20 mins before my midterm exam... Why didn't I look this up before?

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This was awesome! I just spent $40 on a tutor who couldn't explain this an hour and you did it free in 9 minutes and 53 seconds! Thank you!

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It's 2 days to my CHM 101 exam and I can't explain how much this helped DUDE!!!!👍🏾

I had to drop chem because I was really struggling and I just watched this video and this topic suddenly makes sense. You’re a life saver

An important consideration to be made: This approach works when the acids or bases are strong. However, it is not valid for weak acids since they do not dissociate completely. Hence, one must use the Ka to calculate the concentration of hydrogen ions. This is relevant for some of the examples in the video, namely the second dissociation of sulfuric acid and the three dissociation steps of phosphoric acid, each one weaker than the previous one. Keep this in mind and check other videos to complement the information.

You rock dude! That was one of the most enjoyable lessons I've ever had. Thanks!

This guy's is a genius ... helped me out during 2022 online classes era🤣

Dude, thank you so much! My teacher made this so complicated but thanks to you I get it now!! :D

This was AMAZE-BALLS. Dude, you have just saved my midterm. Thank you so much!!!

This so awesome! I've been trying to wrap my head around the way my biochemistry teacher explains this all semester (exam is today!!!) and now I finally get it! Thank you!!

My college chem professor made this seem more difficult than what it really is. Thanks so much dude!

I skipped last weeks class and this video really helped. Thanks!

This made me laugh and concentrate. I hope my professors are like this

Thank you so much! This is going to be one of the problems on my chemistry exam tomorrow and I finally understand! :)

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Wow he actually explains the mechanics behind the equation. Thanks dude!

Your explanations have been amazingly simple and clear to follow. Thank you so much for making your videos.

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taught me more in 5 minutes then my chem teacher did in 2 weeks

"Plug and chug", haha that had me laughing

Hey Dude ! What a wonderful, smooth explanation better than a thousand professor

thanks so much! im having a chemistry test tomorrow and i actually understand something for once!!!

Dude, you make it so easy. It was very helpful thanks

On the uni computers but thought I’d go on my phone since I have an account on here to give you a like and thank you very much for your teaching and enthusiasm. Cheers!

Thanks I was falling out like big times in this chapter and I'm finally starting to understand and the fact that we have to use log books makes it even harder 😅

Thanks for this. It really helped me with my chemistry work

i don't understand how you got 4.82 from 1.4x10^-5. i am not allowed to use a calculator

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I don't care if he keeps on repeating Dude. The importance is his teaching and he is doing that very well and very clearly.

Omg after trying to figure out how to calculate pH values I understand now lol thanks so much for your help ♥

thank you so much this video literally saved me so much confusion!! you made it so simple and easy to understand THANK YOU

the best video on pH out there!! got that surfer dude teacher vibe going for you

thanks dude if i fail ill find you

Thank you so much you are 100 times a better teacher then mine.

To use the scientific calculator for this, do as follows: 1st- push the "log" button. If it doesn't automatically add the open bracket, hit the "(" button and then punch in the numbers. E.g.- 1.2x10 to the -3, but, you do 1.2 then hit the "Exp" button and then the "(-)" button then the 3 and close the bracket ")" and hit exe or the = button.

Hi thanks for the good explaining. Been watching a lot of vids here about solving pH concerning with Molarity but no one could explain it to me better than you!

Thank you so much for your video! No one could explain it so well as you did. Now it became super easy to calculate pH! woooooohoooooo!

Thanks so much! really understand way more clearly now! :) It was really fun doing the practise questions and waiting to see the answers.

this guy is a freaking god. love your laid back style man :) thanks so much :)

Thank you so so much I needed this for my medical school entrance exam and I forgot about it

This a great teaching method you have here sir, very easy to follow and understand. Thank you.

Love your explanations. Total clarity!!!! Saweet!!

This was so helpful for my final on Monday!

Thank you! This was so helpful! God bless!

i swear on god i went all across the internet to find a clear video an here it is bonus: the guy is super funny 10/10 folks

Can we find the pH if we're given Normality or Molality?.... And if so how does one solve it?

Hey dude just wanted to say keep up the great work :)

Thanks dude it's really helpful 🙏 I'm preparing for the end of term STEM Exams and the explanations are pretty good so I really appreciate that explanation of yours. Thanks a lot ❤🙏

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Thank you! You've earned a like and a new subscriber.

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DUDES

Awesome explanation bro, even a five year old would get this. keep it up

Thank you so much. This is very helpful. Just want question though how would do them if you are not allowed to use a calculator ?

It saves me from my modular class during COVID pandemic ..I'm suck at solving.. Specially with no Instructors guiding or teaching me.. 😅

Thank you Thank you Thank you lol.... you made it so much easier to understand.... now I just realize I was over thinking this the whole time :)

1:53 does this rule also apply to bases, please reply fast my test is tomorrow

My chem teacher sucks, he rushes the whole class into learning one unit so we can fit the quiz this week.. also thanks for the video!

I love this! Had some good laughs and smiled because I understand it completely. Thank You and rock on! ^_^

Thanks dude! :)

thank you!! really helped a lot, im in med school and completely forgot how to calculate for ph but it jumped back fast after this vid :)

you are an amazing teacher well explained

Isn't -log(1.4 * 10^-5) = 4.853871964 with significant figure and rounding rules would be 4.8? I was taught for rounding that if the rounding number was even and the number after that was a 5 you don't change it but if the rounding number is odd, you round up. That's why I didn't say 4.9.

I'm 4 years late but this helped me man god blessss

Groovy lesson dude, now let's calculate the pH of an acid that we are going to groove to;)

I really appreciate this video dude

This is awesome - thanks!

Wonderful tutorial. Got to brush up on log calculations.

One thing about you is that you do know how to motivate :) thanks... @9:53, I was all the way with the program :)

Ahhh thank you!! You saved me BIG TIME 💜

Wow soo nice... I have missed my chemistry class but this video helps me to clear this topic.. Thanks...

Thank you so much..!! For explaining this question in easy way...

THANK YOU BROTHER FOR THIS, VERY HELPFUL

Wouldn't you put an absolute value sign for the pH formula to make sure that your final answer is always positive?

When I first take this lesson I was just thinking "why do we use logarthims?!" After I study general chemistry I realized that scientists found the concentration of H+ is really small numbers so its really hard to deal with most of the concentration where like 1×10^-4 etc.. so they just use log to deal with the normal numbers we know like 1 23 just like convert from hard numbers to easy numbers and that make sense to me ! Math is every where😁

The dude thing is crazy, but remember on your problems to use proper number of sig figs. It wouldn't be 4.85 for a pH if the problem is giving you 1.4 M. You have two use two sig figs and round up to 4.9.

You really ROCKED .....thanks dude

@ sciencepost I have a question about the solution. Since it got added to water, and water in itself already has a concentration of Hydronium at equilibrium, shouldn't we add the dissociated Hydrogens from HCL to the amount of Hydronium already in the water?

Do you think it should be round to significant figures?. For example. pH=-log(1.4x10-5)= 4.9 because 1.4 is 2 figures. Your answer is 4.85. Your answer is 3 figures.

totally radical tutorial man.

thanks, easy to understand explaining!!

i love your take on this man :)

This was uploaded on my birthday :)

So are the molarity and the concentration of the H+ ion the same with strong acids with 100% disassociation?

What if with 0.002M of H2SO4.how to find it when Molarity comes like this

Thanks lad, learned a few new things 🤙

#sciencepost make studies interesting.....like here👍🏼

Thank you so much! I will for surely rock my next test!! :))

How do you find H+?

How about finding the mole when the liter and ph is given

This was very helpful, thank you

What about weak acids???

I like this guy.