Heat Transfer (24) - Flat plate convection heat transfer coefficients

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Heat Transfer (24) - Flat plate convection heat transfer coefficients

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Күн бұрын

[Time stamps will be added in the future]
Note: This Heat Transfer lecture series (recorded in Spring 2020 & Spring 2022) will eventually replace the earlier Heat Transfer series (recorded in Fall 2015). The old lecture series had some errors and was lower quality.
Want to see more mechanical engineering instructional videos? Visit the Cal Poly Pomona Mechanical Engineering Department's video library, ME Online: www.cpp.edu/meo...
This lecture was recorded live at Cal Poly Pomona during Spring 2022. The textbook is "Fundamentals of Heat and Mass Transfer", Bergman et al., 8th Edition.

Пікірлер: 25

@emt4921 2 жыл бұрын

Thanks, CPP. I really hope that Dr Biddle finished this playlist before he retired. I'll be waiting for more videos.

@CPPMechEngTutorials 2 жыл бұрын

He did. The remaining videos will be released in the next couple weeks.

@ZalanK77 9 ай бұрын

One step is very painfully missing from this otherwise excellent presentation. To calculate the turbulent heat transfer over the plate h(x)=k*Nu(x)/x is to be used and that needs to be integrated and divided by the length. So, it becomes the mysterious h_avg=0.037*Pr^(1/3)*k*(rho/mu*v_inf)^4/5*L^(-1/5). In this the Reynolds number was already substituted by Re(x)=v_inf/nu*x=rho*v_inf/mu*x as it is a function of x. nu is the greek letter for kinematic viscosity, rho is the density and mu is the dinamic viscosity. Nu(x) is the Nusselt number at location x, h(x) is the heat transfer coefficient the location x.

@rzeeonthemic 9 ай бұрын

What is v infinite?

@ZalanK77 9 ай бұрын

@@rzeeonthemic The velocity far away from the plate, so basically the velocity of the undisturbed fluid.

@chichorro1000 Жыл бұрын

24/37 let´s go! thank for the content guys!

@CPPMechEngTutorials Жыл бұрын

Keep going!

@vicentereiman368 5 ай бұрын

This professor is amazing! Thank you so much sir!!!

@gajendrasingh_384 11 ай бұрын

Great lecture watching from India ❤❤

@CPPMechEngTutorials 11 ай бұрын

Great comment! ❤

@cathysunny1804 2 жыл бұрын

Thank you for keep updating this series!

@CPPMechEngTutorials Жыл бұрын

You're welcome. Not even a pandemic could stop us from completing the series.

@CarlMichaelAAdame 2 жыл бұрын

Thank you very much, cpp

@mohammadaiman4710 Жыл бұрын

what is eqn for hx for turbulent?? The lecturer didn't show in this video. Can somebody help me.

@habibbolgiba8095 Жыл бұрын

I believe he derived it from the Nusselt number, by making hx the subject, therefore multiplying Nu by K and dividing by x. Not sure thou

@willcolletti4357 8 ай бұрын

he kept referring to NU bar as h bar, is there a reason for that

@vladislavbakovic279 7 ай бұрын

average over bar means average

@isk3804 Жыл бұрын

Dr. Biddle is an excellent instructor, however cameraman ruins it a lot!!! :(

@CPPMechEngTutorials Жыл бұрын

The issue got fixed in future lectures.

@jeffsmith7247 Жыл бұрын

@@CPPMechEngTutorials you always say that. lol, Here I am in future lectures..... :/

@CPPMechEngTutorials Жыл бұрын

@@jeffsmith7247 Hang in there... I swear it gets better.

@jeffsmith7247 Жыл бұрын

@@CPPMechEngTutorials haha the last video better be a beauty

@CPPMechEngTutorials Жыл бұрын

@@jeffsmith7247 If it's not, you'll get a full refund.

@Manuel-of7et Жыл бұрын

Great lectures professor. However, the camera man needs to be drug tested.