Anti-Markovnikov Radical Halogenation of Alkenes

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Anti-Markovnikov Radical Halogenation of Alkenes

Рет қаралды 16,577

Leah4sci

Күн бұрын

Пікірлер: 41

@user-pm1hd5sy1e 2 жыл бұрын

Thank you for your videos,which are truly helpful to me .I’m a Chinese teenager,I am watching yours to solve my problems .I hope that you have been sharing your knowledge to make the world richer .If I have the grammar mistakes,please tell me.Thanks, coach.Your channel was， is and will be the best

@Leah4sci 2 жыл бұрын

You're very welcome, I am so happy to hear that my resources have helped you!

@carloseduardoaccorsi7822 2 жыл бұрын

Your serie of videos of the alkenes are the best I could ever ask for, thank you for teaching me so much, Leah! Kisses from Brazil :)

@Leah4sci Жыл бұрын

You're very welcome, happy to help!

@toanjuan 2 жыл бұрын

I like how the pace is slower leaving more time for understanding

@Leah4sci 2 жыл бұрын

Glad you like it!

@_kimseokjin 5 ай бұрын

I was struggling with free radical mechanism and this video really helped me. Thank you ma'am !

@Leah4sci 5 ай бұрын

You're so very welcome, happy to help!

@kiranus8286 2 жыл бұрын

Majority of other never explain stereo configuration of product..brought down very simple and easy way,thankyou

@Leah4sci 2 жыл бұрын

Thank you for recognizing that. I used to be so overwhelmed because I was taught to memorize, and so I try to take that frustration away by showing you WHY. :)

@tharindunawoda Жыл бұрын

you and organic chemistry tutor are lifesavers

@Leah4sci Жыл бұрын

Thanks so much! :)

@diandramcgee3279 9 ай бұрын

This was sooooooo helpful, omg! 😢😊😊😊

@Leah4sci 9 ай бұрын

So glad it helped!

@kerminamaged2002 Жыл бұрын

I'm wondering why did the reaction initiates with bromine not hydrogen?? Thank you is not enough...your videos really helped me

@Leah4sci Жыл бұрын

You're so welcome! The oxide radical grabs the hydrogen from HBr to create a very stable alcohol molecule. (The alternative would be to bond the oxygen to the bromine, and that is not energetically favorable.) That leaves a bromine radical to initiate the radical halogenation. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/

@AvaDuffy-uf8gu Жыл бұрын

your videos are amazing!!! thank you!

@Leah4sci Жыл бұрын

you're so welcome

@jemimachester-morris1707 Жыл бұрын

Great teacher!

@Leah4sci Жыл бұрын

Thank you so much

@pexaminer 2 жыл бұрын

Another great video!

@Leah4sci 2 жыл бұрын

Thank you!

@G0102670 2 жыл бұрын

Your voice is the best

@Leah4sci 2 жыл бұрын

Thanks!

@SkynetT800 2 жыл бұрын

Thank you for the lesson

@Leah4sci 2 жыл бұрын

You are very welcome

@sh-ky6be Жыл бұрын

Thank u is not enough for u 💖💖💖💖💖💖💖💖💖💖💖💖💖

@Leah4sci Жыл бұрын

I'm glad you like the videos! Thanks for watching.

@LangChantreaChemistry 2 жыл бұрын

Thanks 🙏 so much for sharing good lecture for me❤️🙏

@Leah4sci 2 жыл бұрын

You're very welcome

@pratibhakabra688 2 жыл бұрын

You should try solving organic chemistry of JEE Mains/Advanced it will surely boggle your mind.

@Leah4sci 2 жыл бұрын

I've heard it's tough, but many JEE students use my resources to help them as they prepare. Hope this helps you, too!

@cato3414 4 ай бұрын

So H should go on the most stable (substituted) carbon?

@Leah4sci 4 ай бұрын

Yes, you can think of it that way. The radical intermediate will form on the most substituted carbon of the pi bond after reaching for a bromine radical in solution. That leaves the more substituted position available for the H of the HBr reagent.