Frequently Asked Java Program 27: How To Count Words in a String

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Frequently Asked Java Program 27: How To Count Words in a String

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Topic : How To Count Words in a String
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Пікірлер: 96

@rajendramahapatra3293 4 жыл бұрын

There is one more easy approach. String str = “Welcome to the Java tutorials”; String strArray[]=str.split(“ “); System.out.println(“The number of words in a string is “ + strArray.length);

@sdetpavan 4 жыл бұрын

Good

@rajendramahapatra3293 3 жыл бұрын

@ it will work. Array declaration and initialisation have been done in one line.

@gautamkumarjha2686 3 жыл бұрын

This will not give a proper result if there is more than one space.

@chinna12131 3 жыл бұрын

@@gautamkumarjha2686 String sentence = "Java easy peasy when we practise and explore"; String[] words = sentence.split("\\W+"); System.out.println(words.length); The above regex will work.

@sharma3226 2 жыл бұрын

Sir could you Pleasee guide me how to sort number of frequent words used in pdf document. because i want to learn the most important major words for exam would be very helpful 🙏🏽🙏🏽.

@harshitranjanrai7837 2 жыл бұрын

public static void main(String[] args) { int count=1; Scanner sc=new Scanner(System.in); String s=sc.nextLine(); for(int i=0;i

@vishnureddy34 5 ай бұрын

correct

@jashuvadevisetti5860 Жыл бұрын

Easiest way to solve : class Test{ public static void main(String [] args) { String str = "hello walcome to java programming"; String []tokens=str.split(" "); System.out.println(tokens.length); } }

@chinna12131 3 жыл бұрын

One more easy approach. String sentence = "Java easy peasy when we practise and explore"; String[] words = sentence.split("\\W+"); System.out.println(words.length);

@bighitlabels2474 2 жыл бұрын

In this case do we need to add loops also as above program

@Developer138 Жыл бұрын

int count = s.replaceAll(" ", "").length(); System.out.println(count); i think this looks pretty easy love you Sir for ur dedication to videos

@prathameshkanthale6796 Ай бұрын

Yes..I did same

@charanbudama2601 3 жыл бұрын

can we use this ? String s1 ="This is a java program to find the words in the string"; String [] s2 =s1.split(" "); System.out.println("Number of words are " +s2.length);

@saurabhpadwal1427 2 жыл бұрын

It's very easy solution... Thanks brother...

@sdetpavan 2 жыл бұрын

You are most welcome

@EdClarkHYCT 4 жыл бұрын

Awesome solution 👏🏾👌🏾👍🏽!!! Thanks for this!!!!

@sdetpavan Жыл бұрын

Welcome

@shailendraverma4082 8 ай бұрын

Thank you sir ! Really Helped allot ❤❤

@sdetpavan 8 ай бұрын

Welcome

@raghusundaram1057 2 жыл бұрын

import java.util.Scanner; public class CountwordsinaString { public static void main (String args []) { Scanner in = new Scanner(System.in); System.out.println(" Enter a String"); String str=in.nextLine(); int count=1; for(int i=0; i

@MartinoxxHD 3 жыл бұрын

You can actually use the Scanner class for counting letters: private static int cntWords(String phrase) { Scanner in = new Scanner(phrase); int cnt = 0; while (in.hasNext()) { cnt++; in.next(); } in.close(); return cnt; }

@rohithrhegde6597 2 жыл бұрын

@edbubble17 , you are awesome!!! never thought can do this using scanner class

@nileshpardeshi7068 4 жыл бұрын

Hello Pavan sir, This program fails if we haven't entered any string as input, the count is showing 1, bcoz by default count is 1. Another thing if the user entered multiple spaces as input then what logic needs to add to find the total count?

@Abhishek-Khelge 4 жыл бұрын

have u fount an answer for this?

@yasharparis2558 4 жыл бұрын

Answer: String st = "java programming java opps"; String a[] = st.split("\\W+"); for(int i=0; i

@emregeo2799 Жыл бұрын

I think this can be an answer . int count=0; for (int i = 0; i < s.trim().length(); i++) { if (s.trim().charAt(i)==' '&& s.trim().charAt(i+1)!=' ') count++; } System.out.println((count != 0 ? (count + 1) : 0));

@tapaskhandai 3 жыл бұрын

For loop should be i

@shahbajshaikh9196 2 жыл бұрын

That's what i was thinking...

@jagsam123 Жыл бұрын

Here int is starting from 1....so s.length has taken

@haribol3383 Ай бұрын

why its isn't mattering bro? if I am trying so it is giving error

@tapaskhandai Ай бұрын

@@haribol3383because it will not go the last letter of the string. It will find the space character always 2 or 3 characters before the last character. And the goal will be achieved.

@shashavalijava9 2 ай бұрын

Thanks ❤❤❤ sir

@sdetpavan 2 ай бұрын

Welcome

@pankajsahu1657 Жыл бұрын

String S = "Hidndustan India Ganga"; String [] words = S.split(" "); System.out.println(words.length);

@saqlainquazi7600 Жыл бұрын

@prathameshkanthale6796 Ай бұрын

Can it work.... Int a = s .replaceAll(" ", " ").length(); S.O.Pln("a");

@Mm-zt1gk 4 жыл бұрын

What if string is like "naman-singh" It will count them single word i think

@Abhishek-Khelge 4 жыл бұрын

there are many test cases where it will fail not only this one.

@hefshineatulashokugalmugal7030 11 ай бұрын

there are one test case fail in your code ex." atue auah iaajja " output require=3 but your code output is 4

@subhamanand1141 11 ай бұрын

why the count variable is intialized with 1 not zero?

@bhagya6606 2 жыл бұрын

Nice 👍 explanation

@sdetpavan 2 жыл бұрын

Thanks

@dilrubaahmed8302 2 жыл бұрын

some days earleir, Mr. Pavan had shared a link for a new youtuber for learning java and other stuffs.Do anyone know what is the name of the channel?

@sdetpavan 2 жыл бұрын

Teckstack9

@dilrubaahmed8302 2 жыл бұрын

@@sdetpavan thanks , but i cannot access in search button..can u share any video link plz?tia

@anveshreddy1245 3 жыл бұрын

If I want to count unique words in a string then what should be done

@prathmeshgabhale8922 3 ай бұрын

Scanner sc=new Scanner(System.in); System.out. println("enter string"); String s=sc.nextLine(); String a[ ] = s. split(" "); System.out. Println(a. Length);

@joji4776 3 жыл бұрын

thank you so much

@sdetpavan Жыл бұрын

Welcome

@Shreenidhi110 8 ай бұрын

I have one doubt,If we have space in starting of the sentence,we need to keep cunt as 0,but t wont work for count 1.Please suggest!

@aadil_aahil_sheikhabu5181 Жыл бұрын

how can we put count =1; eg user doesn't want to put any word then still it will show 1 words which is not possible

@nainagupta4949 Жыл бұрын

one confusion : in if you used compare "==" for first condition and for 2nd "=" only assignment could you please explain

@adityapanwar9175 Жыл бұрын

It's not a single"=" operator there. It's actually "!=" which means not equal to. hope this helps

@anuragbatham5170 Жыл бұрын

We can also use String tokeniser.

@Ashkilgaming 6 ай бұрын

Why length -1 pls explain simply

@Hzzzzz6 11 ай бұрын

public static void main(String[] args) { String input = "today is a beautiful day"; String words[] = input.split(" "); int count = 0; for (String w : words) { count++; } System.out.println(count); }

@pandutadavarthy8332 2 жыл бұрын

Can any one find 2 letter words 3 letter words upto n letter words in given string using java

@aadityaballal03 Жыл бұрын

if more than one spaces occurs consequetively in between string like = "Welcome to java world" , then how to count words?

@amoghchavan970 Жыл бұрын

String str ="Welcome to java world"; just remove the space of string by str.replaceAll (\\s," ") ; method and then it will be like this Welcometojavaworld then use length method to get the count simple

@vaishnavichittimalla3305 3 жыл бұрын

How to get words not number of words ? After getting words indicate their index values

@sagarahirrao7599 Жыл бұрын

List companies = Arrays.asList("HCL","HCL","HCL","HCL","TCS","TCS","TCS","ZINNIA"); Write a program that returns the name of the company that has the maximum occurennce. for e.g. above list should print HCL can i get ans. of this?👆

@subhojitbiswas3876 11 ай бұрын

I'll give tomorrow

@user-ve8pg5pf9l 9 ай бұрын

@@subhojitbiswas3876 you never came back bro...

@prasannasp2351 4 жыл бұрын

Can we use string.replaceAll(); and count the sentence without spaces and then difference the original length

@sasidharnaidu4507 3 жыл бұрын

I was thinking so.. not sure of all scenarios

@swayamprakashbhuyan2580 3 жыл бұрын

Commenting for better reach

@remixgimix Жыл бұрын

The program fails if you give an empty string like this " "and also if you start the string with a space. How do you handle this scenario? Cuz count is initialized to 1.

@MrDawg69 Жыл бұрын

For the second issue...We can add a trim() function.

@Arjun2mkap3929 Жыл бұрын

If(i==0 &&charAt(I)! =' ') ||(str.charAt(i) ==' ' && str. charAt(i+1) ! =' ')) Use this condition u will get solution to your problem

@sagardumane6982 Жыл бұрын

invalid charecter constant showing in first conditions ==' ' ,how to solve this sir anybody knows this

@Mm-zt1gk 4 жыл бұрын

Nice video

@sdetpavan Жыл бұрын

Thanks

@sharma3226 2 жыл бұрын

Sir could you Pleasee guide me how to sort number of frequent words used in pdf document. because i want to learn the most important major words for exam would be very helpful 🙏🏽🙏🏽.

@atishmule7310 3 жыл бұрын

What if there is space at end

@KajalPatel-hz9vv Жыл бұрын

Make use of trim first

@amoghchavan970 Жыл бұрын

ONE MORE EASY APPRORACH JUST REMOVE THE SPACE BY REPLACE ALL METHOD AND THEN COUNT THE LENGTH OF STRING SIMPLE

@saurabhmishra-nn5xs 2 жыл бұрын

why count=1 ? sir

@abinayarajendran99 Жыл бұрын

why count is kept as 1 instead of 0?

@noorelafifi602 Жыл бұрын

@Isha yadav vii b Ad no. 4679 if i make .length() not -1 and count is 0, its correct?

@AkashYadav-bo3uq Жыл бұрын

Can somebody explain me how to count the number of "and" and "an" in a sentence with working

@ramyachaluvadi4922 3 жыл бұрын

Why should give two spaces s.charat (I)== ' '

@swarajsingha616 2 жыл бұрын

What if I start blank space before string.

@Maghil485 2 ай бұрын

Then you need to give int count= 0 instead of 1.

@kishorebabu1543 3 жыл бұрын

Why did you take count is 1 what will happen if we take 0 ? please answer my question... thank you

@puttaviratkumar7316 3 жыл бұрын

if we are taking count as zero(0) then it should return the number of words must be one less. because it should not count the first word.( we didn't consider the space before the first word)

@shankarlingam4702 2 жыл бұрын

Wow it's like a 🍰

@lakshmireddy9952 4 жыл бұрын

well dooooooe

@sdetpavan Жыл бұрын

Thanks

@arijitghosh2910 Жыл бұрын

import java.util.*;; public class Count_Word { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String s = sc.nextLine(); String[] arr = s.split(" "); int count=0; System.out.println(Arrays.toString(arr)); for (int i = 0; i < arr.length; i++) { if(arr[i]!="") { count++; } } System.out.println("Number of word : "+count); } } You can also try it ☺

@mrb7931 Жыл бұрын

import java.util.Scanner; public class CountTheWords2 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Enter a String"); String str = sc.nextLine(); int count = 1; for(int i=0;i

@kvelez 11 ай бұрын

import java.util.HashMap; import java.util.Scanner; public class Main { public static void main(String[] args) { System.out.print(" Enter a statement: "); Scanner scan = new Scanner(System.in); String statement = scan.nextLine(); scan.close(); String[] words = statement.split("\\s+"); HashMap wordHashMap = new HashMap(); HashMap letterHashMap = new HashMap(); for (int i = 0; i < statement.length(); i++){ char currentChar = statement.charAt(i); if (letterHashMap.containsKey(currentChar)){ letterHashMap.put(currentChar, letterHashMap.get(currentChar) + 1); } else { letterHashMap.put(currentChar, 1); } } for (Character letter : letterHashMap.keySet()){ int count = letterHashMap.get(letter); System.out.println("Letter: " + letter + " appears " + count + " times."); } for (String word : words){ if (wordHashMap.containsKey(word)){ wordHashMap.put(word, wordHashMap.get(word) + 1); } else { wordHashMap.put(word, 1); } } for (String item : wordHashMap.keySet()){ int count = wordHashMap.get(item); System.out.println("Word: " + item + " appears: " + count + " times."); } } }