I have provided the link in the description for the more videos. Also check the community tab section of the channel, where regularly the quiz related to the different topic is posted. If you go to the earlier quiz then you will find some quiz related to RLC circuit as well.

plzz plzzzz plzzz make a video on graphical representation of RC , RL and RLC resonance .. series as well as parallel

how did you get this

It is just representation of the impedance in rectangular form, as impedance we got was in polar form. So, the real part will be the resistance and imaginary part will be the reactance. I hope it is clear to you now. If you still have any doubt then do let me know here.

You see, there is a 30 of Z degrees, then the sin30=Z/X=1/2 => X=6.67/2=3.33 then you find R=(Z^2-X^2)^(1/2)

Yes, correct.

Soon, it will be get added for this video too.

If r

Yeah I don't get that part I tried using the solution provided but I had R=5.94 and X=3.03 please help me

The impedance will have a real and imaginary part. So, it can be treated as a complex number. And the algebra which is used for the complex number can be applied over here too.

Yes.

Thanks

Can u please explain me last question U probably forgot that question but how did we seperate z

I think you mean to say the impedance of the inductor right? The impedance of the inductor or reactance is 2*pi*f*L At DC, f = 0. So, in steady state condition its impedance will be zero.

In the question, only the magnitude of the reactance is considered.

yes

As soon as I get the time then I will definitely make a video, or at least I will update the note on it in the description.

The link for the solution has been already updated. I have already pinned that comment. Here is the link: drive.google.com/open?id=1bMn2TbCP9fF0EceQqxHpi8mYr_l53ZPw

If r ∠ θ is impedance in polar form, then in the rectangular form it is x + j y, where x = r cos θ and y = r sin θ.

Let's say 1V of phasor is making an angle of 45 degrees with the reference axis. Then in rectangular form it will be 1*Cos(45) + j 1*sin(45) = 0.707 + j 0.707

Thanks

Generally, in Series RL, RC and RLC circuits current is taken as reference because current that is flowing through all the components is same, but the voltage is different. And we don't know about the resultant voltage. In the given circuit suppose if you know the resultant voltage amplitude and phase, then you can take it as a reference and current will lead or lag accordingly. For parallel RC, RL and RLC circuits, as the voltage is same across all the components, so voltage is taken as reference and resultant current is found. So, in short, suppose if you take resultant voltage V as a reference then current will lead or lag accordingly. For example, in series RC circuit if you take voltage V as reference, then current will lead the voltage by some angle Phi. I hope it will clear your doubt. If you still have any confussion do let me know here.

In pure R circuit we take, V as reference.. What's the reason?

At 3:56 , you have taken voltage as reference..but here you are saying that we take reference the value known to us... Plz clarify..

No, the amplitude may not be the same. It will depend on the value of R. Let's say I= 2A and R= 2 ohm, then VR = 4V. In that case, both I and Vr are in phase but the amplitude is not the same.

@@ALLABOUTELECTRONICS I think there is a mistake and you wrote "Vm" instead of "Im" at 4:37

@@charleswolfe6849 No, that's alright. If you see the phasor diagram, the voltage leads the current. Or in another way, I can say that the current lags the voltage by some angle. That's why I = Im sin (wt - Φ). I hope it will clear your doubt.

@@ALLABOUTELECTRONICS No it's not about which one leads the other, it's that I think you wrote I = Vm sin(wt - theta)

I have already given in the description along with the solution. Please check the description.

I have collected it... I want some more both questions nd answer.. pls help sir.... nd pls suggest text buk

If you want to solve more problems then I would suggest this book. Network Analysis and synthesis by Ravish R Singh www.amazon.in/Network-Analysis-Synthesis-Ravish-Singh/dp/1259062953/ref=sr_1_1?ie=UTF8&qid=1513183137&sr=8-1&keywords=ravish+singh+network+analysis

thanks sir... if u have some material pls put it

It is used to represent the imaginary part, very similar to complex number A+ jB, where B represents the imaginary part of the number.

4+ j3 is the total impedance (R + jwL) In the given example w= 300 and L = 0.01. S0, wL= 3. Hence, total impedance Z= 4+j3. I hope it will clear your doubt.

I was asking about "5

In the calculator, convert the A+jB into r

Ok.thanks..

@@ALLABOUTELECTRONICS thank you so much

for magnitude we take underroot of( 4square + 3square) for angle we take tan inverse of (3/4)

Its rectangular form to polar form conversion. If a+jb is a complex number then it can be represented in the polar form as r< theta. Where r= sqrt (a^2 + b^2) and theta = tan-1(b/a) I hope it will clear your doubt.

@@ALLABOUTELECTRONICS what is 'a' and 'b'

It is used to define the imaginary term of the impedance. (Similar to the complex number)

If XL > Xc, then VL>Vc. Because they are connected in series and the same current is flowing through XL and XC. So, in the phasor diagram, the net voltage due to Xc and XL would be VL-Vc.

Ka ka Kachi daze

Ratio of two phasors = V/I

The graph is just for the representation of phase difference between voltage and current.

Its rectangular to polar form conversion. Let's say you have A+jB in rectangular form. Then in polar form, it is r

Thanks

It's used to represent the imaginary part. Similar to A+jB in the complex number. Where jB represents the imaginary part.

@@ALLABOUTELECTRONICS thanks