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Find the zero force members in a truss: example #2

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Engineer4Free

Engineer4Free

Күн бұрын

This engineering statics tutorial goes over another example on how to find the zero force members in a truss with a certain loading. The bottom left diagram is missing two ZFMs. They are the members that connect from the to the bottom of the truss 1/3 from the right. Link to that previous video is here: • Find the zero force me... I make note of it in the description there. Thanks @StryderEpic for reminding me to mention it in this video!
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Thanks for watching, I hope it helps!

Пікірлер: 38
@FioDavid767
@FioDavid767 4 жыл бұрын
in my first year of mechanical engineering, I got my first statics exam soon. Well, I love youtube and I love you for making these videos. You are helping a lot of us noobies!
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Awesome, glad you found my channel in your first year, hopefully you get lots of use from my vids throughout you're degree! Tell some friends too 🙂🙂
@raahimhadi4905
@raahimhadi4905 Жыл бұрын
How's final year of mechanical going
@19adhin
@19adhin 7 жыл бұрын
was able to do my entire assignment watching your videos, thanks a lot man !
@sarahguynup6946
@sarahguynup6946 5 жыл бұрын
Thank you for the explanations. It helped me a lot trying to complete my Statics class project.
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Awesome glad to hear it Sarah. Do check out engineer4free.com/statics for the rest of my statics videos if you haven't already!
@user-jz8fp3su7c
@user-jz8fp3su7c Жыл бұрын
Saved one more engineering student here lol. I don't know why now i believe in myself to get a good grade in the exam although I could not understand what is going on with my mechanics throughout the whole semester
@StryderEpic
@StryderEpic 7 жыл бұрын
For those from the previous video the bottom left diagram is missing two ZFM (as stated in his description). It is the members that connect from the to the bottom of the truss 1/3 from the right.
@Engineer4Free
@Engineer4Free 7 жыл бұрын
Thanks for posting this. I made a note in the description of this video mentioning it!
@StryderEpic
@StryderEpic 7 жыл бұрын
This video will definitely help me out in my trials today. I had trouble in my last exam determining a member's force, only to be told after the test by my teacher that it was a ZFM. I will not be tricked again. The marks are mine!
@zhiarsalahaddeen8095
@zhiarsalahaddeen8095 5 жыл бұрын
Thank you bro . You have done a good explanation !
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Thanks Zhiar =)
@bluebox2996
@bluebox2996 5 жыл бұрын
nice videos bro. so much better than my lecturer
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Thanks for the feedback!! =)
@DHNJKL
@DHNJKL 7 жыл бұрын
very useful for my competitive exam.
@Engineer4Free
@Engineer4Free 7 жыл бұрын
Good to know! Make sure you check out the whole free course at engineer4free.com/statics :)
@lisachaudhary4717
@lisachaudhary4717 3 жыл бұрын
thank you i will tell my result, of my test, which is tomorrow!!
@Engineer4Free
@Engineer4Free 3 жыл бұрын
Good luck!! And let me know how it goes =)
@smokeypillow
@smokeypillow 5 жыл бұрын
This is so helpful, thanks.
@Engineer4Free
@Engineer4Free 5 жыл бұрын
You're welcome, thanks for watching!
@abhijithraju4040
@abhijithraju4040 3 жыл бұрын
In the first diagram why didn’t you cancel out the 2nd member from right. It doesn’t have any internal forces .
@dylanbolton6297
@dylanbolton6297 Жыл бұрын
Thanks!
@sunnyd1747
@sunnyd1747 5 жыл бұрын
on the truss on the left, what was the justification for keeping the members of the acute triangle? the right side of the triangle is the third member of collinear members, why would it not go to zero?
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Hey Wesley, you're right. I missed it when I made the video, there is actually a note in the video description that mentions it. Good eye and thanks for contributing to the discussion!
@sunnyd1747
@sunnyd1747 5 жыл бұрын
@@Engineer4Free whoops i missed that!
@simulationbrodhah8542
@simulationbrodhah8542 3 жыл бұрын
@@Engineer4Free had the same doubt.😂😂😂😂
@chetanbagul887
@chetanbagul887 5 жыл бұрын
Nice one
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Thanks Chetan
@borislavvuletici1381
@borislavvuletici1381 2 жыл бұрын
Excellent presentation. Picture in the bottom left position has 4 joints in the bottom line. The 3rd joint from the left is connected to the top joint. Shouldnt this connection be ZFM?
@RajeshKumar-jl3ml
@RajeshKumar-jl3ml 4 жыл бұрын
One doubt right second vertical member also make system in unbalanced , then should be removed
@Engineer4Free
@Engineer4Free 4 жыл бұрын
Keep in mind when I erase the members, I'm not physically removing then from the structure. I'm just making it easier to see which other members will be ZFMs with the current loading scenario. They're a still there.
@chazconnacher6178
@chazconnacher6178 3 жыл бұрын
Hi, brilliant video, I just want to ask about 4:42, what observation can be made about zero force members if that load were just to be one of the two components - i.e either just in line with the collinear members or just in line with the perp. member. Additionality what observation could be made for the mentioned scenarios if the member were not perfectly perpendicular to the collinear members?
@Engineer4Free
@Engineer4Free 3 жыл бұрын
If the applied force was in line with the colinear members, then the third member would have to be a ZFM, as at that joint, there would be no other force acting in that perpendicular direction that could counteract an internal force in the perpendicular member. If the force was applied in line with the perp member, then the perp member would not be a ZFM. In fact, the internal force in the perp member would have to equal the magnitude of the applied load in that case. When an applied force is acting on a joint like thie at some orientation other than 0 or 90 degrees, then it's best to draw a coordinate axis of x' and y', where x' is parallel to the line created by the colinear members, and y' is perpendicular to it. Break down the applied force into its x' and y' components, and also any component (generally the third member) that is out of line with x' or y', and find its x' and y' components. the y' component of the applied force will equal the y' component of the third member. From there, you can use SOH CAH TOA to solve the actual magnitude of the third member's internal force if needed. I've got more videos on trusses here: engineer4free.com/statics see videos 42 - 51
@chazconnacher6178
@chazconnacher6178 3 жыл бұрын
@@Engineer4Free Thank you for your detailed response and great videos.
@maxwelladams5114
@maxwelladams5114 5 жыл бұрын
In the bottom left picture, how come the third from the left internal beam is not zero force?
@Engineer4Free
@Engineer4Free 5 жыл бұрын
Hey sorry there is an error in this video, I mention it in the video description: "The bottom left diagram is missing two ZFMs. They are the members that connect from the to the bottom of the truss 1/3 from the right. Link to that previous video is here: kzfaq.info/get/bejne/aqyliKxltN-7f6c.html I make note of it in the description there."
@STRUCENGG
@STRUCENGG 6 жыл бұрын
I didn't get it sir..
@Engineer4Free
@Engineer4Free 6 жыл бұрын
I recommend taking a few steps back and watching some more basic videos on trusses, check out videos 42-51 here: engineer4free.com/statics
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