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An Interesting Cubic Equation | Algebra Insights
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Күн бұрынAn Interesting Cubic Equation | Algebra Insights
Let's dive into the fascinating world of algebra as we explore an interesting cubic equation. In this video, we'll break down the problem step-by-step, uncover the secrets behind cubic equations, and provide you with valuable insights to enhance your algebra skills. Whether you're a student, educator, or math enthusiast, this tutorial is perfect for deepening your understanding of algebraic concepts. Join us and master this intriguing algebra problem!
👉 Topics Covered:
Introduction to cubic equations
Utility of algebraic identities and formulas from sequence and series
Step-by-step solving process with factorization
Tips and tricks for quick solutions
Additional Resources:
• Cracking the Cubic Equ...
• Two Unique Ways to Sol...
• Outsmarting Cubic Equa...
• Cracking A Very Intere...
Timestamps:
0:00 Introduction
0:24 Algebraic identities
4:10 Formula for sum of n natural numbers
6:10 Solving Cubic equation
8:10 Quadratic equation
8:50 Discriminant
9:38 Solution
9:50 Verification
🚀 Ready to boost your math knowledge? Watch now and conquer cubic equation effortlessly! 📐💡
#cubicequation #mathchallenge #problemsolving #mathematics #educational #algebra #matholympiad
✨ Let us know in the comments if you found this helpful or if there's a specific topic you'd like us to cover in the next video! 👍
Thanks for Watching!!
@mohammedsaysrashid3587 Ай бұрын
It was a wonderful introduction....thanks Sir 🙏 for sharing x= (u-9)/2=>0 ...x=0
@user-kp2rd5qv8g Ай бұрын
Setting x+9/2 =0, we get 4t^3+63t - 648=0, which has t=9/2 as the only real solution. Thus, x=0.
@nasrullahhusnan2289 Ай бұрын
Note that 1³+2³+...+n²=[½n(n+1)]² So 1³+2³+...+8³=(½×8×9)² =36² =6⁴ Thus x=0
@mikelivstone Ай бұрын
This can be solved directly using the formula you finished writing at 4:37. Just subtract the sum of the first x cubes from the sum of the first x+8 cubes.
@user-ee7nw2rx9s Сағат бұрын
Если сделать замену, х+4,5=а, (среднее арифметическое оснований степени) то при раскрытии кубов две пары слагаемых сократятся Выражение вида (x+y)^3+(x-y)^3 получается в итоге
@kassuskassus6263 Ай бұрын
One real solution x=0. Let x+5=t and we have to solve for t after simplifications, 2t^3-3t^2+33t-340=0. We'll get one real solution which is t=5, so x=0.
@manasishastry345 Ай бұрын
let x+4=a then solve .it is very simple calculation.
@tejpalsingh366 Ай бұрын
X= 0
@RealQinnMalloryu4 Ай бұрын
{3x^3+8x3}= 11x^6{ 9x^3+15x^3}=24x^6.{11x^6+24x^6}={35x^12 +24x^3 }= 59x^15 3^17x^15 3^17^1x^3^5 1^1^1x^3^5^1 x^3^1^1 x^3^1 (x ➖ 3x+1)
@RealQinnMalloryu4 Ай бұрын
6^4 3^22^2 3^1^1^1 3^1 (x ➖ 3x+1)
@SidneiMV Ай бұрын
x + 4 = u/2 - 1/2 => x = (u - 9)/2 (u - 7)³ + (u - 5)³ + (u - 3)³ + (u - 1)³ + (u + 1)³ + (u + 3)³ + (u + 5)³ + (u + 7)³ = 2⁷3⁴ 2(u³ + (3)7²u) + 2(u³ + (3)5²u) + 2(u³ + (3)3²u) + 2(u³ + (3)1²u) = 2⁷3⁴ 8u³ + (6)(1² + 3² + 5² + 7²)u - 2⁷3⁴ = 0 8u³ + (6)84u - 2⁷3⁴ = 0 u³ + 63u - 1296 = 0 u = 9 (by inspection) x = (u - 9)/2 => *x = 0*
@user-ny6jf9is3t Ай бұрын
χ=0 στο R
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