Very good explanation of catenary equation. Thanks.
@schizoframia4874 Жыл бұрын
Interesting
@eggonwalterlewinsshirt10712 жыл бұрын
5:46 if you take derivative with respect to x then T1 will no longer remain perfectly in x direction as we initially assumed? Imagine closing in on the midpoint of segment.T1 will surely have a component in negative y direction
@tetrabromobisphenol Жыл бұрын
That's not the case if you are taking the derivative at the point x = 0. It may be true elsewhere, but picking x= 0 as the point to do the analysis makes all of this alot easier. Also remember, this is done in the limit as s -> 0, so the segment has infinitesimal length.
@omermuharremyagcoglu6398 Жыл бұрын
Thank you sir, great lesson...
@shubhodeepde39273 жыл бұрын
Well explained
@DinsDale-tx4br20 күн бұрын
9:40 Once upon a time I tried this problem I didn't know about hyperbolic functions and hence proceeded without Sinh. Using 'normal' trig and multiple substitutions the answer popped out in about 2 sides of A4 and a zillion square roots. This was 50 odd years ago as a teenager. I only mention it because these days folk even define a catenary in terms of hyperbolic functions which although succinct is not necessary. It took me 2 days at the time and I was embarrassed when asked why I hadn't used hyperbolic functions ... I simply has never heard of them.
@knowmore3169 Жыл бұрын
nice explained 😊😊😊😊😊😊
@DotPhysics Жыл бұрын
Thanks for liking
@ifrazali30523 жыл бұрын
Thank you so much
@GammaFZ2 жыл бұрын
nice
@omermuharremyagcoglu6398 Жыл бұрын
Sir, Please solve this problem with variational calculus...
@zsphantom52715 ай бұрын
bro said trust me that's okay 😂 10:29
@Humanwastaken11 ай бұрын
1:46 'i picked this point cus everyone else did it' caught me off guard 😂
@ayyu12 Жыл бұрын
So I’m a bit confused at this step 5:34. You’re considering an infinitesimally small element near the bottom of the curve, so that one of the tension forces is horizontal, and then equating forces. But this expression you get is only true for this element right? Because for the next element both the tension forces will be at some angle. Why are you differentiating both sides as if the expression is true for all elements?
@sundarnarayanan52823 ай бұрын
i think we never had made sure to make one tension to be horizontal for each and every element, the given expression of than(thetha) satisfies for all values of s and their differentiation never gave any relation for dT since T1 is a constant and we never involved the variable T as a function of any s or x or y