Candidate is good with her skills…she is making some of the topics which are bit complicated into very simple thing..that’s shows the experience 👏

Great video! Looking forward to more episodes from chakde interviews!

This video has a lot of great information, but as a beginner, I didn't fully understand some parts like the callback in the initial question, memoization, and other detailed concepts. I plan to watch it again after more practice, and I'm sure I'll understand everything better then. Thank you, Chirag Goel Sir.

Wow this is a fantastic addition. Thanks Chirag sir for this series and all the best for season - 2 🔥🔥🔥

Thank you sir for this a great series. One of the most awaited series.

This was actually a challenging question for first timer.

memoize problem was very good. learnt a new thing. very nice video.

If you put the questions in the description section of the video, it will super helpful to practice along, Please consider it from next videos !! Btw great choice of questions!!

very informative video...waiting for more

memoizeOne function will not work here if we call memoizeOne with different callbacks Eg: if we call memoizeOne with add , and also we call memoizeOne with sub results will be inconsistent because cache map is global one it will be shared by both add and sub callback memoizeOne calls So we need create cache map for each memoizeOne call and return arrow function from memoizeOne

The problem is that similar questions are being asked since about 3-4 years now. I understand that they do a good job on checking the conceptual knowledge of the candidate and reinventing the wheel might not be possible every time but majority of the candidates I’ve seen just learn the solutions by heart and sometimes can’t even deal with a follow up question. People should understand that this is not an exam where you would just empty your pockets when you see a question you’ve already solved or practiced and call it easy. Ofc the interviewer will be more experienced and can read between the lines. We can always try to focus on the concepts as opposed to just going through interview questions.

18:35 we need to create a closure (that holds the cache nothing but arguments and result) and return it ... then it will work independent of function that we are passing. until the functions are pure

I think we could use currying concept for the memoisation problem.

2021 me aapke git videos but were unable to understand but now again I am here after almost 3 years to watch machine coding round questions. Thanks for such awesome content

i hope this EP - 01 will be increase. thanks from bangladesh

Superb question and answers. Thank you chirag.

Kindly put the interview stuff in the description you doing great job ❤

Great insights!

Good interview, Loved it ❤

Loved it

Want more interview videos with different types of questions for experienced Frontend developer, thanks a lot for sharing this knowledge.

Great, thanks for making this video. Curious which platform you used for assessment?

18:35 I think we should concept of decorator function A decorator allow to add new functionality to an existing fun without modifying its structure and return modified fun

Great Video, Please schedule more mock interview for Senior developers also.

can object.entries not be used in the input output snippet?

please make sure you be consistent & complete it 🙏

First question in which foreach use have compile error. forEach() is not closed

❤❤❤ Great 👍👍👍👍

Thank you Chirag bhai pls do some videos on machine coding as well

Her explanation is great although the implementations are okay at best. First problem could be solved used Object.groupBy (I guess he was expecting that), the memorization problem took way too long and then the recursion problem doesn't need an array initialized out side the function. The overall interview also seemed easy for anyone with 2.5-3+ yoe.

Great interview, though in my country (Poland) such questions are asked in junior level interviews

Easy peasy 🔥🔥

Great Questions!!! @chirag.

🎉 Excited for Season 2 of Chakde Interviews! Mock interviews sound like a fantastic addition. As I'm working through Namaste Frontend System Design, I've learned so much from you, Chirag. Thanks a lot for the invaluable insights! 👏

I think this is fine from my side! Anyone can improve this? function memoised(fn){ const cache=new Map(); return (...args)=>{ const key=args.join('-'); if(cache.has(key)) return cache.get(key); const ans=fn(...args); cache.set(key,ans); return ans; } }

awesome sir...

Maja aagya sir 🎉

Thank you, Chirag Goel. Amazing video. I also tried to solve this problems by myself.

❤

Kudos to the interviewee

23:11 did you just cut off the video and told her the solution? 35:02 here too

where are curly braces in foreach question

CODE FOR QUESTION 4 :- const a = [1, 2, 3, [4, [5, 6]], 7, 8]; const func = (arr, output) => { arr.forEach((item) => { if(typeof(item) === 'number') { output.push(item); } else { func(item, output); } }) } const flattenArray = (arr) => { const output = []; func(arr, output); return output; } console.log(flattenArray(a));

Hello Sir, 1. How do you stay active and energetic always? 🤔 2. Can we use internet in machine coding rounds if we dont remember the syntax? Thank you,

Come Satuarday. I leave everything to watch Chirag's video at 10AM.

the memoize one is the challenging one and she tackled it very well......btw how i can give interview to you ?

Overall that's a good interview. Optimized solutions are- Q 2. We can use closures here as mentioned by him will looks like - function memorizeOne(fn){ const cache = {}; return function (...args){ const key = JSON.stringify(args); // Creating unique keys because objects are reference type if (key in cache) { console.log("Using memoized result"); return cache[key]; } else { console.log("Calculating result"); const result = fn(...args); cache[key] = result; return result; } } } const add = (a, b) => a + b; const memorize = memorizeOne(add); console.log(memorize(1, 2)); // Calculates result: 3 console.log(memorize(1, 2)); // Uses memoized result: 3 console.log(memorize(2, 3)); // Calculates result: 5 console.log(memorize(1, 2)); // Uses memoized result: 3 Q 3. Her solution was also good but here I used reduce method const obj = [ { key: 'Sample 1', data: 'Data1' }, { key: 'Sample 1', data: 'Data1' }, { key: 'Sample 2', data: 'Data2' }, { key: 'Sample 1', data: 'Data1' }, { key: 'Sample 3', data: 'Data1' }, { key: 'Sample 4' } ]; function groupBy(arr) { return arr.reduce((value, item) => { const { key, data } = item; if (!value[key]) { value[key] = []; } value[key].push({ key, data }); return value; }, {}); } const output = groupBy(obj); console.log(output); Your explanation of questions are great Krupa. Will wait for next part of the series.

Bro, title to shi rkh lete..she said she has 2 years of experience and you mentioned 4.5 years in video title...phle 1 min me hi video ki authenticity smjh aa gyi

Sorry to point out , but first Output based code won't run , there should be one closing ')' after console.log(x). Other than that her explanation was great 👍🏻

CODE FOR QUESTION 3 :- const add = (a, b) => a + b const memoizeOne = (add) => { const map = new Map(); return (a, b) => { const obj = { args: [a, b] } if(map.has(JSON.stringify(obj))) { console.log('Add function is not executed: previous result is returned -> ', map.get(JSON.stringify(obj))); } else { const output = add(a, b); map.set(JSON.stringify(obj), output); console.log('Add function is called to get new value -> ', output); } } } const memoizeAdd = memoizeOne(add); memoizeAdd(1, 2); memoizeAdd(1, 2); memoizeAdd(2, 3); memoizeAdd(2, 3);

thank you

function memoize(fn) { let memo = new Map(); return function() { const context = this; const args = arguments; if (memo.has(args.toString())) { console.log("return from memoize"); return memo.get(args.toString()) } let result = fn.apply(context, args) console.log(result); memo.set(args.toString(), result); return result } }

all things are great but how to prepare for these kind of question when I google I mostly see theoretical question only

i am a 1 yrs experienced guy but feels like having 6 or 7 years of experience 😢. There was a time where there is less competition for skills for software jobs, now people are having enough skills but very hard to get a job 😕

Flatten array was asked to me in interview with ServiceNow ❤

let obj = [ { key:"sample 1", value:"d1" }, { key:"sample 2", value:"d1" }, { key:"sample 1", value:"d1" }, { key:"sample 3", value:"d1" }, { key:"sample 4", value:"d1" }, ] let output = {} obj.forEach((item,idx)=>{ if(output[`${item.key}`]){ output[`${item.key}`].push(item) }else{ output[`${item.key}`] = [item] } }) console.log(output)

a lot to take away by watching this video.

Can you asked how to browser render html code?

Will this type of questions asked to freshers ???

sir please next video for freshers

Hi Chirag, I'd love to give mock interview with you if you are taking candidates for subsequent videos. Let me know. Thanks

Clement mihailescu came in my mind while watching this video. 😅

Her sister is a Indian cricketer Jemimah rodrigues

she have 4.5 years of experience and you ask him this basic questions.🙄

CODE FOR QUESTION 2 :- const obj = [ { key: 'Sample 1', data: 'Data1' }, { key: 'Sample 1', data: 'Data1' }, { key: 'Sample 2', data: 'Data2' }, { key: 'Sample 1', data: 'Data1' }, { key: 'Sample 3', data: 'Data1' }, { key: 'Sample 4', data: 'Data1' }, ] const normalize = (obj) => { let output = {} obj.forEach(({ key, data }) => { if(!output.hasOwnProperty(key)) { output[key] = []; } output[key] = [ ...output[key], { key, data } ] }) return output; } console.log(normalize(obj))

Please dont get my hopes up...please tell me these are not the questions asked in a real 4+ exp interview I feel these are too easy, maybe for around 1-2 yrs exp?

Sir I am searching for a Frontend Developer job please help me sir if you have any vacancy Thanks

is she really 4.5 year experience, looks like fresher.🧐

4.5 exp , memorised Question takes hardly 3-4mins

🤣🤣🤣

flattened array simple solution : const a = [1,2,3,[4,[5,6]],7,8]; const newArr= a.flat(2); console.log(newArr);

Great video!!, Thank you. and small update in memoization, if combination of arguments changed that has to be handled. ✌ // Memoization const hashMap = new Map(); function memoizeAdd (fun) { return function (...arg) { const key = arg.join('_') const reverseKey = arg.reverse().join('_') let result = '' if (hashMap.has(key) || hashMap.has(reverseKey)) { console.log('from memo') result = hashMap.get(key) || hashMap.get(reverseKey); } else result = fun(...arg); hashMap.set(key, result) return result; } } let addTwoValues = (a, b) => a + b; const addNumber = new memoizeAdd(addTwoValues); console.log(addNumber(2,3)); console.log(addNumber(2,3)); console.log(addNumber(3,2));

I am also starting Frontend Interview Preparation, with an amazing group where we discuss important questions in Zoom meetings regularly. if anyone who is really seriously wants to join let me know.(MERN with JavaScript)

This is not at all a real scenario in an interview even freshers interview are not taken like this anymore please don't prepare according to this interview example this sort of interview are used to happen in 2016 to 2019 only even freshers code better than this nowadays so if you want a job and want to really crack a interview please don't refer this as good interview yet you can refer it as a easy mock interview

seems like scripted interview for youtube and views

console.log('A'); setTimeout(()=> { console.log("B") },[]) ['C','D'].forEach(element => console.log(element); console.log("E") there is no bracket closing it will show error right

In this code: console.log('A') setTimeout(() => { console.log('B') }, 1000) ['C','D'].forEach((x )=> console.log(x)) console.log('E') // Output: 1 Showing Type Error when the code ['C','D'].forEach((x )=> console.log(x)) executed due to semicolon not there end of setTimeOut().

function memomization(fn) { let results = {}; return function(...args) { let cache = JSON.stringify(arguments); if(!results[cache]) { results[cache] = fn(...args) return results[cache] } return results[cache] } } function add(a,b) { console.log("calling .... ") for(let i = 0;i

Hi, I came here becuase of random suggestion on utube,although i hate utube algo becuase they show me irrelevant most of time but this time it landed me on this page and I m happy and I m big fan of akshay saini and now ur also apart from that i m not that experienced guy as the cadidiate is ,she is damn good but i figured out this solution ,if u can check please give me ur feedback const addSum=(a,b)=>a+b; function memoizedFn(fn) { let cache={}; return function(...args) { let key=JSON.stringify(args); if(cache[key]) { console.log("result is already there") return cache[key]; } else { let result=fn(...args); cache[key]=result; return result; } } } const memoizedSum=memoizedFn(addSum); console.time(); console.log(memoizedSum(3,5)) console.timeEnd(); console.time(); console.log(memoizedSum(3,5)) console.timeEnd();