Indeed.

👍🙏

Thanks

Thanks.

Thanks for taking the time to comment.

Good points . Thank you.

👍

Thanks.

Thanks Michael.

Thanks for sharing your thoughts.

Thanks.

Thanks

Thanks.

🙏😊

Thanks for pinout Srinath. The original and my treatment assume a linear inductor (could be air cored).

Thanks.

Thanks.

Indeed. Thanks

😊

👍

Thanks for sharing.

Thanks.

In KZfaq search window look for "sam ben-yaakov inductor" you will find some relevany videos

Thanks.

if the choke and cap produce at start a high enough voltage for generating plasma the lamp will ignite. In fact, there were (I don't know if still available) some lamps with no filament (which is used to lower the voltage needed for breakdown)

Once once understand the fundamental first principles, everything comes into place.

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AS I was explaining in video, if you consider an initial condition in which there is no current in the inductor, then after switch closure the current is in the direction of di/dt. Thanks for illuminating this.

Well, Well Well, Electronics Tutorials. You obviously did not bother to watch, study or understand my video. 1. “The circuit clearly shows the characteristics of a pure inductor, there is no series resistance” ??? The fact that the current reaches a fixed value means that there is a resistance. 2. “Eventually steady-state conditions apply, the coil acts as a simple piece of wire, maximum current flows from the battery source,” ??? What the heck is “the coils acts as a piece of wire”? What the heck is “maximum current flows from the battery source“? Is the “simple piece of wire” with no resistance? Then the current will continue increasing. Non zero resistance? Here is your resistor. 3. “Opening of the switch has the reverse effects.”??? Opening the switch causes the current to drop at a constant slope? This is the worst nonsense of all. So why there is a need to protect coils when turned off? You obviously have no experience whatsoever in electrical engineering. Unless you retract, I will prepare another video on the many ignorant assertions in your response.

what!?? what steady state if there is no resistance? May I suggest you read a "real" textbook on basic circuit theory before writing any "tutorial" on internet.

Sam doesn't need my help defending his explanation, but I can't stop myself. Think about what you just said, Electronics Tutorials. Have you studied calculus at all? Think about Vl = L*dI/dt. Do your KVL. Vbat - L*dI/dt = 0 for the case of no resistor. Vbat/L = dI/dt. Since Vbat and L are assumed constant, then dI/dt is also constant, meaning it does not change. the 'd' in dI/dt is to remind us of "delta". ΔI/Δt = Vbat/L . ΔI = (I_t2 - I_t1), Δt = t2-t1 .. So (I_t2-I_t1)/(t2-t1) .. Where have we seen this form before? Oh right, that's our slope for the line formula, m = (y2-y1)/(x2-x1). y=m*x+b, with m = dI/dt. So, if m is constant, does y = m*x+0 (we assume we start from 0 current so b is 0) ever turn? Try plotting it. Tell me if it ever stops increasing. Put it into wolfram alpha, or a calculator. Try increasing x, (which is time, y is current as a function of time) higher and higher. Does the function ever stop increasing? When does it plateau? Because this is the basic expression for a DC voltage source in series with an inductor without resistance. Your statements unfortunately show a lack of understanding for the fundamental mathematics we use in analysis, putting aside understanding of electrical components. I also think you might not be realizing that there is no discrete resistor component, and that one is not required in order to have resistance. Wire has resistance (let's ignore superconductors as they are not unfortunately not practical in typical electrical applications). Inductors are made up of coils of wire. Those wires have resistance, therefore it is an integral part of the inductor construction itself. It is unavoidable. We cannot physically create an inductor without resistance.If you physically measure a /real/ physical inductor with no added resistor, you will find the model I described lies to you. It needs another term. That term is R for resistance. Of course, every circuit has parasitics. Your capacitors contribute to inductance, so we reduce lead spacing. EMC capacitors are very small and placed just so to reduce loop size or they will generate more parasitic inductance. Capacitors have an ESR among other parasitics as well that is very important to consider in circuit design. Resistors have parasitic capacitance and contribute to inductance as well by forming part of a loop (and circuits are loops, hence the name). It is key to understand that we really can't separate the three circuit component models from each other in the real world. We sometimes or often choose to ignore them when they do not significantly impact the purpose/performance of the circuit vs the model, but they're still there. You don't need to have a device titled an "inductor" to have inductance, you don't need a device titled a "resistor" to have resistance, and you don't need a device titled a "capacitor" to have capacitance. These names are simply to tell you what circuit behavior is intentionally emphasized in the design of the component. Anyway, hopefully I didn't say anything inaccurate. I'm also willing to learn and correct myself if I did.

@@Sevalecan 👍 Thanks for participating in conversation.