This is the famous Putnam Exam Integral from 1980 Integral of 1/(1+(tan(x)^sqrt(2)) from 0 to pi/2, integral of cos(x)/(sin(x)+cos(x)) from 0 to pi/2 If you would like to support this channel, please visit / blackpenredpen
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@ashishbinu53155 жыл бұрын
it is called as king property because it fights integral like a king.
@nachiketsharma45074 жыл бұрын
Indeed
@VANTABL4CK2 жыл бұрын
most kings are lazy and fat and just order people around until the people fight back and execute him
@LS-Moto5 жыл бұрын
Right after surgery, battling cancer and watching blackpenredpen math videos 😂😂😂 ...btw no worries, my chances are at 85 - 90% and one of two tumors has gone today 💪
@faith31745 жыл бұрын
i hope you recover soon. sending you good vibes
@blackpenredpen5 жыл бұрын
I wish you the best luck. Hope you get well soon! I would like to make you a happy mathematician, too. Please send me an email blackpenredpen@gmail.com and we will go from there.
@LS-Moto5 жыл бұрын
@@blackpenredpen that you very much guys.... I will email you right now :) I live in Belgium, but I hope that's ok :)
@MuhammadFarhan-dp5ej5 жыл бұрын
Get well mate
@LS-Moto5 жыл бұрын
@@MuhammadFarhan-dp5ej thank you. Appreciate these kind words :)
@matthewstevens3405 жыл бұрын
Its called the "King" because virtually any trig function can be demolished using the substitution. This is especially true when within logs or when you have a sin/cos pairing. It is also fairly easy to change the bounds from pi/2 to another range by using the R-alpha method or by symmetry on a graph
@herbie_the_hillbillie_goat11 ай бұрын
Source?
@d1o2c3t4o5r5 жыл бұрын
look, whenever I see a definite integral, especially involving trig, I get nervous.
@icespirit5 жыл бұрын
and sqrt2 in the exponent :p
@vivekt18993 жыл бұрын
I just skip the questions lol😂
@sergioh55155 жыл бұрын
It always the most intimidating integrals that have an elegant solution! :)
@blackpenredpen5 жыл бұрын
Sergio H yup!!
@ianmoseley99105 жыл бұрын
Integrals are merely representations of relationships between variables; any intimidation is in your own mind
@sergioh55155 жыл бұрын
@@ianmoseley9910 k
@vesna12354 жыл бұрын
Lmao nice response
@metin4yt5 жыл бұрын
I can't wait to surprise my math teacher by using this at the exam
@blackpenredpen5 жыл бұрын
Stefan Stefi nice!!
@harrabi155 ай бұрын
mine would give me a zero because "we didn't learn it in class"
@Alians01085 жыл бұрын
I love maths. This video was so crazy. Especially I+I = 2I
@icespirit5 жыл бұрын
lol
@kreepi83813 жыл бұрын
Lol
@adamuadam48335 жыл бұрын
Hi Am shedrach from Nigeria Am perplexed with ya teaching As your channel had become my favourite companion and you my favorite teacher Thanks sire
@aurithrabarua46985 жыл бұрын
Absolutely very much important strategy to solve definite integrals. I can assure you that , its my one of the most cherished birthday presents. Thanks Steve. :) :)
@josepherhardt1644 жыл бұрын
I took two full years of calculus and don't recall ever hearing of the King Property. I've had more math fun watching your vids than I ever did in class.
@nootums5 жыл бұрын
It's not nice to say FU 😂😂😂😂😂!!!!
@pgoeds74205 жыл бұрын
Felix Ungar disagrees.
@stuartyeo53544 жыл бұрын
If you say F of u fast if enough you getting f***ing u, and that's not nice as well.
@enrique0974 жыл бұрын
Fu miley sairus song
@cuberkam90723 жыл бұрын
😂😂
@BloobleBonker3 жыл бұрын
Sir. You have a super gift for making maths so easy and fun
@michaelzizzo672610 ай бұрын
I watched your recent video using the king property which brought me to here for the proof of the king property. Amazing how much you have improved over time! You were still a great teacher here, but you are much more comfortable in your most recent videos and your English has definitely improved. Thanks for all the great content!
@biddu26832 жыл бұрын
To the person battling cancer: many, many prayers for your COMPLETE HEALING. Please keep on watching this brilliant channel! Stay blessed my friend.
@mohandoshi6214 жыл бұрын
The explanation of this interesting problem can be described in just two words - SIMPLY AWESOME. BPRP - you rock.
@weinihao36325 жыл бұрын
Maybe the name is derived from the castling move in chess, where the king and a rook switch places?
@z01t4n5 жыл бұрын
Yeah, I'm pretty sure that's the case.
@croxxx32625 жыл бұрын
This seems to be the most correct response! (As well as the most romantic.)
@blackpenredpen5 жыл бұрын
Wei Ni Hao nice!!
@quocanhnguyenle49525 жыл бұрын
Lol, that does make sense!
@ianmoseley99104 жыл бұрын
I was assuming it was named after a professor King?
@diablo62502 жыл бұрын
I absolutely love your channel!
@urmantaqi32534 жыл бұрын
Very clear explanations of complex problems. Thank you.
@hamidbennani19835 жыл бұрын
It's called King Property because it's used only by Kings of integrals 💪
@lucasfrykman58895 жыл бұрын
Wow, so cool! Thanks blackpenredpen.
@tomasblovsky58715 жыл бұрын
Oh..my...god, that is brilliant! Thank you so much!!
@silentintegrals91042 жыл бұрын
Nice video!! What a beautiful integral!
@snejpu25085 жыл бұрын
Happy New Year, mr Chow! If you celebrate this one.
@blackpenredpen5 жыл бұрын
Thanks!!!
@henryvalencia33143 жыл бұрын
This Is so beautiful!!!! Thank you!!!!
@ozzyfromspace3 жыл бұрын
I realized this property a few weeks ago while solving a random research integral involving logs, I had no idea it was called the King Property. Good to know 😊. Geometrically, the king property just says that whether you start from the left or the right, the area under f(x) should be the same, so reflect the curve along the vertical axis and push the curve to the right appropriately, and the property jumps at you. It’s less random than it seems. Nice video BPRP! 🙌🏽🕺🏽🎊💯✨🤓
@mahxylim79832 жыл бұрын
thanks!
@holyshit9225 жыл бұрын
I saw integral from this example on the math forum with polish language One of the guys suggested to use substitution to make interval to be symmetric over zero and then use additive property addition of integrands not intervals After using additive property first integral should be integral of odd function on interval symmetric over zero and second should be easy to evaluate
@user-hq2bu5qp3h5 жыл бұрын
すごい、、、日本の高2ですがただの積分公式とその証明にこれほど驚かされるとは… What a great formula!! I'm surprised that I've been surprised at just a formula and proof (I'm sixteen year-old-student in Japan☺️)
@makhloufbenmehiris95595 жыл бұрын
Thank you professor for the lesson
@blackpenredpen5 жыл бұрын
Makhlouf Benmehiris you're welcome!
@Random-ck7kw6 ай бұрын
youre a funny dude earned my like today.
@ekueh5 жыл бұрын
Happy New Year
@user-xe2rb7vy8y3 жыл бұрын
Thank you soooo much
@kenty2405 жыл бұрын
I am touched.
@sangeetanarendrasingh54165 жыл бұрын
Thank you sir!
@erroraftererror83293 жыл бұрын
lol, I got a Kingsford ad in the process of watching this video.
@karolakkolo1235 жыл бұрын
This is the first putnam integral that I did in my head. I am proud of myself :)
@Patapom35 жыл бұрын
Amazing!
@radiotv6245 жыл бұрын
What a clever technique!
@claudiorebelo Жыл бұрын
Very nice indeed!
@okhtayghorbani63613 жыл бұрын
Amazing👍👍👍👍
@madaaz63335 жыл бұрын
It's amazing! It is to solve an integral indirectly!
@ianmoseley99104 жыл бұрын
If you really want to confuse someone who has not seen this before you could use the i'th root of tan(x)
@wristdisabledwriter28935 жыл бұрын
I love the line about using f of u instead of f U
@TheDigiWorld Жыл бұрын
"it's not nice, say f of u" 😂😂😂 love your sense of humor
@spelunkerd4 жыл бұрын
What a creative solution, another one for the bag of secret tricks.
@gamingbutnotreally60775 жыл бұрын
Good stuff
@Polyy._sw2 жыл бұрын
amazing
@Cliff865 жыл бұрын
After you do the King property can't you just set x = (pi/2) - x Then that tells you that x = pi/4 Or does that only work because 2*I=1
@abelgideons5 жыл бұрын
very cool!!
@neeraj82785 жыл бұрын
When you did the previous Putnam integral, after you put the substitution x = tan theta if you would have applied king rule the integral would have been much shorter
@nanigopalsaha24084 жыл бұрын
Can you please elaborate?
@amithawanigasooriya56452 жыл бұрын
thanks a lot
@silentintegrals91042 жыл бұрын
Totally agree!!!
@christoskettenis8805 жыл бұрын
Very nice property!
@soumyachandrakar91005 жыл бұрын
And here comes the king!
@nicholasleclerc15835 жыл бұрын
Soumya Chandrakar You mean.... The Qin ? Oh, wait, he already did it at 11:14; nvm...
@xcalibur64825 жыл бұрын
how do you know what i am studying right now ??? 我感到震惊!
@user-fc2od9zr9r4 жыл бұрын
Im Japanese and I just started studying English but I could understand this property easily! thank you!
@James-zs3vm5 жыл бұрын
awesome!
@mathematicadeestremo63965 жыл бұрын
1/(1+tan^2½x) =sin^2½x/(sin^2½x+cos^2½x) we use the property ..f(x)/f(x)+f(a+b-x)[integration from a to b]=b-a/2 get the value is π/4 as cos x =sin(π/2-x)
@subaruyagami23275 жыл бұрын
I just calculated the area under the curve, and it came out to be π/4.
@samb93525 жыл бұрын
BPRP, I have kind of a burning math question that has been on my mind for almost a year now, but I've struggled to find good explanations for it online. Basically, I would like to know if there is an easy way to find the equations for some parametric curve (say {x(t),x^2(t)}) where the speed (independent of direction) of a particle on said curve must be constant. I have tried setting up the relationship where sqrt(x'(t)^2+y'(t)^2)=1, but I haven't gotten much farther. An explanation for how one could do this, or whether it can be done would be greatly appreciated, even if there is a simple answer.
@i_am_anxious02475 жыл бұрын
That’s awesome
@iamjcx4 жыл бұрын
In our syllabus my teachers told that as this property is the most useful one so we call it the kings property and if the lower limit becomes 0 then it is called queens property 🤔🤔
@lucashoffses90195 жыл бұрын
Here’s an integral you might want to try solving ((1-u)/u)^x du from 0 to 1. It has a definite value when -1>x>1. The solution can be written in terms of elementary functions. Good luck!
@lucashoffses90195 жыл бұрын
star dust I’m curious to know how you got that answer. Did you look it up?
@danieldanmola826629 күн бұрын
Correct name is called the reflection properties..not King properties.. Nice video
@jaredbeaufait59545 жыл бұрын
No matter the power tangent is raised to, the answer is pi/4, neat
@blackpenredpen5 жыл бұрын
Jared Middle yup!!!
@DragonKidPlaysMC5 жыл бұрын
Can you do a video on how to calculate the sum of a harmonic series? I’m struggling to find the sum of this sequence 1/2+1/3+...+1/2019 any help please?
@wpbn56135 жыл бұрын
Not the nicest answer ever but I think it's ln(2019) + 0.57722 ? 0.57722 is a constant but I don't remember what kind EDIT: it's actually ln(2019) - 0.42278 I think? Bprp should make a video on this, but I do know the formula converges to "ln (x) plus 0.577" for big numbers
@DragonKidPlaysMC5 жыл бұрын
It’s actually called the euler-masecheroni constant. How did you come up with the adjusted value of it for lower values of n?
@mat1305h5 жыл бұрын
DragonKidPlaysMC You can either say that sum_{n=1}^{2019} 1/n = integral_{x=1}^{2019} 1/x dx + O(1) = log(2019) + a constant. The constant depends on 2019 and by definition tends to gamma, the Euler-Mascheroni constant, but the convergence is extremely slow (as you'd expect from a logarithmic convergence). Indeed, for n up to 100 000, there is still a mistake at the 4th decimal of the approximation! You therefore can't reasonably expect a good approximation from values of n this low. You could use Abel's summation formula to derive an exact form. Complete the integral of floor(x)/x^2 dx from 1 to infinity to get 1-gamma (see wiki for the integral forms).
@dolphinlunggrin65945 жыл бұрын
There is no nice result for this. Since you start at 1/2 what you get is 1 less than the 2019th harmonic number H_2019. There is a formula for those but it's not really helpful. H_n = M+D(n+1) Where M is the Euler-Mascheroni constant and D the digamma Function. So your sum would be M+D(2020)-1 Which is about 7.187820910...
@Cashman91115 жыл бұрын
just bring everything to common denominator, easy
@lok73965 жыл бұрын
Plz make videos on complex analysis
@MoonLight-sw6pc5 жыл бұрын
Impressive !
@ThePhenomBot5 жыл бұрын
Moon Light pubg guy
@ThePhenomBot5 жыл бұрын
why did you not tell me this one day before I had my maths exam yesterday.
@martinepstein98263 жыл бұрын
This is analogous to a trick you can do with finite sums: Sum from n = a to b of f(n) = Sum from n = a to b of f(a + b - n) It's easy to see why this works if you write it out: f(a) + f(a+1) + ... + f(b -1) + f(b) = f(b) + f(b -1) + ... + f(a+1) + f(a) You can actually prove the integral identity by applying this trick to the Riemann sums :)
@luigikart22254 жыл бұрын
my skin is peeling, tearing and reaping. my brain is melting, and my hair is falling
@aaishikdas5 жыл бұрын
Yeah...I like it..
@kokainum5 жыл бұрын
Hmm. I'm thinking about switching sqrt(2) to y and then writing this integral as function of y. It's constant so its derivative is 0. Then I'd try to get another equality by derivating function under integral over y. Ofc it needs to be proved that it's valid method but it should be doable and maybe it's gonna lead to something interesting? I'll give it a try when I have more time. It was probably done by someone cause if it's famous (though I probably didn't remember this one during my studies as I'm forgetful) then I'm sure someone did that as it seems natural way to get new equalities that may be useful somewhere. I wonder if you can do same trick with half-derivatives as I don't know if you can move half-derivatives under integral. Actually this makes me want to find out more about half-derivatives. ;)
@MarkMcDaniel4 жыл бұрын
You have a continuity issue since there is an asymptote at pi/2.
@youssefaly70673 жыл бұрын
When I look at the intro and it says Putnam : nope straight to the solution :P
@natealbatros38485 жыл бұрын
can you always call an integral I and then adding and subtracting them?
@frozenmoon9985 жыл бұрын
I am in strong belief that f (u) is indeed not polite to say, however, love u is! So, I wanted to say: I just called, to say, I love you (bprp)!!
@blackpenredpen5 жыл бұрын
Svetozar Delchev thank you!!!
@CrystalClearMaths4 жыл бұрын
It is much nicer to say 10q :-)
@yashtripathi90793 жыл бұрын
When you use blue pen even though your channel's name is 'black pen red pen' haha.
@rakhimondal59495 жыл бұрын
This problem literally came in our unit test...
@rajendrasinghrathore34245 жыл бұрын
@blackpenredpen can i also ask my doubt ..? If yes then where and how?
@ShenghuiYang5 жыл бұрын
Every piece on chess board could have such a property.
@user-db1yz5iu2s3 жыл бұрын
すごごごごごーーーー!!
@NamaSaya-wg9gn5 жыл бұрын
Your face reminds me of my friend
@NavyBlueMan5 жыл бұрын
I feel like the answer is super obvious, but there's also a chance it's just some calc identity I never learnt, but why does it equal 1 at 9.30? It's super late at night and looking at it makes my head hurt and I can't figure out what the process is . Maybe in the morning I'll have an idea of what's going on but yeah, anyone able to explain?
@weenrar5 жыл бұрын
If two separate integrals have the same bounds of integration, you can add them together to make a single integral with both expressions on the inside. BPRP added both integrals together, giving him a single integral from 0 to pi/2. So, 1+(tanx)^sqrt(2) on the top, and 1+(tanx)^sqrt(2) on the bottom. Since they’re the same, you just simplify to 1/1 = 1.
@bijidatome7393 жыл бұрын
Almost i would ask that what if we change the squareroot of 2 after that you said that doesnt matter thanks but why mmm
@sambhav27275 жыл бұрын
Blackpen Redpen Bluepen! YaY!
@tienhulin4 жыл бұрын
Hi, may I ask how to integrate this if the upper limit of the integral is pi? A whole pi. Thank you.
@gauravmandal0075 жыл бұрын
Bro I really like your videos.... But only problem is ur videos are very long...... (I watch ur video in 2× speed) to save time. ...
@loganbaker30005 жыл бұрын
Hey everybody, for my Honors English IV class we have to write a research paper on a modern theory in the field we want to study in college. I am planning on majoring in math but I dont have any ideas for topics. It has to be something I can understand enough to write 25 pages about, keep in mind I only have up until trigonometry (I'm in it right now) under my belt. Does anyone have any suggestions?
@blackpenredpen5 жыл бұрын
I just set up a forum on my site blackpenredpen.com I think it's better for you to post this there since it's kinda hard to others to see this comment.
@angelmendez-rivera3515 жыл бұрын
Try using hyperbolic functions and relating them to the trigonometric functions.
@Munnu-hs6rk3 жыл бұрын
This ques was less than 30sec for me by same method
@kartiksharma71665 жыл бұрын
Bprp is here to like everyone's comment ☺️☺️☺️☺️☺️😊😊
@kartiksharma71665 жыл бұрын
Now please solve this plsplspspplspspspplplsplspls x+x^2+x^4+x^8+x^16+ x^32+..... given |x|
@anushkrajbordia18733 жыл бұрын
These type of questions (on king's property) are taken in beginner level integration classes in India for students preparing for JEE. P.S.: Queen's property: Definite integral of f(x) w.r.t to x from 0 to 2a equals [definite integral of f(x) w.r.t x from 0 to a]+[definite integral of f(2a-x) w.r.t x from 0 to a], where a is a real number, & this can be proved by writing definite integral of f(x) w.r.t x from 0 to 2a as the sum of definite integral of f(x) w.r.t x from 0 to a & definite integral of f(x) w.r.t x from a to 2a, & then substituting x=2a-t in the definite integral of f(x) w.r.t x, where the upper and the lower limits of x are 2a & a respectively, i.e., the second integral of the sum. In addition to that replace dx by (-dt) and you'll get the desired result, or rather I should say, that's a good place to stop (Michael Penn ref. people😊)! Also, my teacher told our class that queen's is generally used with king's property & even though I've no idea where does king's property gets it's name from, I'm sure the name of queen's property is such due to it's usage with king's!!
@maverickgames59722 жыл бұрын
Same here in Hong Kong, it is a primary method for us in the HKDSE Mathematics Module 2 Algebra and Calculus, that we are required to derive the King's property out during the exam and apply it
@srpenguinbr5 жыл бұрын
Let's solve math problems also did a video on this
@bandamkaromi5 жыл бұрын
thumbs up. 😎
@blackpenredpen5 жыл бұрын
Hojeong Lee Like!
@saharhaimyaccov49775 жыл бұрын
Can you prove in a straight triangle when only the sides are divided by 5 then the height to the rest is an integer? I succedded :) . Example- Stand-3 x Stand-4x Over-5x Height -2.4 x Or S-75 s-100 o-125 H-60
@prathameshkurve49823 жыл бұрын
There are three main properties in definite integral so they just gave them the names 1)king property 2) queen property 3) jack property According to my opinion
@sumathi3875 жыл бұрын
That was King level
@Atlas929365 жыл бұрын
"It's not nice to say FU" BAHAHAHAHBABABAHAHAHAHA LOOOL
@kriswillems56614 жыл бұрын
No need to know calculus. Just knowing the integral is the area under the curve is enough. The function is symmetric around (pi/4, 1/2) so the area under the curve is (1/2)*(pi/2). (=average height*width).
@quantumcity66795 жыл бұрын
Hello guys...... I'm not champion in mathematics but I have doubt...on area under the curves..... See if I have an integral of x^3 dx from 1 to -1 ...so it covers the area under the X-axis so we can write it as 2*ingration of x^3dx .....because the area between 0to1 is same as the area between -1to0.....see the graph of x^3 and area should be positive... I gaused.. So the answer should be 1/2...but my professor told me that it was 0...and now I'm getting 😕 on that area..... So can somebody tell me why that is so ? 🙏🤒
@jaymenchang42435 жыл бұрын
You are correct saying that the area is the same in terms of regular terms (absolute value of the area magnitude wise) however when integrating we treat areas under the xaxis as negative, so the area from 0-1 is the negative of -1 to 0
@UjwalAroor5 жыл бұрын
Actually that depends on the question.If your prof straight up just gave you a definite integral to solve then he is right.However if he specifically asked for the area under the curve then you are right. Usually area is positive so yeah.
@BigDBrian5 жыл бұрын
Whenever the function is below 0 you can think of the area as being "signed" with a negative sign (-). Meaning that when you add it up with other areas, you actually subtract it when you take the integral.
@jaymenchang42435 жыл бұрын
Ujwal 9000 the problem with that intepretation is that from -1 to 0 the area is not "under the curve in fact its under the xaxis towards the curve, so the only way it would be "under the curve" is if the function was shifted vertically, or if you were asked to find the area between y= -1, x = 1 and the curve THEN u could interpret it as just the area under the curve, however the integral will give you the correct answer as f(x)-g(x) where g(x) is negative will yield a positive value
@quantumcity66795 жыл бұрын
@@jaymenchang4243 satisfying answer.... Thanks 👍😇
@kingphone88245 жыл бұрын
Hi! you solve the problem but it ........so
@aarondevon81444 жыл бұрын
If the red integral is = to the black integral , and both denominators are the same , dose that mean that both numerators are = ? If so tan(x)^root 2 =1 so the denominator of the red integral = 2 . How come the step with 2i equation is needed?