ASTOUNDING: 1 + 2 + 3 + 4 + 5 + ... = -1/12

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Numberphile

Numberphile

Күн бұрын

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EXTRA ARTICLE BY TONY: bit.ly/TonyResponse
The sum of all natural numbers (from 1 to infinity) produces an "astounding" result.
ANOTHER PROOF & EXTRA FOOTAGE: • Sum of Natural Numbers...
MORE: • Why -1/12 is a gold nu...
NY Times article on this: nyti.ms/1iftqSv
Tony Padilla and Ed Copeland are physicists at the University of Nottingham.
They talk physics at our sixty symbols channel: / sixtysymbols
Grandi's Series: 1-1+1-1.... • One minus one plus one...
Read more about divergent series: en.wikipedia.org/wiki/Divergen...
We also hear that Chapter XIII of Konrad Knopp's book, "Theory and Application of Infinite Sequences and Series", is very good if you can get your hands on it.
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Пікірлер: 18 000
@jojogothic
@jojogothic 8 жыл бұрын
so guys lesson today is if someone offers to give you 1 dollar today 2 dollars tomorrow ect ect dont take the deal since he is obviously trying to steal you
@clockworkkirlia7475
@clockworkkirlia7475 8 жыл бұрын
Luckily our finite lifespans tell us that his plan is doomed to failure and you will die a rich person.
@TrackpadProductions
@TrackpadProductions 8 жыл бұрын
The logic immediately falls apart upon comparing infinity to a quantitative idea. Infinity is not a number - trying to disprove this by treating it like one is immediately self-invalidating.
@jojogothic
@jojogothic 8 жыл бұрын
TrackpadProductions this video just proves that math is broken at some points not that the sum of all natural numbers is negative
@TrackpadProductions
@TrackpadProductions 8 жыл бұрын
Anonb8 Math isn't broken at all. All this video proves is that infinity does not function like a number, and when you try to treat it like a number, weird stuff happens. As it should.
@lukejames4981
@lukejames4981 8 жыл бұрын
That's an interesting interpretation of the Incompleteness Theorem.... Godel said that *if* a mathematical system is complete, *then* it is inconsistent. To interpret this as saying that our incomplete mathematical system is inconsistent seems just... wrong.
@gorillaman283
@gorillaman283 5 жыл бұрын
Top 10 pranks that went too far.
@kishanramani6873
@kishanramani6873 5 жыл бұрын
Brother this formula is find out by greatest mathematicians S.N ramanujan this formula also use in string theory. I understand u can't respect to him this habits is in your blood but don't comments with out any information
@piotrstanczak8319
@piotrstanczak8319 5 жыл бұрын
@@kishanramani6873 This is not true ramanujan provided note that it could be interested when you try to do this on divergent string. Which by the way normally is wrong math.
@harishkumaar9085
@harishkumaar9085 5 жыл бұрын
@@kishanramani6873 Don't embarrass Ramanujan by your stupidity !! If you had any formal education, you would know alternate series properties are completely misrepresented here. Don't go about spreading fake math around without knowing wtf you are talking about.
@piyushjain9913
@piyushjain9913 5 жыл бұрын
@@harishkumaar9085 these western people are just assholes don't waste energy to argue with them they copy our Indian culture and nothing much
@harishkumaar9085
@harishkumaar9085 5 жыл бұрын
@@piyushjain9913 What are you even talking about? I am saying that the procedure adopted here in this video is completely wrong. Don't be an idiot and claim it was derived by Ramunajan and insult his intellect. In fact the person who is claiming this, is an Indian.
@perseusgeorgiadis7821
@perseusgeorgiadis7821 Жыл бұрын
My IQ increased by -1/12 after watching this
@YT7mc
@YT7mc 8 ай бұрын
Infinite intelligence!!!!
@bartekordek
@bartekordek 7 ай бұрын
​@@YT7mcquite the opposite. This is why most people here belive on this video despite ot having numerous errors.
@N269
@N269 5 ай бұрын
@@bartekordektend to agree here.... I reckon this is a series that politicians are forced to believe in before takeing office.
@asuuki2048
@asuuki2048 2 ай бұрын
@@bartekordekWhat errors?
@ChrisJohnson-ww4vs
@ChrisJohnson-ww4vs 17 күн бұрын
⁠@@N269Could either of you point out a single error? Considering there are numerous, a single one shouldn’t be too hard.
@shreyansh2244
@shreyansh2244 Жыл бұрын
If you're from 11th-12th science, and you got some amazing Professor who sometimes taught you this type of curious and out of the syllabus problem , just to keep you hooked to the wonder of science and Mathematics, you're lucky.
@canyoupoop
@canyoupoop 7 ай бұрын
Yeah teaching false assumptions and statements without specifying in what branch we are actually talking about.... I don't think so
@ifeanachosonia5787
@ifeanachosonia5787 4 ай бұрын
​@@canyoupoop😅
@AnasArfeen
@AnasArfeen 2 ай бұрын
​No, but ​@@canyoupoop
@Grgrqr
@Grgrqr Ай бұрын
Yeah my math teacher taught me that when a sequence approaches infinity as its limit, the series will be divergent
@UnknownRager96
@UnknownRager96 5 жыл бұрын
Me before watching this video: liar Me after watching this video: cheater
@xkilla911
@xkilla911 5 жыл бұрын
S2 =/= 1/4 because S1 =/= 1/2 because you can't add itself at a different order in a sequence and expect a correct result after adding a specific number of times.
@LapisCyborg
@LapisCyborg 4 жыл бұрын
why not?
@cpotisch
@cpotisch 4 жыл бұрын
Jax Infinite series are often defined by their order. When there is no set end of the sequence, you can’t just reorder things.
@GurmeetSingh-qv7dp
@GurmeetSingh-qv7dp 4 жыл бұрын
This can explained by reimann hypothesis. If you don't understand it doesn't make it wrong. Explanation may be wrong but result is true.
@zankhanabose6625
@zankhanabose6625 4 жыл бұрын
Its ramanujan infinity sum
@bilbo_gamers6417
@bilbo_gamers6417 5 жыл бұрын
A simple stack overflow bug. God will patch it in the next update.
@lavishkumar5062
@lavishkumar5062 4 жыл бұрын
Wow! You're the forefather of Albert Einstein.
@LilMissMurder3409
@LilMissMurder3409 4 жыл бұрын
Quality.
@waitweightwhite793
@waitweightwhite793 4 жыл бұрын
Still no updates, support is clearly messing
@Gruntled2001
@Gruntled2001 4 жыл бұрын
@@waitweightwhite793 Just hope they don't wipe the drive and do a fresh OS install...
@kangkanlahkar9045
@kangkanlahkar9045 4 жыл бұрын
But you won't get negative of irrational numbers. SO error in java would be some integers
@rupertolababwe5973
@rupertolababwe5973 8 ай бұрын
The analytic continuation of the Riemann Zeta function does indeed map -1 to -1/12, however this does not mean that the sum of all positive integers is -1/12. The whole point of analytic continuation is to extend the function to the domain where the original function is divergent, and after doing that u CANNOT say that the original function maps the analytically continued domain to all these extended points
@draganradosavljevic8982
@draganradosavljevic8982 7 күн бұрын
Thank you! Guys are easily deceived by their ignorance.
@backugai007
@backugai007 2 жыл бұрын
>This sum is actually used in physics so we know it's true! >*shows a book on string theory* bruh
@diogenescinico
@diogenescinico 2 жыл бұрын
I don't know what drives someone to use greentext on KZfaq
@irokosalei5133
@irokosalei5133 2 жыл бұрын
It's used in Quantum Electrodynamics so yeah it is.
@douggwyn9656
@douggwyn9656 2 жыл бұрын
@@irokosalei5133 It's not "used", in that there are only a couple of applications in QED and the one shown in that book is wrong, leading to the multiverse instead of the observed data.
@wonderland9052
@wonderland9052 2 жыл бұрын
wow i never knew youtube greentext was used in quantum electrodynamics
@AYVYN
@AYVYN 2 жыл бұрын
It’s used in physics in the sense that you have to adhere to the same mathematical limits for it to work. It isn’t a number like planck's constant
@sempertard
@sempertard 3 жыл бұрын
i always multiply both sides by zero. Seems to fix things up pretty well.
@diinobambino822
@diinobambino822 3 жыл бұрын
Just like my future! :D
@achyuthamunimakula8212
@achyuthamunimakula8212 2 жыл бұрын
I try differentiating both sides always....funnily I get the same result as multiplying with zero
@youme1414
@youme1414 2 жыл бұрын
Zero is not really a value.
@alice_in_wonderland42
@alice_in_wonderland42 2 жыл бұрын
@@youme1414 it is but u don't get the point
@elementalneil7967
@elementalneil7967 2 жыл бұрын
I mean, at this point, it seems to be a more logical way to go about it than whatever that was.
@almircampos
@almircampos 4 жыл бұрын
After having watched this video for infinite times, I realized that my knowledge had increased by a -1/12 factor every time I watched it.
@matejalmasi6533
@matejalmasi6533 3 жыл бұрын
After having watched once, then having read the comments with all the controversy, then having read an article explaining real maths behind this, then understanding the problem was with what they didn't say, my knowledge actually increased well beyond what I am expecting from watching a video on KZfaq.
@divergentmaths
@divergentmaths 3 жыл бұрын
If you are interested to learn more about divergent series and want to understand why and how 1+2+3+4+5+6+... = -1/12, I recommend the online course “Introduction to Divergent Series of Integers” on the Thinkific online learning platform.
@rajatgoswami2000
@rajatgoswami2000 3 жыл бұрын
Means decreased 😓
@keirblank4870
@keirblank4870 3 жыл бұрын
I really hope you didn't watch this 12 times
@tiny_toilet
@tiny_toilet 3 жыл бұрын
Huh, shoulda only happened once but never.
@carpaltullar
@carpaltullar 5 ай бұрын
We were allowed to make an intuitive conclusion about 1-1+1-1…, but weren’t allowed to make a much more intuitive conclusion about 1+2+3…
@marcop1563
@marcop1563 7 күн бұрын
You can show it by using a trick similar of that used for S2. You sum S1 to itself and you compute the sum by shifting one of the two series one to the right so you have 1+(-1+1)+(1-1)+...=1+0+0+...=1 so 2*S1=1 and that means S1=1/2. Of course all of this is arbitrary since these sums don't converge so they are actually undefined.
@coach_rohit
@coach_rohit Жыл бұрын
I think the biggest assumption is that S1 is 1/2 which I think is the reason why we got all the natural numbers sum to -1/12
@quantspazar6731
@quantspazar6731 Жыл бұрын
The assumption was the = sign between S1 and the literal mathematical gibberish on the right. If you have an ellipsis (...), then there is a pattern we didn't write in full, but understand what it means. That part is ok but if you have an infinite sum, the value is takes is the limit of partial sums. For S1, we look for the number that partials sums of S1 approach, but those partial sums alternate between 0 and 1, a divergent sequence, so no sum. S1 doesn't exist, and nothing makes sense after. Same can be said of all other sums here
@rum-ham
@rum-ham 2 ай бұрын
Exactly
@NotBamOrBing
@NotBamOrBing 2 ай бұрын
​@@quantspazar6731The explanation given as to why S1=1/2 wasn't great, but the answer is still right. For a better explanation, if you take 1-S1, that evaluates to S1, and the only number that works for is S1=1/2
@quantspazar6731
@quantspazar6731 2 ай бұрын
@@NotBamOrBing Unfortunately the standard framework of analysis does not give a value to the sum S1. If we want to assign it a value we must use another system (like Ramanujan summation) that extends what kinds of sums actually have a value. But there's multiple systems that extend summing in different ways, so we must explicit what system we used to compute S1. What they did with S1 was not a rigorous calculation, because there are ways to compute the same sum in different ways using that system that will give you different answers
@NotBamOrBing
@NotBamOrBing 2 ай бұрын
@@quantspazar6731 but have you considered that the sum of all natural numbers is -1/12
@stormysamreen7062
@stormysamreen7062 4 жыл бұрын
Tony: "The answer can be either 1 or 0, so we take the average 1/2 Me: "Ok, now that's where you screwed up"
@RaRa-eu9mw
@RaRa-eu9mw 4 жыл бұрын
No. This is the universal value given to 1-1+1-1... Whenever it is given a value, the only one that makes sense and ends up being internally consistent is 1/2.
@brandonklein1
@brandonklein1 4 жыл бұрын
@@RaRa-eu9mw what are you taking about? This is a discrete function, not a continuous one. To assign any value to this other than 1 or 0 depending on the nth term is absurd.
@robertdarcy6210
@robertdarcy6210 4 жыл бұрын
WHY does everyone say this? He literally states at that point in the video they have another video going into detail about why that sum is 1/2. Go watch that one
@brandonklein1
@brandonklein1 4 жыл бұрын
@@robertdarcy6210 dude I've watched the video, they even say in that video that they are using a formula outside of it's radius of convergence. There are more rigorous methods for describing series like that, all of which, still do not converge. I know it is tempting to assign a value to such an object, but in doing so, you not only encounter absurdities like presented in this video, as well as others, you *never* can"assign" a value to a sum just so it looks nice, such series explicitly remain defined on their nth term.
@efeyzee
@efeyzee 4 жыл бұрын
@@RaRa-eu9mw So the thing I don't understand about that is sum((-1)^n) from 0 to infinity fails the geometric series test (r=-1) and therefore does not converge. How is anyone claiming both this and the geometric series test is correct?
@jiggybau
@jiggybau 8 жыл бұрын
Let me prove that 1 = 0, using this premise: S1 = 1 + 2 + 3 + 4 + 5 ... = - 1/12 S1 - S1 = 1 + 2 + 3 + 4 + 5 + 6 ... - 1 - 2 - 3 - 4 - 5 ... = 1 + 1 + 1 + 1 + 1 + 1 ... Since S1 - S1 = - 1/12 - (- 1/12) = 0 It follows that 1 + 1 + 1 + 1 + 1 .... = 0 Let's name this sequence S2: S2 = 1 + 1 + 1 + 1 + 1 ... = 0 Now let's subtract it from itself: S2 - S2 = 1 + 1 + 1 + 1 + 1 ... - 1 - 1 - 1 - 1 .... = 1 Given that S2 equals 0, we can also write this as: 0 - 0 = 1 Which implies that 1 = 0.
@SomeRandomFellow
@SomeRandomFellow 8 жыл бұрын
+Enzo Molinari *claps*
@SomeRandomFellow
@SomeRandomFellow 8 жыл бұрын
Gregery Barton what a buzzkill
@AkshayAradhya
@AkshayAradhya 8 жыл бұрын
+Enzo Molinari Im pretty sure you can prove anything with this premise. Event that Kim Kardashin is smart
@AkshayAradhya
@AkshayAradhya 8 жыл бұрын
+Enzo Molinari Im pretty sure you can prove anything with this premise. Event that Kim Kardashin is smart
@AkshayAradhya
@AkshayAradhya 8 жыл бұрын
***** His proof is absolutely correct. Btw limits dont even come into the picture here. They used a sequence of numbers in the video. Not limits, which are completely different. What are you even talking about. ... ?
@GamingBlake2002
@GamingBlake2002 Жыл бұрын
It seems like there's all kinds of tricks you can pull to get whatever result you want, once you throw rigor out the window. For example, he took the average of 1 + 1 - 1 + ... to get 1/2. You could also do this: 1 - 1 + 1 - 1 ... = (1 + 1 + 1 ...) + (-1 - 1 - 1 ...) = (1 + 1 + 1...) - (1 + 1 + 1...) = 0
@AchtungBaby77
@AchtungBaby77 Жыл бұрын
This should be a pinned commercial, well said 👏
@aryan_verma_1729
@aryan_verma_1729 11 ай бұрын
No bro...we do not know whether bith series have equal no. Of terms or not same condition is therebin this one also...i.e 1-1+1-1+1-1......if its ending with a 1 then result will be 1 is ends with -1 then 0 ...therefore we cannot say anything because its diverging... But we can use zeta function concept Let 1-1+1-1....=S Take minus as common after first 1-(1-1+1-1...) =S Means 1-S=S Hence S=1/2 These physicists ...idk after what logic they said take out the average...which is just logicless...this which i have given is real explanation..
@chromiumbook-marx4417
@chromiumbook-marx4417 8 ай бұрын
I dont understand the shifting tho, is it arbitrary? And could you just start S1 at -1 instead and end up with its value being -1/2? This seems like fishy logic
@REALSLIK
@REALSLIK Ай бұрын
This is correct. The sum of 1-1+1-1+1... is 0 because omega is even, and so this sum converges to 0 at infinity.
@Prs722
@Prs722 6 ай бұрын
Trolley Problem: A trolley is on a track headed towards one person, and after this one person is two people, and after that is 3 people, and so on. You can flip a lever to send the trolley onto an empty track. Do you flip the lever?
@mwzngd1679
@mwzngd1679 6 ай бұрын
lol this is the greatest trick question of all time if you don't flip the lever than -1/12 people will die so you will save more people than if you do flip, in which 0 people will die
@Prs722
@Prs722 6 ай бұрын
@@mwzngd1679 But, say you didn't flip the lever and there was an actual trolley headed towards people. Would you truly be saving a 12th of a person, or would you be killing an infinite number of people. I think the true answer is similar to dividing by zero. It is undefined. You can define it in various ways that can potentially have use, but the true answer is undefined. Likewise, 1-1+1-1+1... is undefined. Yes you can define it as 1/2, but you will never truly get an answer, so it is undefined. It will never equal 1, it will never equal 0, and it will never equal 1/2.
@paulzapodeanu9407
@paulzapodeanu9407 4 жыл бұрын
To quote a math teacher from my uni: "It's extremely unpleasant to approximate solutions that don't exist."
@aeroscience9834
@aeroscience9834 4 жыл бұрын
paul zapodeanu unpleasant. But not always useless
@wangdave5574
@wangdave5574 4 жыл бұрын
Aeroscience in this case very useless
@aeroscience9834
@aeroscience9834 4 жыл бұрын
Wang Dave not at all. Eventually this stuff lead into the Riemann zeta function. Which is very useful.
@pankajmundhra7421
@pankajmundhra7421 4 жыл бұрын
Such a boring maths teacher you got
@achyuththouta6957
@achyuththouta6957 3 жыл бұрын
@@huhun23 There are other ways to prove it using basic arithmetic such that a 5th class student can understand. No need of zeta functions
@beardjoe11
@beardjoe11 4 жыл бұрын
Watching this makes me think of the mathematician who, after watching two people go into a house and then later seeing three people come out, declares that if one more person goes into the house it will be empty.
@hemangabaruah2486
@hemangabaruah2486 4 жыл бұрын
This is not for the calculation in a universe of 3 dimension, but for more that that which is totally out of our reach till date So have some sense not to comply things to everything
@emmynoether5878
@emmynoether5878 2 жыл бұрын
What if one of the person that goes in was pregnant
@ncrohawk
@ncrohawk 2 жыл бұрын
no, they would declare the house has as many people as it had before
@acudaican
@acudaican 2 жыл бұрын
That's just bad practice as a burglar, assuming the house is empty.
@CAMohitShah
@CAMohitShah Жыл бұрын
What of that one person is a serial killer with suicide mentality
@shafaque1390
@shafaque1390 7 ай бұрын
The statement that the sum of all natural numbers equals -1/12 is correct within the specific mathematical context of zeta function regularization used in theoretical physics and certain areas of number theory. However, it's important to emphasize that this result should not be interpreted as the sum of natural numbers in the traditional sense, which is a divergent series. In everyday arithmetic, the sum of all natural numbers is not -1/12. This concept is a result of mathematical manipulation and regularization techniques used in specific mathematical and physics contexts.
@RaRa-eu9mw
@RaRa-eu9mw 7 ай бұрын
This concept that youtube commenters have of "the traditional sense" needs to stop. Every context where the sum of the naturals appears, it is always taken to be equal to -1/12. It's useless talking about what the sum is "in everyday arithmetic" (whatever that is) when the sum never appears in everyday arithmetic.
@raenfox
@raenfox Жыл бұрын
Mathematician: **calculates something, result doesn't make any sense.** Mathematician: "I define this as correct."
@Sadnessiuseless
@Sadnessiuseless Жыл бұрын
it does make sense?
@_bleck
@_bleck Жыл бұрын
@@Sadnessiuseless stay in school kids
@bardofhighrenown
@bardofhighrenown Жыл бұрын
He's a Physicist. You'd be surprised how rough and sloppy their math skills actually are. I know I was when I took my first physics class.
@SuperRaidriar
@SuperRaidriar Жыл бұрын
You have to realize the reason they assign the value -1/12 to this sum is because it is useful in some way.
@scoobydoofan3275
@scoobydoofan3275 Жыл бұрын
@@SuperRaidriar I feel like there's a logical physical explanation for that which doesn't include abusing analysis
@ludvigpio9605
@ludvigpio9605 3 жыл бұрын
But S1 and S2 are divergent series, they can't be assigned a value. This video just shows that if you try to assign a value to divergent series you can prove nonsense such as sum of all positive numbers equal -1/12
@RAWestover
@RAWestover 2 жыл бұрын
It's kind of like how you can prove 1=2 if you divide by zero, or you can prove 0=1 if you ignore that the square root of a positive number has two answers.
@1willFALL
@1willFALL 2 жыл бұрын
Exactly, this seems very contrived
@user-fl2hl8qg7s
@user-fl2hl8qg7s 2 жыл бұрын
this comment should be pinned
@AdelaeR
@AdelaeR 2 жыл бұрын
I agree 100%. I love math, but when it does hocus pocus with infinity and then tells me that by adding all positive numbers the outcome is a negative number, then that tells me that the hocus pocus with infinity must be wrong. Another fine example of this is when they tried to convince me that two parallel lines meet at infinity, to which my answer was: "No. Your logic must be wrong because it goes against the definition of parallel lines".
@vallarisharma7391
@vallarisharma7391 2 жыл бұрын
Hey,I've actually seen the proof of it ..I've also read the book but the person who proved the value of infinity himself -The Indian mathematician Ramanujan.Its not as easy as the proof shown in this video,but there's a more complex algebra involved, which can make the impossibility of getting a negative value out of adding all positives, a possibility.
@jerrysteffens4540
@jerrysteffens4540 5 жыл бұрын
This video represents negative knowledge; if you watch it, you will know less about mathematics than when you started.
@saratoga123321
@saratoga123321 5 жыл бұрын
Jerry Steffens video represents more knowledge than you can comprehend
@GurisaYudistira
@GurisaYudistira 4 жыл бұрын
@@saratoga123321 you're negatively missing the jokes.
@craneology
@craneology 4 жыл бұрын
It does, since it is false.
@dropdatabase2569
@dropdatabase2569 4 жыл бұрын
@@saratoga123321 It has error in the very first line...
@UnknownRager96
@UnknownRager96 4 жыл бұрын
@@dropdatabase2569 r/woooosh
@andrewazariah8356
@andrewazariah8356 2 жыл бұрын
When you do 2S2, isn't it going against rules when you shift the bottom set of numbers by one place ?
@marcevans2620
@marcevans2620 Жыл бұрын
That's what I thought
@atifrafique3764
@atifrafique3764 7 ай бұрын
these 2 series were added (1-2+3-4.................. and 1-2+3-4............) to give 2S. we can get two different results if we shift right and not shift what is with that, that shift result will give 1-1+1-1........... and without shift it gives 2,-4,6................. is both of them same ??????? is my point logical .@@marcevans2620
@jannatunnayeem3631
@jannatunnayeem3631 24 күн бұрын
Not really, it technically means you're basically adding a 0 to the bottom set of numbers before adding it to the top
@jessenelson8106
@jessenelson8106 6 ай бұрын
I’ve watched this video almost -1/12 times, and it never gets old.
@divergentmaths
@divergentmaths 3 жыл бұрын
A reminder of the golden rules to be adhered to when dealing with divergent series: 1) Do not use brackets. 2) Do not remove any zero (unless you have proven that the divergent series is stable). 3) Do not shuffle around more than a finite number of terms. Not adhering to these rules yields incorrect sums.
@mantejsingh5438
@mantejsingh5438 3 жыл бұрын
I think they don't read the comments
@divergentmaths
@divergentmaths 3 жыл бұрын
@@harry_page The correct sums for the following divergent series mentioned in the blackpenredpen video "Not -1/12" are: 1 + 2 + 3 + 4 + 5 + 6 + ... = -1/12 1 + 9 + 18 + 27 + 36 + 45 + ... = 19/4 3 + 25 + 50 + 75 + 100 + 125 + ... = 161/12
@Anchor9Studios
@Anchor9Studios 3 жыл бұрын
Username checks out
@gamester2495
@gamester2495 3 жыл бұрын
but you can prove 1-1+1-1..... = 1/2 by using binomial theorem if you use n=-1 and x=1, then on left side u get 1/2 and on right side u have 1-1+1-1....
@harry_page
@harry_page 3 жыл бұрын
@@gamester2495 I think that formula only works when -1
@ToothBrush531
@ToothBrush531 2 жыл бұрын
“So now do you believe me?” Me: *No*
@jamesgrist1101
@jamesgrist1101 2 жыл бұрын
numberphile is disseminating wrong maths and false claims. This vid should have been an april fool. But its still up after 7 years.
@gurkiratsingh7tha993
@gurkiratsingh7tha993 2 жыл бұрын
@@jamesgrist1101 I agree
@TacticusPrime
@TacticusPrime 2 жыл бұрын
@@jamesgrist1101 You can also prove it with Rieman Zeta function.
@tarunsidambaram6579
@tarunsidambaram6579 2 жыл бұрын
@@jamesgrist1101 maybe numberphile did not explain the topic so well but THAT DOES NOT mean that the equation is wrong, kid.
@tarunsidambaram6579
@tarunsidambaram6579 2 жыл бұрын
see, Ramanujan's problem is hard to believe but does not mean it's wrong, infinity is big and you can not imagine and you just can't say your OPINIONS on it, instead go find out more on this problem, go and study this properly
@Tobiasberger
@Tobiasberger 6 ай бұрын
Combining two positive numbers will always be a positive number, no matter how far you go. It’s like a function thats trending towards infinity. It just cannot be negative
@xenqor5438
@xenqor5438 5 ай бұрын
Wow you’re so smart 😮 😱
@user-rl5dl2ff5o
@user-rl5dl2ff5o 4 ай бұрын
@@xenqor5438 That's not nice at all, he's trying his best, let him arrive to the conclusion O_O
@moestietabarnak
@moestietabarnak 9 ай бұрын
obvious error, the sum of +1-1+1-1+1-1 ..is NOT 1/2 .. this is a DISCONTINUED function that alternate between 1 and 0 ... YOU DO NOT AVERAGE IT !
@helter6541
@helter6541 9 күн бұрын
4+8+16….. Shouldn’t be = 4S.
@craigburkhart1616
@craigburkhart1616 3 жыл бұрын
After watching this I have some idea why string theory went off the rails.
@jeffw8218
@jeffw8218 3 жыл бұрын
Yup, in science we need to be able to test hypothesis. And if strings are too small to be observed, then we can’t gather anything scientific from them.
@katyab92
@katyab92 3 жыл бұрын
Hahaha!! Only physicists...😓
@nich8244
@nich8244 3 жыл бұрын
This is a result that explains the Casimir Effect...physically. The analytical continuation of the Reimann Zeta function.
@RWBHere
@RWBHere 3 жыл бұрын
String Theory is exactly what it's name says; a theory. It has never been proven to be valid. Mathematicians are not normal people. It seems to me that every mathematician I've met or read about has been eccentric in one way or another. Erdös, Einstein, Turing, Gauss, Feynman, Gödel,..... read about any of them, and it becomes clear that their minds were not in the same world as the minds of ordinary people.
@microsoftword213
@microsoftword213 3 жыл бұрын
@Brandon Neifert dont get excited that 44 is out of 200
@joshboone33
@joshboone33 5 жыл бұрын
I think this video perfectly illustrates Proof by Contradiction: Start with nonsense, end with nonsense.
@x_theandrey9614
@x_theandrey9614 4 жыл бұрын
it all started when they used infinity as a number
@dannyboy12244
@dannyboy12244 4 жыл бұрын
How did they start with non sense?
@midknight1339
@midknight1339 4 жыл бұрын
@@x_theandrey9614 Where?
@Jahus
@Jahus 4 жыл бұрын
Exactly.
@hecticfreeze
@hecticfreeze 4 жыл бұрын
@F a Except even in basic maths this kind of thing is done all the time. Pi might be an infinitely long string of numbers but we can still assign it a finite symbol (the letter pi) to represent it and then use it to perform useful calculations. It's also possible to sum an infinite series and get a finite value, like 1+1/2+1/4 etc equals 2 Theres a reason the "rational" numbers are a very small subset of all numbers. Because most numbers behave irrationally.
@keithhigh7773
@keithhigh7773 Жыл бұрын
Shame you did not mention the great Indian (largely self taught) mathematician Srinivasa Ramanujan who first postulated this idea back in the early 20th Century. He died in 1920 aged 32. Even today, the work he left behind is still proving both challenging and useful.
@sreenavenugopalan936
@sreenavenugopalan936 Жыл бұрын
Absolutely 💯
@ritwikbasak4960
@ritwikbasak4960 10 ай бұрын
True
@zebt7477
@zebt7477 10 ай бұрын
He didnt because he knew that this infinite summation result is false
@akshit5363
@akshit5363 Жыл бұрын
The sum of 1 to infinity is given by Indian Mathematician 'Srinivasa Ramanujan'
@Rustamdeep
@Rustamdeep 10 жыл бұрын
Sum of first series is NOT DEFINED
@DreIsGoneFission
@DreIsGoneFission 3 жыл бұрын
One of the angriest KZfaq comment sections since the incident with the forest in Japan
@RWBHere
@RWBHere 3 жыл бұрын
You'll have to explain that reference to me.
@KahraLoding
@KahraLoding 3 жыл бұрын
@@RWBHere Logan Paul incident
@NOAH-hu6be
@NOAH-hu6be 3 жыл бұрын
That analogy is inaccurate because this was here before then
@culwin
@culwin 3 жыл бұрын
A little different, because nobody liked Logan Paul in the first place.
@MikehMike01
@MikehMike01 3 жыл бұрын
Because this video is spreading lies and making people stupider and less interested in math. It’s immoral.
@SpartanDemiGod
@SpartanDemiGod Жыл бұрын
I don't understand how can you shift a set of numbers to the right just like that ??
@sidgar1
@sidgar1 3 ай бұрын
Shifting them doesn't change their values, it just changes which numbers in the 2 sets you are going to pair to one another.
@adamheuer8502
@adamheuer8502 17 күн бұрын
Well it doesn’t change anything just like writing plus one on both sides of an equivalency function doesn’t change it. This proof is nonsense because it doesn’t follow the rules of convergence. Just go watch one of the disproval videos of this proof and they will explain it better than I could
@arpitloveen6997
@arpitloveen6997 15 күн бұрын
That's not the problem, it can be done. But the problem is S1 =1/2
@awlabrador
@awlabrador Жыл бұрын
I saw this for this first time today when my son drew my attention to it, and I immediately knew that S1 wasn’t convergent and that the entire argument fell apart from that point. It gave me a headache to sit through. I felt like the person who yells at the television telling the teenagers not to go into the barn alone and unarmed in the middle of the night while that masked serial killer is still on the loose. Except I don’t watch those kinds of shows. One huge benefit, though, was in being able to have a nice discussion with my son about math and physics, mathematicians, theorists, and experimental physicists. And yes, I’m a physicist, too.
@RSLT
@RSLT Жыл бұрын
Note that you can say X^2+1 =0 has no solution, and that could be correct. There are different levels of math. In level zero, 1+2+3-... doesn't have a limit (like x^2+1=0 has no solution). However, at a higher level, the roots of X^2+1=0 are well defined. Your laptop or cellphone car,... works based on complex analysis principal. At that level, there is no question that 1+2+3...=-1/12
@Gunz_o
@Gunz_o Жыл бұрын
@@RSLT 1+2+3... *is associated with* -1/12. It's incorrect to use "=" here without that clarification.
@HotslutGG
@HotslutGG 10 жыл бұрын
The problem/flaw of all this begins at the assumption that the "average" of 1-1+1-1+1.... equals 1/2
@sivad1025
@sivad1025 7 жыл бұрын
Watch their proof. It's in depth and makes sense. Additionally: s=1-1+1-1+1... 1-s=1-(1-1+1-1+1) =1-1+1-1+1 therefore: 1-s=s 1=2s s=1/2
@maljamin
@maljamin 7 жыл бұрын
but saying 1-s = s when you're dealing with this infinitely "oscillating" thing means: "0,1,0,1..." = "1,0,1,0...". It does and doesn't. 1-s doesn't mean what it would mean if s were a number. To my mind, S something unresolved, a superposition of answers. 1-S is a similar "unresolved" but it is "out of phase". Any moment you stop it is 0 when S is 1, and 1 when S is 0. So the best way I could make it seem less resolved is maybe to change the claim that 1-S=S (which is merely a guess based on what it "looks like"). Let's revise that claim to this instead: -S + 1 "=" S. In my view, adding 1 to a superposition merely "resembles" another superposition.
@cygil1
@cygil1 8 жыл бұрын
This is an excellent proof of the fact that if you attempt to sum a divergent series, you get a garbage result.
@erroid
@erroid 8 жыл бұрын
+cygil1 which is not so garbage for physicists if they say those number occur evrywhere
@douggwyn9656
@douggwyn9656 8 жыл бұрын
+erroid The problem is that since it is garbage logic, you can't trust it in applications. In another thread I gave the example of a bridge designer who uses an infinite series to approximate local stresses on a long bridge; if the approximation mathematically shows that the stress on the bridge exceeds any supportable value, but he recalls this video and substitutes -1/12 which would be more than safe (if it were only correct), would you want to drive over his bridge?
@alexkfridges
@alexkfridges 8 жыл бұрын
+erroid "string theorists" not physicists ;)
@Trias805
@Trias805 8 жыл бұрын
Well, according to the video, the theory is matched with experiment resulsts, so we cannot completely disregard this, however mindblowing it is.
@douggwyn9656
@douggwyn9656 8 жыл бұрын
String theory doesn't have any experimental results yet, and anyway mathematical verification is to be found in rigorous, logical proof, not in physical experiments. In this particular case, the actual sum of all positive integers is provably divergent (to +infinity), not -1/12, and the errors in the reasoning have been pointed out several times in the commentary: The -1/12 comes from something else (Riemann zeta) that is not equal to the original series but is a substitute for it. No justification has been given for making the substitution, but even if there were some form of justification, it could not be on the grounds of numerical equality, since obviously -1/12 is not equal to +infinity.
@godbroccoli11
@godbroccoli11 8 ай бұрын
Pretty sure shifting the second set of S2 over one space is why this shouldn't work. While each sum of numbers is infinite, by adding them all together in such a way you technically leave out the very last number of the second sum which was added to the first sum. So instead of 2(S2) = 1/2, I think 2(S2) = 1/2 + (last number added in sum), which thus would make everything else inaccurate due to the last number being undefined and now making the set undefined. Just my guess though
@-entr0pY
@-entr0pY 3 ай бұрын
There is no last number tho.
@godbroccoli11
@godbroccoli11 3 ай бұрын
@@-entr0pY That’s why I said technically. At any point in time there is one less number in the second set than the first
@-entr0pY
@-entr0pY 3 ай бұрын
@@godbroccoli11 But that logic doesnt work because it implies the series end at some point where one other number can be left out.
@vickm7761
@vickm7761 2 ай бұрын
@@-entr0pY I agree with Entropy--the sliding of the numbers is merely a strategy for organizing the infinite list into a more easily-understandable sequence. "One less number in the second set" doesn't apply here, as these sets have infinite elements. It's not something intuitive at all, but neither is the concept of infinity.
@viola_case
@viola_case Жыл бұрын
Mathematics when KZfaq removes the dislike button:
@anothergol
@anothergol 6 жыл бұрын
I prefer to see this as a demonstration that 1-1+1-1+1-1... does NOT equal 1/2
@CyrusBeaman
@CyrusBeaman 5 жыл бұрын
Yeah because in reality, the actual answer would be a superposition of both zero and one, so basically there is no answer, it's like trying to say if infinity is either odd or even, its neither. So to use that to answer so many other things is ridiculous
@Marco-zv8xm
@Marco-zv8xm 5 жыл бұрын
@@CyrusBeaman i would prefer saying s = 0;1 at the same time. It has 2 possible answers so that would be the way to go i think
@_Nibi
@_Nibi 5 жыл бұрын
@Sari Çizmeli Mehmet Ağa infinity is equal to two times infinity plus 1. Infinity is odd.
@BUE687
@BUE687 5 жыл бұрын
You are so right, showing that the limit does not exist is quite simple
@pain10227
@pain10227 5 жыл бұрын
S=1-1+1-1+1-... S=1-(1-1+1-1+1...) S=1-S 2S=1 S=1/2
@giacomoverardo6446
@giacomoverardo6446 4 жыл бұрын
Yesterday I solved an equation and got 2 solutions: 0 and 1. However, I wanted to save time and only wrote that there was only one solution and that was the average 1/2 . Dunno why, I got a bad mark
@arshawitoelar7675
@arshawitoelar7675 4 жыл бұрын
Ikr, this video feels like a scam
@nycolasfelix8828
@nycolasfelix8828 4 жыл бұрын
I mean, there is another way to prove it
@nycolasfelix8828
@nycolasfelix8828 4 жыл бұрын
You see, we have: S1 = 1-1+1-1+1.... Taking 1- out , we have: S1 = 1-( 1+1-1+1-1...) Which is the same thing as : S1= 1 - S1 Therefore... : S1 + S1 = 1. 2S1 = 1 S1 = 1/2
@giacomoverardo6446
@giacomoverardo6446 4 жыл бұрын
@@nycolasfelix8828 Come on man, 2S1=2 -2 2 -2 ..., that doesn't converge to any value just like S1
@shivamsahu
@shivamsahu 4 жыл бұрын
@@giacomoverardo6446 I absolutely agree , you just put a 1 there
@nintishia
@nintishia 2 жыл бұрын
The message is loud and clear -- DO NOT MESS WITH A NON-CONVERGENT SERIES, YOU WILL NOT GET ANYTHING MEANINGFUL. Let me just illustrate what I mean. Consider the infinite sum mentioned also in the video: S=1-2+3-4+5-6+... One could write this as: S=1+(-2+3)+(-4+5)+... which tends to +infinity or as: S=(1-2)+(3-4)+(5-6)+... which tends to -infinity And please, please, please do not say we should sum the two to get S=0.
@satvikrajput847
@satvikrajput847 Жыл бұрын
Only few people here would know that this was actually theorem by Srinivasa Ramanujan the greatest Indian mathematician of all time.
@CapsUnlocked
@CapsUnlocked Жыл бұрын
This theorem is incorrect
@mikosoft
@mikosoft 9 жыл бұрын
Just an astounding leap of logic. How can you say that a sum is an average? Average is a sum divided by the size of the data pool. A sum is a sum. Your sum 1+1-1+1 ... is divergent and cannot be solved. The case is closed.
@numberphile
@numberphile 9 жыл бұрын
mikosoft One minus one plus one minus one - Numberphile
@mikosoft
@mikosoft 9 жыл бұрын
Numberphile Yes, that's nice that you use Cesaro summation, however, this summation is not a strict sum. It is still an average. Just because it has summation in the name doesn't mean you can use it as a sum. On the other hand, if you in your videos consider "=" to be something else than standard equal sign then it's all right but you have to define your operators first. But considering your "=" is not equality than your arithmetic gymnastic has no practical application anyway.
@numberphile
@numberphile 9 жыл бұрын
mikosoft Tony's article is also good - bit.ly/TonyResponse - I am not really having arguments with people, and certainly when we start saying "this summation is different to this one" that is important stuff, but starting to move away from the realm of a quirky, smiling KZfaq video. Don't get me wrong, a section at the start of the video defining operators sounds fun and all, but... :)
@AndreaRoll
@AndreaRoll 9 жыл бұрын
i think the problem is not the first sum S1. Even if you don't do the average you still have that the result is 1 or 0 depending on where you stop. this leads the second sum to be equal to 1/2 or 0 and in the end you still have a finite number to handle. i think the problem is that he handles the S2 in the wrong way. He basically usues normal algebra to handle the infinite order. Therefore he would for example say that infinite divided by infinite ( oo/oo ) equals one. ( in the specific case of the demonstration he will say that at some point infinite minus infinite equals one )
@zacharyst0ne
@zacharyst0ne 9 жыл бұрын
Numberphile Let Z=1-1+1-1... then Z+Z=(1-1+1-1...) + (1-1+1-1...)=1-1+1-1... It follows that 2Z=Z. If Z=1/2, then we arrive at 1=1/2, which is clearly a contradiction.
@oralboytoy
@oralboytoy 8 жыл бұрын
You made two blatant mathematical fallacies in your video. 1. The sum of the first series you showed is absolutely not 1/2. It will never be 1/2. This is a divergent and discrete, oscillating series. You calculated the arithmetic mean of the series for every finite truncation, which will never be equal to the sum, because the sum doesn't exist. 2. When you add two series, you can't simply shift all of the terms to the right or to the left for the convenience of whatever result you're trying to attain. I can easily disprove that. Consider two series. The first is (1+2+3+4+5+6+7+...). The second is (-1 -2 -3 -4 -5 -6 -7 -...). The second series is simply the negation of the first. Obviously their sum is the convergent constant series, (0+0+0+0+0+0+...). However, if we inexplicably decide to shift all of the negative number in the second series to the RIGHT as you did in the video, and then add the terms of the two series vertically, we'll now get the series (1+1+1+1+1+1+1+...) which is a divergent series, and not a remotely accurate result. If string theory is based on this illogic, then theoretical physicists should refine their arithmetic abilities.
@Prochillah90
@Prochillah90 8 жыл бұрын
thats exactly what i thought! why even "shifting" in the first place? for what reason? in your example you could shifte one more time without a reason and you would get (1+2+2+2+2+2+2...) for me thats the same as saying "ok now once we know we have this result, we could add a banana to it! and for that we got banana(1+2+2+2) So with that we can prove that mathematics are really made for monkeys".
@noobslayeru
@noobslayeru 8 жыл бұрын
I don't understand why they shift it in the first place.
@qantj
@qantj 8 жыл бұрын
Infinity does weird things to mathematics.
@oralboytoy
@oralboytoy 8 жыл бұрын
TheMentallord I'm a calculus teacher with a math degree. UT, class of '14.
@TheMentallord
@TheMentallord 8 жыл бұрын
+jg bubba then you should be fired immeadiatly. no calculus teacher should ever say that the sum of 2 divergent series is 'obviously' 0, because they are DIVERGENT. you cant say that infinity - infinity = 0, thats just plain wrong.
@Chazulu2
@Chazulu2 10 ай бұрын
Using the methods used in this video I was able to show that the summation from n=2 to inf of {S(Pn)*[Pn+G(Pn)]+n} = 1 where S(Pn) is the summation of all of the numbers with non trivial factors strictly greater than Pn. Pn is the nth prime if you include 1 as being prime P1. Thank you all for the inspiring video.
@Chazulu2
@Chazulu2 10 ай бұрын
Update. Showed that G(Pn)= 1+ 1/(Pn+1) -Pn.??? 🤷‍♂️
@Bollibompa
@Bollibompa 8 ай бұрын
​@@Chazulu2 Use the methods presented in this video with heavy caution. They are in no sense of the word robust or deterministic since the underlying framework requires another approach, i.e. analytical continuation of the Riemann Zeta function, regularization and renormalization.
@Chazulu2
@Chazulu2 8 ай бұрын
@Bollibompa I agree, tho I think the result I got is indeed interesting. Like, it's obviously "nonsensical" in the same way that -1/12 is, but the magnitude of the result is just less than the prime number. Note, the result I got was G(Pn)=-(Pn+[1/n^n-1*S(Pn)]-1/Pn-1) Where S(Pn) is the sum of all positive natural numbers with no divisors less than or equal to Pn other than the trivial divisor of 1. I posted the handwritten work on mathoverflow, but they blocked it and sent me to mathstackexchange. I had little desire to post to their presumed sister site after having already been jerked around significantly. If you or others are interested in how I got the result, I'd be happy to post a picture of my work somewhere. I took the sum of all primes to the even powers, multiplied the summation by the prime to get them all to all of the odd powers, added those sums together to get the prime to all of the even and odd powers then took a difference of two squares and canceled a common facror in the numerator and denominator of the general expression. I then essentially shifted the S(Pn) function described earlier and multiplied it by the subsequent prime (or the prime + the prime gap). I also had to get the bounds of the summation to all start at n=2, so I rewrote a +1 as the geometric series. Then, since they were all integer summations from n=2 to inf, I asked the question if canceling the summations is logically consistent. It was a lot of fun, and I would be happy to talk to someone capable and willing to read over my work... let me know if you want me to post the picture somewhere specific (it's like a 1.5 pages)
@Chazulu2
@Chazulu2 8 ай бұрын
Lol, I forgot to circle back to why I think that it's interesting. It could be related to the intuition that in the limit, the gap between prime numbers should be bound by the size of the most recent prime number (even if composite numbers are maximally dense) I have no clue if or how it could relate to the twin prime Conjecture, as I'm not a professional. If analytical continuation relies heavily on the first derivative of a function and the 0th derivative, then the 1/2 vertical line could be a reflection of the 0, 1, oscillation leading to 1/2 used in the 1-1+1-1+1-... portion of the discussion in this and related videos.
@renu1729
@renu1729 Жыл бұрын
Just curious are there any videos explaining where this divergent series sum is being used in physics.
@plat2716
@plat2716 9 ай бұрын
It's used in string theory.
@stefanogandino9192
@stefanogandino9192 4 ай бұрын
If you wonder how string theorists come up with thousands of dimension, particles and still be unable to describe the real world, this is why
@pluto9000
@pluto9000 2 ай бұрын
String theory is the physics they teach you as a joke.
@fyodordochievsky4376
@fyodordochievsky4376 Ай бұрын
This is why string theory is a joke
@iammaxhailme
@iammaxhailme 10 жыл бұрын
This whole "astounding" fact sums from the fact that people are mistaking Grandi's series for the ACTUAL sum. The sum of alternating ones is not a half, it SHOULD be a half. A half is an approximation, not the actual answer. The actual answer is that there is no defined sum. There's a big difference..
@matthiash.3749
@matthiash.3749 5 жыл бұрын
That is true. Saying that it IS one half is just like saying that the sequence (1,0,1,0,1,...) tends towards 1/2 which is just complete rubbish.
@dangerlahori9058
@dangerlahori9058 5 жыл бұрын
4-4/4-4=1/2 prouf this question solved
@manun7105
@manun7105 5 жыл бұрын
Maa H. > He never said that this "sum" is the limit of partial sum. It is an other algebraic operation with sum properties, that's why it is correct to say that the sum of this alternating serie *is* 1/2. (1,0,1,0,1,0,1,...) does not converge in the usual sense but with a generalized notion of limit, it is correct to say that it tends toward 1/2.
@mikeharpes7573
@mikeharpes7573 5 жыл бұрын
No Manu N. It is not, like most of the content of this video it is pure nonsense. The basic error they are making is assigning arbitrary 'sum' values to series that are non-convergent and as anyone with a basic familiarity with mathematics knows, by appropriate use of brackets you can 'make' a non-convergent series 'sum' to pretty much anything you like, if you are an idiot. For example, their chosen series 1+(-1)+1+(-1)+.... can be bracketed as (1+(-1))+(1+(-1))+..... which = 0+0+0+0+..... which clearly sums to 0, but they proved it 'sums' to 1/2 => I've just proved 0 = 1/2, quick call the news papers, I'm a genius, NOT. They are just hiding their specific use of brackets by taking the series and 'shifting' them which is equivalent to adding brackets, but because the brackets aren't explicitly added the weak minded (like yourself) mightn't notice. Bottom line, the series being considered here are non-convergent and => you cannot perform algebraic manipulations on them. The only thing that converges to -1/12 is the analytic continuation of the Riemann Zeta Function evaluated at z=-1 and this is NOT equal to the sum of the natural numbers, if it was then there would be no need for analytic continuation in the first place.
@cenowador
@cenowador 5 жыл бұрын
Mike Harpes I'm waiting for your paper debunking mathematical theories. You know that a lot of mathematical institutions would be very glad to give you 1 million dollars for that, right? The incentive is there. Go for it, big boy.
@ravenlord4
@ravenlord4 10 жыл бұрын
The US government is trying this with the national debt.
@gangulic
@gangulic 10 жыл бұрын
the best comment ever!
@ayushdhakal333
@ayushdhakal333 3 жыл бұрын
@@gangulic you guys still alive? Just curious 😁
@gangulic
@gangulic 3 жыл бұрын
@@ayushdhakal333 allo allo zis iz night hawk can you ear mi?
@paulmccartney8293
@paulmccartney8293 2 жыл бұрын
@@gangulic wow he's alive
@shig8888
@shig8888 2 жыл бұрын
Wow! No visible dislikes, I'm sure the community really loved this one!
@Lordidude
@Lordidude 10 ай бұрын
KZfaq removed dislike display.
@RiannaPeterson
@RiannaPeterson 10 ай бұрын
@@Lordidude sorry but................ wooooooooooooooooosh
@Lordidude
@Lordidude 10 ай бұрын
@@RiannaPeterson what?
@AchtungBaby77
@AchtungBaby77 10 ай бұрын
​@@LordidudeHe's implying the joke went over your head.
@depression_plusplus6120
@depression_plusplus6120 Жыл бұрын
What pains me is in that textbook, they used Ramanujan's result. But did not mention or gave him any credit. He lived his whole life full of struggle and poverty, still contributed to the archives of knowledge. Give the man the most deserved respect, even thou he left us.
@vladimirprotein3275
@vladimirprotein3275 Жыл бұрын
But it's wrong right?
@depression_plusplus6120
@depression_plusplus6120 Жыл бұрын
@@vladimirprotein3275 ofcourse. But nothing can be done. We can just remember him and let our future generations know bout him
@MuffinsAPlenty
@MuffinsAPlenty Жыл бұрын
@@vladimirprotein3275 The way that it is used in the physics textbook is not wrong. They use a method called regularization to assign the value of -1/12 to the series. The method of regularization matches with the result from Ramanujan's method which matches the result from analytic continuation (Riemann's method). But if you watched this video without studying more about working with divergent series, you would have no idea how these techniques worked or even where to look to understand these techniques. You may even try to replicate the methods used in this video and produce contradictions. So I thought I would give you the names of things like regularization, Ramanujan summation, and analytic continuation, and I think I would like to direct you to the links in the video description so you can learn more.
@LfeinYT
@LfeinYT 9 жыл бұрын
This is not an astounding result, it is simply a false one. Whatever result this leads to cannot be the sum in the sense of the result you get when you add all the positive integers together. if you start with 1, the sum of all the integers must be greater than 1 because there are other integers to add. If you take the first 2 integers, the sum of all of them must be greater than three, because there are other integers left to add. And so on, potentially forever.. Since I'm not a mathematician, I can't deny that there may be a relation between the positive integer set and -1/12. You could call it the Riemann zeta function sum or the Rajamujan sum or some such (pun intended), but it clearly cannot be the sum in the first-grade sense of that term. To claim it is only tends undermine the integrity of mathematics. The men's demonstration is not at all convincing. They simply changed the subject, and never even addressed how these other series have anything to do with the original problem.
@numberphile
@numberphile 9 жыл бұрын
Here you go: www.bradyharanblog.com/blog/2015/1/11/this-blog-probably-wont-help
@janwollert1559
@janwollert1559 9 жыл бұрын
Brance Finger Thanks for clearing it up, imo the video should get removed from KZfaq.
@SamVidovich
@SamVidovich 9 жыл бұрын
Brance Finger "Guys, I've never studied infinite series or any math, really, but this is totally not true."
@janwollert1559
@janwollert1559 9 жыл бұрын
Sam Vidovich Why your quotation marks? This is simply not true, 1+2=positive, 1+x, while x>0, sums up to a positive term no matter how you look at it.
@SamVidovich
@SamVidovich 9 жыл бұрын
Jan Wollert It is indeed, because you can make assumptions about sums tending toward infinity by comparing them to other, similar sums. An example of this is the direct comparison test - en.wikipedia.org/wiki/Direct_comparison_test
@VecheslavNovikov
@VecheslavNovikov 8 жыл бұрын
Dear God, I'd like to file a bug report (see attached video) Amen.
@TTIOttio
@TTIOttio 8 жыл бұрын
My thoughts exactly XD
@declanpeters3305
@declanpeters3305 8 жыл бұрын
I don't get it
@nickjohn2051
@nickjohn2051 8 жыл бұрын
+Declan Peters It means even infinite sum number could result in -1/12. That odd especially infinite is larger than -1/12.
@MhD39
@MhD39 8 жыл бұрын
+Vecheslav Novikov looooooooooooool
@spinzed
@spinzed 8 жыл бұрын
The most correct comment I've ever seen (this one is a little broken).
@sadas3190
@sadas3190 10 ай бұрын
The trick is S2 is divergent so you cannot just shift it along to evaluate a rational number out of it.
@atifrafique3764
@atifrafique3764 7 ай бұрын
yes , my point too , i want to shift 10 places or 20 places or even infinte places to right or left and call it 2S , f+ck me
@Bowl_O_Udon
@Bowl_O_Udon 2 жыл бұрын
I just have a simple question- to deduce 2S2, why did he move S2 along by a digit when he was adding ? Is there any significance of that ?
@Hot_Guac
@Hot_Guac 2 жыл бұрын
Yes! That seems like a big step with no explanation.
@str0680
@str0680 Жыл бұрын
To make the other terms easier to cancel out, imagine he wrote 0 instead of nothing, since 0 + 1 - 2 + 3... = 1 - 2 + 3... That is if we assume that the sum is convergent, they sure assumed that, and it sure isn't convergent, so you end up with the magical -1/12.
@SkyWKing
@SkyWKing 10 жыл бұрын
I'm no professional mathematician but I figured out why it is wrong. At least the method used here. You cannot do a shift addition or subtraction with a divergent infinite series. Remember how they get Grandi's Series to be 1/2? They manipulated the second row so it's shifted by one place, and assume the second row to be the same as the first row. In fact it's not: Grandi's series: 1-1+1-1+1-1+1...... "Shifted" Grandi's series: 0+1-1+1-1+1-1...... But you will say "well anything plus zero is itself isn't it?". No, it's not in this case. The Grandi's series follows the pattern 1,0,1,0,1,0; the "Shifted" series is 0,1,0,1,0,1, now every term in the "Shifted" series is different from the original. Therefore by adding a zero to the beginning you get a different series. So now you cannot use 2S1=1. Try this at home: dilute the Grandi's series with 0 after each negative one, and do shift addition with three rows, you will get a number. Then dilute it by placing the zero after each positive one and do shift addition again. Compare the results (I will not spoil your fun of doing this). This happened at the end of the proof where he assumed 4+8+12+16......=4*(1+2+3+4......). Well it's right, but this is not the series appeared here. It's in fact 0+4+0+8+0+12+......You will figure out why they are different if you do the dilute Grandi's series experiment. In conclusion the method of shift addition to sum a divergent infinite series is inherently flawed. I cannot comment on the average partial sum method though. But I guess partial sum method is not enough to prove 1+2+3+4+......=-1/12.
@sivad1025
@sivad1025 7 жыл бұрын
Simple answer: the numbers are infinite. The numbers will never end. You can shift it because of that. Why wouldn't you?
@Deathnotefan97
@Deathnotefan97 10 жыл бұрын
If A=B, then AB=B^2 AB-A^2=B^2-A^2 A(B-A)=(B-A)(B+A) A=B+A A=2A 1=2 Math makes so much sense now!
@MrAljosav
@MrAljosav 5 ай бұрын
Nice try but that doesn’t work. Since B-A=A-A=0, so dividing right hand side by zero results in infinity. Thus, the only solution is the trivial solution which is when both A and B = 0
@mattiashakansson5867
@mattiashakansson5867 2 жыл бұрын
S1 goes 1, 0, 1, 0, 1, 0 and the average is 0,5. Therefore S2 should be 0 as it goes 1, -1, 1, -1, 1, -1 where the average is zero. The final equation should state S - 0 = 4S => S = 4S => 3S = 0 => S = 0
@BleakTheLabRat
@BleakTheLabRat Жыл бұрын
i have a question regarding the addition of S2 to itself @ ~ 3:12 . by shifting the value one number to right, even though both are infinity, aren't you adding two "different values" of infinity ? and not strictly 2*S2
@telugufacts7126
@telugufacts7126 Жыл бұрын
Same to me
@jonijessen
@jonijessen 11 ай бұрын
When adding numbers together, you can always shift the sequence as many times as you want. It should always give the same answer. For example, if you take (1+2+3) and add it to (1+2+3). You can set it up the normal way, above each other. 1, 2, 3 + 1, 2, 3 = 2+4+6 = 12 But you can also shift the bottom row as you please. 1, 2, 3, 0 + 0, 1, 2, 3 = 1+3+5+3 = 12 Always the same result.
@ShinyStarOfDeath
@ShinyStarOfDeath 3 жыл бұрын
The issue started when you assumed S1 = 1/2 when you divided (1+0)/2. All the points after that make sense but they are built on a questionable foundation. S1 does not end, simple as that.
@pierrecurie
@pierrecurie 3 жыл бұрын
There are more shenanigans later - with divergent sums, you can't shuffle terms around willy nilly, etc.
@Ennello
@Ennello 3 жыл бұрын
I'd say the S1 assumption is actually quite logical for physicists. But as soon as they start adding up series, they forget they're actually dealing with infinity and they screw up...
@xeroxsaw1303
@xeroxsaw1303 2 жыл бұрын
The problem is these are all divergent series and thus do not converge, even tho with a Césaro Sum the first two series can converge, the other two don’t This all should have been explained as values of the Rieman Zeta function
@TacticusPrime
@TacticusPrime 2 жыл бұрын
You sound like someone claiming that you can't take a square root of a negative number, therefore math with i doesn't make sense.
@ShinyStarOfDeath
@ShinyStarOfDeath 2 жыл бұрын
@@TacticusPrime We call them Imaginary Numbers for a reason. Not 1/2.
@BrianBell4073
@BrianBell4073 7 жыл бұрын
This is bollox. For S1, you can't just stop on odd or even. Infinity is infinity. It is a concept. It isn't a number. You have to keep going.
@numberphile
@numberphile 7 жыл бұрын
Yet sometimes these ideas/series appear in nature and physics, where saying things like "forever", "infinity", or "it just blows up" can't be accepted so easily. (I also imagine you have already seen our Grandi's Series video kzfaq.info/get/bejne/hqmlkqV_s6-ZqGg.html which covers the multiple ways in which S1 can be argued to equal 1/2....) www.bradyharanblog.com/blog/2015/1/11/this-blog-probably-wont-help
@RetroAdvance
@RetroAdvance 7 жыл бұрын
If it can't be accepted so easily, then the series 1+2+3... itself isn't an appropriate model, as simple as that. Rather there are several infinities at play, and this is just a trick to cancel out the infinite "junk" out of them, given the right conditions/context. Otherwise I could also claim that S = 1+2+3+4... = 1, I only forgot to tell you that my condition/context is that I divide it again by itself, S/S :P
@BrianBell4073
@BrianBell4073 7 жыл бұрын
+RetroAdvance.....when you get down to the hard sums then treating infinity as a number allows you to prove anything. I think the flaw is that treating infinity as a number for a 'well behaved' series gives a common sense result.....which is then extrapolated to the series which are not 'well behaved. I suspect the 'well behaved' series results are nothing more than a fluke and should not be extrapolated
@RetroAdvance
@RetroAdvance 7 жыл бұрын
I think it is actually another concept, an analytical continuation, there can be a function that also assigns a value to a divergent sum. But this value has a different meaning, it's the "imaginary part" so to speak. The problem is only that it is not introduced as such in the video. All that is said or hinted at is "but if you go to infinity you will get -1/12 as a conventional limes", which simply is not the case as infinity is bigger than every finite sum of the series.
@tomkrausz2166
@tomkrausz2166 7 жыл бұрын
BrianBell4073 yes I'm sure you're better than a proof in a published textbook
@oscarfernandez8791
@oscarfernandez8791 4 ай бұрын
Consider that sequence as the partial sum n(n+1)/2 and plotting that you'll see that -1/12 is the integral between [-1, 0] - this is a hint that this result is not a sum but something that makes sense in another ruleset. So this result needs to be considered _contextually_ in the sense that it's not measuring a sum, but it's the result of the Riemann Zeta function on domain points that only make sense by analytic continuation. The same way that sqrt(-1) is nonsense in |R but makes sense and gives valid results when we change the context to the |C complex domain.
@A_Turner
@A_Turner 9 ай бұрын
Why are these guys so poorly funded that they’re writing their maths on old envelopes instead of fresh paper?
@sxnchou
@sxnchou 9 ай бұрын
beats me 😂😂
@lchen1144
@lchen1144 3 жыл бұрын
The key thing to note is that one should never add or minus with infinite on each side of equation. For example, 5 + oo = oo and 10 + oo = oo. Therefore, 5 = 10. That is how the mathmaticians trick our ordinary folks.
@ammaleslie509
@ammaleslie509 2 жыл бұрын
You can't add or subtract infinities for the same reason you can't divide by zero. It's too easy to end up with 0 = 1
@jaysukhbhaivaddoriya5621
@jaysukhbhaivaddoriya5621 2 жыл бұрын
You can't compare two infinity if you want to compare two Infinity you need limit to compare infonity
@Ray25689
@Ray25689 2 жыл бұрын
Physicians* Mathematicians care about this and don't trick people with false calculations
@prashanthadepu3013
@prashanthadepu3013 2 жыл бұрын
@Tom Petitdidier it's just hard coded subjectivity induced by scientists to make things less complicated and more useful.
@prashanthadepu3013
@prashanthadepu3013 2 жыл бұрын
@Ray becoz physicians work in lab, mathematicians work on paper. everybody can do math until u go to the lab. physicians don't trick its just necessity. physics is a superset of math. maths is just a tool to support and build physics concept, sometimes u run out of tools so does the tricks
@ultimateredstone
@ultimateredstone 9 жыл бұрын
I am amazed at the number of people who claim they know 100% that this is rubbish. The nice thing about some parts of physics is that you can think about it without having learnt the maths behind it, but this is not one of those things. I have doubts and issues with what was shown here but I not so stupid to claim that huge branches of physics are just completely wrong, I just don't know enough about this...
@dreamlandnightmare
@dreamlandnightmare 9 жыл бұрын
ultimateredstone Ditto. I'm not about to dismiss it simply because I don't possess the knowledge/intelligence to digest it intuitively. All I will say is that I don't understand it. Until I understand the math behind it better, I cannot challenge its veracity.
@ultimateredstone
@ultimateredstone 9 жыл бұрын
***** although, I want to add, with problems where you do *not* need to know a lot about the subject, people should stop telling other people to stop challenging what's been said in the video. even with this problem, people can challenge all they want, they just can't claim to know better
@Sahuagin
@Sahuagin 9 жыл бұрын
ultimateredstone the problem with it (string theory) is that it's not based on observation. that this "fits" with string theory (they say "physics" in the video) doesn't mean it "fits" with reality, you need observation for that.
@freedom13245
@freedom13245 9 жыл бұрын
Finally a clever comment
@ultimateredstone
@ultimateredstone 9 жыл бұрын
***** *facedesk* edit: unless sarcasm. if sarcasm, then lol
@acasualviewer5861
@acasualviewer5861 2 жыл бұрын
sloppy use of the = sign The String Theory book used -> for a reason.
@soonahero
@soonahero 9 күн бұрын
This convinced me
@TheNeilBlack
@TheNeilBlack Жыл бұрын
I just cannot comprehend how adding positive numbers can ever lead to a result that's smaller than you started with. How does it ever go down?
@Manu-se5tx
@Manu-se5tx Жыл бұрын
because the math used is wrong, you can't subtract infinity to infinity or rearrange the values as done in this video.
@Gunz_o
@Gunz_o Жыл бұрын
It all makes perfect sense if you see it from the perspective of a physics lecturer who can't math.
@hypersonicmonkeybrains3418
@hypersonicmonkeybrains3418 5 жыл бұрын
Damn, i was hoping the answer would be 42.
@harishkumaar9085
@harishkumaar9085 5 жыл бұрын
Since all the basics of maths are ignored here. You could possibly get that too , by careful manipulation.
@codywang1801
@codywang1801 5 жыл бұрын
hitchhiker lol
@hmmm3210
@hmmm3210 5 жыл бұрын
42 likes rn
@sniper1326
@sniper1326 5 жыл бұрын
@@harishkumaar9085 the proof shown here isn't the real one...but this is the simplest one...
@tommyvasec5216
@tommyvasec5216 4 жыл бұрын
@Dr Deuteron Negative Infinity! Do I get an A?
@km1dash6
@km1dash6 2 жыл бұрын
You can reject the claim that 1-1+1-1... = 0.5 and instead say that it has no solution, or an indeterminate value. If you do that, the entire system falls apart. The thing is, this uses a different summation method than what most people are used to.
@mutt8553
@mutt8553 2 жыл бұрын
This whole video is extremely nit-picky and circumstantial. Sure it’s -1/12, but when you manipulate all of the factors to your bidding it can be anything
@cottoncandycloudsrobloxedits
@cottoncandycloudsrobloxedits 2 жыл бұрын
@@mutt8553 It seems like a bit of a gimmick to me so not all that serious
@TheScienceNerd100
@TheScienceNerd100 2 жыл бұрын
The whole series S1 = 1 - 1 + 1 ... is like any Supertask explained in Vsauces video. Say you take S1 and sum up the next turn, decreasing the time interval by a half each time. Say you start with 1, then after a min you get 0, then half a min 1, then a quarter min you get 0... After 2 mins you'll have the answer, but what would you get? After ever time you get a 1, you take 1 away, but after every time you take 1 away, you add 1 back. Its a paradox. Randomly making it 1/2, you can basically do anything you want now and make it *look* like it works. But it doesn't work like that, this is why String Theory failed.
@Ray25689
@Ray25689 2 жыл бұрын
@@mutt8553 "it" isn't really -1/12. You can make sense of it when you change the meaning of the + symbol or talk about holomorphic continuation of the zeta function, but assigning the series a value doesn't make sense when dealing with the usual addition
@JoeThomas-lu6fy
@JoeThomas-lu6fy 2 жыл бұрын
You can also claim that 2+2=-1/12 if you want, but without evidence it doesn't really matter.
@rohanjain7839
@rohanjain7839 Жыл бұрын
The great Indian mathematician gave this sum called THE RAMANUJAM PARADOX.
@McDaniel77
@McDaniel77 10 жыл бұрын
Nonsense is still nonsense, no matter how you explain it.
@vollsuessaba_9190
@vollsuessaba_9190 7 жыл бұрын
"The divergent series are the invention of the devil, and it is a shame to base on them any demonstration whatsoever. By using them, one may draw any conclusion he pleases and that is why these series have produced so many fallacies and so many paradoxes …" - Niels Henrik Abel 1820
@mr.coconut2310
@mr.coconut2310 6 жыл бұрын
fukn rekt
@wohdinhel
@wohdinhel 6 жыл бұрын
Vollsuessaba _ because calling something “of the devil” is truly scientifically infallible
@zoltankurti
@zoltankurti 4 жыл бұрын
@@wohdinhel you clearly didn't get the point. They are abusing infinity in this video without clear definitions. Without definitions they twist the rules as they want, and hence get what they want. This is the meaning of the quote, unpacked for the weaker minds.
@HL-iw1du
@HL-iw1du 4 жыл бұрын
Zoltán Kürti You clearly didn’t get the point. There is no answer that mathematicians “want”. They are simply trying to further their understanding of mathematics and of the Universe (hence the video’s mention of string theory). Also, by many different methods, only one sum is derived for each traditionally infinite series. So they can’t get “anything” that they want, if they want anything at all, since there is only one option. This is the meaning of the video, unpacked for weaker minds.
@zoltankurti
@zoltankurti 4 жыл бұрын
@@HL-iw1du alright, I will try again since some people are truely resistant to criticism. The video contains false information, the end. They never mentioned that they are not using the standard notion of summation. And they are not matjematicians in the video, they are physicists who communicate science in a very shameful way. They didn't specify what definitions they are using, and they could have arrived at a different answer very easily.
@ajitmali3821
@ajitmali3821 5 ай бұрын
chatgpt: the series of natural numbers diverges, and we represent this divergence by saying the sum is infinite (∞). The idea of the sum being -1/12, as mentioned in certain contexts such as in complex analysis or theoretical physics, is a regularization technique and should not be interpreted as the actual sum in the traditional sense of arithmetic summation. In standard mathematical conventions, the sum of natural numbers is not a finite value.
@TheMathGeek_314
@TheMathGeek_314 3 ай бұрын
I looked into this a bit, and I believe I've found the flaw (but when I say "flaw" I'm merely attempting to explain why the intuitive result differs from the mathematical proof shown here) Also since I am unable to use the fancy formula symbols, I'm just going to paste the raw data that will format itself in desmos . The important thing to note here is that you are choosing an arbitrary stopping point, so I've rewritten the formulas to account for this point that may or may not be infinity. For example, s1(3) = 1-1+1, and s1(6) = 1-1+1-1+1-1 The formula for s1 would be s_{1}\left(x ight)=\sum_{n=1}^{x}\left(-1 ight)^{n-1} The formula for s2 would be s_{2}\left(x ight)=\sum_{n=1}^{x}n\left(-1 ight)^{n-1} . Now, you say that s2+s2=s1, but that's not entirely true. You're offsetting the stopping point by one, so the true formula must reflect this: s_{1}\left(x ight)=s_{2}\left(x ight)+s_{2}\left(x-1 ight) (this one doesn't have a summation so I could write it normally, but I'm just being consistent for the sake of copy/pasting into desmos) . This altered formula does still hold true, but I feel like it breaks the reality of adding the "same" summation to itself due to the differing stopping point. There will always be that one missing term from the shortened version, and that singular term will become infinitely large as the stopping point extends toward infinity. To account for this last term, I've added it onto the formula as shown here: s_{2}\left(x ight)+s_{2}\left(x-1 ight)+x\left(-1 ight)^{x-1} or alternatively s_{1}\left(x ight)+x\left(-1 ight)^{x-1} This extra term should be considered a part of s2+s2 now that they have the same stopping point, and this means that the sum is not equal to s1 anymore. Therefore any of the following conclusions drawn from this claim can no longer be considered valid either because 2 * s2 ≠ s1
@coreymagin
@coreymagin 10 жыл бұрын
How can you just average the stopping point and call that a solution? You should call that an average?
@thejordyoshi
@thejordyoshi 7 жыл бұрын
If 1+2+3+4+5...=-1/12, does that mean that 1>1+2+3...?
@captinobvious4705
@captinobvious4705 7 жыл бұрын
don't open pandora's box
@gioschrijver5683
@gioschrijver5683 7 жыл бұрын
Hold on... He is telling us that SOMETHING LESS then S = 3xS. For example S=5 (in my imaginary world) "something less then 5"=4. Then S = 3xS that means 3x5=15. does that mean 5=15?
@VicenteCamposMX
@VicenteCamposMX 7 жыл бұрын
Josh Yord yes
@sliceofgarlicbread6868
@sliceofgarlicbread6868 7 жыл бұрын
+josh Lord From a mathematical perspective that is wrong; from a physics perspective that is right.
@douggwyn9656
@douggwyn9656 7 жыл бұрын
It's wrong from a physics perspective too, as was appreciated by quantum field theorists in the 1960s, if not before. But they use the trick anyway, because they haven't figured out how to formulate their models so that singularities don't arise in the first place. If you could show how to avoid the divergences it is likely that you would win the Nobel prize in physics.
@collinbryant5081
@collinbryant5081 2 жыл бұрын
I've come up with a counterproof: For 1+2+3+4+...+n If 1+2=3, then 1+2+3+4+...+n>3 (where n>n-1) -1/12 is not greater than 3 Therefore 1+2+3+4+...+n=-1/12 is disproven.
@RaRa-eu9mw
@RaRa-eu9mw 2 жыл бұрын
Not quite. You've proven that the partial sum for any finite n>2 is greater than 3, not that the sum of the series itself is greater than 3. Similarly, if you consider 1/2+1/4+1/8... the partial sum up to the n-th term is less than 1, but the value of the series itself is not.
@Ither1
@Ither1 Жыл бұрын
What bothers me about this is that to get 1/2 and to get 1/4, you have to end the infinite sum, yet you can’t end the infinite sum of 1+2+3+4+…. Sounds like they’re using different rules for the different infinite sum…
@blakecarlson1057
@blakecarlson1057 7 жыл бұрын
I love how he says it's not a bunch of mathematical hocus pocus one second then says you have to do the mathematical hocus pocus in order to reach such a result.
@mrbdzz
@mrbdzz 7 жыл бұрын
Hocus pocus indeed. The fundamental problem here is that (1 - 1 + 1 - 1 + ... ) does not actually converge to 1/2 nor any other number. This is a classical case of applying a false statement, which allows one basically to get whatever as the end result. In this case, 1+2+3... = -1/12. BTW, 1+2+3+... does not converge either. However, this does not mean that the related physics are readily wrong. The Cesaro sum, which is a transfomation of the series, actually gives you 1/2. The cesaro sum gives correct limits for converging series, and limits for some non-converging series, too. But there are other transformations, which also yield correct limits for convergible series, but other limits than 1/2 for the 1-1+1-... series. If these things work in physics, it tells you that the physics are actually more related to the Cesaro sums (or other transformations) of these series instead of the series themselves. It wouldn't be the first time the physicists take little shortcuts in their math, but I think we can forgive them doing that if the end results match with experiments.
@douggwyn9656
@douggwyn9656 7 жыл бұрын
Note that the Cesaro sum for 1+2+3+4+... is infinite, so that series behaves even worse than 1-1+1-1+... Your point about the physics is valid: the original model that has been set up makes a bad prediction, and "regularization" amounts to a distributed smoothing procedure that "tames" the divergence. Why the particular procedure is adopted has to my knowledge never been clearly explained, other than by saying that it seems to "work". At the very least, better explanation is needed, or better yet, a model should be developed that doesn't yield infinity for what are physically finite quantities.
@Hasan...
@Hasan... 7 жыл бұрын
I thought the same too, but I tried with the other possible answers of: S1 = 1 - 1 + 1 - 1 + 1 .. and the answer has to be either 0 or 1, correct? But even if you take 0 or 1, and continue with the rest (with no more assumptions), you end up getting S = 1+2+3+4+5.. = either 0, or, -1/3 !! Try it out. Can you explain this?
@douggwyn9656
@douggwyn9656 7 жыл бұрын
The explanation could be that you can get a wide variety of different finite results by manipulating terms of a divergent series. None of them is "correct".
@dashpowers22
@dashpowers22 7 жыл бұрын
+Doug Gwyn is the real hero in this comment section.
@resistance7538
@resistance7538 6 жыл бұрын
According to riemann's rearrangement theorem; Infinity - infinity = (*any number*) Its just the way you rearrange the series...
@raudh1
@raudh1 6 жыл бұрын
According to the Riemann-Dini theorem *
@edbear94
@edbear94 6 жыл бұрын
It's also commonly infinity
@JorgetePanete
@JorgetePanete 6 жыл бұрын
Adeel all it's*
@prim16
@prim16 6 жыл бұрын
Exactly.
@JorgetePanete
@JorgetePanete 6 жыл бұрын
Adeel all It's*
@louismahon792
@louismahon792 2 жыл бұрын
This is what happens when you let physicists try to do maths
@crilillo1431
@crilillo1431 2 жыл бұрын
“This is not mathematical hocus pocus” “You have to do the mathematical hocus pocus to believe it”
@AnAverageRecon
@AnAverageRecon 10 жыл бұрын
There is no logical way you can get a NEGATIVE fraction from only adding positive numbers.
@j2kun
@j2kun 10 жыл бұрын
I have now had multiple friends ask me to explain to them why this video is wrong. I don't care much that you want to keep things informal and allow for casual fun maths. What bothers me about the video is that you're claiming this is unconditionally true (by the fallacy of authority), and that there's nothing deeper going on for people to read about when in fact there is and the particular proof given in this video is flat out wrong. It doesn't matter that the "result" is used in physics (physicists are well known to abuse mathematics because the "results" are interesting), or that there is a second video explaining things in more detail (though I don't think it goes far enough to make it clear where the line between truth and falsity was blurred in this video). What matters is that this video, standing by itself, is spreading massive amounts of misinformation. This is numberphile's blessing and its curse: it's so popular now, and has gained so much influence, that the majority of ignorant viewers (which is the vast majority of all viewers) take what is presented as gospel. You might say that's their problem for being ignorant and not questioning things, but I think it's also seriously dishonest to knowingly do such a thing. To think that mathematicians, who so rarely get as wide an audience as numberphile has, would knowingly lie about mathematics! I can hope it was more of a misunderstanding on the editor's part, but until I see evidence of that, this video has made me lose a lot of respect for numberphile.
@SpTh2
@SpTh2 6 жыл бұрын
They never claimed it is the undeniable truth. Numberphile isn't suitable for teaching people math, it's suitable for getting people to get interested in math. They did show the textbook that claims this and this series clearly has use when it comes to specific context and limits. You are being overly dramatic here by claiming they knowingly try to "fool" their viewers as the description of the channel itself simply states "videos about numbers", not "free PhD online, sign up now".
@hotpotato5587
@hotpotato5587 9 ай бұрын
A while back I learned what p-adic numbers are, and I’m starting to think this absolutely makes sense in a mathematical context.
@hydra314
@hydra314 2 жыл бұрын
can't believe 4 years has gone by and this is still ridiculous.
@michaelosborne9279
@michaelosborne9279 4 жыл бұрын
Is this how the financial crisis happened? Add together ever-stacking credit risk to get no credit risk? Note to investment bank CEOs, do not hire physicists.
@hdjdco5428
@hdjdco5428 3 жыл бұрын
No, they were making more money each day and ended up with negative money xd
@williamrosenbloom215
@williamrosenbloom215 3 жыл бұрын
It's funny because they actually love hiring physics majors
@francoiso
@francoiso 4 жыл бұрын
The golden rules to be adhered to when dealing with divergent series are: 1) Do not use brackets 2) Do not remove any zero 3) Do not shuffle around more than a finite number of terms
@rhythml6229
@rhythml6229 4 жыл бұрын
Francois O yah this video is definitely miss leading
@AbCd-zo5tb
@AbCd-zo5tb 4 жыл бұрын
Thankuee sir
@Mecal21
@Mecal21 4 жыл бұрын
Yeah, I came here from another video saying that they're wrong so I came here to see if people know
@aadithyahrudhay2269
@aadithyahrudhay2269 4 жыл бұрын
I love you so much right now.
@farrel_ra
@farrel_ra 4 жыл бұрын
But we need to converge this divergent series into concrete number so it can be used in string theory..that's why that result came up. I mean, jokes aside, dont take this video "mathematically". What Numberphile did in this video is explaining things about number in Physic fields, not Mathematic. Because in mathematic, u have infinity as a concept, while in Physic, u dont know about infinity.
@timelsen2236
@timelsen2236 Жыл бұрын
S2=1/4 can be done directly as a 4 term partial sum average on even term sums and odd term sums giving 1/4[ ( n-n)+(-m+m+1) ] =1/4 as a variety average of types.
@MichaelClark-uw7ex
@MichaelClark-uw7ex Жыл бұрын
The law of whole numbers says that whole numbers are closed for addition and multiplication. Which means that the sum or product of 2 or more whole numbers is always a whole number. There is also a rule that states that the sum of 2 or more positive integers is always a positive integer.
@PARAMONARIOS
@PARAMONARIOS Жыл бұрын
all the people who accepted that guy's proof (sum = - 1/12), are the same type of people who fell for Ponzi scheme, Madoff scheme etc.
@ignacioarroyo3385
@ignacioarroyo3385 Жыл бұрын
This reasoning cannot be applied to infinite series. One counterexample would be arguing that the sum over 1/n^2 (from 1 to infinity) must be rational because Q is closed under addition.
@adryanus9
@adryanus9 10 жыл бұрын
i'm just astonished how a infinite sum of positive numbers is a negative number, and people act like it is physicaly possible... i bet it happens in "theoretical physics", that is still unproven and higly theorectical, it might explain everything, or it might just be wrong as everything... i have a really low education in maths, but an infinite sum of a alternating series, doesnt converge to a number, is diverging, and certainly not 1/2
@FragMentEditing
@FragMentEditing 10 жыл бұрын
I don't think everyone in these comments realizes that they're using averages, since those sequences don't have an actual sum.
@darkspace5762
@darkspace5762 7 ай бұрын
I wouldn't think that the first sum equals 1/2. I would just think it was undefined.
@DoppeD
@DoppeD 5 ай бұрын
It is, under normal summation. They are using Cesàro summation.
@jakupi268
@jakupi268 4 ай бұрын
@@DoppeDcan never equal half tho can it
@the_eternal_student
@the_eternal_student 6 ай бұрын
If i understood this correctly, 3 Blue 1 brown provided a better explanation of this. The sum is not -1/12 except when you modify it to fit the context of providing symmetry for the Riemann hypothesis; it is a modification.
@filipgagacev6697
@filipgagacev6697 4 жыл бұрын
This video is like that episode of fairly odd parents where timmy got a mathematician to prove to his teacher that 2+2=5
@trevinbeattie4888
@trevinbeattie4888 3 жыл бұрын
That equation is obviously true … for large values of 2 and small values of 5. ;)
@Bruno_Noobador
@Bruno_Noobador 3 жыл бұрын
@@trevinbeattie4888 (QED)
@alan137
@alan137 3 жыл бұрын
That mathematician was Stephen Hawking, a physicist 😄
@Wyvern07_
@Wyvern07_ 7 жыл бұрын
So by only adding positive numbers you get a negative number?
@kevinwilbert3966
@kevinwilbert3966 7 жыл бұрын
unintuitively yes
@Zenmuron3
@Zenmuron3 7 жыл бұрын
--Wyvern07-- of course not. There are thousands of ways to disprove this silly video
@Zenmuron3
@Zenmuron3 7 жыл бұрын
Avana Sure. The series created by n, where n is a natural number, is a divergent series because the sequence of partial sums, Sn = n = {1, 2, 3, 4, ...} is a divergent sequence. Proof: Let Sn be the sequence of partial sums of the series of n. Let M be any natural number. Let N be M + 1 (The smallest natural number larger than M). Then for any n > N, we have Sn = n > N > M. Thus this sequence is unbounded and increasing (increasing is easily proven using induction). Thus this sequence is divergent to infinity. By definition, the sequence of partial sums Sn is divergent if and only if the series created by n is divergent. I don't want everything you own, I would rather have you learn real mathematics. Do not believe what you watch "smart" people say and do, PROVE IT your self!
@Zenmuron3
@Zenmuron3 7 жыл бұрын
When you read mathematical proofs, as a reader you look to break the logic. When I say, for example, "let M be any natural number" you are supposed to try to find a "M" (natural number) that will be a counter example to my argument. However, when I say "let Sn be the sequence of partial sums" you are not able to change this because this is from the definition for what a series (or sum of all) is. Your question is slightly confusing me, but I think I understand. My argument is quite the opposite of "random" and is in-fact very precise. There's a reason why I chose everything the way it is, and it's because it works logically. The reason why he can't use "a random string" to solve the equation "with that" is because this equation has no solution because it is a divergent series (diverges to infinity, obviously). If numbers and mathematics really fascinates you, then it's better to read actual mathematical documents and literature.
@sandraviknander7898
@sandraviknander7898 7 жыл бұрын
The thing is that, this isn't a mathematical result much less a mathematical proof it's more of a physical definition made becaus it works to describe certain physical phenominon. This video realy should have ben uploaded to sixtysymbols instead of numberfiles.
@jhg8464
@jhg8464 Жыл бұрын
first mistake he made here was assuming any arrangement of natural numbers summed up gives you unnatural numbers
@arthurchase7716
@arthurchase7716 11 ай бұрын
problem 1: there was no test for convergence. one of the first things taught when you learn to evaluate infinite sums is that you have to test for convergence. this sum does not converge, it just goes to infinity. so, even if you find tricks like this to solve it, it will not converge 1.1: even if this sum converged, this all hinges on the fact that 1+1-1… converges. which it doesn’t. it oscillates, which means it does not converge 2. you can’t displace an infinite amount of terms when you add together 2 series like this. when you “stretch out” one series and add it to the other, it will not have the same value as before
@IronicTB
@IronicTB 8 жыл бұрын
2,818 people think they're smarter than the majority of mathematicians and scientists.
@TheRemixDenuo
@TheRemixDenuo 8 жыл бұрын
IronicTB -1/12=sum(n) from 1 to inf =1 + sum(n) from 2 to inf =1 + sum(n+1) from 1 to inf => sum(n+1) from 1 to inf = -13/12 => sum(n+1) from 1 to inf - sum(n) from 1 to inf = -13/12 - (-1/12) => -1 = sum(n+1) from 1 to inf - sum(n) from 1 to inf = -1 = sum(1) from 1 to inf = -1 + sum(1) from 0 to inf => 0 = sum(1) from 0 to inf = sum(1) from 1 to inf = 1 but 0 = 1 cant be true no matter what.
@dhmdm3106
@dhmdm3106 8 жыл бұрын
IronicTB The "majority" of scientists is 2 people?
@IronicTB
@IronicTB 8 жыл бұрын
DHMdM I can assure you that quite a lot of important people agree with the two people in this video.
@dhmdm3106
@dhmdm3106 8 жыл бұрын
IronicTB Such as...? (by the way, ever heard of 'appeal to authority'?)
@dhmdm3106
@dhmdm3106 8 жыл бұрын
First, It is NOWHERE mentioned in the book that the sum of all natural numbers is equal to -1/12. Go to the part where he shows the book and look closely. It's an ARROW, not an equal sign. And yes, it does make a difference! Second, most mathematicians would probably feel uncomfortable with the proof presented in the video. Notations are not well defined, false assumptions/contexts are made at the beginning (for example just assuming 1-1+1-1+...=1/2 even though it's a divergent series) etc. Third, I don't know much about string theory, but I do know enough about the mathematics involved in the video. I know about the zeta function, about analytic continuation and Ramanujan summation. And by that I mean I didn't just read the Wikipedia page, I actually studied these topics in depth. I don't know about your mathematical background (maybe you can tell me), but If you want I can point out what's wrong with the methods used in the video and explain some of the background to shed some light on it.
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