@TateJenson 9 ай бұрын
crystal clear!!! Thanks for your explanation...and excellent penmanship!
@buzzz241 7 ай бұрын
Nice method and clear video! Subscribed!
@MrFrmartin 6 ай бұрын
How I factored this was: 1) x (2x2 - 7x - 15) 2) x (x^2 - 7x - 30) # multiply A & C 3) x (x - 10)(x+3) --> x (x - 10/2)(x+3/2) #Factor, then divide the constants by 'A' Answer: x = 0, 5, -3/2
@phaganators 6 ай бұрын
Thank you
@fredrickeffi2143 5 ай бұрын
U made it look easy
@fr0sty_saiyan491 4 ай бұрын
That's not a quadratic tho, it's a cubic polynomial
@davidwebster9788 4 ай бұрын
It was quadratic after she factored out the x.
@jaggisaram4914 2 ай бұрын
❌(❌-5)(2❌+3)
@davidwebster9788 4 ай бұрын
Is there an explanation of the method using an a b c trinomial?
@MathlessonswithLinda 4 ай бұрын
Yes, it is this video and others like it. A trinomial is three terms, you only need to factor out the x as a GCF first.
@davidwebster9788 4 ай бұрын
@@MathlessonswithLinda I was refering to quadratics and understand what you mean by factoring. What I mean is given this trinomial, A*x^2+B*x+C, is there a general rational for the method and choices you described. Or, why not just use the Quadratic Formula.
@buzzz241 7 ай бұрын
Great Method! I’m having trouble solving 2x^2 - 6x - 10 with this method. What 2 factors of -20 sum to -6? 🤷♂️
@MathlessonswithLinda 7 ай бұрын
Keep in mind that not everything is factorable with integer solutions. You will need to use a different method, either completing the square or the quadratic formula.
@user-xq8dc9ex5j 7 ай бұрын
2x^2-6x-10=2(x^2-3x-5) :)
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