Transient Analysis: Solved Examples on First order RC and RL Circuits

Рет қаралды 249,537

Күн бұрын

In this video, Examples/Problems on the First order RC and RL Circuits have been solved.
So, in this video, before solving examples, initial conditions and final conditions for the basic circuit components during the transient have been discussed.
Then after, steps to solve the First order transients problems have been discussed.
And after that three problems based on this first order RL and RC circuits have been solved.
Link for the PDF file for more examples based on this RC and RL circuit has been given here:
drive.google.com/file/d/0B3FO...
To learn more about the transient analysis, check out my other videos:
1: Transient analysis: Behaviour of the basic circuit components
• Transient Analysis: Be...
2: Transient Analysis: First order RC and RL Circuits
• Transient Analysis: Fi...
Timestamps for the different topics in the video are given below:
0:00 Introduction
0:40 Initial conditions and final conditions for the basic components like inductor and capacitor.
2:50 Steps to solve the transient problems for the first order RC and RL Circuits
4:57 Example 1
8:58 Example 2
11:01 Example 3
This video will be helpful to all students of science and engineering in understanding the concept of transient analysis and it will help them in solving the problems based on this first order RC and RL circuits.
#TransientAnalysis
#ALLABOUTELECTRONICS
Follow me on KZfaq:
/ allaboutelectronics
Follow me on Facebook:
/ allaboutelecronics
Follow me on Instagram:
/ all_about.electronics
Follow me on Twitter: @rushalmshah
Music Credit:
www.bensound.com/

Пікірлер: 240

@ALLABOUTELECTRONICS 6 жыл бұрын

The solution of the examples given for the practice has been uploaded in the PDF format. drive.google.com/file/d/0B3FOmN0FcD6OWFc2OXAtcUtmcXc/view?usp=sharing&resourcekey=0-yNuVb1wrtYbtPSk9wSTHuA

@jahnavidhanireddy5069 6 жыл бұрын

ALL ABOUT ELECTRONICS

@bestfriends7607 5 жыл бұрын

Sir plz send me more examples. Very important sir

@jatinmaheriya2343 3 жыл бұрын

🙂😇

@sangeethatatineni6214 4 жыл бұрын

How could I ever thank you for saving my life with these short and informative videos

@brandonyin5214 5 жыл бұрын

wow!!! while going over this in class and reading the textbook, this topic was clear as mud. I watched this and saw how you explained these circuit analysis and I have a greater clarity on what is going on. Keep up the great work on your videos because they help a lot.

@noweare1 5 жыл бұрын

Excellent work again. I did confirm example 3 using LTspice. The equation is spot on and corresponded with the graph of the current through the resistor at different times.

@thatguymax 4 жыл бұрын

thank you for these clear videos. they have helped me in my circuits class so much!

@srilathasunkara150 5 жыл бұрын

Superb and simple explanation 👌

@ryandrums2112 4 жыл бұрын

Bruh amazing videos, so clear

@mdamanansari7234 3 жыл бұрын

Great job man ... you did an amazing things👌

@madhusmitabehera500 4 жыл бұрын

Sir excellent explanation ....Thank u....

@shashankcholleti8855 2 жыл бұрын

16:22 sir il at 0- and 0+ are equal to 0.75 then y have u writtten at 0 0.375 flows it flows through the parallel resistors isn't sir

@thirumal1086 4 жыл бұрын

Very good explanation..please do more videos on second order series & sinusoidal ,step ,square response as well as the parallel rlc ckts , concept s damping factor ,root locus

@babanpreetsingh9800 2 жыл бұрын

thank you so much sir for making such a usefull vedio

@mayurshah9131 7 жыл бұрын

Superb Presentation!!

@keertilata20 3 жыл бұрын

Thankyou sir, you cleared all my doubts!🙏

@abhijithmadhusoodanannair9830 5 жыл бұрын

NOTHING BUT.........................................................AWESOME

@harshadgupta4384 4 жыл бұрын

in which particular branch we have to find out i(0-) and i(infinite)

@dennis.B 4 жыл бұрын

at 5:40, i didn't quite get how capacitor get shorted in the equation. Can you elaborate it more?

@ganeshmeesala133 Жыл бұрын

Coz current choose low resistive path to flow, it doesn't flow through 20k ohm resistor and since current is zero, we are assuming there is no 20k ohm there

@muddamsravanthi4975 5 жыл бұрын

Thank you so much sir

@venkatalokesh1117 4 жыл бұрын

Sir in extra example 1 At t=0+ why 8ohm resistor is considered?..

@arunchand201 5 жыл бұрын

nice explanation brother

@ajaychopra9509 5 жыл бұрын

which tablet/phone do uu use ?

@MAAslam-bh8ss 3 жыл бұрын

Sir please give some clarity to the doubts asked by others.... It might help others for getting more clarity information...

@mayankprajapati9719 5 жыл бұрын

There was one doubt if value of the is given then how to find e^( )..

@VAISHNADEVIGECEUG- 2 жыл бұрын

SIR NOW ITS WORKINKG SIR THANK YOU SIR

@imSurajsingh24 2 жыл бұрын

well explanation ️👍❤️

@sarangghatkar3937 6 жыл бұрын

Thank you sir

@apalabukun5076 Жыл бұрын

How do i know when i am to find the current at infinity ?

@pavansaigrandhi7284 5 жыл бұрын

For finding equivalent resistance we have to short circuit the independent sources or open circuit them??

@ALLABOUTELECTRONICS 5 жыл бұрын

If the independent source is voltage source then it will be short circuited. If it is independent current source then it will be open circuited.

@amansajwan6411 5 жыл бұрын

Sir we have to find i(t) which is the circuit response or current through inductor so why we are using 0.375 instead 0.75

@Jinkazama123 4 жыл бұрын

We use .75 amp at t=0+ not .375

@rakhatthenut3815 3 жыл бұрын

We are asked to find the current of one of the resistors, not of the inductor. be careful

@trupti8440 2 жыл бұрын

Yes we have to use i0+=0.75 in this formula that is current through inductor.

@varunborugadda 6 жыл бұрын

sir at 12.54 why did you take the 0.75A of current as leaving for the node ..why it can't be incoming?? please answer my question

@ALLABOUTELECTRONICS 6 жыл бұрын

If you apply KCL at that node, then remaining 0.75 A current should leave the node towards two 10 ohm resistors. Similarly, at the datum node or reference node, the summation of currents through resistors and 0.75A should sum up to 1.5 A. And that is only possible when current is leaving through resistors and not entering into them. I hope it will clear your doubt. And still, if you have any questions then do let me know here.

@varunborugadda 6 жыл бұрын

ALL ABOUT ELECTRONICS Thank you sir..I got my doubt clarified..

@mayankprajapati9719 5 жыл бұрын

Hi there was a superb video and it is easy to learn. My humble request is plz make video about intial condition this is chapter of Circuits and network. (BE EC 3rd Sem)

@ALLABOUTELECTRONICS 5 жыл бұрын

I have already made a video about the initial conditions. Please check the following video: kzfaq.info/get/bejne/ab-ZodCT0LuUdHk.html

@hafeezorakzai3589 Жыл бұрын

Sir why you divide current 1.5 by 2

@yuktatayi4801 5 жыл бұрын

In the third example at t =infinity, why is the inductor considered as short circuit and not as a current source along with the short circuit?

@ALLABOUTELECTRONICS 5 жыл бұрын

At t= infinity, the circuit is in steady state. so inductor will act as a short circuit. And the current which was flowing through the inductor will continue to flow through it. So, here there is no need to show it through a separate current source.

@baswarajsghali2074 4 жыл бұрын

Sir can u make videos on programming of 8051

@ankitchaudhary2074 5 жыл бұрын

sir, can we use this formula 【i(t)=i(inifinite) + ( i(0)-i(infinite))*e^(-t/T)】for resistor also???

@lakshjaisinghani7813 5 жыл бұрын

The V/I relationship for resistors is constant, we use Ohms law to determine them. The value of voltage and current also change instantaneously, so there is no need for i(infinite) and i(0).

@iamtomcstllo 5 жыл бұрын

Sir, how about if the current source is being series with RC circuit? what is the proper computation for that? thanks

@ALLABOUTELECTRONICS 5 жыл бұрын

In that case, the current through the circuit will remain the same. Only the voltage across the capacitor will change with time (as capacitor charges)

@berylkeziahmonterona4844 3 жыл бұрын

hello, sir. in example 2, why is the voltage at the resistor negative?

@siddharthareddy3071 2 жыл бұрын

The current and Voltage are in opp. direction

@rishabhtiwari3545 4 жыл бұрын

sir please give the answer of pdf question for confirmation...only answer

@venkatalokesh1117 4 жыл бұрын

Sir I want answers for the extra examples

@shashankcholleti8855 2 жыл бұрын

5:52 sir the capcitor is shortckted due to its property but why is the 20kohm shrtckted sir why cannot the loop b closed so that it forms a new circuit with 2 20kohm resistors

@PavelowB99 7 жыл бұрын

fantastic!

@hongjiaoqiang5090 4 жыл бұрын

super helpful!!!

@sujatasapte5959 3 жыл бұрын

In last example we have not to find current through inductor.We have to find current through 10 ohm resistor.. So why we used the Inductor Current formula I(L)at t.

@ALLABOUTELECTRONICS 3 жыл бұрын

That formula is also vaild for finding the current through the resistor. Because we are taking the current through the resistor at t=0 and t = ∞in that equation. Alternatively, if you are still in doubt, you can find the current through the inductor using the same formula and then applying at the KCL at the common node, you can find the current through 10 ohm resistor. 1.5A = IL(t) +2*Ir(t) You will get the same result. I hope it will clear your doubt.

@sujatasapte5959 3 жыл бұрын

@@ALLABOUTELECTRONICS sir will you make video on that pls

@ALLABOUTELECTRONICS 3 жыл бұрын

@@sujatasapte5959 I have already covered many similar type of examples on the second channel. Please go through it.

@ghostgamingshiv6059 3 жыл бұрын

In Ex 3 why I(0+) is not equal to l(0-) in inductor. I am getting confused. Please help 🙏🙏

@waraysplayground26 3 жыл бұрын

It is equal Sir. It such that the I(0+) being used in the equation is the current at 10 ohm resistor( below the switch ). I think the problem here is that the current equation is not clear as to what part of current in the problem is indicated. Hence, he expect it to be the current of that 10 ohm resistor.

@farhanchowdhury6238 3 жыл бұрын

I don't understand how(in 6:05) the capacitor becomes short circuit(which is fine) but then how did the 20K ohm become short? Can you explain?

@ALLABOUTELECTRONICS 3 жыл бұрын

20 kΩ resistor is in parallel to the capacitor. When the capacitor acts as a short circuit then 20 kΩ resistor will be in parallel to a short circit. So, it will also get short circuited. I hope it will clear your doubt.

@galaxyfarhan 3 жыл бұрын

please help me. my lecture give me quiz but there is no R. how can i find that resistor :(

@sonujss 6 жыл бұрын

you said at t=0+ inductor act as open ckt where it used ????

@blessoneasovarghese9834 4 жыл бұрын

at t=0+ inductor acts as open circuit only if current through it was zero earlier. If there was already some current flowing through inductor, it will maintain a same current initially.

@aarjuparween8724 4 жыл бұрын

In 1st question, we can also find capacitor voltage first at t>0 and then we can find ic(t) across capacitor then why answer is differing. Please explain

@venkatalokesh1117 4 жыл бұрын

We cannot find capacitor voltage at t>0.because.there it is open circuit.

@arvindaswal8607 6 жыл бұрын

superb

@chandrasekar3653 6 жыл бұрын

Sir to find I(t) why are we considering the current through a resistance parellel to the inductor in example 3

@ALLABOUTELECTRONICS 6 жыл бұрын

Because the current I(t) is the current flowing through the 10-ohm resistor. And to find that we need to consider these resistors. I hope it will clear your doubt. If you still have any doubt then do let me know here.

@chandrasekar3653 6 жыл бұрын

Sir in the first problem how can u write the current equation I(t) for the capacitor as it is mentioned already that is used for inductor

@ALLABOUTELECTRONICS 6 жыл бұрын

Are you talking about the first problem solved in the video or the practice problem given in the description?

@aryankumar87771 5 жыл бұрын

Sir in example 2 at t (0+ ) why is the entire current assumed to be going towards the 20 ohm resistor in parallel with the inductor ? Why can't a part of the current go towards the other 20 ohm resistor ?

@ALLABOUTELECTRONICS 5 жыл бұрын

If you observe, at t= 0+, there are two closed loops. Each with 2.5A current source with 20-ohm resistor. So, at t=0+, the current flowing through each 20-ohm resistor will be 2.5A. But in the example, as we have been asked to find the voltage across the bottom 20-ohm resistor, I didn't mention about the second resistor. I hope it will clear your doubt.

@alienmoondudes8071 5 жыл бұрын

What if the risistors aren't the same resistance. Will they be -V/R?

@vaikh8450 5 жыл бұрын

@@ALLABOUTELECTRONICS sir please be more specific . Unable to understand

@SaurabhKumar-gc1ko 3 жыл бұрын

@@ALLABOUTELECTRONICS how is it possible why won the 2.5 A current pass through short circuit instead of going through resistance?

@satyamev_jayatey_ 2 жыл бұрын

@@ALLABOUTELECTRONICS why there is current in bottom 20 ohm resistance if should not, all current is through short circuit... Then voltage across bottom 20 ohm resistance should be 0 sir

@luvchugh616 5 жыл бұрын

In question 3 it is given that switch is opened for a long time then it is closed at t=0 so as switch is open and due to rule ki instant change oppose kerta hai then how current is being flow and and at t=0- how inductor act as short circuit????

@luvchugh616 5 жыл бұрын

Switch to open tha to 0- pe inducors short kaise hoga???

@luvchugh616 5 жыл бұрын

Pls reply

@sangameshmpatil4789 7 жыл бұрын

sir what is the o/p if we connect current source to rc ckt

@ALLABOUTELECTRONICS 7 жыл бұрын

I hope you are talking about the circuit in which current source is connected in parallel with R and C. (i.e parallel RC circuit). Well, in that case, the capacitor voltage equation will remain same, Vc(t)= V([1-e^(-t/RC)] ; where V is the final value or voltage across capacitor in steady state. Please try it by yourself by applying KCL in such circuit.

@zaid7168 6 жыл бұрын

Nothing but ...... its good really

@preethimj1570 Жыл бұрын

How we get 0.75 can u please explain sir

@singiri697 5 жыл бұрын

Sir at 5:50 why is 20k ohms resistor is short?

@raz7543 5 жыл бұрын

Because potential is same in parallel .zeo potential simply represent by wire.

@SaurabhKumar-gc1ko 3 жыл бұрын

in 2nd question voltage across 20 ohm should be Ldi/dt but since at t=0+ di/dt is 0 voltage across 20 ohm should also be zero ? please clarify it If mine explantion is wrong explain it how?

@ALLABOUTELECTRONICS 3 жыл бұрын

You also need to consider the initial condition. At t= 0-, the current is already following through the inductor. You also need to take this into consideration. What you are saying is true, if no current is flowing through the inductor at t = 0 -.

@pks2089 4 жыл бұрын

Draw Req arrow from right to left.

@MohitVerma-zp2ck 5 жыл бұрын

Super ....👌👌👌👌👌👌👌👌

@riyakalita89 5 жыл бұрын

What if the capacitor has some initial charge and the switch is closed at t=0

@ALLABOUTELECTRONICS 5 жыл бұрын

If it has some initial charge, then it will act as a voltage source at t =0 +.

@kolluruyashwanth9381 3 жыл бұрын

In parallel rlc circuit how can we consider case 4: R=0 as R is in denominator of alpha But you explanation is awesome

@ALLABOUTELECTRONICS 3 жыл бұрын

Yes, That's by mistake. It should have been R = ∞.

@maneeshachaganti5789 2 жыл бұрын

Excellent

@bharathin8180 3 жыл бұрын

how to check transients and solve the problem

@sakthivishvanathan9820 3 жыл бұрын

Sir u r telling that two resistance which r parallel are in series with third resistance,then how can u divde voltage equally between 3 resistance (example 3) pls explain me🙏🙏🙏

@ALLABOUTELECTRONICS 3 жыл бұрын

Before time t=0, when the switch is open, in steady-state, the inductor will act as an open circuit. And hence, 1.5A will get divided between two 10 ohm resistors. (i.e 0.75A)(Another 10-ohm resistor is still open at t=0-). At time t=0+, once the switch is closed, then there will be three 10 ohm resistors in the circuit. But as you are aware, the inductor opposes the instantaneous change in the current. That means current through the inductor at t=0+ will also be 0.75 A. Hence, the current, through a resistor which is in series with inductor will also be 0.75A. The remaining, 1.5 - 0.75 A will get divided between the two resistors. Now, at a steady state, once again, the inductor will act as a short circuit (after t=0+). And in that case, as shown at 13:59, three resistors will be in parallel. So, current will get equally get divided between them. I hope it will clear your doubt.

@sakthivishvanathan9820 3 жыл бұрын

@@ALLABOUTELECTRONICS thank you sir 🙏🙏🙏

@RishabhKumar0094 4 ай бұрын

sir in example 1 how you used formulla of inductor current as capacitor current

@ALLABOUTELECTRONICS 4 ай бұрын

It is not inductor current. Its capacitor current only. The formula I (t) = i (∞) + [ i (0) - Ic (∞)] * e^(-t/T) is the general formula for first-order RC or RL circuits. It can be used for both inductors and capacitors. Only the time constant T will change. For RC circuit T = RC. For RL circuit T = L / R. I hope, it will clear your doubt.

@language_loom 4 жыл бұрын

If capacitor is shot circuited then why the parallel register also gets short circuited ??? Please help 🙏🙏🙏 🙏🙏🙏

@ALLABOUTELECTRONICS 4 жыл бұрын

When the capacitor acts as a short circuit then it offers zero resistance. And anything which is in parallel to it will also get short-circuited (Req = R1*R2 / (R1+R2), if R1 or R2 is zero, then the equivalent resistance Req = 0). Because the entire current flows through the capacitor. I hope it will clear your doubt.

@Chandan.Gupta.sirkefan 3 жыл бұрын

Thank u 🙏

@nayeemchadinoo8092 5 жыл бұрын

in the example 3, i0+ is .75A but in the formula we have write i0+ is .375A plz tell me

@ALLABOUTELECTRONICS 5 жыл бұрын

See, the initial current through the inductor is 0.75A. But we have been asked to find the current through the 10-ohm resistor. (The second 10 ohm resistor which is in parallel with another 10 ohm resistor) So, at t=0+, out of 1.5 A, 0.75 A current will flow through the inductor. And remaining 0.75 A current will equally get divided between two 10 ohm resistors. That's why it is 0.375A. I hope it will clear your doubt.

@shankysays 6 жыл бұрын

in qs 3 , why you used i 0+ as .375 ? should it be .75 ?

@ALLABOUTELECTRONICS 6 жыл бұрын

I(0+) current through the resistor will be, 0.375 A, as 0.75 A current will be divided between two 10 ohm resistors. If you are taking about inductor current at t=0+, it is 0.75 A.

@ShawnDypxz 4 жыл бұрын

@@ALLABOUTELECTRONICS So, that's why we should use 0.75 as initial current in inductor

@abdullahinkshary5563 Жыл бұрын

@@ALLABOUTELECTRONICS Shouldnt I use the current in the Inductor (0.75) not the resistor (0.375)? Plus I don't understand how the current in the resistor was 0.375 .. we completely ignored the main current source in this computation

@amaljithodukkathil8247 Жыл бұрын

why I(0+) is taken as the current flowing through the switch but not through the inductor?

@ALLABOUTELECTRONICS Жыл бұрын

Hi, would you please mention the timestamp where you are refering. It would easy for me to answer your question.

@Noname-nw9gt 5 ай бұрын

@@ALLABOUTELECTRONICSat 13:00

@AubaidAhmadWaniGCET-- 5 жыл бұрын

Thanks Sir g

@waraysplayground26 3 жыл бұрын

Hello, with the 1st problem, initial current is 0.5mA, why you just use 0.5 in the i(t) equation you forgot *10^-3.

@jeffreyaigbovbiosa7880 2 жыл бұрын

Noticed the same too it could be an oversight

@prakashkannan2900 2 жыл бұрын

@@jeffreyaigbovbiosa7880Yeah me too noticed the same.

@prakashkannan2900 2 жыл бұрын

yeah, I too found the same thing, it is 0.5 milliampere, so have to multiply the same with the output!

@jayarangarakesh4581 3 жыл бұрын

for i(0) ,should we take i(0+) or i(0-) ?

@ALLABOUTELECTRONICS 3 жыл бұрын

I (0+)

@rabecamohammed9518 2 жыл бұрын

@5:47 why does the 20kohm get shortcircuited along with the capacitor?

@ALLABOUTELECTRONICS 2 жыл бұрын

At t=0+, the capacitor will act as a short circuit. Since, the 20k resistor is in parallel with capacitor, so it will also get short circuited. I hope, it will clear your doubt.

@rabecamohammed9518 2 жыл бұрын

@@ALLABOUTELECTRONICS Thank you for the explanation! But is it a general rule? As in if something is shorted in a branch, everything in the branch opposite to the first branch will also be shorted?

@ALLABOUTELECTRONICS 2 жыл бұрын

Yes, in parallel, if any branch is short circuited, then every branch in parallel to it will also get short circuited.

@rabecamohammed9518 2 жыл бұрын

@@ALLABOUTELECTRONICS Thank you so much!

@pratiklodha5108 5 жыл бұрын

At 11:54 from where has that 2 in denominator come from

@ALLABOUTELECTRONICS 5 жыл бұрын

At t=0-, before the switch is getting closed, the 1.5A current is getting divided between the two 10 ohm resistors. (Considering inductor as short circuit). That's why current through inductor at t=0- would be 1.5/2 = 0.75 A. I hope it will clear your doubt.

@pratiklodha5108 5 жыл бұрын

@@ALLABOUTELECTRONICS thank you for clearing my doubt

@maheshkalluri502 5 жыл бұрын

Bro..but as two 10ohm resistors are in parallel Req=5ohms

@briankibet9387 4 жыл бұрын

sir please do video of two port network

@kamalkishoremahato2673 3 жыл бұрын

Sir please can u explain me why u put Ic(infinity)=0??? At time*8:22*

@ALLABOUTELECTRONICS 3 жыл бұрын

If you look at the circuit at t= infinity at 7:18, then at t= infinity, the capacitor will act as open circuit and hence no current if flowing through capacitor. Therefore, Ic (infinity) = 0. I hope, it will clear your doubt.

@kamalkishoremahato2673 3 жыл бұрын

@@ALLABOUTELECTRONICS clear sir , thank u

@mohammadsyahmibinshebli8239 3 жыл бұрын

on minute 11:50 how he can get 1.5/2..can you explain about how u can get 2?

@ALLABOUTELECTRONICS 3 жыл бұрын

At t= 0-, the switch is still open. The inductor will act as a short circuit and therefore, only two 10 ohm resistors are there in the circuit. So, current will get equally get divided between two resistors at t= 0-. I hope it will clear your doubt.

@pranakag681 5 жыл бұрын

nice video sir very helpfull

@003_maliksheeza3 6 жыл бұрын

SIR in qno 3 ,the question was like the circuit has been open for a long time and that at t=0 the switch is closed. that means at t=(0-) inductor should have been an open circuit becoz the current flowing is zero n in t=0+ also inductor should act as open circuit.why u have shown it as closed circuit as the circuit has closed just then ?

@ALLABOUTELECTRONICS 6 жыл бұрын

The property of inductor is that it opposes the instantaneous change of current. It means that if any current is flowing through inductor at t=0-, then same current will flow at t=0+ too. Here in example 3, at t=0-, the current through the inductor is 0.75A. So, the same current will continue to flow through inductor at t=0+ as well. I hope it will clear your dobut.

@003_maliksheeza3 6 жыл бұрын

thnks alot..

@CorporateCat 6 жыл бұрын

In example 3, if current through inductor at t =0+ is 0.75A as you said then why have you taken i(0) as 0.375A at 16:18 in the final formula?

@ALLABOUTELECTRONICS 6 жыл бұрын

Here I(o) is the current through 10-ohm resistor which is in parallel. I think you misunderstood the resistor which is in series with an inductor. Please check it once again. And still, if you have any confusion then do let me know here.

@bhaskaralakshmiganisetti3779 5 жыл бұрын

@@ALLABOUTELECTRONICS sir at 11.53 but in the question u don't mention its charged for some time how to take it as a short ckt ( can I take it as charging from initial(0A))

@shashankcholleti8855 2 жыл бұрын

sir for practicing more problems not only for this topic for imp.topics post some WORKSHEETS in the description with solns it will b more hlp ful for students like me

@ALLABOUTELECTRONICS 2 жыл бұрын

There is a seperate channel for the questions. Please check ALL ABOUT ELECTRONICS- QUIZ. You will find the different playlist. ( You may check Network Analysis playlist)

@rishabhsharma7701 2 жыл бұрын

@@ALLABOUTELECTRONICS thank you sir ...🤩

@alokajayawardhana9472 4 жыл бұрын

thank u sir

@zebrhehagos6233 5 жыл бұрын

It is a great explanation but , in the third example how can the inductor acts as a short circuit at t=0?

@zebrhehagos6233 5 жыл бұрын

I mean at t=0_,,how it acts as short ckt? wasn't it open long before t=0?

@ALLABOUTELECTRONICS 5 жыл бұрын

If you observe, the switch is connected to the resistor (and not to inductor). So before t=0, in steady state condition, it will act as a short circuit. (i,e at t=0-). And when the switch is closed, it will act as a current source. I hope it will clear your doubt. If you still have any doubt then do let me know here.

@zebrhehagos6233 5 жыл бұрын

Exactly, I have gotten it.

@hanupawandwivedi6613 4 жыл бұрын

20 kohm is short circuited? Can anyone tell?

@ALLABOUTELECTRONICS 4 жыл бұрын

In the first example, the voltage across the capacitor is zero at time t= 0-. And capacitor opposes the instantaneous change in the voltage. That means Vc(0+) = 0V. Hence, at t= 0+, the capacitor can be replaced by the short circuit. And as 20k ohm is in parallel with the capacitor, it will also get short-circuited at time t= 0+. I hope it will clear your doubt.

@user-jk6qi9tj8s 3 ай бұрын

Hlo bro given circuit is with source or without source how can we gues????

@ALLABOUTELECTRONICS 3 ай бұрын

If the circuit has any voltage or current source then it means that, some source is connected with the circuit.

@sarangghatkar3937 6 жыл бұрын

Sir can you please provide the solved examples with all minor details in the form of pdf that you have solved for practice & please refer textbook for us.... Our exams are round the corner please help sir

@ALLABOUTELECTRONICS 6 жыл бұрын

Yes, I will upload the pdf of solved examples in 2-3 days. And you can refer books like Network analysis by Van Valkenburg (But initially it will be slightly difficult to understand) Or you can refer Network analysis and synthesis by S.P Ghosh and A K Chakraborty

@ALLABOUTELECTRONICS 6 жыл бұрын

The solution of the examples given for the practice has been uploaded in the PDF format. drive.google.com/open?id=0B3FOmN0FcD6OWFc2OXAtcUtmcXc

@sarangghatkar3937 6 жыл бұрын

Thank you sir

@bhaskaralakshmiganisetti3779 5 жыл бұрын

At 11.53 why inductor shortckt At t= 0- the switch is opened that means no current flow in that case inductor is oc Plz clarify my doubt

@ALLABOUTELECTRONICS 5 жыл бұрын

Although the switch is open at t=0-, the current will still flow through inductor via a 10-ohm resistor. If you closely look the circuit, the 1.5A current will through 10-ohm resistor and, 10hm resistor and inductor pair. I hope it will clear your doubt.

@bhaskaralakshmiganisetti3779 5 жыл бұрын

@@ALLABOUTELECTRONICS tq sir

@Hh-ze4vm 4 жыл бұрын

minus 2.5 kese explain toh kro pura

@venkatalokesh1117 4 жыл бұрын

sir.in example 3. At i=0- I(l)=1.5/2..from where did we get 2. Can you say?

@ALLABOUTELECTRONICS 4 жыл бұрын

1.5 A current is getting divided between the two 10 ohm resistors. That means half of 1.5 A (0.75A) will flow through one 10 ohm resistor and the remaining 0.75 A will flow through second 10 ohm resistor. That's why its 1.5/2. I hope it will clear your doubt.

@venkatalokesh1117 4 жыл бұрын

@@ALLABOUTELECTRONICS ss very clear

@g.nagarajug.nagaraju8656 3 жыл бұрын

@@ALLABOUTELECTRONICS at t=0- as inductor is short circuited then three 10 ohm resistors will be there.then current is 1.5/3.but why 1.5/2 I did not understood please explain

@yasso3319 6 жыл бұрын

how did you go from 40 to 25?? someone explain please

@ALLABOUTELECTRONICS 6 жыл бұрын

If you observe 40 is actually 40 ms, that is 0.04 seconds. So, 1/0.04 = 25 I hope it will clear your doubt.

@yasso3319 6 жыл бұрын

ALL ABOUT ELECTRONICS yes thank you

@SomnathMalik__EC 4 жыл бұрын

Waha t>=0+ bola tha t>=0 nhi. Donome difference nhi hota kya?

@amierulhaqimi3428 4 жыл бұрын

Mantap sir 👍👍👍

@fazilahmadpala5472 5 жыл бұрын

Sir why you short circuit the resistor at 5:50

@fazilahmadpala5472 5 жыл бұрын

Also at 9:53 when u short circuit the inductor u also short the resistor which is in parallel with this inductor.can u explain sir

@ALLABOUTELECTRONICS 5 жыл бұрын

At time t= 0+, the capacitor will act as a short circuit. And the resistor is in parallel with this capacitor. Ao, it will also act as a short circuit.

@siddharthareddy3071 2 жыл бұрын

Eg. 2 At t=0, shouldn't the Inductor become Open Circuit?

@ALLABOUTELECTRONICS 2 жыл бұрын

I am referring to the steady state condition before the switch was opened. In steady state condition, it will act as a short circuit. I hope, it will clear your doubt.

@siddharthareddy3071 2 жыл бұрын

@@ALLABOUTELECTRONICS Yes, it did. Thank you.

@rutendogwese5201 4 жыл бұрын

12:07 where is the 2 coming from

@SovereignSonu 4 жыл бұрын

Because of symmetry ( same 10 ohm resistor)

@user-cy8sd1ln7q 7 ай бұрын

6:48 WHY CAPACITOR ACT AS OPEN CIRCUIT???

@tirthrajgandhakwala9972 6 жыл бұрын

only one doubt. we have to find Req for Time constant at which time. in first example it was found at time t=0 and in third it was found at time t=0+ , can anyone plz help ?

@ALLABOUTELECTRONICS 6 жыл бұрын

We always find the time constant of the circuit for time t>0. You can try this for any example on transients. I hope it will clear your doubt.

@tirthrajgandhakwala9972 6 жыл бұрын

so why was it found for t=0 in example 1 ? this one doubt is scrambling my mind otherwise got all my concepts clear about transient. can you help me clear this one ?

@ALLABOUTELECTRONICS 6 жыл бұрын

In example 1 also, RC time constant is in fact at time t>0 only. In example 1 circuit is same (Circuit components are same) at time t=0- and t=0+. In some cases, particularly when you have the switch in the circuit which connects some part of the circuit with another part at time t=0, there you will see the difference in time constant at time t=0- and time t=0+. I hope, now it will clear your doubt. If you still have any confusion, then do let me know here.

@tirthrajgandhakwala9972 6 жыл бұрын

I am sorry but I still don't get it. the resistance is short circuited at t=0+ and so is the capacitor. how the circuit is same at t=0- and 0+

@ALLABOUTELECTRONICS 6 жыл бұрын

See, the capacitor will act as a short circuit at time t=0+, or Vc(0+)=0, that is initial condition of the circuit. But it doesn't mean capacitor is not present in the circuit at time t=0+ and so as the resistor. So, physically both are present in the circuit and so they are in finding the time constant of the circuit. While, if you see in some examples where the switch is connecting any element or some part of the circuit to the another circuit. In that case at t=0+ and t=0-, the circuit will be different physically. (might have additional components depending upon the switch position). In such case time constant of the circuit will be different at time t=0+ and t=0-. So, in that sense in example 1, the circuit will be same at time t=0+ and t=0-. I hope it will clear your confusion.

@robertlake2753 6 жыл бұрын

Got a circuit you wanna build? Test it out here first. Arrive at: 'Circuit Solver' by Phasor Systems on Google Play.

@subhabhaskaran1827 4 жыл бұрын

At 10.47 why it is minus 2.5A ???

@ALLABOUTELECTRONICS 4 жыл бұрын

Because the Vx is measured from the right to the left. I mean positive terminal is on the right side, while the negative terminal is on the left side. While the current is flowing in the anti-clockwise direction (from left to the right in resistor). that's why there is a minus sign. I hope it will clear your doubt.

@subhabhaskaran1827 4 жыл бұрын

ALL ABOUT ELECTRONICS Thank u