18.3 Gibbs Free Energy and the Relationship between Delta G, Delta H, & Delta S | General Chemistry

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Chad's Prep

Chad's Prep

Күн бұрын

Chad continues the chapter on Thermodynamics with an introduction to Gibbs Free Energy. Simply put, Gibbs Free Energy is the energy available to do work. For a spontaneous reaction, the change in Gibbs Free Energy (Delta G) is negative. For a nonspontaneous process, the change in Gibbs Free Energy (Delta G) is positive. And for a reaction that has reach equilibrium, the change in Gibbs Free Energy (Delta G) is equal to zero.
Mathematically, Delta G is defined in terms of the enthalpy and entropy changes as follows:
Delta G = Delta H - T(Delta S)
A reaction for which Delta H is negative and Delta S is positive will be spontaneous at all temperatures.
A reaction for which Delta H is positive and Delta S is negative will be nonspontaneous at all temperatures (or the reverse reaction will be spontaneous at all temperatures).
A reaction for which Delta H is negative and Delta S is negative will be spontaneous at low temperatures.
A reaction for which Delta H is positive and Delta S is positive will be spontaneous at high temperatures.
I've embedded this playlist as a course on my website with all the lessons organized by chapter in a collapsible menu and much of the content from the study guide included on the page. Check this lesson out at www.chadsprep.com/chads-gener...
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00:00 Lesson Introduction
00:24 Introduction to Gibbs Free Energy
04:13 Derivation of Gibbs Free Energy
09:57 Delta G = Delta H - T(Delta S)
14:25 Negative Delta H, Positive Delta S
15:51 Positive Delta H, Negative Delta S
17:11 Positive Delta H, Positive Delta S
22:16 Negative Delta H, Negative Delta S
26:25 Delta H, Delta S, and Temperature of Phase Changes
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So at 26:08 you have the Haber process on the board which I heard happens at like 400-450C but if you calculate T = delta H / delta S for the point where the reaction stops occuring spontaneously I got 463.64 K or 190.49 C, which is less than the actual temp at which its carried out industrially, this confused me at first but apparently its bc of le chaliter's principle -- its carried out at high enough pressure to favour the side with low moles. I just thought i would comment this if anyone had the same Q or something
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