Yess bro, digit ooda function yennanu theriyala

Same doubt bro digit ++yedhuku, increment process but yepudi..

sure 👍🏻👍🏻

​@@codeio cut panatha again details ah solunga bro

It is used for finding the no of digits in given number bro. Intial la digit oda value va 0 nu assign panikitu then while la oru oru last digit ah remove panrapo digit ah increase by 1 panna u will get the no of digits in the given number.

Bro apdi ila ipo 370/10 vanthu 37 varum apo digit=1 agum 2timee panum pothu 3 varum apo digit =2 agum 3 time panum pothu 0 varum digit =3 agum loop close airum

Yeah bro

n oda value change aairum bro. Apdi change aaita. If(sum==n) condition ah check pannum pothu false nu varum.

122%10=2+ 122/10=12 12%10=2+ 12/10=1 1%10=1+ 1/10=0 + podurukathu elam sum la pogum bro sum of digits program mari 1^3+2^3+2^3 pakanum yena 122 um 3 digits iruku

this helps to find the no.of digits

In the for loop, since we are changing the value of copy after each iteration, if we didn't create a copy, then we wouldn't have the value of the original input to use in the next loop

Bro check whether have you missed statement terminator anywhere else...

Int num1 = 3; Int num2 = 3; for(int i = 1; i < num1; i ++) { num1 = num1 * num2; }

@@kirubakaran1547 Thanks bro💗

copy=num; for(digit=0; copy>0; digit++) { copy=copy/10;

Intha loop namma input value oda digit count find panna use panrom. Eg: input = 2753. Digit = 4 nu count pannum.

Digit theringa tha power ku value kuduka mudiyum. Hope you understand.

Ama bro

Happy to hear that 🤩🤩🤩

na unga videos pathu tha bro learn pantra super ah solitharinga... 5:15 skip anatha again upload pani videos potunga bro

if sum contain any number or garbage value we cant calculate the sum of the digit .

Declarations of sum=0 the code will work

// Using for loop // #include #include #include int main(void) { // Variable declaration // int num, i, int sum=0; int digit=0; // Receive input // printf("Enter a number to find whether it is an Armstrong: "); scanf("%d",&num); // Calculate no of digit // for(i=num;i>0;1/-10){ digit++; } // Sum of individual bits // for(i=num;i>0;1/-10){ sum=sum+pow((i%10), digit), } // Display output // printf("The given number is %d digit. ", digit), if(sum==num){ printf("%d is an Armstrong number.", num); } else{ printf("%d is not an Armstrong number.",num); } return EXIT_SUCCESS; }

while loop finish aana peragu n ooda value 0 aagidum so, namma n=copy endru loop start aaguvathairruku munnadi declear pannurom ok

Purijathu thanks bro

ok

do you know how many programming languages? i know only 1 that is c program nan intha channel la pathu than katukuthan you?

I also bro