Central Difference Approximation | Lecture 61 | Numerical Methods for Engineers

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3 жыл бұрын

How to approximate the first and second derivatives by a central difference formula.
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Пікірлер: 22

@sonukumarbhaskar8937 Жыл бұрын

THANKYOU SO MUCH SIR . I AM ABLE TO SCORE COMPLETE 6 MARKS IN MY BSC HONS MATHEMATICS EXAM OF DU ...... GOT 98 OUT OF 100

@majormelon8855 11 ай бұрын

wow that explanation was soooooo much better than my professor. Thanks!

@MOHAMMAD07854 2 жыл бұрын

that has been amazingly helpful, thanks for the effort

@mugerashalifu9539 2 жыл бұрын

I appreciate your work sir

@sudhakarmathsacademy 3 жыл бұрын

Great explanation sir thank u

@mortenviersimensen4316 3 жыл бұрын

great video. Thanks

@pey3243 Жыл бұрын

how about getting the third and fourth derivative?

@lovesonmukombiwa3093 3 жыл бұрын

Thanks proff

@papidepiso 2 жыл бұрын

Thank you 😊

@VikkuGoyal 2 жыл бұрын

Thank you

@chrisluala9937 Жыл бұрын

What about 3rd derivative sir?

@fuji4128 7 ай бұрын

what if I wanted a finite difference of a priorly selected Error? say the first derivative of Oh^4 Error?

@donathakamugisha-fz7hs Жыл бұрын

Nice

@zbryce1106 2 жыл бұрын

Elegant

@jayeshjadhav4579 6 ай бұрын

QUESTION: Does having higher Order of ERROR (here O(h^2)) mean that I can diffrentiate a Funtion Upto That order (2) without having any error OR habign the Minimum numer of Order for a Function in order to Have Maximum ACCURACY? can anyone please Explain...thank you

@rizkamilandgamilenio9806 11 ай бұрын

Great explanation sir!, but i still dont understand why its equal to O(h^2), please sir or anyone let me know the explanation

@user-do2vu1kv2i 10 ай бұрын

because when we look at the first derivative we multiply it by h, next term (second derivative) cancels and we have next but one term that multiplies by h^3 what means h*h^2 and when we divide it by h, we have h^2