Thank you very much for your wonderful video! it is so brilliant! Since not all methods are exact, I was curious to find out whether the angle QBC is indeed 72 degrees. So, I tried to proof it as follows: First, use the right-angle triangle MBP to compute the length MP. For clarity, denote the base AB = b. This yields MP=0.5*b*sqrt(5). We now compute the length AC which equals AQ. Since AQ = MP + 0.5*b, it follows that AC = 0.5*b*(sqrt(5) + 1)). The triangle ABC has a base length of AC and two equal sides of length b. Using the cosine rule: AC^2 = 2*b^2 - 2*b^2*cos(gamma), where gamma is the angle ABC. This yield cos(gamma) = 0.25*(1 - sqrt(5)).= -0.3090. gamma = acos(0.3090) = 108 degrees. The angle QBC is then 180 - 108 = 72 degrees. It remains to be proved that point D is indeed the top of the pentagon. This is proved by the fact that the triangles ABC and BCD are congruent and thus BC = CD. Arthur, in contrast to other methods, your method is exact! Thank you again for your crystal-clear video which inspired me to do this exercise with tools we learned 50 years ago. Let me know if I missed out on something.

I got scared looking the intro , i though it was the actual construction😂

This is BETTER than watching a Hollywood blockbuster movie.!!

Great.....to see how KZfaq can be utilized to do useful stuff....

I have to draw all the polygons from 3 sides to 8 sides for my project. Your videos really helped me. I couldn't have asked for a better tutorial. Thank You sir.

awesome video helped me so much god bless ya bro

🙏💕 thank you you help all students👦📖🎒👦📖🎒👦📖🎒

Thank you sir apne mere submission me help ki 🤗

you are the best one

I needed to make a pentagon with 5” sides for my 3D art class and this was extremely helpful; turned out perfect. Thanks!

Thank you so much

So interesting, I can see how this works now. From the line AB you have determined the point Q. The line AQ is the golden ratio (Phi) of AB. The opposing corners of a pentagon e.g. line AD is the result of multiplying the side length of the pentagon by Phi (1.618....)

Wowwwwww. It actually works. It's like magic.😮. May God bless you😇 and Thank you sir.😋

OMG! this type of videos are amazing for do arts homeworks.

I am building a 5 sided cupola to go on a pentagon shaped gazebo. It is an inverted radius conical cupola. I needed this one formula to lay it out. Thank you.

Oh wow, it turned out great. Thank you so much !!

Thank you!

Thank you Aurther Geomitry!!!You helped me with my module in my math!it was so hard until I saw this!!😄😄😄

Love from Nepal

Thanks for your tutorial.

LEGEND!!!

Thank you very much ❤

This was a tough one kept getting confused over the changing radius and where to put the compass point, had to rewatch a fair few times

Thank you it helped ma a lot

Omg so simple and easy. I got it on the first try. Thanks.🤗🤗

Thanks!

Im doing technical drawings and I missed this class so thank you

Thank you so much sir....26/10/2021....Really help me with my school work

Sir thank you very much

A god amongst men,thank you

enjoy this pentagon is very beautiful, thanks very much. cute pentagon!

Thank u so much have a test tomorrow and this helped me loads fam thanks

This help me a lot in my submissions

Finally found one that works, much appreciated thank you so much!

Rlly appreciate it

thanks you, it's so helpful

THANK YOU SO MUCH u explained it so well

Awesome! Thank you for taking the time to create this video and post it. This is the perfect information I was looking for that will allow me to construct my device.

I've been saved Thank youuuuu

Ah seriously, thank you so much. I've already watched two of your videos and it's been going great! Taking Tech Draft class was probably a bad one on my side but I can't help but try to widen my knowledge at some point.

Nice man

Was stuck on an assignment and this helped me out. Gracious 😇

Let me guess you're here because you have an EGD exam coming soon I know...I know same reason

Thanks man, your better than my teacher

Thank you this will help me on my drawing s

That's Awesome, I always wanted to draw a pentagon without using a protractor.

Ommmggg ur a live saver !!

thanks! worked for me

4 years later and you're helping me pass my last year of school

very useful, good job

Helped a lot thanks

Thankz alot....u really explain very well and it's very easy to understand

Oh you GODSEND

Pentagon process is lit

thank you very much for your easy tutorial!

Thank you so much!😊✍

Thank you

Very helpful

Very good and easy steps

thanks you

thank you, keep up the good work in teaching and helping students.

Great work! Thank you.

thanks for this video

Thank you so much sir... 👍🏻

Wonderful... this is so helpful, i have been struggle to draw a pentagon now i got it exactly. Thanks more your video helped me out.....

thankyou

Thank youuu❤❤

I have a hmwrk assessment to do and this helped a lot

Thanks a lot, Sir! Really helpful and easy to learn.

Sir, Thank you so much. Because I was badly in need of a Pentagon. This video is easier than others.

Very helpful thank you

Intro🔥🔥🔥🔥🔥

waoooo... thank uuuu sooooo much buddy... great help.... great help....

Super it helped me a lot

really helpful

Thank you so much ✨

understandable video, nice

Thanks it was awesome

Clear information

Sir...this video is good

Thank you very much sir

Sick bro

This was very helpful. thank you :)

Please give us a video on "Drawing Pentagon Using Perpendicular bisector method"

Thanks for video

Thank you sooo much

Thanks a lot for this my Pentagon turned out perfect!

Thank you so much man i love you Fun fact: i am from italy and i understood YOUR explanation and not my teacher one LOL

thnx......i actually know a method tht can draw a pentagon too easier though...but i cannot remember.....it all starts w/ cross and circle.....but urs are a bit complex but still easy to understand....

Thankyou

A very interesting construction. Thank you for it. Have you a geometrical proof that ED and DC are equal in length to AB?

tqsm

Thank u so much

Very helpfull

FINALLY

this is gonna take a bit to make a dodecahedron for my purposes, but thanks alot!

first class instruction,thank you.

Thanks

Nice sir 👌

Thanks sir