problem during my JEE days and have come to IIT BHU after qualifying JEE23 . Thank you sir for bringing out such problems
@mananluthra68319 ай бұрын
Hey did you solve this by this method only ?
@itsshubh34309 ай бұрын
Sale flex maar. Rha h tu
@susmitadutta10299 ай бұрын
@@itsshubh3430 If he really did this tough problem all on his own he can flex and deserves the honour,kudos to the guy👏👏
@rajcr8778 ай бұрын
Congrats bro❤
@mayurgaming3478 ай бұрын
Q@@😊@😊
@nicogehren656610 ай бұрын
very well explained and nice approach. thank you!
@shyamaldevdarshan10 ай бұрын
Well explained sir!! I appreciate your effort 😊👍 But sir ,,i have an another excellent approach,,which is luckily a brilliant and time saver approach for this particular question!! We have a formula ,,,sinπ/n .sin 2π/n .sin3π/n ... .sin (n-1)π/n = n/{2^(n-1)}. In this particular problem we have value for sinπ/7 sin2 π/7 ...sin6π/7 = 7/(2^6).. Now we let us assume sin π/7...sin3π/7 =X .then the next three terms can be transformed in terms of Series of X.as eg:-sin4π/7 =sin 3π/7..now the series become X^2 in LHS...now apply root both side .we get value as √7/8.. Its so simple,,can be done within 4-5 lines😊😎🔥🤘 Lets have a look to my approach! Hope u like it !!. Thankyou! Radhe radhe🙏
@shauryagupta364410 ай бұрын
Could you pls share with me a link for the proof of this formula, or just hint me the approach to prove it? Thanks
@shyamaldevdarshan10 ай бұрын
@@shauryagupta3644i appreciate your curiosity 😊!! And thankyou for read my approach 😊 . To be honest ,,this formula is not related to intermediate level directly!! And the proof is so lengthy ,you have to use eulers identity ,concept of limit ,and little bit use of complex no. Yeah iam also an iit jee aspirant right now😊 so ,no doubt you can understand the whole proof almost ! But this will worthless for u right now !! The result is important ,,so plz try to keep that result in mind ! Remember,,you cant use this formula in every situation,,the major condition is the coefficient of π in last term is 1 less than the denominator !!and the product should be continuous!! Further modification in this formula led to the result of "Riemann integral ". But still you want to know the proof ,,i have done an effort in searching the video you need to get the proof . Iam providing you link ,,you can chek it out!😊👇 kzfaq.info/get/bejne/nrdlZpWEz8jcfqM.htmlsi=auUbzdDu8AipVGw_ This contain the proof u want,,and given by any university professor !!👍. Once again ,i say ,,result is important!! Thankyou to love my approach!!😊👍 Radhe radhe 🙏
@timewalkwalker10 ай бұрын
@@shyamaldevdarshan thanks I applied without knowing proof definately gonna learn proof after my complex number course.
@shyamaldevdarshan10 ай бұрын
@@timewalkwalker welcome! Yeah sure! You can learn😊👍 Radhe radhe🙏
@atharvsalunke87810 ай бұрын
Yes
@shreyashsinha725510 ай бұрын
Nice Explanation Sir. but I have another approach for this question as we know that CONTINUED PRODUCT(k=1 to n-1) sin(kpi/n)=n/(2^(n-1) HERE S= sin(pi/7) x sin(2pi/7)x sin(3pi/7) S=sin(6pi/7)sin(5pi/7)sin(4pi/7) =>S^2 =CONTINUED PRODUCT(k=1 to 6) sin(kpi/7)=7/2^6 =>S= sqrt(7)/8 HOPE U LIKE IT!! THANK YOU
@benYaakov10 ай бұрын
Yes. It's a general formula which can be easily proved using complex numbers and a little bit algebraic manipulations.
@harashisharora152110 ай бұрын
This is exactly what i thought when I saw this.
@user-dd6cu2zw9c10 ай бұрын
Can we get in touch please I think u can help me in mathematics.
@Player_is_I9 ай бұрын
Your solution seems to be based on an interesting topic can you tell me more about that and for me there are some things that are unclear in your solution like how is s is equals to 2 products which are different I mean can you elaborate your solution
@benYaakov9 ай бұрын
@@Player_is_I First, it's S^2 . Note that after squaring, each terms on RHS appear twice so that now we have a pair of each term which was present in S. Now , take exactly one term of each pair and use the identity sin(x) = sin(π-x) to get the desired product.
@bhaumikbhandari400129 күн бұрын
Sir this question can be easily solved Let y = π/7 x = sin y × sin 2y × siny 3y x = (sin y × sin 2y × sin 3y × sin 4y × sin 5y × sin 6y)/ x [ because sin 4y = sin 3y , sin 5y = sin 2y and sin 6y = sin y] By using Π( multiplication of series) sin rπ/N = N /2^(N-1) x = 7/[(2^6) × x] x² = 7/2^6 x = √7 / 2³ = √7 / 8 Sir please reply to my method
@hretz10 ай бұрын
There's one more method ∏^n−1k=1sin(kπ/n)=n/[2^(n−1)] we need to find sinpi/7.sin2pi/7.sin3pi/7 but to use the formula Given above we need to have 6 terms as k goes from 1 to 6 we also know that sin(pi-pi/7)=sin(6pi/7), sin(pi-2pi/7)=sin(5pi/7), sin(pi-3pi/7)=4pi/7 so we can say that [sin(pi/7).sin(2pi/7).sin(3pi/7)]^2 = ∏^6 k=1sin(kπ/7)=7/[2^(6)] so now we can take root on both the sides and get our answer as root 7/ 8
@MathsStar-qo1fn10 ай бұрын
Awesome ❤
@dexroner10 ай бұрын
Ans the proof of that formulae comes from complex numbers
@slimshadyff784810 ай бұрын
Can you please explain that to me 😅
@hretz10 ай бұрын
@@slimshadyff7848 explain what? We only need to use the formula for this method, but the problem is most of us aren't aware of this formula. To calculate answer using the formula we need to make sure that we've 6 terms as the formula requires us to use from k=1 to k=(n-1) here n is 7 so k will be 6. Rest is basic, sin(pi-x) = sin x as second quadrant sinx is positive
@ad5998610 ай бұрын
@@hretzbro pls can you give name of the formula so that i can learn it .
@MikeHenry000110 ай бұрын
Maza aa gaya sir, Definitely looking up for more such videos❤
@yxsh50338 ай бұрын
When we got 8xy=x, why can't we do this to find x 👇 8xy-x=0 x(8y-1)=0 x=0, y=1/8 It would've been much faster
@adarshsubramanian95608 ай бұрын
wrong if y=1/8 x can be any value
@yxsh50338 ай бұрын
@@adarshsubramanian9560 bro xy = x/8 wat are you talking about
@adarshsubramanian95608 ай бұрын
@@yxsh5033 For example if y=1/8 then if u take x value as 1 then also equation is satisfied
@avtar00794 ай бұрын
because x is not equal to zero
@bijender651110 ай бұрын
Sir please derive formula . I always mug up and can't understand relationship between the formula . √( s . S- a . S- b. S- c)
@mamtamittal305110 ай бұрын
Just search for derivation of Heron’s formula
@neerajprajapati385210 ай бұрын
It's easy you can find so many videos on it in English and may be in Hindi too
@UGC1810BCАй бұрын
Good explanation sir 👏🏻.. but we can also solve this by following method Cosπ/7.Cos2π/7.Cos(π-4π/7) = Cosπ/7.cos2π/7.cos4π/7 =Sun(2.4π/7)/2³.sin(π/7) =Sin(π+π/7)/8sinπ/7 =Sinπ/7/8sinπ/7 =1/8 Thankyou!!!!
@mrstrange15yp26 күн бұрын
Buddy don't u think ki tumhare method se answer -1/8 aaega because cos(180 - x ) is -cos(x) 🤔
@Enstine.cricketer10 ай бұрын
Appriciate for those student who solved. This question 😮
@MehtabHussain-vh3bl10 ай бұрын
Bruh it's a basic question 🤖
@nikhildhanotiya531210 ай бұрын
@@MehtabHussain-vh3bljee also ask basic question
@sohambaviskar22Ай бұрын
sir!! PW kyu chhoda ??
@thewickedphenol00610 ай бұрын
Req to you sir..pls start PYQ solving of last 3-4 years Maths
@Rishi_Ji10 ай бұрын
Bekar Sin ko cos me covert karo aur CosA cos2A cos4A....= sin2n/2nsina
@yash344910 ай бұрын
"BHANNAAAAT IS A ICONIC WORD" LOVE YOU SIR❤❤❤
@videepreddyjalapally69244 ай бұрын
sir have very fast solution for this with complex no there is a trig identity of sin(pi/n) *sin(2pi/n) .... *sin((n-1)pi/n) = n/2^n-1 now keep n = 7 and now sin 4pi/7 is same as 3pi/7 and so on therefore ans = sqroot(n/2^n-1)
@twinopedia765210 ай бұрын
power of aman sir- only 525 views and 106 likes❤🔥❤🔥❤🔥❤🔥🔥🔥🔥l
@subhadraprasad767610 ай бұрын
ध्यान से देखो😂
@wipergaming144810 ай бұрын
5:20 x zero nahi ho sakhta aapne kaise judge kiya sir? Plz batadijiye.
@neerajprajapati385210 ай бұрын
Kyunki sin. 0 180 360 me hi zero hota hai baki jagah nahi
@wipergaming144810 ай бұрын
@@neerajprajapati3852 bhai lekin x toh multiplication of sin fn hai toh vo zero bhi ho sakhte hai.
@neerajprajapati385210 ай бұрын
@@wipergaming1448 dekho anuj yahan sin p/7 sin2p/7 sin3p/7 ki bat hai aur ye teeno non zero hain aur teen non zero quantity ka product bhi non zero hi hoga
@navisleegaming7453Ай бұрын
Kaisa hai @@wipergaming1448
@sarthaksheregar266313 күн бұрын
Hum is problem ko 2 to 3 lines mein bhi solve kar sakthe hein.. Sin pie/7 sin 2pie/7 sin 3pie/7 ko square kare tho sin(2n pie/2n+1) ka format ayega tho uska answer ayega 7/64 tho uska square root lelenge tho Aya root7/8
@satyam92679 ай бұрын
x aur y me jo sin aur cos ke values diye hai na usme cos ke aur sin ke angles same hai toh hame ye a,b,c vale chakkar me fasne ki jarurat hi nhi hai let y= cos(p)=1/8 then x=sinp=√(8²-1²)/8=√7/8 Sir pin kardo dil khush hogaya hoga aapka ye mera comment padhke
@youcandoit2911Ай бұрын
Ye questions agar adv mein kiya toh mera IIT jayengaa....😂
@yugantar0110 ай бұрын
Sir sin(2pie/7)=sin(5pie/7) As we take 7@=(2n-1)pie We can make sin4@=sin3@ Expanded to °4cos@(1-2sin²@)=3-4sin²@(because sin@=0 is rejected) °then squaring both sides 16(1-sin²@)(1-2sin²@)²=(3-4sin²@)² °-64sin⁶@+128sin⁴@-80sin²@=9+16sin⁴@-24sin²@ °64sin⁶@-112sin⁴@+56sin²@-7=0 (is the equation in which if we take roots in form of sin²@, roots are sin²(pie/7),sin²(3pie/7) and sin²(5pie/7)) Lets comment on the values for all three angle sin give positive value ) From equation produts of roots in form of sin²@: sin²(pie/7)sin²(3pie/7)sin²(5pie/7)=7/64 Then sin(pie/7)sin(3pie/7)sin(5pie/7)=square root (7) /8 Sir I did this please see this one time sir .
@bhagatsingh91018 ай бұрын
Iska easy answer batau,?? =Sinπ/7. Sin2π/7.sin 3π/7 =Sin180/7. Sin360/7.sin 540/7 =Sin180/7.sin0/7 . Sin540/7 =Sin180/7. 0.Sin540/7 =0 Easy, why respected sir make a video of 14 minutes 17 seconds And i already did it in just one minute without google
@sarthakgupta24632 ай бұрын
Nice one
@ManiramBasumatary-yj6ymАй бұрын
u can't use sin(360/7)=0 it's sin(360/7) and not sin(360)
@manaspratimsarma499420 күн бұрын
You are really a great teacher who can turn the most hated question to most loveliest one.
@Bheemki_chaddi10 ай бұрын
Re-upload 😊
@30rahulukey4210 ай бұрын
Toh last time the answer was wrong as he forgot to multiply by 8
@ratandassarkar668210 ай бұрын
5[1.96-sin^2{(cos^-1 (0.02)}° ] find the value of it . Challenge to you sir 😊😊😊.
@user-eb8fw3df2t10 ай бұрын
Good evening sir.Sir pyq solving videos please
@16melsterjesujegan58 ай бұрын
Sir you can solve using π/7 property 4π/7=π -3π/7 It will give ans in 2 steps Sinπ/7 sin2π/7 sin4π/7 multiply divide by 2cosπ/7 and it will give ans 1/8
@MAYANK.BRAHMAN95814 күн бұрын
I am also getting same
@soumyasharma53189 ай бұрын
If I get this question, thsn I will focus on other problems than this one. IIT JEE failed person (rank 2k in 2004) this side..lol Probably justifies why I didn't qualify for IIT but doing better than 50% IITians by knowing how the world money flows.
@sleha41069 ай бұрын
So how exactly does money flow
@amitmahato527827 күн бұрын
Maturity is when you use calculator and get something different from √7/8 😂
@umeshguddad84278 ай бұрын
I learnt trigonometry in the early 70s.Now a retired banker. You said that the problem is with the approach, and not with formulae. Right? My question is why does my approach gets to be wrong. It was incorrect 50 years back and is incorrect even now.
@dixitkumarkumar620510 ай бұрын
Kya sir apply formula of trigonmetric series😮
@arnavsingh758010 ай бұрын
Bro there is only formula for continued product of cosine series and not of Sine series
@gaussiit48558 ай бұрын
Complex numbers se kijiye alag swaad aayega. (use 7th root of unity)
@UttamSingh-i1x15 күн бұрын
Bro kaise
@UttamSingh-i1x15 күн бұрын
Kaise Bhai thoda hint batao
@VishnuGupta-pb5pe9 ай бұрын
Different approach - for series that is in product and is in form of sin theta we can use √2n+1/ 2^n . N - no of terms
@user-rf6ly9lk3s9 ай бұрын
Use of complex no
@biriyanilover55966 ай бұрын
Abe chup gawar
@jeetverma39774 ай бұрын
"Maths approach ka game hai " 🔥🔥
@Ayushsrivastava-nn6qg2 ай бұрын
भाई मुझे तो पता ही नहीं था l Thanks for telling .
@hardikkumar86308 ай бұрын
Another good and easy solution - Take theta = pie/7 Then, taking sin both the sides we have - Sin 7theta = Sin pie Sin 7theta = 0 Sin (4 theta + 3 theta) = 0 Sin4theta.cos3theta + cos4theta.sin3theta = 0 By multiplication rule - ½[sin(7theta) + sin theta]+ ½[sin(7theta) + sin theta] = 0 Then, Sin7theta + sin theta = 0 Sin7theta = 0 (as from upper portion) Sin(theta) = 0 Hence sin(pie/7) = 0 Hence if one term is zero then all are 0 Then correct answer is 0 Thanks for reading this solution till here. Please hit that like button 😅
@hardikkumar86308 ай бұрын
I know answer is wrong butt find any mistake 🙃
@Benzene428 ай бұрын
You born with mistake
@primeeditor81648 ай бұрын
Wrong
@primeeditor81648 ай бұрын
You used wrong formula in by multiplication rule
@primeeditor81648 ай бұрын
Also you idiot how is sin(pie/7) =0
@ABHIGAMING-yo9my9 ай бұрын
Let T=sin(pi/7)sin(2pi/7)sin(3pi/7) T=sin(6pi/7)sin(5pi/7)sin(4pi/7) Multiply both equations T^2=sinpi/7)....sin(6pi/7) Then put formula sin(pi/n)sin(2pi/n)....sin((n-1)pi/n)= n/2^{n-1)
@Errorless-Math9 ай бұрын
As this is a IMO problem.............So This should be one of the hardest problem....
@KrakenZYT3 ай бұрын
Actually, this question is from a book named A das gupta
@syedmdabid71918 ай бұрын
Sin m^n=? ( No expansion, should be FINITE SERIES.)
@tanveer796910 ай бұрын
Sir ... is it the only solution for this question..... if any solution is there please tell
@shaatirop890110 ай бұрын
Apply direct formula for product series
@shyamaldevdarshan10 ай бұрын
Check my comment 😊👍
@syed33449 ай бұрын
@@shaatirop8901WHAT??WHICH FORMULA
@maniratnamray388810 ай бұрын
why video was deleted and reuploaded sir?
@user-ku6fh6le3j10 ай бұрын
Super explanation sir 👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻🥳🥳🥳🥳
@gaurav37948 ай бұрын
Wow! nobody will mind even if you also declare it as the most hated question in JEE level.
@hard802110 ай бұрын
Good qustion sir jeee namste🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
@theimp1628 ай бұрын
My whole high school life ended learning this sin-π cos-π but still i dont know where to use this math formulas in my daily life.
@SaketRaman-jh6fwАй бұрын
This level of complex math is obviously not made for the average person. Its required to get into IITs and other colleges depending on the performance, the better you do, the better your placement, that's the system, there is NO application for it in your daily life.
@ptksax8 ай бұрын
apart from hard this seems to be quite a pointless problem in trigonometry, as both engineering and scientific point of view it has no significance, just few stupid formulas to learn to screw the lives of students and solve a pointless problem, how on earth would any student will logically come to the next step of getting the answer, this is mug up the solution kind of problem
@pankajsinha42808 ай бұрын
Very nice sir. Quite inspirational solution
@SoloManpower0318 сағат бұрын
it can be easily done by complex number tried and tested
@ANDROIDPOSTMORTEM8 ай бұрын
Solved it...!... Loved the problem... I tried straight for two days for it 😂
@The._boss8998Ай бұрын
Khatarnak question
@omsahani84410 ай бұрын
Sahi bola sir, formula hai sara yaad pr question nhi bn pata mere yaar
@adityasart264410 ай бұрын
This can be solved Put pi/7 = @ Now 2pi/7 , pi/7 , 3pi/7 will staisfy it We have pi = 7@ Pi - 4@ = 3@ Take sin on both sides Sin4@ = sin3@ Now apply their formula make a polynomial and its roots will be Sin pi/7 , sin 2pi/7 , sin 3pi/7 Just apply product of roots u will get answer
@vineetsadarangani564Ай бұрын
why are we not considering the negetive counterpart of x?
@nimbu935610 ай бұрын
Reupload?
@Pika_quest10 ай бұрын
You are the best guruji, thanks for the question practices ❤❤
@udayrathorevlogingАй бұрын
Let me do it Sin 22/7 /7 will take common then(2*3) Sin22*6 Sin132 😅
@gamingtips294110 ай бұрын
Legends ->> repload
@rahulpratap34595 ай бұрын
Can u please solve this question using quadratic equations/polynomials?
@user-rf6ly9lk3s9 ай бұрын
Very easy question of complex no.
@sandy_211216 күн бұрын
Need aa gyi dekhte dekhte😮
@RajeshYadav-qc3oo4 ай бұрын
I am read in class 6 th but I love seening this video l can understand this video 😊😊 and I am not joking😊mane apne maths wale sir se ye swal pucha tha but unohe ne 22÷7 man liya fir pura galt kar diya 😊 and i am preparing for Jee advanced and my some friend jeolus me and ma kabhi bhi 1st nhi aaya hu and i am watching this video 2024 😂 and mera result 5 aprail ko aayenga 😊❤and hare Krishna
@RajeshYadav-qc3oo4 ай бұрын
Radhe Radhe hare Krishna ❤❤❤
@RajeshYadav-qc3oo4 ай бұрын
Vo wahar lal nehru scool❤
@Kush113 ай бұрын
Lol
@MaheshKumar-lx1ku2 ай бұрын
😂😂😂😂 learn counting from 1 to 100 properly. Edit. Thanks for 2k likes.
@vedant912710 ай бұрын
Can also be done by complex no
@chandranisahanone10 ай бұрын
U teach so well that MATHEMATICIANS will try to learn from uuu❤❤❤...
@Amaan_khan33410 ай бұрын
Sir please solve jee main 2023 1st feb shift 2 sequence and series question 🥺🥺🥺
@pyazkachori1238 ай бұрын
You should also prove why you took the positive part
@MrMarshallAC8 ай бұрын
The basic orthogonalality of sine waves is demonstrated here.
@rockerstudio4324 ай бұрын
Maza aagaya sir but itna time kidhar hai solve karne ke liye ek question ko
@sidharthsuna38622 ай бұрын
2 ko 4 time multiply karne se 8 kaise hoga sir.
@nakulmanchanda812910 ай бұрын
For such ques....Complex no. God
@melancholystar61415 ай бұрын
Arjuna 1.0 adv lecture tarun sir ne iske 3 methods bataye the 7 months pehle 😂
@vinodjoc17524 ай бұрын
Pr sir na ak method se solve krdiya it's talent😂
@Devansh_6655Ай бұрын
Mt sir ne 10 Saal phele💀💀
@nijwm1916Ай бұрын
@@Devansh_6655 mt sir ka lecture?
@jyotikabuchha63609 ай бұрын
Sir ne bhot bade tarike se karvaya hai
@sunnysharma0063210 ай бұрын
We love you sir❤
@MPC-JEE8 ай бұрын
Assumption ka game hai...
@indiandefencelover760010 ай бұрын
Sir please NDA ka batch start kr do yt pe please sir😢😢😢😢🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼
@Halamadrid06-y7q7 ай бұрын
Can also be done by complex no.
@shanthamanir306010 ай бұрын
Bio students attendance please 👇
@astikkar797810 ай бұрын
Sir wbjee k liye kuch class hota to acha hota
@Dhanika112Ай бұрын
Loved it ❤
@jec_ecart8 ай бұрын
Biggest question is that is trigonometry useful? Mostly no.
@rudrayadav_2_00_510 ай бұрын
Kya sir ne yeh video doobara post kra hai isse pehle yeh video sir ne kya post Kiya tha jo delete kr diya tha koi batao
@PEACE.5410 ай бұрын
Don't do this long bro, we know that sin(π/n)sin(2π/n)....sin[(n-1)π/n]=n/[2^(n-1)] In this question put n=7, multiply divide by sin(π/7)sin(2π/7)sin(3π/7) and assume it T T = (7/2^6)/T T=√7/8 👍🏻 Easy
@Parth_tiwari_10 ай бұрын
Ye bhi issi se aya hai
@PEACE.5410 ай бұрын
@@Parth_tiwari_ ?
@CBSEGamerYt78610 ай бұрын
Is this a formula bruh??
@PEACE.5410 ай бұрын
@@CBSEGamerYt786 yes
@syed33443 ай бұрын
Solved using complex numbers
@SatyamKumar-jp7zi7 ай бұрын
Sir isko complex no se kiya Jaye to 2 min me ho gayegaa
@Viralshorts00012-r10 ай бұрын
I don't think it was too hard because your have think approach of this question by basic mind.
@mkgclasses20426 ай бұрын
Put value of sin 180
@v.ssingh51777 ай бұрын
Sir kya ye question class 10 ke liye bhi hai
@niloyniloy82378 ай бұрын
As a 12th class student i can guarantee guys this is nothing . If u are an engineering student u have to been through a lot .
@MyOneFiftiethOfADollar8 ай бұрын
I can guarantee you could not have solved this problem had you not seen the solution in advance. So this problem is SOMETHING.
@KhusbuGupta-oq3kd3 күн бұрын
Lillyput sums😂 for jee aspirants
@sunnysharma0063210 ай бұрын
Sir apse defense ka preparation krna hai kaise kre ❤
@aaravjayalwal34165 ай бұрын
legendary, 2 saal purana doubt solve hogaya
@usampathkumar8 ай бұрын
If the answer is wrong they have not answered.
@ae005058 ай бұрын
Mujhe bhi apne EX ki talash hai, chhodunga naheen bas ek baar mil jaye...