Deflection of beams 10 //Macaulay’s method//simply supported beam with two/2 point loads

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Deflection of beams 10 //Macaulay’s method//simply supported beam with two/2 point loads

Рет қаралды 75,959

Mech PM

Күн бұрын

Пікірлер: 75

@siyakimasti6969 Жыл бұрын

Thank you so much for this video.

@AlbertEinstein-he8hk 3 жыл бұрын

so wisely presented....you have got a new subscriber.

@mechpm 3 жыл бұрын

Thank you so much ❤️

@nanipsudharsanraosudharsan1982 Жыл бұрын

Good morning sir through see your video concept is very easy to understand

@mechpm Жыл бұрын

thank you🙏

@gopalpatil2968 2 ай бұрын

thank you sir Fantastic work for student

@mechpm 2 ай бұрын

welcome 😊

@kavishjayakumar8095 4 ай бұрын

Hi, you know how you separated the deflection equation into each separate part of the beam, why does the constants comes into the first part? Thanks

@mechpm 4 ай бұрын

Because if we add in first portion then it can be accommodated in any padt of beam. If you add constant in last portion then for first portion you need to add different constants

@incometaxAmar 2 жыл бұрын

Thanks sir u clear my doubt

@mechpm 2 жыл бұрын

welcome 🥰

@atzilut540 2 жыл бұрын

is dy/dx shear force? and can we find the max moment by integrating that using these equations? Because by plugging in the (1) equation into my graphing calculator I tried finding the maximum moment, but the location and magnitude seems very incorrect.

@mechpm 2 жыл бұрын

dy/dx represents slope of beam. if you want to find Shear Force then you have to differentiate Bending equation. means you have to find d3y/dx3. anyway I have solved all type of problems in this channel so if you want to learn then go to playlist and watch from 1st video

@M.S.U_Engineering Жыл бұрын

Nice explanation sir 😊

@mechpm Жыл бұрын

Thanks and welcome🙏

@saziyasheikh722 3 ай бұрын

Ager maximum slop find karne ko bola hoga ager to kya hum c1 ki value jo ayegi vhi consider karaygay

@tania1090 6 ай бұрын

Thank you so much sir 😊

@rajeshjayasetti993 2 жыл бұрын

Sir 3m length above the (x) distance but (x) value is 2.8 how is it 🤦

@sasankmedicharla1493 8 ай бұрын

13:43 how to re arrange

@mechpm 8 ай бұрын

Just open the bracket and expand (x-1)^2 then you can add similar terms

@professor4304 Жыл бұрын

Sir at 2:51 in Mx equation we only considered left part of the x like ra , 48kn & 40kn but we didn't consider the right side part rb in the equation. Don't we need to consider that ?

@mechpm Жыл бұрын

I think there is no need because you can move x distance up to last end of the beam plus when you are calculating deflection in any portion you have to consider only left side forces. in case of overhanging or cantilever beam you may have to consider but in SSB when x= L moment will become zero around that load anyway. you can watch this video for basics of Maycaulay's method kzfaq.info/get/bejne/rbx2gt11r6ycZJs.html

@professor4304 Жыл бұрын

@@mechpm thank u for ur reply sir I understood now after watching the video u suggested 🙂

@mechpm Жыл бұрын

welcome and thanks for appreciation❤🙏

@ckkoech1519 2 жыл бұрын

you made it simple👍

@Akashsky0007 4 жыл бұрын

Nice video

@mr.nobody8784 2 жыл бұрын

Great work ❤

@rohitVERMA-dy4nd 3 жыл бұрын

Helpful video

@mechpm 3 жыл бұрын

Thank you so much

@shreekaalikamba9280 2 жыл бұрын

How to find slopes at each support sir

@mechpm 2 жыл бұрын

dy/dx represents slope from equation 2 you can find it at different points like x=0 at left support and x= Length of beam at right support

@king56789 2 жыл бұрын

Which book u r referencing????

@mechpm 2 жыл бұрын

indian books

@Vikas_Urn 4 ай бұрын

Why didn't take 3rd section in making Quadratic equation

@mechpm 4 ай бұрын

Because in Macaulay's method you have to consider upto that section only where deflection is to be calculated. you can watch from 1st video of this method from playlist to understand it better.

@arjunsaini2207 3 жыл бұрын

For slope calculation why didn't u take (x-3)^2 into consideration?

@mechpm 3 жыл бұрын

Because In this method you write equation for all loads and supports in one line but during calculating deflection or slope we have to consider terms upto that point only where you are calculating slope. In this case the termed I neglected is towards other side of the maximum slope. We have to consider only terms or loads which are left to maximum deflection point. I hope you got it still if you have doubt I will try to clarify

@arjunsaini2207 3 жыл бұрын

@@mechpm ok...if we have another load of same 48KN at a distance of 4m from left end than should we have to consider this 3rd load in slope calculation?

@mechpm 3 жыл бұрын

No because from symmetry you can guess that maximum slope will occur at 3 m from left so you have to consider all loads only upto 3m.so we will not include 48 kn at 4m.

@arjunsaini2207 3 жыл бұрын

@@mechpm ok thank you...👍

@mechpm 3 жыл бұрын

Welcome 😊

@Akashsky0007 4 жыл бұрын

Good job

@redhi5381 3 жыл бұрын

Sir... Good presentation... Can we use the formulae to find this... Wa2b2/3EIL for max deflection

@mechpm 3 жыл бұрын

You can't directly use this formula because this formula is used directly for single centric load on SSB. But you can use superimposition method of two SSBs with formulas wa2b2/3EI and for second beam wl4/48EI

@mechpm 3 жыл бұрын

For this you have to consider 2 beams with single load each then find deflections individually and then add both

@redhi5381 3 жыл бұрын

@@mechpm i try like this.. But my final answer is wrong

@mechpm 3 жыл бұрын

There may be done mistake but method is correct. You can read about superimposition method

@redhi5381 3 жыл бұрын

@@mechpm okay sir.. Thank you for your information.

@SunnyCreations803 2 жыл бұрын

Sir 30x²-163.33-24(x-1)² 6x²+48x-187.33=0 How to come in value sir Please explain this value sir

@mechpm 2 жыл бұрын

30x2 -163.33-24(x2+1-2x) = 30x2-163.33-24x2-24+48x =6x2+48x-187.33

@Udhav_786 Жыл бұрын

Thanks sir

@mechpm Жыл бұрын

welcome 😊

@palamarthigirijakumari7585 2 жыл бұрын

plz explain the moment area method

@mechpm 2 жыл бұрын

I have already explained in these videos. kzfaq.info/get/bejne/iqxhoMR0lrO0iYE.html kzfaq.info/get/bejne/pM6frc-E0ZytdY0.html kzfaq.info/get/bejne/bZmae6uC09G9n40.html

@palamarthigirijakumari7585 2 жыл бұрын

Bro

@mechpm 2 жыл бұрын

please share

@palamarthigirijakumari7585 2 жыл бұрын

@@mechpm kk bro

@sameermirashi21 6 ай бұрын

❤

@BhimKumar-tw6zr 28 күн бұрын

Moment minus me lena hota h sir formula me

@BhimKumar-tw6zr 28 күн бұрын

EI d2y/dx2= - M

@mechpm 27 күн бұрын

Yes it's convention but you can assume any direction positive or negative as per convenience

@RahulSharma-zo5wo 2 жыл бұрын

I am only confused in Boundary conditions, like in every Simply Supported beam we have to take X=0 , Y=0 / X=L , Y=0

@mechpm 2 жыл бұрын

you take like that because at ends beams are supported so they don't get deflected. please watch in playlist from start. I have explained

@atzilut540 2 жыл бұрын

13:37 "if you..." what?

@mechpm 2 жыл бұрын

if you convert KN-m3 to N-mm3 that is for terms within the bracket excluding 1/EI

@atzilut540 2 жыл бұрын

@@mechpm Oh gotcha. Can this be used with distributed load and points loads on top of each other? For every section I was observing I always included the distributed load if I was there. Is this how we are supposed to do it?

@davidemazzella8268 Жыл бұрын

Do you have the general formula?

@mechpm Жыл бұрын

As you know distance and laod can change and different situations can be provided in problem so it's better to know basic and how to solve it properly

@basicimproveskill.8501 3 жыл бұрын

×= - 48+-√(48)2 *4*6*187.33÷2*6 . How do you taken this values is over here in no. 2 , 4 , 6 especially . Can you please explain me.. Sir...How it come?? Or which formula did you applied here it.. Sir.

@mechpm 3 жыл бұрын

That's simple quadratic formula. it's x= -b +-√(b^2-4*a*c)/2a Where quadratic equation is ax^2+bx+c=0 Sorry by mistake I have written + in place of - in video

@manalichougule7299 Жыл бұрын

@@mechpm sir, but how did you get 2.87 as the answer? What are the steps ?

@mechpm Жыл бұрын

@@manalichougule7299 i just used standard quadratic formula. if you forgot how to do that you can watch following video kzfaq.info/get/bejne/iqube91jzrC3naM.html