You’re famous in our university in Saudi Arabia 🇸🇦 Your lectures are understandable and so easy❤️👌 thanks for making Bioc easy for us.

My friend right now I'm a student and I'm broke af, but the moment I graduate ad I get a job I'm fucking going to hit that 200$ donation button, thank you for the immense help you are giving us, *ak lectures is the best!!* a big hug from Italy :)

Your lectures are literally on par with my biochemistry lectures haha, your lectures are a lot easier to understand. Thank you!

Saved my day again, by the way thank you so much literally, all the students in my university watch your lectures and I got all my friends to watch your lectures too , keep up the good work ❤️

I really love this channel. it makes things so easy to learn...I like the lecture methodology...

waw waw waw ... thank you so much you bro deserve more than 400K subscribes ,, you deserve to talk on the red carpet

Your tutorials are amazing, tnx god for ppl like you !!

You're the real MVP!!

if i was taught like this from begining i would be a very very intelligent student. but sorry to say that our teachers have a lot knowledge but they have not the potential to teach like this. thank you sir . love from india.

what a lovely and clear your language. thank you very much

Wow …😱😱what a great lecture thank you❤️

You just make so much sense. Thank you!

Thankyou thankyou thankyou to universe for making u sir

The best ever 🙏🙏🙏🙏🙏🙏u are such a blessing to us

best so far n till now

Great work :)

Hi, thanks for this lecture about Thermodynamics of chemical reactions. I have a small concern with the upper right part of your board; It seems that you forgot the standard gibbs free energy (DelatG°). In fact "DeltaG = DeltaG° + RTLnKeq", and when reaching the equilibrium, DeltaG equals zero means that DeltaG° = -RTlnKeq (but does not mean that k1=k2). Otherwise all equilibrium constants would be equal to 1. In other words reaching the equilibrium allows one to quantify Keq, the equilibrium constant (which is also : Keq=k1/k2) and this value not necessarily equals to one. I would rather say that reaching the equilibrium means that k1*[substrate]=k2*[product] (forward velocity equals reverse velocity) The case you are mentioning, (i.e. when k1=k2) is just a particular case where reactants and products have the same level of energy and they are both at the same concentration at equilibrium (50% of reactants + 50% of products at equilibrium). Or that "k1=k2" means DeltaG = DeltaG° and DeltaG is independent of the temperature at wich the reaction takes place. But I agree with the overall message that at equilibrium the kinetic of the reaction has stopped and DeltaG equals zero.

Thank you, this was perfectly explained.

Love from india thank you sir

Please help me understand this. I was able to follow until the 11th minute where you say that the enzyme lowers the activation energy hence allows the reaction to reach equilibrium faster (this I understand) but now what confuses me is that you said that lowering of the activation energy results in stabilising the transition state. Now, won't stabilising the transition state mean that it will take longer for the equilibrium to be reached because the components of the transition state are no longer unstable - isn't it that instability is associated with readiness to react and stability takes a longer time to reach?

U are best bro My new.sir keep it up

Amazing! Thank you

Excellent 🔥

Thanks very much 🔥

Thank you so much

Is activation energy the difference between the energy of transition state and energy of reactants ?

you are amazing. thanks so much.

Good

what's the difference between endergonic,exergonic and endothermic , exothermic..thank u by the way,ur videos are so helpful

Really great video!! I finally understand this! Thaaaanks :) Best regards, Idil from Denmark

Thanks for explaning....You do a great job....i had a question regarding activation energy of surface chemistry... amongst physisorption and chemisorption,which of the two has greater activation energy?

Hello, I know this isn't directly related to the video but you have talked about this before in another video so I'd like to ask- does chymotrypsin also cleave at the c terminus of methionine? Or does it only cleave after large aromatic residues? Also, I read somewhere that similar to typsin, chymotrypsin only cleaves at the c terminus of large hydrophobic residues ** UNLESS THE next amino acid is proline- is this true?

You are choo cute AK..i love your lectures😍

really helpful.. thanku ..

great job !!!!!

Thanku sir

At 8:32, if you don't know what the transition state looks like, how do you make transition state analogs? Thanks again for the video :)

GREAT VIDEO

Can anyone tell me that what is K1 and K2 ??

thank u thank u thank u

5-stars

thanks you rock !!!

Brain goals

thank you so much! :)

I love you

Why no sound???

cant hear sound:(

No sound 🙁

No sound

😔No sound

👍👍👍👍

Sound

Why doesn’t this video have sound or is it just me🤨