Can You Solve The Three 3s Challenge?

Рет қаралды 2,083,463

5 жыл бұрын

Thanks to Yale from Hong Kong for suggesting this problem! This problem went viral after Carl Ho's video (in Chinese), and there are many fun ways to solve it. My challenge is: find two answers to 3 3 3 = 10 using only the symbols + ! ( ). There is a way you can do this!
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Пікірлер: 5 700

@CarlHoHK 5 жыл бұрын

Glad to see my question in this channel :D and yes, the "subfactorial" should be the better way to solve =10 question.

@MindYourDecisions 5 жыл бұрын

Thanks! I encourage everyone to watch the video on Carl Ho's channel, you'll definitely enjoy it: kzfaq.info/get/bejne/bMeTdbCWlbvLqWw.html And here's another clever solution to the bonus, which was emailed to me: !(!3 + !3) + !(!3) = 10. This solution breaks down as !(!3 + !3) + !(!3) = !(2 + 2) + !(2) = !4 + !2 = 9 + 1 = 10. (But please don't email me any more as I get too many emails!)

@gourmet_salad 5 жыл бұрын

i found two simple ways: 3.3(repeating) *3 = 10 3*3 + Floor function of sqrt(3) = 10

@barontau6552 5 жыл бұрын

(3+3+3)++ = 10

@Toddchanw 5 жыл бұрын

hi 卡爾

@shams24aks 5 жыл бұрын

3square + (3/3). (3 cube +3)/3.

@arjunck07 3 жыл бұрын

Arjun(3+3+3) = 10 Arjun is a function created by me which adds 1 to the result

@SlipperyYayas 3 жыл бұрын

I feel like that’s cheating. That function doesn’t even exist, and makes no sense whatsoever.

@thepanthar 3 жыл бұрын

@@SlipperyYayas Its a joke.

@SlipperyYayas 3 жыл бұрын

@@thepanthar It doesn't feel like a joke honestly

@mattmartin7028 3 жыл бұрын

@@SlipperyYayas lmao its obviously a joke

@petr9516 3 жыл бұрын

function Arjun(value) { return value+1; } ... now it exists

@nasekiller 5 жыл бұрын

the only hard thing about the bonus is knowing that subfactorial exists, lol.

@mohamedaminekhadhraoui6417 4 жыл бұрын

Ive never heard of it either. Does it have any practical use anyway?

@jamieducator 4 жыл бұрын

Same is here

@mihirkarwani8891 4 жыл бұрын

I have never even heard of FACTORIAL

@eriknystrom5839 3 жыл бұрын

I have a Masters in Physics, so I know what factorial is, but I have never ever heard about subfactorials.....

@nasekiller 3 жыл бұрын

@@eriknystrom5839 you dont really need a master in physics to know about factorials though

@Buttered.Coffee 2 жыл бұрын

When you were showing alternate solutions for 0-9, I saw a decimal point being used for 7 and I realized an easy way to do 10 is: (3! - 3) / .3 = 10

@arhonvalran1551 2 жыл бұрын

I had this same. Until then, I assumed that the use of the dot itself is not allowed, because I would have to add 0 in front.

@joelpazvalladolid3418 2 жыл бұрын

√3*√3/.3=10

@icoczolc7276 2 жыл бұрын

3!/(.3+.3)=10

@MultiChrisjb Жыл бұрын

Yeah I guess they were being pretty slack with rules for this one. The arctan solution is a stretch too, it needs to be equal to 10 not 10 degrees. Then they started using floor functions, then I rage quit. I mean I may as well make up an arbitrary function and use it. eg f(x) = 10, so f(3+3+3) =10. and done. Also I didn't think bit shifting was a mathematical operator...

@3946520 Жыл бұрын

(3! - 3) /3 = 1+0

@lordrindfleisch1584 2 жыл бұрын

The derivative solution for 10 was really cool

@amit_bisht 5 жыл бұрын

Easy! (3+3+3)++ = 10 As notation used by programmers seems to be acceptable.

@riccardospolaor9294 5 жыл бұрын

++(3+3+3) or else it will become 10 but still give you 9

@paparocks7122 5 жыл бұрын

He hav to use pre increment .

@mnfen9792 4 жыл бұрын

programmers: 333 != 10

@argus456 4 жыл бұрын

@@mnfen9792 Webprogrammers, maybe

@dearalzghoul4760 4 жыл бұрын

The U.S. 5

@SebastienPatriote 3 жыл бұрын

3.3 repeating (use a bar on top of the second three) multiplied by 3. 3.3....×3=10

@deept3215 3 жыл бұрын

This is more satisfying than any of the proposed solutions tbh

@hafizhperdana 3 жыл бұрын

Yes, you genius hahaha

@hafizhperdana 3 жыл бұрын

But you only can use + ! and (), not .....

@SebastienPatriote 3 жыл бұрын

@@hafizhperdana Well that was for the "Super hard bonus" rules. I'm offering a simpler solution.

@barrymidkiff175 3 жыл бұрын

It doesn't equal 10. It comes as close as possible to 10 without being 10. 33/3 does equal 10.

@taglolxd 2 жыл бұрын

Use the zero power. Anything to the power of zero always equals one, so you can just do 3 x 3 + 3º and 3º equals 1

@Ashbakhaaz 29 күн бұрын

You can't use other digits than 3, and 0 is a digit

@Spax5 10 ай бұрын

No rules specifically mentioned about adding operations to the right side of the equal sign: (( 3 - 3 )/ 3 )! = log(10) Also allows for other neat stuff such as: ( 3 + 3 )!/ 3 ! = 5!

@BubblewrapMe 3 жыл бұрын

I don’t think casually changing 3 to 0.3 in one of your solutions is acceptable.

@PavelSTL 3 жыл бұрын

I agree. I would go even further and say applying arbitrary functions like arctan is cheating as well. What stops me from defining a function such that it transforms 3 to whatever I want, and then applying that function. 3 should remain as 3 and then use a given set of operators to relate those 3's to produce a given number.

@gagan00 3 жыл бұрын

By changing 3 → .3 3! /(.3+.3) =10 Lol😆😆😆

@cdemr 3 жыл бұрын

@@PavelSTL It's certainly because I'm not native speaker but your sentence "What stops me from defining a function such that it transforms 3 to whatever I want, and then applying that function." doesn't make any sense.

@cdemr 3 жыл бұрын

@@PavelSTL Oh ok thank you I understand now

@TheGrapeApe22 3 жыл бұрын

Yea... if it was, I would do sqrt(3×3)/.3 = 10

@abysslight2490 5 жыл бұрын

I definitely think using a decimal point as an operator is definitely cheating. .3 is not an operator acting upon 3, it is simply a different number. You can make a similar case for 3% as well, it is simply a different number.

@lh1690 4 жыл бұрын

And rounding just stinks.

@prsh9610 4 жыл бұрын

Exactly.. I lost interest due to this twisting..

@rayane--21pilots8 4 жыл бұрын

Smart ^^

@josepherhardt164 4 жыл бұрын

Though I will say that using a decimal point is the least egregious of various ploys that I've seen. E.g., to do 11 = 33 / 3, you're concatenating two 3's together to form 33. Is that allowed? You could also do 11 = 3 x 3 + Γ(3).

@Shadow-dv1fy 4 жыл бұрын

3! is 6 so it’s a different number it doesn’t worj

@samloose7526 9 ай бұрын

The solution for 10 really baffled me as I didn't know about subfactorial, but a great new thing to have learnt! Thanks :)

@sharifikiasmethodsinmathem5914 2 жыл бұрын

The other eleven relationships are: ☆ncr(3!-sgn(3) ,3)=10 3×3+sgn(3)=10 3!+3+[Ln3]=10 3×3+[arcsec3]=10 [Ln(3+3)^3!]=10 ((The symbol [ ] is the correct bracket or component function.)) Also, the following six relations are based on the number of divisors of the numbers: 3!+d(3^3)=10 d(3^(3×3))=10 3^d(3)+sgn(3)=10 (3!-sgn(3))×d(3)=10 ncr(3!,3)÷d(3)=10 npr(3!,d(3))÷3=10 In the above relations, d(n) is the number of divisors for natural number, n. We begin by writing the number as a product of prime factors: n = p^a× q^b× r^c... then the number of divisors, d(n) = (a+1)(b+1)(c+1)... To prove this, we first consider numbers of the form, n = p^a. The divisors are 1, p, p^2, ..., pa; that is, d(p^a)=a+1. According to the law, we must act in such a way that we only use the number 3, 3 times, and therefore we can not use decimal, non-3 and radical power, which is a kind of power.

@yasseindahshan3556 Жыл бұрын

you forgot this -> (3! - 3) / .3 = 10 and these -> 3 x 3. ͞3 = 10 -> (3/3)^3 = (1+0) -> Finally only using : + ( ) . . . . . . 3 = (1)(0)(3)+3) Thank me later.

@thuglife1219 Жыл бұрын

Who asked?

@freerobux49 5 ай бұрын

@@thuglife1219 i did

@davidhutagaol4860 3 жыл бұрын

who else didn't know the term subfactorial exist until this day?

@naveen2992 3 жыл бұрын

I knew

@davidreich2433 3 жыл бұрын

I do not understand!

@JV-pq3qn 3 жыл бұрын

I didn't and I still don't

@robinvsdk 3 жыл бұрын

I didn't knew about ! in the first place, but it's actually very simple

@mincento 3 жыл бұрын

ME! Didn't even know 'factorial' until today... got 3! + 3! - !3 = 10 after the 'sub' revelation. Loving these videos

@Me-da-Ghost 3 жыл бұрын

For "0", you could just do (3 - 3) * 3.

@PlanesAndGames732 3 жыл бұрын

or (3-3)/3 too

@user-hf6vy8xc4i 3 жыл бұрын

-3+3x3

@PlanesAndGames732 3 жыл бұрын

@@user-hf6vy8xc4i No cuz that is -3+9=6

@user-hf6vy8xc4i 3 жыл бұрын

@@PlanesAndGames732 ok (-3+3)x3?

@PlanesAndGames732 3 жыл бұрын

@@user-hf6vy8xc4i makes sense

@adamlord1891 2 жыл бұрын

For a non-super-hard bonus expression to produce 10, I came up with the following that uses the ceiling function instead of the floor function: ceil(sqrt(33*3)) = ceil(sqrt(99)) = ceil(9.9498...) = 10

@Mike-rw1jw Жыл бұрын

floor(33/3) = 10

@tolipydob 2 жыл бұрын

If we follow the convention used for hexadecimal number representation but use base twenty seven then 3 ( 3 ( 3 ) ) = 10 or 3 * 3 * 3 = 10 In base nine, 3 + 3 + 3 = 10 If we are already shifting bits in previously displayed examples, we can also choose to not limit ourselves to 10(base two) numbering systems. 10 has a disguise for every day of the week.

@fuzzymandrake 6 ай бұрын

I mean, you don't *need* to shift bits for any of 0 thru 10 3! - 3 - 3 = 0 3! / (3 + 3) = 1 3 - 3 / 3 = 2 3 - 3 + 3 = 3 3 + 3 / 3 = 4 3! - 3 / 3 = 5 3 - 3 + 3! = 6 3 / 3 + 3! = 7 (3! / 3) ^ 3 = 8 3 + 3 + 3 = 9 !(!3) + 3(3) = 10 I don't think that change of base is fair because you need to (rather, ought to) write in your bases as a subscript

@TyTheRegularMan 3 жыл бұрын

I was expecting double factorial, so I found this: (3!)!! = 6!! = 6*4*2 = 48 ((3!)!!)/3 = 16 ((3!)!!)/3 - 3! = 16 - 6 = 10

@chiahow 3 жыл бұрын

genius

@brucefrykman8295 3 жыл бұрын

You found a solution following the rules, congrats

@jeffersonpaesdefariasfilho 3 жыл бұрын

This is the best way to solve the problem, congratulations!! Nice search man

@djamila9804 3 жыл бұрын

Better than Yale, congrats!

@alibabapirce9782 3 жыл бұрын

its old but maby somehow you end up reading it. you can do !(3+3+!3)=10

@Inspirator_AG112 9 ай бұрын

*@[**04:35**]:* For malicious compliers... • round(exp(3)) ÷ (3!) × 3 • superfactorial(3) - 3! / 3 • 3! + round(exp(3!) / hyperfactorial(3)) • √(hyperfactorial(3) - (round(√3))³)

@Inspirator_AG112 9 ай бұрын

Another one: round(exp(-ln(ln(3) - 3 ÷ 3)))

@venomxhawk8427 2 жыл бұрын

Thanks for letting us know about subfactorials! I'm sure its gonna help me in the future!

@rayzen119 Жыл бұрын

Dude.. i'm 1 year from the future and it's still useless. 😥

@pierre1069. 4 күн бұрын

Dude I'm 2 yrs from the future and it's still useless 😢

@jarlfenrir 3 жыл бұрын

3*3+sgn(3) = 10 Simple and elegant. Since we can use arctan, using signum fucntion should also be allowed.

@lucasmartiniano6915 2 жыл бұрын

nicely found!

@jarlfenrir 2 жыл бұрын

@@lucasmartiniano6915 Thank you.

@Yerflua 3 жыл бұрын

Old memes: on the Pentium, 3+3+3 = 10 for very large values of 3

@maiaallman4635 3 жыл бұрын

The good old days, when you were the envy of the engineering class when you had a brand new Pentium.

@theUberduckMashups Жыл бұрын

If we're going the CS method (and he did set the precedent with the

@vineetsharma0124 Жыл бұрын

Using double factorial, another solution can be attained for 3,3,3 = 10: (3!)!! / 3 - 3! ! is obviously the product down towards 1 (ex, 4! = 4*3*2*1) ! is the product of the integers from n to 1 with the same parity (ex, 5!! = 5 * 3 * 1 and 6!! = 6 * 4 * 2) Therefore, 3! = 6, and 6!! = 6 * 4 * 2 = 48 So 48 / 3 - 6 = 10 :)

@RedIceberg Жыл бұрын

At that point, you may as well do: (3!)! / (3!)!!!! / 3! = 10. (An N-th factorial does n(n-N)(n-2N)... until it becomes less than 1)

@user-kh5tv9rb6y 5 жыл бұрын

The set of allowed operators really should've been defined before asking for solutions. The subfactorial thing for 10 makes it seems like it was a trick question. Everyone knows ! as the factorial, and hardly anyone knows about the subfactorial, so those who do might think you only mean to use that factorial. Hell, without a defined set of operations, I could define my own operation ? that just brings everything to 10: 3?+3-3=10. Done!

@eduardofernandes7889 5 жыл бұрын

I mean, because of comments like yours I can learn some new set of operations, so I think it's valid to not define it beforehand

@darreljones8645 5 жыл бұрын

I was a math major in college, and I never once saw (!n) used for subfactorial n as defined in this video.

@cadias 5 жыл бұрын

You just defined the Termial operation en.wikipedia.org/wiki/Termial

@cadias 5 жыл бұрын

And you also can use it as well!

@SuperDreamliner787 5 жыл бұрын

Damn man, you killed me with that 3?

@plavyn 5 жыл бұрын

Why do none of the 10 solution seem satisfying

@Themonkeymartin 4 жыл бұрын

Yeah they seem like cheating

@carlospereyra6144 4 жыл бұрын

Try 3²+3/3

@faraonzeu9462 4 жыл бұрын

Here is one satisfiyng 3(at power 2)+3÷3=10

@Themonkeymartin 4 жыл бұрын

@@carlospereyra6144 you cant just add the number 2

@mackan2277 4 жыл бұрын

try ceiling(33 x .3)

@snaketail114 2 жыл бұрын

One 3 equations: 0=!(!(!3)) 1=!(!3) 2=!3 3=3 (Radians) 4=ceil(sqrt((3!)!°) (°) 5=floor(sqrt(tan(acos(3%)))) 6=3! 7=floor((3!)!%) (°) 8=floor(sqrt(atan(3))) (°) 9=ceil(sqrt(atan(3))) I will think of more And you could just use ++ to add one. Also would doing -bit-wisenot(x)=x+1 or -infinity?

@Luroux 7 ай бұрын

Here's my solution for 3 3 3 = 10: (3!)!!/3 - 3! I personally doesn't like it that much because the double factorial is a rather uncommon operation. (Btw it means that if the number is even then: n!! = 2 * 4* 6 * ... * n , so you multiply all even numbers until n and if it is odd then: n!! = 1 * 3 * 5 * ... * n , so you multiply all odd numbers until n)

@100carlosfermin 3 жыл бұрын

At the beginning of the video, the instructions say: “Make each equation true using mathematical operations”. So I just did: 3! / (3+3) = 1+0 Hahahahahaha

@HL-fv7rp 3 жыл бұрын

nice

@enes-di6uw 3 жыл бұрын

300IQ

@epigone1796 3 жыл бұрын

3 3 3 != 10 Ez

@mk_rexx 3 жыл бұрын

Of course that's not allowed, but you gave me an idea if we are allowed to add symbols on the otber side. 3+3-3 = [[√10]] because √10 is close to three

@AttachmentStudios 3 жыл бұрын

Cheating :/ EDIT: But Smart

@pibb2474 3 жыл бұрын

My immediate thought was (3 x 3) + (3^0) = 10. I wasn't sure if using "to the power of 0" was a legal move, so I watched the video.

@daneshjunior3387 3 жыл бұрын

i think one of the rules of the challenge was that we cant introduce a new number (0)

@pibb2474 3 жыл бұрын

@@daneshjunior3387 Oh, I know my "solution" doesn't actually work. I just thought my fellow math-minded viewers would appreciate my thought process.

@daneshjunior3387 3 жыл бұрын

@@pibb2474 understandable, have a great day

@suriya8857 3 жыл бұрын

@@daneshjunior3387 however the square root function technically introduces the 1/2 number

@Kettwiesel25 2 жыл бұрын

@@suriya8857 well you don't write it out though. Maybe taking the square root an infinite number of times could introduce ^0 though similarly.

@IceAngel Жыл бұрын

I haven't ever known the !number before. I only knew number!, so this was soooo helpful. Thanks for this video!

@SeegalMasterPlayz 2 жыл бұрын

3! + 3! - 3! = 6 Edit: Another solution for the above is (3(3/3))! = 0 Another solution for 3 3 3 = 0 is 3(3-3) = 0

@Arob4343 4 жыл бұрын

Glad to learn that “!” Can be used another way

@Thebiggestgordon 3 жыл бұрын

Have you heard of double factorial? Yet another way to use the ! symbol, double factorial is the product of every other number below it. So 6!! is 6x4x2 = 48. This creates the solution: 10=(3!)!!/3 - 3! =6!!/3 - 6 =48/3 - 6 =16-6 =10

@shawnreinerdavid6848 3 жыл бұрын

English: Exclamation mark Math: Factorial

@hellothere-sf1gl 3 жыл бұрын

@@Thebiggestgordon no, but good to know

@paulembleton1733 3 жыл бұрын

@@shawnreinerdavid6848 Programming: logical operator

@joyeetabhattacharya5902 3 жыл бұрын

Same for me.

@nikhilmohakar3122 5 жыл бұрын

Hey, I have an amazing answer using Gamma function. We know , gamma(n) =(n-1)! So, gamma(3)+gamma(3)+3!=10

@jacobrobinson884 5 жыл бұрын

Also used gamma but the other way: 3! + 3! - Γ(3) = 10

@diptojitdhar1757 4 жыл бұрын

Hey what is gamma?

@DLAppleGamez 4 жыл бұрын

Diptojit Dhar Gamma is a function where n x gamma is equal to n-1!. So if 5 was n, then 5-1 is 4, and 4! is 24. So 5Γ (5 x gamma) is equal to 24.

@guilhermeg.2150 8 ай бұрын

The crazy hard bonus can be improved, since: !3 + !3 + 3 = 7, 3 + 3 + 3 = 9, and !3 + !3 + 3! = 10, So we actually have 3 answers instead of 2!

@aaaaaa69420 Жыл бұрын

well if you're gonna let us use programming operators then here you go: 3+3+(3++)=10

@C4ZWX 5 жыл бұрын

Bonus question: 3+3+3+()! = 10 Parenthesis build a zero :)

@madhusudansingh9925 4 жыл бұрын

That seems to be valid, however, implied 0(zero) would still be considered an extra number that may make it invalid.

@sarpbilgesenkardesler7434 4 жыл бұрын

GENEIOUZZZ

@Themonkeymartin 4 жыл бұрын

But in that case you could literally do any number so pretty boring

@cristiluchian3567 4 жыл бұрын

!3×3!-!3=10

@juliuss2056 4 жыл бұрын

Madhusudan Singh I guess square roots and logarithms are all of the table as well then as they also imply numbers

@yep5700 3 жыл бұрын

The problem with this is that the rules are ambiguous, there's no way to verify or to know in advance if you're allowed to transform one of the 3's into an exponent, or use arctan etc...

@catgenix6031 9 ай бұрын

none of the problems NEED arctan or exponents and are just there for extra solutions

@markscheuer8648 Жыл бұрын

I found 3x(3.3) with a repeating bar over the last 3. Another solution is any calculations gives a whole number greater than 1... in that base (ie., 3+3+3=10 base 9) although one could argue that this also involved a 9.

@user-kufihfmurb Жыл бұрын

Buttered side down(3+3+3) = -9 A function by me that does the opposite with the mathematical symbols like × now works like ÷ ÷ works like × + works like - - works like +

@AyrtonTwigg 5 жыл бұрын

3.(3 repeating)*3=10 (3 with the line on top to make it 3.33333333...) EDIT: 3.3... * 3 = 10

@mparagames 5 жыл бұрын

LOL

@Tanishq801 5 жыл бұрын

one of the best solns i've found

@0Clewi0 5 жыл бұрын

I also thought of this one and actually jump right into the video to check if it was there.

@R4F4ELLO 5 жыл бұрын

@@0Clewi0 the same ;)

@laur1976 5 жыл бұрын

Just add round: round (3.(3)*3) = 10. I saw that he agreed with IT rules.

@ericintheclouds8937 3 жыл бұрын

I see in a lot of the solutions for 3 3 3 = 10 that the square root was taken. This is the same as raising to the power of 1/2 which leads me to assume that I can raise a 3 to any power I want...like 0. this means I can say (3 x 3) + 3^0 = 10

@hamzaj975 3 жыл бұрын

that's right

@neyt9699 3 жыл бұрын

Я решил так же

@Kettwiesel25 2 жыл бұрын

You cannot do this, because it uses a new 0, but you could take the square root an infinite number of times maybe, which amounts to ^0 as well.

@fr9714 2 жыл бұрын

This is a fantastic interpretation of the problem and I actually thought something similar that sq root means ^1/2 which albeit an operator, who's to say you can't do 0th power of 3?

@maxshasorro7269 2 жыл бұрын

ONLY +, !, and () - u didn't solve

@Angelblue1302 Жыл бұрын

Simple Solution for 10 is ((3^3)+3)/3=10 (That is if we're allowed to add new numbers)

@leonardosartori7150 Жыл бұрын

In the last one i came up with !{[!(!3)]+3}+[!(!3)] which is !4+1 which is 9+1=10

@galilelolparodien 4 жыл бұрын

I've never heard of "subfaktorial" neither did any of my calculators

@amzwl1671 3 жыл бұрын

@@somebody700 I wouldn’t call it uncommon. If you follow mathematics, it’s used quite a lot

@amzwl1671 3 жыл бұрын

@@somebody700 Bruh my apologies. I read it as factorial, not subfactorial. Yeah this is the first time I’ve seen subfactorial

@sarthakmandal4082 3 жыл бұрын

we are taught to use this in School [ 12th grade ]

@sdfsef5968 4 жыл бұрын

Cos(d/dx 3) + 3 * 3. This was my initial thought after staring at that problem for about an hour.

@seebugamer5918 3 жыл бұрын

Nice

@LlamaBG 3 жыл бұрын

initial?

@indigoziona 2 жыл бұрын

Haha, I came up with 3 x 3.3 (with an added dot/bar to show it's recurring) tried the bonus for a few minutes and... well now I see the answer I still like mine best ;)

@aroundandround 7 ай бұрын

f(3, 3, 3) = 10 where f is defined as the set of all functions that can use three 3’s and massage them according to Talwalker rules to get 10.

@coolbojy 5 жыл бұрын

are we allowed to use infinite roots? 3x3 + sqrt(sqrt(sqrt(.....sqrt(3).....))) = 10

@jyl123 5 жыл бұрын

Hans Berkvens cheatER

@wenhanzhou5826 5 жыл бұрын

If you can express infinite series of roots without number then I guess yeah.

@TheSudhanshuSoni 5 жыл бұрын

Use GREATEST INTEGER FUNCTION outside that .

@Tfin 5 жыл бұрын

He showed a solution using the floor function, which just means "round down." Using the ceiling function ("round up") is equally valid, so you don't even need infinities. You just need to get close and add one of those two in. :/

@xyz.ijk. 5 жыл бұрын

Very clever, IMO

@nayutaito9421 5 жыл бұрын

4:57 WAIT. Arctan must return the value as radian...

@sunsetflory 5 жыл бұрын

that's what i thought, but firstly i think in ° than in radian

@jabarzua Жыл бұрын

I liked the solutions by Yale. The 10° one feels like cheating to me because it's like adding a arbitrary constant, like I could say N=10/9 and do N(3+3+3)=10. Also I feel like using .3 shouldnt count because thats just an incorrect way of writing 0.3. That being said, an interesting way (imo at least) of getting 10 would be to do 3.3(with the recurring thing on top)*3

@PaulJosephdeWerk 2 жыл бұрын

I don't recall learning subfactorial in school. Thank you for that lesson.

@shafin3520 5 жыл бұрын

I have another answer for the problem how about !(!3)+3!+3=10

@SwishyFishy 5 жыл бұрын

or 3x3+(!(!3))=10

@lh1690 4 жыл бұрын

But what is 6 ÷ !(!3)? Should I divide the 6 by the ! first?

@Nemmark4 4 жыл бұрын

Also (!(!3)+3)! -!3 = 10

@nouarkansas9386 4 жыл бұрын

or (3!)! - (3/3)!

@AnhThuNguyen-zz2hm 4 жыл бұрын

Shady Kardz That's subtraction. Not addition.

@antoninduda9078 3 жыл бұрын

for '3', I came up with ³√(3³).

@MyOneFiftiethOfADollar Жыл бұрын

Your unrivaled crowning achievement is your presentation platform. I would pay a large sum to know how you do it. Highlight, erase, disappear, reappear abracadabra

@carnivorecaveman Жыл бұрын

My solution, using the symbols of the C/C++ programming languages: (3+3+3)++ The result is 10. Without any questionable "subfactorial"... The ++ symbol is the symbol of incrementation in those programming languages. Valid, and frequently used symbol.

@canary1386 3 жыл бұрын

also, using subfactorial you can do !(!3) + 3(3)

@xyz.ijk. 5 жыл бұрын

3+3+3=10 base 9

@DanielSong39 5 жыл бұрын

Best answer

@ericpenguin9550 5 жыл бұрын

J G sadly, then you have an extra nine

@xyz.ijk. 5 жыл бұрын

Interesting. Persnickety, but interesting. I suppose you are correct, but I think it is a fair answer because Presh used several additional symbols and letters to generate additional answers. Presh ... your judgment?

@xyz.ijk. 5 жыл бұрын

Well done! 6 base 6 ... I missed that one.

@chevon1920 5 жыл бұрын

@kmilorestre5223 2 жыл бұрын

What about 3^2 +3/3 ?

@yyndsai Жыл бұрын

3^2+(3/3)=10, you literally forgot to mention easiest solution

@jokernormangames6556 2 ай бұрын

You aren’t allowed to introduce any new digits, and the 2 is a new digit, so that’s not allowed

@NestorAbad 5 жыл бұрын

That was quite tricky! I made 10 using the !! (double factorial), which is defined as the factorial but counting two by two, for example: 2!! = 2 3!! = 3x1 4!! = 4x2 5!! = 5x3x1 6!! = 6x4x2 and generally n!! = n(n-2)(n-4)... until you reach 2 if n is even or 1 if it's odd. With this in mind, combining ! with !! we can do (3!)!! / 3 - 3! = 10. I wasn't able to use only + ! ( ), though :-D

@MindYourDecisions 5 жыл бұрын

Nice! I have been searching to put the double factorial in one of my videos too (perhaps I'll do it for my next calculation puzzle ;). I came across the double factorial in the derivation of the the Wallis product formula for pi, but that video was nearly 12 minutes so I didn't include that topic there. For those curious, here's an amazing formula for pi! Wallis product formula for pi kzfaq.info/get/bejne/e8CDnLSnxK2deIE.html

@alejandroduque772 5 жыл бұрын

@@MindYourDecisions you should do more videos like that one. I really like them :)

@isaacaguilar5642 5 жыл бұрын

That’s how I did it too😂😂😂

@Max_Power_ 5 жыл бұрын

I didn't know that, I was using double factorial like Google interprets it 3!! = (3!)! = 720 😂

@wenhanzhou5826 5 жыл бұрын

Hmm, I don't know if it's valid but what about (3!-3/3)!!!?

@Arnianor 3 жыл бұрын

Let's point out that you can also do: floor(ln(3))+(3*3) = 10 (plenty of similar solution with logs in different bases) and for the bonus, since you displayed the bit shift, I guess I'm allowed the same kinda cheat: 3+3+3 != 10

@dhananjaya.mishra Жыл бұрын

It can be solved without using sqr root and subfactorial; {log3}+3×3 where {} is a least integer function.. or [log3]!+3×3 where [ ] is greatest integer function (floor function)

@christianwolirdeng4766 Жыл бұрын

If given a single 3, can you make any other number using only !, sqrt, and rounding down?

@Maxime-fo8iv 4 жыл бұрын

Another solution for the =10 equation : (√3 × √3) / .3 = 10

@poiofrito4722 3 жыл бұрын

Thats equal to 1 lol

@poiofrito4722 3 жыл бұрын

Oh i didnt see the . Sry

@ranvijaytanwar 3 жыл бұрын

Nope that's 10 Cool , good one

@Bhuvan_MS 2 жыл бұрын

Simplest solution

@leokoten 4 жыл бұрын

By the definition of Sloane and Plouffe of Superfactorial, you can make the following operation: 3$ - (3!/3) = 10 Because 3$ = 3!2!1! = 12

@ReenaKumari-vq2rk 4 жыл бұрын

But $ and - r not allowed in the bonus ques.

@nepasdisponible 4 жыл бұрын

He has just found out another way of doing it.. The answer need not be formed only from the given three symbols.

@jaykoppada7 4 жыл бұрын

+,(),! Only these dude

@ThePiMan0903 Жыл бұрын

Nice video MindYourDecisions!

@BobBob-ye4vz 2 жыл бұрын

really good solution (3.3...) x 3 =10 im still using only 3 threes, sue me

@chetanphoenix 4 жыл бұрын

this is the simplest way to get to 10 since we already used .3 earlier. (3!-3)/.3

@george_364 3 жыл бұрын

True, but using the dot (decimal sign) felt like cheating to me. I don't think a dot can be considered a mathematical operation.

@kingsley. 3 жыл бұрын

find a solution for 4 (3+3)-([sq.3]) then find 6 (3!)-3+3 (3!-([sq.3]))+3!

@youleq3968 3 жыл бұрын

@@kingsley. what about this. (3! / 3)^2 + 3!

@Steven-ov4no 3 жыл бұрын

@@youleq3968 You can’t use 2

@HappyDay2283 5 жыл бұрын

You can also get 0 Like this: 3x(3-3) 😁

@jimih02 Жыл бұрын

You can solve 8 and 10 by squaring 3. A square of a number can be used as well because it does not serve as a number but a mathematical operation the same as the square root factorials and subfactorials.

@raiedmaskar Жыл бұрын

One way that I had in mind for (3 3 3=10) is by using Sigma, or small sigma to be accurate (as I understood from math class, small sigma can be used to sum the number with all numbers before it up to one, like factorial but sum instead of multiply, for example: Σ3=3+2+1=6, so my answer is Σ(3/3+3), this leads to Σ4 which is equal to 4+3+2+1=10. is this solution acceptable as I had a long disccusion with my friends that Σ is not known as I used.

@Vishnu_00 5 жыл бұрын

5:32 you can do this without using % (√3×√3)÷ .3

@Singh-be2qn 4 жыл бұрын

Nice

@rafatazzam2079 3 жыл бұрын

Thank you to let me know about subfactorial , it is my first time I hear about it.

@ericb6793 Жыл бұрын

Simple: 3/(.3) + d/dx(3) = 3/(.3) + 0 = 10. The derivative of a constant is 0 and we're allowed to use .3,

@gamingcreation3961 Жыл бұрын

I don't think i am just watching this to entertain myself

@louismelahn1805 3 жыл бұрын

3:40 and 4:45: Hm. By taking the square root of 3, aren’t we slipping in a 2 that wasn’t in the original problem?

@n.gineer8102 3 жыл бұрын

I agree if you can take the square root (1/2) then why not raise to power if 2? So SQRT is not acceptable.

@alex2005z 3 жыл бұрын

@@n.gineer8102 why not make it 0= (3-3)÷(10×3)? Nodoby said stick to your side of the equation

@dxtfx1912 3 жыл бұрын

This is also true for factorials, as you are technically adding a 2 and 1 (3! = 3*2*1)

@tiemen9095 3 жыл бұрын

@@dxtfx1912 I don't agree with that, as the factorial is an operation that does not require a base. In contrast, roots and powers do require a number for the base or exponent. In the case of the square-root, the base is 2. In this commonly used case, it is common practice not to write the 2 - but that doesn't mean it isn't there! But allowing that seems arbitrary as it is just a convention to eliminate writing it.

@ulmersapiens 3 жыл бұрын

@@tiemen9095 I agree that operations that imply a quantity are mostly okay, like a natural logarithm. I’m only barely okay with square roots, because I think they’re a gateway to other fractional powers (cube roots would have my full support). I absolutely cannot, however, abide by the garbage that is dividing by 10 or 100 and pretending that adding the decimal or percent sign are “operations”. I almost stopped watching there - he is Fonzie and that decimal point is the shark.

@classicalhero7 5 жыл бұрын

First time I've heard of subfactoral.

@erayyertass 3 жыл бұрын

There are Hyperfactorial, superfactorial and more as well :)

@koro-sensei9783 3 жыл бұрын

Good isn't it, we are learning many things for Presh

@oraz2857 6 күн бұрын

Honestly a have problem with allthe other solution you had for 3 3 3=10 except for the last one. 1. While using arctan, you get degrees, yet degrees are not numbers, radians are. And this arctan's value is about 1. 2. While using square root, you define the root by the number 2 which is not part of our system. 3. Percentage is also taking a number and divide it by 100, which is not in our system. For me, only the last 2 solution (the bonus and the one with the diviation) are applicable, but i must say, the are amazing 👏

@user-do2yy6gv8x Жыл бұрын

We can make 10 with only three 3s and three dots, the method is 3⋅3.ᣮ = 10. The last dot is above the last 3, which represents a repeating decimal 3.333... .

@esyrim 5 жыл бұрын

Am I going insane, or did you already do this? Or was it with the 6's?

@mpd177 5 жыл бұрын

I was thinking the same but in the end it was all numbers from 0 to 10 that equals ( like 0 0 0 = 6 or 4 4 4 = 6)

@SuperNolanMan 5 жыл бұрын

It was with 6s. Or some other number, but this is the first with 3s 👍🏼

@janarthanams1897 5 жыл бұрын

@mparagames 5 жыл бұрын

I think that it is easier to do it with 6 than it is with 3.

@tubular618 5 жыл бұрын

Which question should we answer first?

@alansmithee419 3 жыл бұрын

5:00 It really should be specified in the question that you can do this. Even had I considered trig, I would've used radians because that is the formal unit for angle. Can you use gradians too? Now it seems you could just define any unit for angle you want and go "huhuh arctan(3+3+3)=23874 of this unit I just invented."

@MultiChrisjb Жыл бұрын

and when they started using floor function....

@ba3382 Жыл бұрын

Nice,

@Nathan_Avril Жыл бұрын

If you allow to play with the units, you could also use a conversion so you just have to get 1 cm, then you convert to 10 mm

@Stickman_Productions Жыл бұрын

I learn about tetrations > I see tetrations everywhere I learn about subfactorial > I see subfactorial everywhere I notice or learn anything > I see it everywhere I didn't imagine using subfactorials for this though, I was completely focused on getting 10 and not using it right

@avielcohen9514 Жыл бұрын

For 3 3 3 =10 you can do: 3²+(3÷3)=10 Very simple solution.

@SeegalMasterPlayz Жыл бұрын

You cannot use powers of 2 since you are introducing a new digit 2.

@gncgenz5829 5 жыл бұрын

For the regular 10 answer, I used logarithms in a weird way. 3!+(ln(3)/ln(sqrt(sqrt(3))))

@elinaevans5803 5 жыл бұрын

Brandon Ignacio Wow, that's cool)) IMO, very good way 😁

@superalpha 5 жыл бұрын

Your left shift operator,

@Tfin 5 жыл бұрын

Well, getting to 30 makes getting to 10 pretty easy, as well.

@gregoryfenn1462 5 жыл бұрын

How do you get to 30?

@superalpha 5 жыл бұрын

@@gregoryfenn1462 left shifting one place is the same as multiplying by the base, right shifting is the same as dividing by the base. So base 10 left shifted is the same as multiplying by 10.

@gregoryfenn1462 5 жыл бұрын

Ahh I see. I'm used to python3 logic whereby "10 > 1 == 4". That is, the operator always works in base-2 under the hood, even if you write in base-10 numerals.

@MindYourDecisions 5 жыл бұрын

I'll mention that WolframAlpha evaluates the expression as 6, as seen in this link: www.wolframalpha.com/input/?i=3%3C%3C(3%2F3)

@chrisbreisch7366 7 ай бұрын

Once you add things like floor() and ceil() to the mix, 10 is easy. Another one - floor(3*3 + sqrt(3))

@user-anonyzous Ай бұрын

Me when I see the thumbnail: √3+(3/3) Me now: (3!+something something)

@alejandro_a 4 жыл бұрын

Since you once used a decimal point, I just came up with: (√3*√3)/.3 = 10

@alex2005z 3 жыл бұрын

I came up with a solution for all of them. Make it 0=(3-3)×(10×3) easy. They didnt say stick to fhe left side

@mrcydonia 3 жыл бұрын

Any time that I feel like I'm smart, I can just watch one of these videos and quickly get reminded that I very much am not.

@jaadd0 2 жыл бұрын

can i take the square root of 3 an infinite number of times, therefore 3^1/2.1/2.1/2... which would approach 0. So my solution would be 3^0+3x3. Would that be an acceptable answer?

@smylesg 8 ай бұрын

If you can use C's left shift operator, then the logical not ! should also be allowed. When applied to any non-zero value, the result is zero. That yields the simple expression (!3)!+(3)(3): (not 3)=0, 0!=1, 1+3×3=10

@karinisvetcool 5 жыл бұрын

Okay but the 《 method was kinda bs

@asterpw 5 жыл бұрын

So was percent or moving the decimal point. Those aren't mathematical operations.

@DerMarkus1982 5 жыл бұрын

If you come across some programming language, you may convince yourself that there really is a

@karinisvetcool 5 жыл бұрын

@@DerMarkus1982 no i believe that, it's just a bit weird that your use that for maths when it's meant to be for programming

@tombratcher6938 3 жыл бұрын

As with the six challenge, if you allow log, exp and sqrt it's possible to construct a function that takes a triplet of any real number and returns 10

@user-kufihfmurb Жыл бұрын

Intimate(3+3+3+me) Intimate is the function created by me which needs the "me" variable in the parenthesis and the "me" variable is worth 1

@zyonixyxn 2 жыл бұрын

if its not against the rules u can do: 3² + 3/3

@adiuntesserande6893 3 жыл бұрын

I’d think the easiest way to do this is by drawing a single line. 3 3 3 ≠ 10

@mariosdoub2207 2 жыл бұрын

It said in the beginning "using the equation symbol"

@dracokinerek Жыл бұрын

and for 3 you can do 3=3=3=3

@danielferencz479 5 жыл бұрын

3×3.(3)=3×3.3333333..=3×10/3=10 I think this is the easiest 😁

@JoeMac1983 5 жыл бұрын

@Nicholas Frieler yeah, you just show us how to put that bar over the 3 on a youtube comment and we'll admit you're right. Until then, all of the thumbs up for his comment knew exactly what he meant and that the bar over the three was implied.

@danielferencz479 5 жыл бұрын

Idk 'bout that guys i learn that way in school as I wrote down 🤔

@NecRock 5 жыл бұрын

Well, that depends on where you are, doesn't it? According to en.wikipedia.org/wiki/Repeating_decimal#Notation there isn't a universally accepted notation, and there are places where the standard practice is to use brackets.

@danielferencz479 5 жыл бұрын

@@NecRock Thank you for that, I didn't know this stuff 'til now.. and yeah I live in europe.. so here this is a legal and good solution I guess 😅

@marial4948 5 жыл бұрын

@Nicholas Frieler you would be surprised, but math notation is not universal across different countries. In most European countries a number in parentheses after a decimal point (or more often comma) is repeated infinitely.

@charlemagnesclock 6 ай бұрын

BTW, there is another solution to 3 3 3 = 10. If you map the digits on the left side into base 4 and the ones on the right into base 10, then 33+3=10.

@ninjadoughnut4837 Жыл бұрын

I would disagree with the first solution for 10, because degrees is a unit, and both sides of the equation are unitless. Radians are unitless, so arctan(rad3) should be pi/3