Code and Deploy Java XML Web Services (JAX-WS) on Tomcat

Рет қаралды 16,585

Күн бұрын

How to configure Java web project to host Java XML Web services, to be discover-able and consumed by clients.
* Software Programs used:
- Java Development Kit (JDK) 8+
- Eclipse IDE 2019-09
- Apache Tomcat 9.0
* Steps to code and deploy Java XML Web services on Tomcat:
- Create Java Dynamic Web Project (+Maven)
- Specify JAX-WS Runtime Dependency
- Create a Java XML Web Service
- Configure Web Services Endpoints
- Configure JAX-WS Listener & Servlet
- Code a Client program & Test
To download the sample project, refer to text-based tutorial: www.codejava.net/java-ee/web-...

Пікірлер: 44

@secretaryofstate1 2 жыл бұрын

My teacher always recommended examples from your website .. I swear from your examples I learned how to write java proficiently… I still use your examples.. I can say you’re one of the biggest helps in me getting the job I have now

@CodeJava 2 жыл бұрын

That's great! Congrats for your new job!

@deepthinker1710 7 ай бұрын

your tutorials always best i remember your name

@CodeJava 7 ай бұрын

thank you. I'm glad that you found my videos helpful.

@sangramshete3984 3 жыл бұрын

Thank you, this video help me a lot.

@CodeJava 3 жыл бұрын

Glad it helped!

@yaseminoguz2720 3 жыл бұрын

Thanks for the video :)

@CodeJava 3 жыл бұрын

My pleasure! Also check my playlist "Java Web Services Tutorials" here: kzfaq.info/get/bejne/mraajdqTs8_Gc30.html

@SudhanshuShekharRajhansh 4 жыл бұрын

Thanks, your tutorial help me a lot.

@CodeJava 4 жыл бұрын

You're welcome. Why don't subscribe to my channel?

@SudhanshuShekharRajhansh 4 жыл бұрын

@@CodeJava Subscribed

@akhil.o_s Жыл бұрын

Thank you for this video.

@CodeJava Жыл бұрын

Glad it was helpful!

@RicardoGonzalez-je9tq 2 жыл бұрын

Thank You !

@CodeJava 2 жыл бұрын

You're welcome!

@jdss7120 3 жыл бұрын

Gracias!!!

@CodeJava 3 жыл бұрын

you're welcome. Thanks for watching :)

@bogdanbilcan8335 Жыл бұрын

Hello. Nice tutorial. I have one small question. Why did you use the jax-ws listener and endpoints? Doesn't the webservice runs anyway based on the web.xml definition? Like if you go and specify the servlet and url pattern directly in web.xml to point to your hello class , it's not working? Why do we need a wrapper on top? Is it because of tomcat app server?

@CodeJava Жыл бұрын

good question. You can use plain Java servlet to achieve the same result. Using JAX-WS wrapper (via WSServlet and WSServletContextListener) will provide service description (WSDL) which is helpful to clients to explore the web services.

@bogdanbilcan8335 Жыл бұрын

@@CodeJava but, isn't the WSDL generated automatically anyway if you just mark the service class with @WebService and required methods with @WebMethod , and have the service class marked as servlet inside web.xml and deploy the war ? I ask this because i already did only this and i can see the WSDL without any issues. And from my point of view, i don't see the benefit of using JAX-WS wrapper or for example Apache CXF, or any other framework on top the already existing ones offered by JAX-WS that comes with the JDK. The only difference i saw when using a wrapper is that i get an http response with details and error about SOAP action not supported, or something like that, if i try to access a soap endpoint directly in the browser, otherwise, for me it is just adding complexity to the code of a SOAP webservice.

@oanxuanson7654 3 жыл бұрын

I have a problem in 19:41 "'wsimport' is not recognized as an internal or external command, operable program or batch file." Can u solve it? Thanks

@CodeJava 3 жыл бұрын

The wsimport tool is available in JDK 8 only.

@mukunds3144 2 жыл бұрын

I am facing this situation. So when I start the tomcat from the eclipse, it is working fine. But when I start the tomcat from startup.bat inside bin folder, I am not able the access the WSDL. Do you know why?

@CodeJava 2 жыл бұрын

I don't know. What is the error? 404 or 500?

@mukunds3144 2 жыл бұрын

@@CodeJava There is no error. It is only looking into webapps folder. Even I copied from wtpwebapps but still not picking it up. But anyway we can leave this here as I was only curious to know why it is behaving differently. Thanks a lot.

@mukunds3144 2 жыл бұрын

Thanks for your video. But Why JDK 8? We cant do this using JDK 11?

@CodeJava 2 жыл бұрын

it's because only JDK has the tools for generating Java code from WSDL.

@mukunds3144 2 жыл бұрын

@@CodeJava Yeah but my question why not JDK 11?

@CodeJava 2 жыл бұрын

@@mukunds3144 because JDK 11 doesn't have such tools

@mukunds3144 2 жыл бұрын

@@CodeJava Oh Okay Thanks.

@customcustom5226 Жыл бұрын

You set jdk 11 but why did you used java 8 library?

@CodeJava Жыл бұрын

it's because only JDK 8 has the wsimport tool. The newer versions remove it.

@asaithambir6550 Ай бұрын

Hi, How can we disable xxe injection for this ws?

@CodeJava Ай бұрын

I do not know. Can you show me?

@aduc8386 2 жыл бұрын

dude! are u VNese??

@CodeJava 2 жыл бұрын

yes, I am.

@aduc8386 2 жыл бұрын

@@CodeJava biết ngay mà haha

@jessicawang5363 3 жыл бұрын

Content is good, pronunciation needs improvement

@CodeJava 3 жыл бұрын

thanks. this video was made in the early days - now my English is better, though I need to improve more.

@tuanluong7338 3 жыл бұрын

@@CodeJava your English is fine. You are not English teacher

@yesmineabid5627 2 жыл бұрын

@akhil.o_s Жыл бұрын

SEVERE: Error configuring application listener of class [com.sun.xml.ws.transport.http.servlet.WSServletContextListener] java.lang.ClassNotFoundException: com.sun.xml.ws.transport.http.servlet.WSServletContextListener This happened when I exactly followed your steps What did I miss to do

@akhil.o_s Жыл бұрын

To solve this problem : right click on project name select deployment assembly choose add select java build path entries then select maven dependencies and finally click finish

@CodeJava Жыл бұрын

thanks for sharing your solution!