definitely. mine was way harder

@@RazorFistMusicOuttaTheWorld What was your question that they gave you?

This isn't an interview for maths, but for natural sciences. Maths questions would surely be harder

and interview for a maths undergraduate course will have harder questions, this is most likely for natural sciences, computer science, etc.

How would you approach drawing that? How would you know the Y value when X tends to zero? You knew l'hopitals rule at age 17?

the fuks the fbi doing here

quick burn the hard drive

haha. Other ways to become employed as an engineer is to note that 3^2=pi^2=g=10

@@NitroniumGaming Or even better: ∫cos(x)dx from 0 to π/2 cos(x)=1 therefore we have ∫xdx from 0 to π/2 Fundamental Theorem of Calculus: (π/2) - 0 = π/2 Consider: π=e and e=2 2/2 = 1

Sure, but that's a tricky equation to draw a graph of (which is why it's a question for a place at Cambridge), because of what happens at x=0.

@@Treviscoe graph is discontinued at x=0

@@samuel08790 No it is 1.

@@bawseeeee602 no, the function approaches 1 around x=0, but it's undefined at x=0

@@Rokkc you're not allowed to use lhopital for sinx/x, its a mathematical definition

mine is on 12pm on wed as well!

@@ngocanhdoan4835 Mines wednesday too!

hope it went well!!

how’d it go?

tell us how it went!

Lol

You would determine if there's any symmetry, see where the graph crosses the x and y axis (if it does cross). Find stationary points and their nature, find points of inflexion, find asymptotes and see how the value of the function changes as you approach said asymptote, and see how the graph behaves as x approaches infinity in the positive/negative directions.

Hi Rohith, I'm not sure what you meant when you typed 'solecrd'. If you want to see an example of how an interview will be conducted online this year, watch this: kzfaq.info/get/bejne/i9d8aMSD1bO1dWg.html. Whilst the physical set-up will be different, the content of the interview, and how Colleges assess candidates’ knowledge and potential will be the same as it is for in-person interviews. There is more helpful advice at www.undergraduate.study.cam.ac.uk/applying/interviews/online-interviews

@@MathematicsatCambridge I think he meant 'scored'.

@@cloroxbleach7554 Bruh that's the worst typo ever

Yes but plz correct me if I am wrong. This is for high school students and from I know, calculus 1 is done at college.

True calculus is a college course. Many high schoolers do take calculus as seniors.

@@irwinsaltzman979 thanks for the info. Also, can you plz let in on what you mean by that (senior). I live in england so am not really familiar with the american education system but I am quite interested tho.

Final year of high school in US the students are classified as seniors.

@@irwinsaltzman979 ok thx. Also if you dont mind, cab you plz send s link yo the syllubus for everything that is covered in high school. I am quite intrigued. Thank you

Divide p on both sides and n=1 ez where is my million bucks

@@h4z4rd28 What if p=0 though?

@@farazriyaz9078 bruh man you dont know that p stands for prime?😂

@@h4z4rd28 Well, does it? P stands for Polynomial Time, and I don't think that has anything to do with primes. Correct me if I'm wrong haha

@@farazriyaz9078 P also stands for the set of all polynomials over some field but yeah, in this case its prime in my opinion. And btw i still didnt get my fields medal idk whats wrong with them

well for people that is capable in math the question will be considered easy, its not for the average student though. Also the point of this interview question is just to show how you think its never meant to be hard (to compensate for that Cambridge has the STEP examination) :) .

@@adrianwongso3784 oh!! I didn't know about the examination! Thanks!!

Yes, but this interview is probably for a BSc and not for a MSc.

I'm pretty sure this is not the full depth of mathematical questioning being asked lol

Put x=90 and your equation fails. Because then y=1/90

@@afrinahmed1620 its a meme.. dont take it seriously

The unit of x axis is radian not degrees

Start by the Taylor series expansion of the function around the origin and you quickly see the parabolas emanating. Now that would impress the interviewers. But then you have to be careful not to embarrass them in the process else you'll be disqualified.

@@spicyy812 Exactly, I know😊😇

Lhopitals rule?

@@nonamesleft9699Nice Bro😀😅 But only when lim x tends to zero. Here it is exact zero. There is no limit introduced here. Only the graph of the function is demanded.

it is indertemined there but limx->0 is 1

Uhh, you can perfectly draw the graph of this function. The fact it is undefined at 0 doesn't mean it's undrawable. If that was the case, 1/x would be undrawable too, because it's undefined at 0 When you want to see how a graph will behave when reaching a point at which it is undefined, you check the side limits (knowing the existence of the limit as a whole isn't necessary for drawing a graph). In this case, the lim of sinx/x when x is tending to 0 is 1, from both sides (you can check it using De L'Hospital rules) so what you do is make the graph so as to go close to 1 when x is approaching 0 and put a white circle on the point (0,1). Also, graphs of the type sinx*f(x) where f(x) is a polynomial, a logarithm, an exponential and prolly other shorts of functions, have the "property" that the sinx function is essentially deformed so as to match some of its points to those of the original f(x) and -f(x), thus making it easier to draw Edit: did a mistake with calculating the limit, it tends to 1 Edit 2: Influenced by the original sinx function, I initially said that the local maxima and minima of an f(x)*sinx are matched to points of f(x) and -f(x). Those points aren't necessarily local minima or maxima. Edit 3: just a heads up; when it comes to sinx/x, note that using De L' Hospital rules isn't considered a proper way to prove that lim(sinx/x) = 1 when x tends to 0. It's more of a way to confirm that.

@@bigshrekhorner Exactly sir, the behaviour of the graph will hint us that we need to put a white circle there but this also means that at x=0 we are not allowed to draw. That is what I said we can draw the graph but not at x=0 directly.

Hahahahaha yep it was a horrible experience for me last year. Even though I didn't get in I'm kind of glad, since I would have enjoyed learning in that environment even for a second

over half of the people who study at cambridge went to non private schools

@@benatronbtang6877 A policy since year 2000

You soon realize that the world revolves on BS. This is just that first step.

Not really true tho is it look at they admission stats

Not true at all salty because you cant get in

What a load of nonsense. If you look at the stats most students are from state schools. My local state school sends 20 per year

@@hungryhog1 The number your state school sends is irrelevant. How many get a place? Probably zero. Smegma College Worksop get zero also.