A Terrific Radical Equation | Can You Solve this?

A Terrific Radical Equation | Can You Solve this? | Algebra

Рет қаралды 1,638

16 күн бұрын

A Terrific Radical Equation | Can You Solve this? | Algebra
Welcome to another thrilling Math Olympiad prep challenge! 🎉 In this video, we dive into a terrific radical equation that will test your problem-solving skills and mathematical prowess. Can you beat this challenging equation and find the solution?
Join us as we walk you through the steps, provide useful tips, and unveil the solution to this radical equation puzzle. Whether you're preparing for a math competition or just love tackling tough problems, this video is for you!
🔔 Don't forget to subscribe for more math challenges, tips, and tricks to enhance your skills!
We'll cover:
Key concepts and definitions
Common pitfalls and how to avoid them
Detailed example problems with solutions
Tips and tricks to solve these equations efficiently
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Пікірлер: 12

@kassuskassus6263 15 күн бұрын

Two real solutions w=4 and x=5.

@RajeshKumar-wu7ox 15 күн бұрын

-1,-2,4,5

@gnanadesikansenthilnathan6750 15 күн бұрын

Got this problem

@woobjun2582 15 күн бұрын

Squaring and rearranging, x²(5 +6x -x²) = 42x +40; x⁴ -6x³ -5x² +42x +40 =0 with (-20/21) ≤ x ≤ 5. Then by RRT and SDMs (x +1)(x -4)(x² -3x -10) =0; (x +1)(x -4)(x +2)(x -5) =0, that is, x = -1 (rejected) x = 4 (accepted) x = -2 (rejected) x = 5 (accepted) Thus, x = 4, 5

@abcekkdo3749 15 күн бұрын

X=5,4

@user-ny6jf9is3t 15 күн бұрын

Χ=4 ,χ=5

@user-kt1dm9jz5t 15 күн бұрын

X>0, X=4,5

@user-kp2rd5qv8g 15 күн бұрын

After squaring and rearranging, we get x^4-6x^3-5x^2+42x+40=0. By inspection, we see that x=5 is a solution. [x^4-6x^3-5x^2+42x+40]/(x-5) = x^3-x^2-10x-8. x^3-x^2-10x-8=0 has x=4 as a solution and [x^3-x^2-10x-8]/9x-4) = .x^2+3x+2. x^2+3x+2=0 has x=-1,-2 as solutions but by inserting them into the original equation, we see that these are spurious solutions. So, x=4,5,

@tejpalsingh366 15 күн бұрын

X= -1; 4; 5; -2 -1&-2 not viable Hence x= 4; 5 are only solns.

@mulla_modi 15 күн бұрын

X=4,5, but I must add with disappointment that this was not at all a terrific problem

@tieshanhuang2466 11 күн бұрын

This is not real mathematics, but some kind of arranged lucky draw like cheating. I solved it very easily, as I have to believe that it has simple solutions, then I simply try and find that -1 and -2 are preliminary solutions of the quadrap equotion. Based on that, then I easily got the other two true solutions 4 and 5 as for the original equation. A new but a real challenge, we change the problem a little bit, change number 40 to 41 for instance, can anyone still solve the problem? That's why I say this is not real mathematics but arranged lucky draw, some kind of cheating game. By similar tricks, I can list hundreds of similar testing problems in one week and let thousands of mathematics genius to scratch their heads for one month!

@RealQinnMalloryu4 15 күн бұрын

{42x+42x ➖ }=82x^2{40x+40x ➖}=80x^2 {82x^2+80x^2}= 162x^4/{5x+5x ➖ }=10x^2 {10x+10x ➖ }=20x^2 {10x^2+20x^2}=30x^4 (x^2)^2 =x^4 {30x^4 ➖x^4}= 30x 162x^4/30x=5.12x^4 5^1.3^4x^4 1^1.3^2^2x^2^2 3^1^1x^1^2 3x^2 (x ➖ 3x+2)