Fair enough, perhaps a topic for a future video!

Great to hear, thanks for watching!

Thank you!

Great to hear - good luck with the course!

@@DrBenYelverton I’m currently preparing for IB physics exams rn, the lectures are shockingly terrible. You think this channel would be a good substitute?

@@peterpoli2839 I have a couple of videos that are relevant to the IB course, but as a relatively new channel I don’t have anywhere near enough content yet for this to be a viable alternative to lectures. The best advice I can give for exam prep is just to do as many past papers as you can. I know it’s annoying that there are no mark schemes (even when I was supervising I didn’t have access to such things) but you can often get a good sense of whether you’ve answered a question correctly (e.g. many questions are “show that”; you can also check things like dimensions and whether the order of magnitude of your result is sensible). The way I always did things was just to try exam questions and look things up in the lecture notes when I didn’t know something, rather than try to learn all the theory first and then test myself. While the lectures are not always great, the lecture notes are generally pretty good and contain everything you need to know.

​@@DrBenYelvertonWhat evidence is there against the geocentric model called the Neo-Tychonic model in which the planets revolve around the sun, but the sun revolves around the earth in the center?

@@moneyheist_- so much 😂

Thanks!

Indeed, I've been meaning to do a video on this for a while!

@@DrBenYelverton looking forward to it!

It is certainly not an easy thing to understand at first! Ultimately the key idea is that in a rotating frame, the rate of change of a vector quantity is different from what we might expect, because the basis vectors themselves are changing over time. See this video for the details: kzfaq.info/get/bejne/jMelp9Vi0aquZ2w.html

Yes, according to the formal definition the d/dt (S) operator is the "true" time derivative. Personally I do find the d/dt (S') notation to be helpful for conceptual understanding because it's the operator that gives the rate of change that would be observed in S'. But looking at it from a strictly mathematical point of view I can see how it might cause confusion.