Gaussian Elimination and Gauss-Jordan Elimination Four-Variable Linear System

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Күн бұрын

www.greenemath.com/
/ mathematicsbyjgreene
In this video, we will look at one example of how to solve a four variable linear system using Gauss-Jordan Elimination.

Пікірлер: 46

@rda2743 3 жыл бұрын

Thanks sir. Big help and detailed explanation how to solve the variables.

@Greenemath 3 жыл бұрын

I'm glad you found it helpful! :)

@lillianidahosa3266 Жыл бұрын

Life saver:) Thank you so much for this video you are amazing at explaining things:)💯

@Greenemath Жыл бұрын

Awesome, glad to hear that.

@Sd20067 10 ай бұрын

Thank you so much!! This video is really helpful 👍

@Greenemath 10 ай бұрын

Glad it was helpful!

@ramdhanakmaludin1530 2 жыл бұрын

maybe it's too late to ask, but I'll still ask can we not swap the first row with the fourth row? will the end result be the same? or different?

@Greenemath 2 жыл бұрын

You can swap any two rows you want. Just like if you wrote out four equations it wouldn't matter the order.

@ramdhanakmaludin1530 2 жыл бұрын

Thank you sir, the solution you provide is very helpful

@clarenceandino424 3 жыл бұрын

How do you get the matrix?

@Greenemath 3 жыл бұрын

It comes from the equations. It's at 1:21 where I start filling it in.

@jijovarghese8662 3 жыл бұрын

Thank you sir❤️

@Greenemath 3 жыл бұрын

Most welcome! 😎

@adrianquinones3081 Жыл бұрын

Thank you mahbro!

@Greenemath Жыл бұрын

No problem

@mantombazanefortunate 4 ай бұрын

Hi sir where can I find part 1

@Greenemath 4 ай бұрын

I don't know what you mean by "part 1"

@paulwinson1500 Жыл бұрын

Thank you so much

@Greenemath Жыл бұрын

You're most welcome

@user-kh4jp5jt6m 2 жыл бұрын

What if we get a non-square matrix?? How do we determine the diagonal ?

@Greenemath 2 жыл бұрын

What's the example you are working on?

@user-kh4jp5jt6m 2 жыл бұрын

@@Greenemath I have 4 unknowns and 3 equations!! How do I find the upper triangle and determine the pivot??

@Greenemath 2 жыл бұрын

When you have n equations and m variables that n < m you must consider (m−n) variables free and fixed (they can take arbitrary value) then you try to solve your equation with n equations and n variables. You can post the question to reddit: www.reddit.com/r/LinearAlgebra/ or you can try the www.reddit.com/r/learnmath/, someone can explain and post pictures for you. Make sure you type the full problem out or take a clean picture of it written out. Good luck.

@user-kh4jp5jt6m 2 жыл бұрын

@@Greenemath Thank you very much, I appreciate your effort....

@Rewguz Жыл бұрын

Gracias, Amigo :)

@Greenemath Жыл бұрын

denada

@zvokz126 2 жыл бұрын

WHAT, for the last one, why didn’t u multiply with the last column 16:40

@Greenemath 2 жыл бұрын

It's explained in the video if you keep watching. The short form is to look at the zero in row 4 and pause for a minute and think about what happens when you change each element in column 3 into a zero.

@zvokz126 2 жыл бұрын

Ohhhhh I see, thank you

@Greenemath 2 жыл бұрын

@@zvokz126 You are welcome, really surprised someone actually read my reply. Good luck with your studies :)

@manaal2868 2 жыл бұрын

thank youu.

@Greenemath 2 жыл бұрын

You're welcome!

@AmpongJnr. 4 ай бұрын

Thanks

@Greenemath 4 ай бұрын

Welcome

@jkpanes0708 2 жыл бұрын

We were given a 5 equations with 5 unknowns and i cant solve it. Is it possible that the equations are incorrect and there are no values that can't satisfy them?

@Greenemath 2 жыл бұрын

It's always possible that you have a system with no solution. Given that you have five equations and five unknowns, I would plug it into Mathway and see what you are supposed to get. It would be really easy to make a mistake when working a problem of that magnitude.

@faizanshaikh6036 3 жыл бұрын

When u take 2R2+R4 in 3rd step

@Greenemath 3 жыл бұрын

The value is correct, please check the video and watch what's going on. You are making a sign mistake and that is leading you to get the wrong value. One is positive and the other is negative. You have positive 14/3 and -6/3. The sum of these numbers is 8/3 which is shown in the video.

@faizanshaikh6036 3 жыл бұрын

You take wrong value of R4.its not 8/3it is -28/3

@Greenemath 3 жыл бұрын

The value of 8/3 is 100% correct. This is at 9:21. We are first multiplying 2 by 7/3 which gives us 14/3. Then we are adding -2. 14/3 - 6/3 = 8/3. You are probably getting confused with your signs.