In this video we will design an automatic battery cutoff circuit to prevent damaging over discharge of rechargeable batteries.
Пікірлер: 16
@BenMitro4 жыл бұрын
That was quite descriptive, thanks. One can incorporate reverse voltage protection in place of the shottky diode as you have the P channel fet in place already to reduce power losses and heat even further, with a diode and a resistor between outputs (Vcc and GND) to the gate of the n-channel fet **I think** would do it - though, it will need a bit more thought than this (maybe a second n-fet?) in order to keep the power consumption during low battery condition to a minimum as the current circuit does already.
@murilofreire4 жыл бұрын
Great job! If we have any solution to deal with voltage regulator draining battery... It would be great too!
@avejst3 жыл бұрын
Hm. Both MOS-fets is N-channel in the diagram. But I understand the diagram. I couldn't find a P-channel MOS-Fet in Eagle ether.... Thanks for sharing.
@6c1212 жыл бұрын
Thanks a ton for this video. Personally I'm gonna use a XC61CN voltage detector, PMOS AO3401A and NMOS BSS138. I noticed you use a 5Mohm resistor. If I understand correctly, when this is fed to the NMOS it's going to charge the input capacitance of the NMOS anyway, so a big resistor shouldn't be a problem? All the best! Thanks again
@ForceTronics2 жыл бұрын
Glad the video was useful. Yeah you got it, 5Mohm resistor serves as a pullup unless the cutoff is triggered. High value is chosen to reduce current flow as much as possible with the pullup function still working. You can play with higher values to see if they do the job and further reduce current flow from the battery
@galinjm2 жыл бұрын
Nice explanation, can this circuit be modified to monitor a 144 volt battery to shut down at approximately 90voltd?
@ForceTronics2 жыл бұрын
I am sure it could be. Just need to setup the right resistor divider network. My videos are meant to be examples that others can modify to fit their application
@Jan-gj8bm18 күн бұрын
Great videos man, juat curious why you use one mosfet to control another instead of just using an nchanel mosfet and the high signal to open it
@ForceTronics17 күн бұрын
Thanks for the comment. N channel MOSFETs are better used as low side switches. An N MOSFET does not just turn on with a "high" on the gate. The gate has to be higher in potential than source. For instance if the source has 10v on it then gate needs like >12v to turn on. Hope that makes sense
@Jan-gj8bm11 күн бұрын
@@ForceTronics that makes a lot of sense and im designing a circuit using information from your video! thanks for the great explanations
@Jan-gj8bm10 күн бұрын
@@ForceTronics what would you think about increasing R1 to a much higher value? For my circuit 100k is 1.7ms vs 4.7M is .08s on time which is much slower but that way we limit the current loss even more through the NPN mosfet
@nmf500310 күн бұрын
You can use any resistor value you want. Just need to make sure enough current is getting to the gate of the mosfet to turn it on. @@Jan-gj8bm
@UmairAhmadh4 жыл бұрын
Waiting for the part 2
@Reach3DPrinters3 жыл бұрын
Part 2 is available
@abdular85812 жыл бұрын
Hello how can I order the circuit please
@ForceTronics2 жыл бұрын
It is not profitable enough for me to build and sell these circuits. We provide the video free to help you design your own. If you want ForceTronics to design a custom one for you go to our website and fill out a request. We charge $90 US per hour for design work