When working in polynomial rings over an integral domain, polynomials can be either reducible or irreducible. We begin to discuss some of the consequences of this.
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@priyamhazarika2744 Жыл бұрын
Thank you 😊, it was helpful and time saving
@Forced24 жыл бұрын
Amazing video.
@patrickjones15104 жыл бұрын
Thank you. I created these videos for an online class that I was teaching, and I'm always happy that other people find them useful.
@bobonaqa2 жыл бұрын
am more confused than before haha... but don't worry, it's probably just me
@sangeethag14083 жыл бұрын
Prove that Any polynomial in F[x] can be written in a unique manner as a product of irreducible polynomials in F[x] , can you give a proof for this question?
@patrickjones48133 жыл бұрын
The basic idea, which you'll have to add details to, is that suppose f(x) is a polynomial is F[x]. It is either reducible, or irreducible. If it is irreducible, you're done. If it is reducible, then it factors into polynomials of lower degree than the original. Those polynomials are individually either reducible or irreducible. Repeat the original argument. Because the degrees have to be lower each step, this can't be an infinite process.