Cell Potential Problems - Electrochemistry

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Күн бұрын

This chemistry video explains how to calculate the standard cell potential of a galvanic cell and an electrolytic cell. This electrochemistry video contains plenty of examples and practice problems.
Intro to Galvanic & Voltaic Cells: • Introduction to Galvan...
How To Draw Galvanic Cells:
• How To Draw Galvanic C...
Standard Reduction Potentials:
• Standard Reduction Pot...
Cell Potential Problems:
• Cell Potential Problem...
Cell Notation Problems:
• Cell Notation Practice...
___________________________________
Concentration Cells:
• Concentration Cells & ...
Cell Potential & Gibbs Free Energy:
• Cell Potential & Gibbs...
Cell Potential & Equilibrium K:
• Equilibrium Constant K...
Nernst Equation:
• Nernst Equation Explai...
Electrolysis of Water:
• Electrolysis of Water ...
_____________________________________
Electrolysis of Sodium Chloride:
• Electrolysis of Sodium...
Electrolysis & Electroplating Problems:
• Electrolysis & Electro...
Electrochemistry Practice Problems:
• Electrochemistry Pract...
SAT Chemistry Subject Test Review:
• SAT Chemistry Subject ...
Carbon -14 Dating:
• Carbon 14 Dating Probl...
Beer Lambert's Law:
• Beer Lambert's Law, Ab...
______________________________________
Final Exams and Video Playlists:
www.video-tutor.net/
Full-Length Videos and Worksheets:
/ collections
Chemistry PDF Worksheets:
www.video-tutor.net/chemistry...

Пікірлер: 256

@TheOrganicChemistryTutor Жыл бұрын

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@srinidhi3106 7 ай бұрын

@tbdrosa8542 2 жыл бұрын

another neat way to determine which cell potential is "flipped" is which is more negative. The more negative a cell potential is, the more it wishes to be oxidized. And when we oxidize reactions in problems similar to these we will flip the reaction, which also can flip the sign to its corresponding reduction potential

@shan8613 Жыл бұрын

Thanks!!!

@Feyangel23 4 жыл бұрын

For anyone wondering why at 7:40 the answer is -2.20V it's because electrolytic cells can have negative cell potentials which is the difference between galvonic cells. When electrolytic cells have negative cell potential values they need energy to run. It's like when your smartphone is dead; you need to recharge it first before it can run again

@starsuperville6863 4 жыл бұрын

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@antoniojosiahphilipm.7817 3 жыл бұрын

How did u get -2.20V at problem 3?

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@ShubhraShandilya29 5 жыл бұрын

Explained wonderfully! Thanks!!

@Cryptomaniac719 3 жыл бұрын

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@jesus_saves_15 11 ай бұрын

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@CaptainKanundrum 3 жыл бұрын

Thank you so much for this video, it is exactly what I was looking for! One question: for cases like Ag/Mg reaction, why does multiplying the Ag equation by 2 not change the cell potential at all? I keep thinking that if I have to move twice as many electrons, the potential should double.

@arhamralam 2 жыл бұрын

Cell potential is an intensive property, so it will not change even if the number of moles vary.

@xii-cb.s.gokulakannan1945 2 жыл бұрын

hi dude the basic thing of this chapter is electrode potential do not change with how many moles , pressure , temperature you add the ep donot change . i think my answer would clear your doubt .

@nofacefreak8986 5 жыл бұрын

You just explained what my teacher told us in 1 and half hour in freaking 10 mins

@sumaiyarashid8930 4 жыл бұрын

true dat my teacher just confused me so much that i had to revisit the whole thing again

@arielwise9664 3 жыл бұрын

what do you do when you're not told if it's electrolytic or galvanic?

@ruthkoi8165 3 жыл бұрын

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@sneha3927 4 жыл бұрын

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@arexqui625 6 жыл бұрын

In Standard cell potential don't we subtract the cell potential of cathode from anode as per formula?

@shubhamsinghhh99 5 жыл бұрын

Bkr video h nhi hai isko knowledge

@chisomovuegbe4248 5 жыл бұрын

Mohammad nasir you do, but he reversed one of the reactions, that’s why he still got the correct answer despite adding them.

@manishbarnwal3816 4 жыл бұрын

@@shubhamsinghhh99 I think you should check yourself before accusing him.

@jerymarschmid6176 3 жыл бұрын

yeap it should, that's how is shown on the books

@thabangmoloi1553 3 жыл бұрын

His half rxn are standard hence he can choose to reverse the other one

@atttomole Жыл бұрын

Interesting. It’s a bit confusing when it comes to the redox flow battery. Can you do it for iron redox flow battery reactions.

@JulianHernandez-bt7il 2 жыл бұрын

"A standard cell potential has to be positive" can't believe my professor never mentioned that in lecture man haha

@avationmusic 2 жыл бұрын

Keep in mind when he says that it has to be positive, he means the overall potential for the entire cell, and it only applies to galvanic cells. Electrolytic cells can be negative because they are powered by an external source. You can also use the value of the cell potential to determine if the reaction will be in equilibrium (Ecell = 0) or if it’s spontaneous (Ecell = positive) or non-spontaneous (Ecell = negative). Hopefully you knew this already but I’m adding it just in case :)

@AverageMED 2 жыл бұрын

@@avationmusic can an electrolytic cell be positive?? I am having a hard time wondering why they ever would be

@user-pr5py8cw9x 2 жыл бұрын

@@AverageMED He's wrong. An electrolytic cell, by definition, has a negative Ecell. Always negative. Never positive. First time I've seen him make a big mistake in a video.

@AverageMED 2 жыл бұрын

@@user-pr5py8cw9x yeah i was gonna say by definition it has to be negative

@nurislamshimul5402 6 жыл бұрын

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@ab123tube4 Жыл бұрын

Great.please make video how to affect using active and inert electrode on the product of electrolysis

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@ramao79615 3 жыл бұрын

the way he says reaction🥺❤️3:41

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@pydipaparao5379 6 жыл бұрын

should we multiply the E°cell value when equation is being multiplied?

@TheKennethfilm 4 жыл бұрын

No since the standard potential is in volts and not in volts/mole.

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@davidcherilus9112 2 жыл бұрын

Can anyone explain equation 3 ? Thank you. In contrast to a galvanic cell,the most positive standard reduction half reaction within an electrolytic cell is the one that experiences oxidation. With that in mind, Why did he reverse iron half reaction and not the Br half reaction (where Br would be our anode and Fe be our cathode? Ered of cathode - E red of anode.

@catastrophicdemon949 2 жыл бұрын

Br is the one receiving the electron therefore it is a reduction and Fe is losing electron therefore it’s a oxidation. Knowing that reduction is cathode and oxidation is anode. Using the formula Ered-Eox or Ecathode - Eanode = 1.09-(0.77) which is 0.32

@kashrathore3146 5 жыл бұрын

How did u get -2.20 ..I got +2.20 in the last question

@mohammadrezasharghi8648 3 ай бұрын

In an electrolytic cell, you have to put in energy to do the electrolysis, so Gibbs free energy is positive here, which means cell potential needs to be negative, not positive.

@brianreyes5831 3 жыл бұрын

thanks for always making it all seem easy :))

@govindarajuankadala8563 4 жыл бұрын

Best explanation

@themaninred7352 4 жыл бұрын

Hi question, does molarity of the substances affect the cell potential?

@jarodhans3758 4 жыл бұрын

yes it does. for calculating cell potential in standard conditions (1M) use the method in this video. for concentrations other than 1M use nernst equation

@Bohnr 2 жыл бұрын

I always have to speed these up, but good stuff

@Sammi-nm8bg 4 жыл бұрын

dude. if i had a million bucks i would give it all to you

@Fifi00416 5 жыл бұрын

i was soooo confused, thank you sooooo much

@biancafrancis7788 2 жыл бұрын

how did you come up with the reduction potentials?

@binodanandbipin5960 4 жыл бұрын

Do we have to remember the data as you have shown in example 3..

@sumaiyarashid8930 4 жыл бұрын

this video was helpful

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@freezer-monkey Жыл бұрын

Bro this guy is a better teacher then my actual teacher

@sanchitbolinjkar8291 3 жыл бұрын

Electrode potential is an intensive property and non additive in nature so we can't directly add it the way you did. Instead what we have to do is add all the reactions and equate it's Gibbs free energy to the final free energy. Could you pls solve this confusion for me?

@moonandtanu7591 2 жыл бұрын

Yea thats what im thinking

@zoudek123 4 жыл бұрын

In 10:56, +109, pls tell me how to get that number..

@sajidmehmood6976 6 жыл бұрын

Dont you think when we subtract one from other with opposite charge the net result with sign of those which is larger term...as you did in case of secnd e.g ...suggest me please

@sajidmehmood6976 6 жыл бұрын

As in Ni and Fe eg. The net sign is negatve... I have read this eg in another book with Ni used as oxidation

@nathanmulopo9366 5 жыл бұрын

@@sajidmehmood6976 If Ni is used as oxidation it's wrong cause with half - reactions, one half - reaction must be reduced and the other oxidized . Both of them can't be oxidized. Fe is already oxidized

@brennan7846 2 жыл бұрын

I just wanted to know if the balancing of the electrons changed the cell potential for my homework. Thankfully I have found somewhere where it says that it does not change. Where else can I find the answer to this question? Like actually I was surfing this channels videos to find this answer.

@BrownCookieBoy 5 жыл бұрын

First you say the cell potential has to be positive, then you introduce a nonspontaneous reaction (were the potential is negative) without explaining. Im confused. So i wouldve had the wrong answer if i flipped the Standard for aluminum so i could do 1,66 - 0,535?

@giordicsaga 5 жыл бұрын

same here! XP

@iubescman 4 жыл бұрын

for galvanic cell, that's the rule that it must be positive. in electrolytic cell it can be either

@nourahd6994 5 жыл бұрын

Why i didnt watch your videos a couple of years ago 😣

@sangeetakala1797 4 жыл бұрын

Seriously man🙁🙁🙁🙁

@bbboyyy51 3 жыл бұрын

Please tell me why souldn't we need to balance the last example?

@emmanueljohngallo8007 5 жыл бұрын

thanks master 🙇

@inaj9455 5 жыл бұрын

Thank you po

@aliyaiffat5217 2 жыл бұрын

Forgalvanic cell cell potential hs to be positive. For electrolytic cell it can be negative positive or zero.

@alphajohnalbert4517 3 жыл бұрын

Where did they get the value of Voltage?

@lizardis89 11 ай бұрын

I learned in class the formula for ecell was to subtract ecathode and eanode? Can you explain why you are adding them?

@101nevergiveup 3 ай бұрын

This is the same problem I'm facing 😭

@kehdu 2 жыл бұрын

Thank you

@saramohamed.8403 Жыл бұрын

Thank you, sir

@sunny11097ify 6 жыл бұрын

wait, isn't getting the cell potential of a galvanic cell done in a way in that, E(oxidation)-E(reduction)? And it seems like we do not gave to change the signs when flipping the equations around....

@skygazer2678 3 жыл бұрын

Thanks man!

@Roshankc12 5 жыл бұрын

Good explain

@nathanmuni3745 3 жыл бұрын

How do we know which reaction we have to reverse??? Either one or two 🤔🤔

@ZainabOyetola Жыл бұрын

Will the cell potential value for each reaction be given ?

@omsingharjit 3 жыл бұрын

Why cell potential of lead acid battery is 2volt if lead and sulpher potential is much lower ????

@aliveforalife 5 жыл бұрын

You are best ... India 🇮🇳

@sneharyan9701 5 жыл бұрын

Where the hell comes india man.. can you see anybody commenting usa france Germany etc.. don't make india look bad because of your stupidity. . I am indian also but for god sake don't write everywhere i am from india love from india

@ethioupdatedinfo. 5 жыл бұрын

On question 3) (7:35) you don't multiply Fe^2+ potential by two. So the overall result should be -0.45v not +0.32v. If this is the answer why galvanic cell result negative?

@nahuelfernandez4190 5 жыл бұрын

because its asking for an electrolytic cell.

@xtiiin4467 2 жыл бұрын

In your second example, why did you reverse Fe and not Ni?

@khnithhgor9698 3 жыл бұрын

when the electrons are present on the same side then which reaction is to be inversed and on what basis?

@andrewquintana2068 3 жыл бұрын

If a galvanic cell, invert the reaction that will result in a positive E. If an electrolytic cell, it depends what they are looking for. The "E" can be negative, positive, or zero. Thus it doesn't matter which you invert.

@venusz6134 4 жыл бұрын

hmm I'm not quite understanding how he got +0.21V for Q2. After reversing the iron's rxn, it becomes an oxidation (anode) with E= +0.44. So should it be: E cell = E cat - E ano = -0.23 - 0.44 which is

@sandeepsammy9480 4 жыл бұрын

Even I have the same doudt and going through the comments...so that anyone can reply me .

@sandeepsammy9480 4 жыл бұрын

If your doudt has clarified .. can you please tell ?

@venusz6134 4 жыл бұрын

@@sandeepsammy9480 Sure thing. For this question, it'd be helpful to arrange the half-rxns in the decreasing order of standard cell potential values - we will have Ni (-0.23V) then Fe (-0,44V) so Ni+2 rxn is reduction (cathode) and Fe+2 is oxidation (anode). The formula (Cathode - Anode) works according to the standard potential values of reduction half-rxn. Thus, since anode = -0.44, Cathode - Anode = -0.23 - (-0.44) = 0.23 + 0.44. Hope this helps :)

@venusz6134 4 жыл бұрын

@@sandeepsammy9480 Also it's a galvanic cell meaning Cathode - Anode always > 0

@sandeepsammy9480 4 жыл бұрын

@@venusz6134 thankyou ...I understood ..thanks for the clarification

@Neerajkumar-bv8hq 5 жыл бұрын

how to find the value of n in it

@user-gr3ml7kl7w 3 ай бұрын

Thank you soo much

@adinahojda6669 4 жыл бұрын

when we calculate the cell potential we have to do subtraction. The formula is cathode - anode. In the first example you added the values and now i am confused.

@ayushdudhani 3 жыл бұрын

In that formula we use reducation potential where as he used oxidation and red potential respectively

@allandumagay9908 3 жыл бұрын

Bro +0.80-(-2.37)=+0.80+(2.37) Still the same bro.

@winproduction7585 Жыл бұрын

Thank you sir

@atlma2 6 жыл бұрын

Should the cell potential for electrolytic cells always be negative (so deltaG is +) since its nonspontaneous via the equation G = -nFE?

@johnhopley154 5 жыл бұрын

yes my same thoughts. especially for the Br2 2Fe2+ one he does at like 7:30

@antoniojosiahphilipm.7817 3 жыл бұрын

Saeemm

@jameschem 9 ай бұрын

The question 4 was kinda weird to me, hope you could explain more

@nimoosman7716 Жыл бұрын

Thank you❤

@dbismark8696 3 жыл бұрын

Thanks dude

@shrdani 4 жыл бұрын

THANK U MAN

@johnnyzheng423 3 жыл бұрын

An easier and quicker way is looking at the electric potentials of both half reactions and picking the largest electric potential. That will be your Ecathode , so you can subtract that with the lower electric potential (your Eanode) to get your overall cell potential. For example, for #1 you pick the 0.8V since it is the larger number and subtract that with -2.37V which will give you 3.17V.