liked because of the awesome "fomp fomp fomp fomp" sound effects XD

i came here to review my E&M, i stayed for your perfect drawings and awesome sound effects. thank you for making these videos, I hope you're doing well!

Your familiar voice is so good to hear before major physics tests or exams

you are without a doubt better than any college prof that i have taken in college and i am currently in physics 3.

you explained this concept the best!! thank you!!

You are the true definition of a teacher :)

Excellent videos! I really appreciate the help. I'm using this to help me in college level physics because I didn't take AP physics during high school.

We use F = (current)(length of wire in the B field) X (B field) = Lorentz force to create coherent accelerations of the charged particles in very thin layers of metal. We are using UV light in an attempt to increase the number of free electrons in the thin metal layer to boost the effect. (UV light induces the photoelectric effect in metals) The thin metal layer gets its current from eddy current coils that are in close proximity to, but not touching, the metal 'foil' layer. It's similar to your drawing: vertically oriented magnetic field, current flow in a conductor (the thin metal) at a 90 degree angle to the B field, resulting in coherent motion of the charged particles in the layers. To cut down on the remanence, the thin metal has no trace of iron, cobalt or nickel. The eddy current coil is fed with a very high frequency amplifier, and the signal alternates (it's not DC). So the current flow induced in the thin metal layer swaps back and forth at the frequency fed to the eddy current coil. Remanence would generate heat and impede the back-and-forth accelerations of the charged particles in the metal. We use the Lorentz force to create coherent accelerations (back and forth) of the charged particles in the metal layers. Thanks for your great video!

Your videos have bee extremely helpful. You are Able to explain the concepts very well, way better than my teacher. Thank you soo much!

thank you very much for your time and effort this is very helpful

Thank you sir.Your videos are really helpful

Frequency is so critical, changes all connectivity to any material

Thanks, it really hellps 👏👏

Thank YOUUU

which is the next video??

Full marks!!! Topped the college!

That was perfect for my finals. You, sir are a perfect teacher.

How can you totally ignore the "B" field. the most powerful part of the magnet??

Quick question if there is a current through the wire would it not then create a magnetic field itself in a different direction than the already present magnetic field?

You supposed current to be positive, Isn't current contain electrons, or negative charges?

What if I is not given

I would like to know howdoes the current becomes a vector in this situation: (I want to calculte the force per lenght) \vec{F} = i \vec{L} x \vec{B} becomes \vec{F_L} = \vec{i} x \vec{B} Do you know why? Thanks! ps: I think I know already that this might be true \vec{F_L} = (\vec{F})/(\vec{dL}) = \vec{i} x \vec{B} But I don't see so much sense with diferentiators, vectors and scalar exchange...

Torque sounds like tweak

I don't understand where the force is coming from. The current through the wire creates a magnetic field around the wire. On one side of the wire the mag field is a vector in one direction and on the other side it is a vector in the opposite direction. So with the wire residing in a uniform field, those two vectors of the wire's mag field are opposing and attracting the uniform field. So shouldn't the effect just cancel out and no force results?

thank you a lot :)

I hope he supplys his paper from Dunder Mifflin.

what is B

fwoom fwoom fwoom fwoom fwoom

Go define FIELD son. You have NO hope of it.

shoomp