Element Deletion in Abaqus based on Continuum Damage Mechanics

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Element Deletion in Abaqus based on Continuum Damage Mechanics

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Күн бұрын

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Chapters 6 and 11 of the package are related to this tutorial.
Step by step tutorial for defining and using ductile damage model:
• Damage Analysis of Not...
Don’t hesitate to ask any questions you might have about the explanations presented in this video using the comments below. We try to answer all questions regarding the video details in the comments below.
in Continuum Damage Mechanics, damage propagation in the material is modeled by deletion of completely damaged elements. For simulating damage propagation, at first you must define damage initiation and damage propagation (damage evolution) criteria in property module. In addition to these settings, there are several options in Step and Mesh modules to have more control on the damage propagation analysis. In this video, these options and the effect of each of them on the simulation results are explained in detail.
Table of content:
- Status in Field Output request
- SDEG in Field Output request
- DMICRT in Field Output request
- Choosing the appropriate step
- Static general step settings for damage analysis
- Mesh design for damage analysis
- Element specifications in damage analysis
- Comparison of the effects of mesh module settings on the result of tensile test simulation
- Element deletion settings
- Force-Displacement curve of tensile test
- Element Deletion versus no Element Deletion
- Mises Stress-Equivalent Plastic Strain (PEEQ) curve for deleted elements
#tensile_test
#damage_analysis
#continuum_damage_mechanics
#damage
#ductile_damage
#Abaqus

Пікірлер: 28

@amrounesalah8706 11 ай бұрын

I want to express my gratitude for you sharing this amazing video.

@FemexIran 11 ай бұрын

Thank you so much. We have also These premium step-by-step tutorials for damage analysis: kzfaq.info/get/bejne/erWijMd9s6-wimw.html kzfaq.info/get/bejne/Zqh0mtafqNm0pmw.html kzfaq.info/get/bejne/js15dcme39Cyipc.html

@rasoolmokhtarihomami9169 3 жыл бұрын

Thank you very much for your explanation. Keep it up. it is perfect.

@hosseinmohammadtaheri1688 Жыл бұрын

Thanks for such a good video

@FemexIran Жыл бұрын

Hi. You are welcome.

@naderzamani5752 10 ай бұрын

Excellent presentation. You must have done a thorough research to get this much technical informationn about the ABAQUS implementation and the "secret" switches.

@FemexIran 10 ай бұрын

Hi. Thank you so much. Actually I am using Abaqus since 2012. Also there are some other tutorials about damage analysis in our KZfaq Channel. This one is a free tutorial: kzfaq.info/get/bejne/qbOXaqSLm6uRo2Q.html And these ones are two premium ones: kzfaq.info/get/bejne/erWijMd9s6-wimw.html kzfaq.info/get/bejne/Zqh0mtafqNm0pmw.html Premium ones are completely step by step. Also if you want to buy each of them or other premium tutorials, you can use the discount code mentioned here: kzfaq.info/get/bejne/g8mIibRh36q5lGQ.html

@alokdwivedi1949 2 жыл бұрын

VERY NICELY EXPLAINED THANK YOU CAN YOU PLEASE MAKE A VIDEO ON HOW TO GIVE MATERIAL PROPERTIES FOR DYNAMIC EXPLICIT MODELLING...ALONG WITH THE DAMAGE INITIATION AND DAMAGE EVOLUTION CRITERIA IN DETAILS... tHANK yOU

@FemexIran 2 жыл бұрын

hi. you are welcome. actually we explain what you mentioned in our online tutoring sessions. for more information about our services you can contact me via email.

@khtibariabderrahim6334 2 жыл бұрын

شرح لينا بالعربية والفرنسية الله يحفظك

@prakashthamburaja574 2 жыл бұрын

I have some questions on the element deletion usage in the Abaqus/Standard environment: since it is an implicit solver, how does Abaqus perform the solution of the implicit FEM equations and solve the deformation problem when the stiffness of elements become zero (when it is fully-damaged)? That is, how does Abaqus perform the implicit calculation and achieve convergence since the global stiffness matrix, K, becomes non-invertible due to elements having zero stiffness? Thank you so much for your kind explanation. By the way, your KZfaq video is fabulous!

@FemexIran 2 жыл бұрын

hi. you are welcome. actually you asked an important question. I think its answer is mentioned in the documentation. as far as I know, when the standard solver is used, Abaqus cannot set the stiffness equal to zero because of the convergence issues. so it set the stiffness to a very small value. actually the fully damaged elements will not be removed from the analysis completely. only they will be removed graphically. even by using this procedure, convergence issues can arise in the damage propagation analysis. but as there is no convergence issue in using the explicit solver, always it is the best choice for solving the damage propagation. this is the link of the preview of one of our premium tutorials about damage analysis via both of the mentioned solvers: kzfaq.info/get/bejne/erWijMd9s6-wimw.html during this tutorial, even by implementing all of the available tricks, the standard solver faces difficulty to solve the problem but the explicit solver does not.

@prakashthamburaja574 2 жыл бұрын

Thank you so much.

@FemexIran 2 жыл бұрын

@@prakashthamburaja574 you are welcome.

@enriquecernasaguilar7463 2 жыл бұрын

@@FemexIran Sir, this is exactly my question. I am using Abaqus Dynamic, Implicit. I noticed that Abaqus removes the fully damaged elements graphically, but a relationship still remains between elements even after fracture. My question is do these deleted elements continue to influence stress and strain after "deletion"? If so, how can we completely remove them and any effects they may still have? (Using only implicit solver)

@FemexIran 2 жыл бұрын

@@enriquecernasaguilar7463 Hi. As far As I know and according to my experience, the deleted elements in the Abaqus/standard solver, do not cause any problem or warning or error. Also no critical point is mentioned about them in the Abaqus documentations. If you have any problem in your analysis, you must find another source of problem.

@paradise_nsh Жыл бұрын

Thank you very much for this useful video.I have plotted misses to peeq in my damage model for one of the damaged elements.However the PEEQ in elastic region wasn't zero!DDoes this mean my model is not correct?

@FemexIran Жыл бұрын

Hi. You are welcome. Actually I must check this issue myself in your results. Also your model should be checked. I can do these in an online session. To use our online service, please send an email to me : mirzabozorg71@gmail.com

@muralikartheekss2932 Жыл бұрын

Hi very interesting video. I have a doubt. In a hollow particle and matrix system, I want to provide the damage model to the ceramic hollow particle and metal matrix. Can you suggest the material properties need to be considered along with the other parameters that you have shared in the video. Thank you.

@FemexIran Жыл бұрын

Hi. Thank you so much. We have a step by step premium tutorial about damage analysis using the ductile damage model. This is its preview : kzfaq.info/get/bejne/erWijMd9s6-wimw.html Also please read the description below the video. You can buy it to get the answer of your questions or you can use our offline or online services. To know about these services, you can send email to me. This is my email : mirzabozorg71@gmail.com

@Jade-jv6eq 2 жыл бұрын

hi thank you for sharing,how to get strain stress curve,average all element‘s strain and stress values?

@FemexIran 2 жыл бұрын

hi. you are welcome. actually there are to procedures to get the stress-strain curve : 1) using the force-displacement curve. force must be divided to the cross sectional area and displacement must be divided by the length of the specimen. so the nominal stress-strain curve is obtained. finally by using the plasticity equations, we can obtain the true stress-true strain curve. this way works only for the flat dog-bone specimens used for tensile test. 2) using the stress and strain data of a single element and combining them using the XY data tool. the second way is used in the video and it is more exact in comparison to the first way.