Thanks❤

Thanks bro🌼

гальваника будь внимателен яйца не поджарь.

这样做太危险了，一不小心可能会触电或做成其他事故，而且灯泡故障不是经常发生，搞一个“测试器”也要时间和金钱。买一个新的灯泡花几块钱，不要因少失大，误了生命！

Ni idea tienes de lo que dices 🤦‍♂️ jajajaja

Thanks bro

Thanks bro

شكرا لك صديقي العزيز

ευχαριστώ αδερφέ

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

Se encenderán más débilmente si pones las mismas. Este suministra una corriente media de alrededor de los 10-12 mA a 230 V porque lleva dos resistencias de 10k (20k efectivos). Si es para 120 te generará alrededor de 5 mA. Si quieres puedes poner dos resistencias de 4k7 o 5k6 para hacerlo similar.

Use the same values for 120 volts

Thanks bro

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

Thank you for your attention to the quality of the video Yes, the video camera unfortunately burned down and I had to buy a camera with a higher quality

hi . 110 and 220 volt

¿Para qué?

А лучше-языком.

​@@user-ce5uc5cs8x сначала руками, потом языком вот и проверим безопасна ли данная сборка

@@user-xx5xd5kd2g опасна конечно и проверять не надо

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

220v AC .and working by 110v

This is very good, I'm glad

This diagram is not needed anymore, dear friend one diode bridge and two 10k resistor؛only this

🧡🌼

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

Please do not spread false information. thank you dear friend

thanks bro

Do not change the training process. Proceed as in the tutorial

I din't notice . What do you mean by storm? What do you want to get rid of my friend?

@@Simple.E.P Maaf kawan, yang kumaksud strom adalah sengatan listrik.

@@yepidia2311 ⚡💜

This is an LED tester circuit, not an LED driver circuit

@@Simple.E.P oh but it's very useful for me thankyou lot ❤️

220volt

পিন টাতে দরলে শক করবে না?

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

Warning Never do you do this

No . But it is better not to do this

@@Simple.E.P Thanks

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

Thanks bro

Input:AC & Output:DC . Auto voltage

Thanks 👍

Thank you for your attention, dear friend I do not currently live in the UK

پراب مولتی متر -- دوشاخه برق -- دیود 4007 ، چهار عدد -- مقاومت 10 کیلواهم 1/4 وات ، دو عدد حتما قسمت توضیحات ویدیو را ترجمه و مطالعه بفرمایید

Please be careful and take care of yourself

@@Simple.E.P Thank you, but I don't fully understand, is it dangerous to do this?

@@umitylmaz3123 It is better not to do it. This circuit is designed only for LED testing and does not have enough resistance for all DC devices, therefore there is a possibility of damaging the circuit. You are doing a good job of asking questions before doing something you are not sure about

@@Simple.E.P Thank you very much, I thought it would make all the DC circuits work, thank you very much again, otherwise my circuits would be damaged, thank you again, have a good day

@@Simple.E.P Thank you very much, I thought it would make all the DC circuits work, thank you very much again, otherwise my circuits would be damaged, thank you again, have a good day

No need dear friend

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

@@kennmossman8701 While I generally agree that this contraption is just horrible, I have questions on details. Since the resistors are in series, shouldn't that divide the voltage?

​@@ImieNazwiskoOK no, here the resisters only limit the current, there is noi resistor divider

High DC . Auto Voltage 0 ~ 200 v

​@@Simple.E.Pis this is Sirig bord?

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

Auto Voltage . 1 ~ 200 Volt DC No need to change parts. You can make and use according to the sample. Just be careful of electrocution

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae coud damae a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted.. It is clear to me that this guy lacks knowledge

Almost all input is output

such a bad idea and construction and some ill-informed comments First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

There is no need to change the parts, please continue your work as per the tutorial

Yes bro . ⚡Danger⚡

Ma meno di 12 mA. Fastidioso ma non pericoloso

@@fulgen It is not dangerous, but it is better to follow the warning to be sure and save life

You cannot connect it to the voltage indicator, but you can connect it to a multimeter to measure the voltage of the LEDs

@@Simple.E.P yes that's what i've done today. Succeeded. Thank you so much.

10K

Thank you.❤

Yes

Everything that was used in the training

@@Simple.E.P which diode is it? 1400N? What is the resistance of these resistors?

Mention proper details of the resistor and diodes

@@mahaniaz5734 Did you not notice these in the video? Diode:1N4007 4pcs Resistor: 10K Ohm 2pcs

​@@mahaniaz5734and it's auto DC volt 1~200

No

Dear friend, you don't need to make any changes, just design and use it, there will be no problem. Just be careful of electrocution

Yes, it is

no my friend The potential for harm is high

Yes bro . thanks

such a bad idea and construction First this is DANEROUS - it is not isolated from the Mains voltage, so a nasty shock - even a fatal shock is possible. The voltage [for 220VAC mains] at the probes is over 300VDC VDC-peak = VAC rms x 1.4 - Vf of diodes That is a standard well-known equation - this guy says its 0 to 200DC which is nonsense. While the resistors limit the current - a small current at that voltage is dangerous Another point is that LEDs have a low reverse voltage rating so this high voltae could damage a LED. A led tester that can damage the DUT ------ not smart at all then the construction sucks. The resistors should not be soldered directly to the prongs. And there should be better strain relief. Plus the wires need to be rated for that voltage In conclusion a bad and even dangerous circuit that is poorly constucted. It is clear to me that this guy lacks knowledge

But Why.? Please Explain.

​@@vijaymhatre2676 Because you can die. The resistors are 10K/0.25W. If you short circuit the resistors get too much power and can damage (in this video at 4:53) P = 230V*230V / 20000 Ohm = 2.645 Watt 2.645 more than 0.25. Nobody guarrantees the resistors no lose them value. If the circuit shorted and you contact pins you can get more than 20-30milliampers and you will be died. If you do not know and do not understand safety regulations and sources of danger you do not use 230V (or more than 40V Voltage) The idea is good, but you should use less than 40V instead of 230V. For example an 18V accu is good for this.

@@istvannagy3069 Okay. Thanks for explaining.

@@istvannagy3069 2,65 W divided in two. Maybe, if you not used during a long time, with 1W resistors could be enought

@@fulgen Yes, 2.65W divided in two. But it is 2.65/0.5= 503% overload. And if you short the phase wire with a grounded case of other device P = 230V*230V/10000 Ohm = 5.29 Watt on only one resistor. The point is that the electricity is dangerous. More than 40V can cause damage. If somebody use 230V (100-250V) the safety regulations must be followed. I'm sure there is no country where this is allowed

Hi dear friend. Wouldn't it be better if you watched the video till the end and then judge?? This circuit does not cause sparks and damage to home or work wiring. You should read about rectifier diodes

Saludos tengo mucho tiempo utilizando este circuito sin problemas, con las resistencias de 10k tal cual el circuito descrito y ha resultado excelente facil de usar y seguro en su uso, gracias amigo por compartir sus conocimientos.suerte@@Simple.E.P

Thanks bro🌼@@germansirgo8853

Simple and perfect, bro Thx ❤

20k impedance ! No short circuit but resistors could dissipate both more than 1W. Maybe is better higher power capbility instead 1/4 W

Please listen to our dear friend

Ты почистил зубы, малыш? Иди в свою комнату и подумай о том, что ты сказал.😆

Действительно, вам, россиянам, запрещен доступ к KZfaq.