Construction and Working of He-Ne laser

Рет қаралды 102,192

3 жыл бұрын

This video explains Construction and Working of He-Ne laser. After explanation of construction, role of Helium in He-Ne laser is discussed. Answer to the question why the proportion of He:Ne is 10:1 is also discussed. Working is discussed on the basis of energy level diagram and at the end, merits and demerits are discussed in brief.
Sound credit : Chaitanya

Пікірлер: 79

@your_only_kouhai 7 ай бұрын

I passed my semester exams because i watched your videos

@sujalkumarsangem9619 2 жыл бұрын

Thank you sir, u gave a very comfortable class sir . I think all the people who see this will understand very quickly including me....

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Most welcome.. and best luck..👍

@zk-fc4so 3 жыл бұрын

best video for understanding He Ne laser action.. Thank you

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Thanks🙏

@Muskanperveen07 5 ай бұрын

Thank you sir ❤ I am really looking for such type of explanation thanks again😁

@lavanyam270 7 ай бұрын

Well explained all the topics👏. Thank you sir.

@ramakrishnasrram6712 Жыл бұрын

Simple and perfect explanation sir 👌 Thank you so much!

@EngineeringPhysicsbySanjiv Жыл бұрын

Most welcome.. Glad it helped you 🙂

@Tarunkumar-ff8sb 3 жыл бұрын

Hi sir your videos are really helpful to me in my preparation Thank you sir

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Thanks

@jayavishwanathraut3115 2 жыл бұрын

Sir you explain in such manner that all concept are easily cleared

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Thank you for the complement..

@shounaksarkar1480 2 жыл бұрын

I like your lucid way of explanation.

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Thanks.. please share with ur friends also

@user-fz6er8mh3c 7 ай бұрын

thanks sir🥰🥰 It's so helpfull in exam time😍🥰😇😇🤗🤗

@sujathak8101 11 ай бұрын

Excellent explanation sir

@Manishamanu06 Ай бұрын

Well explained sir👏👏

@mayankagrawal6109 2 жыл бұрын

Very well explained thank you very much sir for this video 😀

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Thank you

@jackhammer9489 5 ай бұрын

For any reason the sound is not clear of your videos. Sometimes it gets difficult to understand what you are saying. Except that I found your class is really helpful.

@Health_asset 2 жыл бұрын

OP explaination sir, many many thanks sir 👌👌

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Most welcome..

@deepakrajpoot2536 Жыл бұрын

Great explanation ...thank u very much sir..

@EngineeringPhysicsbySanjiv Жыл бұрын

Most welcome and best luck 👍

@Tooba-1218 4 ай бұрын

Great video. I have one question though, how come heavy Ne atoms gets excited by light He atom ? And eventhough the energy levels are at same level, does not it means Ne atoms will also require same amount of energy to gets excited because obv He atoms will only dissipate energy equivalent to what they have absorbed as a result of exvitation.

@thorer6778 3 жыл бұрын

Very well explained Greetings from germany

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Thanks a lot.. keep watching..

@jacobvandijk6525 3 жыл бұрын

I always think that lasers are useful (too) because of the energy they create. But how much is the net gain?

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Energy is not created. It is converted from one form to other. The efficiency of laser is very low..

@jacobvandijk6525 3 жыл бұрын

@@EngineeringPhysicsbySanjiv I wasn't aware of that. Thank you for your reply. This link confirms what you say: www.rp-photonics.com/wall_plug_efficiency.html

@user-fz6er8mh3c 7 ай бұрын

thanks sir It's so hepfull in exam time🥰🥰😍😍🤗🤗😇😇😇😇😇🙂🙂😊😊😊

@drsumankhanal 2 жыл бұрын

Great video. I am curious what would happen if partially reflecting mirror is replaced by a plane glass?

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Then photons wont be reflected back, all photons will be transmitted and amplification will stop. So laser beam will not be intense..

@ezkodes 3 жыл бұрын

Explanation 🔥🔥

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Thank you..

@shashankravibhagwat1 3 жыл бұрын

Amazing sir!

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Thanks a lot!

@srikanthchebrolu1091 2 жыл бұрын

Well demonstrated 😊

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Thank you

@yash-xx2pu 2 жыл бұрын

thank you so much sir !!

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Most welcome.. share with friends also..

@adityapulipati1221 10 ай бұрын

Not admitted in somaiya college but getting benefit wow thats amazing

@learner0010 2 жыл бұрын

Excellent explanation sir!🙂

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Keep watching

@blazeindian667 Жыл бұрын

Very well explained sir

@EngineeringPhysicsbySanjiv Жыл бұрын

Thank you..

@goldenera2210 2 жыл бұрын

Best explanation 😊

@EngineeringPhysicsbySanjiv 2 жыл бұрын

Thanks a lot 😊

@jabbariqra6097 Жыл бұрын

Why metastable state has more life time than other excited state?

@EngineeringPhysicsbySanjiv Жыл бұрын

It is just the lack of efficient processes for depopulating a certain level. For example, spontaneous emission may be prohibited by selection rules, i.e., by certain symmetries of wavefunctions.

@jabbariqra6097 Жыл бұрын

@@EngineeringPhysicsbySanjiv thanks sir ,God bless you

@CodewizardSumit 19 күн бұрын

🔥🔥

@jkfantasyworld Жыл бұрын

Thanks a lot

@EngineeringPhysicsbySanjiv Жыл бұрын

Welcome

@abhionyoutube792 3 жыл бұрын

Sir make a video on Ruby laser if possible...

@EngineeringPhysicsbySanjiv 3 жыл бұрын

will try to upload

@abhionyoutube792 3 жыл бұрын

Thank you sir, also make a video on Nicole prism sir

@EngineeringPhysicsbySanjiv 3 жыл бұрын

Noted.. will try..

@abhionyoutube792 3 жыл бұрын

@@EngineeringPhysicsbySanjiv thank you sir

@user-bi7hl4lm4h 3 ай бұрын

🤩🤩🤩

@dr.mrs.archanasrivastava4062 Жыл бұрын

when spontaneous emission takes place between E3 to E2 in Ne atom, then what is the role of emitted photon.

@EngineeringPhysicsbySanjiv Жыл бұрын

spontaneous emission results into releasing the energy in the form of a photon, which is emitted in a random direction and does not contribute in light amplification.

@dr.mrs.archanasrivastava4062 Жыл бұрын

@@EngineeringPhysicsbySanjiv Thank you Sir. That means photons emitted due to transition between E3 to E2 are incoherent.

@rohanchoudhary2115 3 жыл бұрын

sir ruby laser per video bna dijie

@EngineeringPhysicsbySanjiv Жыл бұрын

kzfaq.info/get/bejne/Y8B7m9uGrba3Z3k.html

@ajmal770 3 жыл бұрын

Sir pls do raman spectroscopy classes

@EngineeringPhysicsbySanjiv 3 жыл бұрын

will definitely try..

@ajmal770 3 жыл бұрын

Ok sir

@satyajeetpatil6899 Жыл бұрын

@saheligarai4063 Жыл бұрын

Sir please upload this notes...

@EngineeringPhysicsbySanjiv Жыл бұрын

Notes links drive.google.com/file/d/1Ikw8Z0T6GRiRNnNOcjAK5Awprm0m9pXt/view?usp=drivesdk drive.google.com/file/d/1DK4jO1E-8qEojxkqHrDOwsefhAQ9iqkv/view?usp=drivesdk

@hp10p35 9 ай бұрын

Notes please pdf

@EngineeringPhysicsbySanjiv 9 ай бұрын

Engineering Physics Notes links drive.google.com/file/d/1Ikw8Z0T6GRiRNnNOcjAK5Awprm0m9pXt/view?usp=drivesdk drive.google.com/file/d/1DK4jO1E-8qEojxkqHrDOwsefhAQ9iqkv/view?usp=drivesdk

@EngineeringPhysicsbySanjiv 9 ай бұрын

Engineering Physics Notes links drive.google.com/file/d/1Ikw8Z0T6GRiRNnNOcjAK5Awprm0m9pXt/view?usp=drivesdk drive.google.com/file/d/1DK4jO1E-8qEojxkqHrDOwsefhAQ9iqkv/view?usp=drivesdk