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A Nice Diophantine Equation | Math Olympiad

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infyGyan

infyGyan

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A Nice Diophantine Equation | Math Olympiad
Welcome to another exciting Math Olympiad challenge! In this video, we explore a fascinating Diophantine equation problem from Math Olympiad. This problem will test your algebraic skills and problem-solving abilities. Whether you're a student preparing for math competitions or a math enthusiast looking for a stimulating challenge, this video is for you.
Pause the video and try solving the problem on your own before watching the solution. Let's see if you can solve this intriguing Diophantine equation!
Topics Covered:
1. Understanding the basics of Diophantine equation in integers
2. Analyzing the given equation using prime factorization
3. Step-by-step approach to solving the Diophantine equation for integer
4. Tips and tricks for handling tricky equation like a pro
5. Algebraic identities and manipulations while solving equations
#mathematics #diophantineequations #integers #problemsolving #algebra #education #numbertheory #matholympiad #matholympics
🎯 This video is perfect for students, math enthusiasts, or anyone seeking to sharpen their problem-solving skills and gain confidence in dealing with radical equations. 🎓📈
🔔 Challenge yourself and see if you can solve the equation before we do! Hit the like button if you're up for the challenge and remember to subscribe for more exhilarating math content! 🛎️🔔
Additional Resources:
• Solving an Intriguing ...
• Diophantine Dilemma: S...
• Diophantine Delights: ...
• Cracking the Diophanti...
Don't forget to like, comment, and subscribe to join our math-loving community. Let's get started on this exciting journey together! 🤝🌟
Thanks for Watching!

Пікірлер: 5
@mohammedsaysrashid3587
@mohammedsaysrashid3587 Ай бұрын
Wonderful explanation thanks Sir 🙏 for sharing
@ashokdubey8415
@ashokdubey8415 Ай бұрын
(x,y)=(3,2), (-4,-5), (-1,10), (-12,-1)
@RajeshKumar-wu7ox
@RajeshKumar-wu7ox Ай бұрын
(x,y)=(3,2) also other solutions
@RealQinnMalloryu4
@RealQinnMalloryu4 Ай бұрын
2y^2/y^2 =2y^1 (y ➖ 2y+1).{2x^2/x^4+22x^2/xy^8}=24x^4/xxy^12 =2xxy^3 (xxy ➖ 3xxy+2).
@user-ny6jf9is3t
@user-ny6jf9is3t Ай бұрын
Εχω τελικα (χ-y)(χ+y+χy)=11. Αλλα 11=1×11ή 11×1 ή-1×(-11) ή -11×(-1). Τελικα (χ,y)=(-4,-5) (3,2) (-1,10) (-12,-1)
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