Error Correction in Hamming Code

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Error Correction in Hamming Code

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6 жыл бұрын

Error Correction in Hamming Code
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Lecture By: Ms. Gowthami Swarna, Tutorials Point India Private Limited

Пікірлер: 36

@TutorialsPoint_ Жыл бұрын

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@sunnysiddela2313 5 жыл бұрын

How we take E3,E2,E1 POSITIONS

@guyswapnil 3 жыл бұрын

Reffer to previous video

@keerthikrishnab8808 3 жыл бұрын

your classes are amazing mam

@adelmahfooz4041 2 жыл бұрын

Amazing explanation. Within few minutes she made the whole concept crystal clear.

@rishabhjha921 6 жыл бұрын

Thanks It's clear as well as brief. That's what students want.😀😀

@Jay-st1hc Жыл бұрын

Amazing explanation mam

@yakkalaj.v.l.jeeshitha6446 Жыл бұрын

Thank you mam its very easy to understand mam

@manikantachittiprolu3164 6 жыл бұрын

Explanation is very nice..

@shubhamsrivastava6028 6 жыл бұрын

Mam, please make video on turbo codes.. Reed Soloman code Bcjr codes Hamming and Singleton bound

@sahithd3125 5 жыл бұрын

Don't follow this, she is teaching wrong method

@siripuramnikhil1739 3 жыл бұрын

Yes bro, numbering should make fromr right to left to the given code but made from left to right

@muthinenianjibabu1934 3 жыл бұрын

Parity positions lo error position check chestaamaaa? Please reply mam

@sunny-in9kd 3 жыл бұрын

Mam how we can know that we want to take 4,5,6,7 places for E3???? Can you please explain once???

@mayurgare 3 жыл бұрын

Hey, maybe you have got the ans. to your question, but i'll still tell it for others checking the comments. Ma'am had explained this point their previous video : (explanation of the point at the end of the video) kzfaq.info/get/bejne/i79gidOi3rCXhWg.html Hope this helps someone. Welcome !!!

@hotaru6765 5 жыл бұрын

good thanks

@kachamnikhil4868 4 жыл бұрын

How did we got e3,e2,e1 is 1 for odd parity??

@travelnlearn 5 жыл бұрын

Very informative video mam

@shaikabdulbaseer4211 4 жыл бұрын

mam in the given explaination it should be E4 not E3.....rest of it was great from u....

@akashnimi9666 2 жыл бұрын

No bro she is correct but she teach another way parity bit considering P1,P2,P3 and Data bits are D1,D2,D3 that's it

@alexpotts5417 2 жыл бұрын

Is it E3E2E1 or can we take as E1E2E3????

@crazygamerboysiva7334 3 жыл бұрын

How to take E1,E2,E3 values mam

@sayansrighosh8616 6 жыл бұрын

Well explained

@krishnaprasadperam6353 3 жыл бұрын

Thank you 😁

@yashwantjha8545 6 жыл бұрын

Mam if e3 =0 and e2 and e1 =1 then how to do? Plz send reply

@hotaru6765 5 жыл бұрын

than e1e2e3 would be 110, convert it to decimal you get 6. meaning you have an error at 6th place.

@sivasankaripalanikumar8151 3 жыл бұрын

Error=e3e2e1 =011 corresponding decimal number is 3 .. so the error it bit position 3

@lalblinktea 5 жыл бұрын

1:36 part is not explained...how and why is that?

@drunkenundergraduate2904 5 жыл бұрын

check and skip technique is used for e1 {1,3,5,7.....} where 2468 etc... are skiped for e2 {2,3,,6,7,,10,11,,.....} in this 45,89..... etc similarly for e3 this skips four numbers in between starting with 3rd parity number in our case its "4" hope u understand my friend .....>>

@khanfatima647 3 жыл бұрын

1100 is all so even so y u r adding 0

@khanfatima647 3 жыл бұрын

0 add q kiye

@bhavanamaurya4321 4 жыл бұрын

Mam plz 0011100101101 ka bta dijiye

@codeminatiinterviewcode6459 4 жыл бұрын

Okk i have solved this ques.... I can explain u in short... 1. We will require 5 parity bits at position 1,2,4,8,16.... Because the total length of the msg is 13+5 = 18... I got 5 parity bits by the formula 2^p > p+m where p is no. Of parity bits... 2. Then for calculating i have considered even parity and hence P1 = 1,3,5,7,9,11,13,15,17 P2 = 2,3,6,7,10,11,14,15,18 P3 = 4,5,6,7,12,13,14,15 P4 = 8,9,10,11,12,13,14,15 P5 = 16,17,18 HENCE final msg will be 110101101001011001

@khanfatima647 3 жыл бұрын

Even parity m

@khanfatima647 3 жыл бұрын

0000 is even