de hecho a mi me prendio fuego la bateria Xd

who cares? Hype is must.

çıkışa zener diyot ekleyebilirisiniz. ayarlı olan tl431 olan bu işi görecektir diye düşünüyorum.

Maybe there is resitor on board

I'm pretty sure the pin on the board is already driving an onboard FET. This is adding an extra Fet in parallel to that.

@@robmc3338 There is no external power mosfet.

@@robmc3338 😂so is it practical to do this reply

I agree with You. This kind of batteries are really dangerous when You Charge them with higher currents than the nominal.

@@jjcreacionessoluciones Definitely a very dangerous video. Not everyone is as knowledgeable as we are.

I guess it makes whatever amps it gets, as the FET works in a switch mode :)

.

among other things, it is not certain that the current is distributed uniformly in all 4 cells, some could absorb more, some less increasing the risk of overheating.

As well as the temperature of the external field effect transistor. After all, the power on it will stand out considerable./ Равно как и температуру внешнего полевого транзистора. Ведь мощность на нём выделяться будет немалая.

hi, what is 1C mean?

@@ClassyJohn It means the Capacity of the battery. Example a 1000mah battery which is 1A battery can not be safely charged at 1A and it could cause damage to the battery or even make it explode. The typical safe recommendation is 0.5C which is half the capacity of the battery, so 500mah charge rate in this example.

@@Angryhelder What if a battery is charged with less than 0.5C, like 0.2, will it damage the battery?

@@naingtheawperc3817 preferably you want 0.5c or less so that is fine.

Thanks for watching

окончание заряда контролирует микруха, по напряжению на банках.

@@user-oy8kd4ux5q да, но CC/CV тут явно не работает. Вернее, работает только ограничение по верхнему напряжению. Но там должны быть всякие trickle charge режимы и т.д. Будут ли они корректно работать или нет неизвестно.

@@wirtdonners4212 известно. не будут. Тут показан вообще "апгрейд" для идиотов желающих спалить свой дом. Здесь просто вставили ключ (транзистор) который тупо напрямую подключает АКБ к источнику питания. И разомкнётся только при достижении на батарее 4.2 В. Токоограничения кроме сопротивления проводов нет (если его нету у БП).... Да лучше тогда просто плату защиты поставить и так же напрямую к источнику подключаться. Автор этого "улучшения" либо идиот, либо вредитель

@@user-jd6yf9yl6g Согласен, так себе идея.

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?

@@plutonianfairy Look at 4:22 - the input voltage is passed directly to the battery via the IRF9540. There is no current or voltage limit in the circuit. What should be the maximum charging voltage of a 18650 cell?

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при такой схеме контроль тока зарядки вообще отсутствует.

Заблуждение. Зарядный ток литийных элементов может быть в половину от емкости батареи. Не путайте со свинцовыми.

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Yes, this is just a test.

@@PhdHung I understand. Just telling other people. Also, this mosfet has a little bit high Rdson for 10A. Check out the IRF5305

I think banks should be charged to the minimum of 10% of their storage capacity, for example if I have a 100Amp bank I must charge it to 10 Ah, so as not to increase the internal resistance every time I loaded it, the idea is great only that that mini battery bank is too small to load it that way. If you want to charge so fast, better use Ultra LTO Capacitors

@@rickhuntraslam2925 what you mean is you want to never discharge below 10%... there is already a security threshold. We do no discharge Li-Ion or Li-Po under 3V per cell, yet each cell could get down to about 2.5V before any real damage happens! Also a 100A bank doesn't mean anything, it's 100Ah! A are used to measure a current flow! Ah are used to measure a capacity, it's how much A you need to draw to drain the battery in an hour! That is a very common mistake I have even seen on official products like more or less famous bluetooth speakers!

@@Zebra_Paw ok

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He bypass the IC with Z44 MOSFET

At 1:34 you can see on the pinout of the TP4056 that pin 2 connects through R-PROG to ground. This resistor's value tells the chip which output current to use - so it has "programmable" output, up to 1000mA. The pre-installed resistor will be chosen to provide this maximum rating. With this hack, this circuit (output current regulation) as well as the circuit for voltage regulation are bypassed. So, you are feeding whatever voltage and current capacity your power supply provides directly into the battery. To answer your question, then, it is the internal resistance of the battery that dictates the current draw, up to the maximum rating of your power supply - 30A in your case. The battery's resistance would certainly limit the current to something less than that, but it would very likely be too much current for safety. Therefore, the only function then that TP4056 is now providing is the charge termination, which is supposed to cut off the charging circuit when the current draw reaches C/10 ...typically this is around 100mA. It is unlikely that the TP4056 will provide this function at these higher voltages and current. So, if you're thinking of doing this hack you might as well just connect your battery directly to your 5V source!

схема плохая! транзистор не может регулировать ток и это не минуемая гибель акб или вовсе взрыв...

Это схема хороша если ты пожар хочешь устроить. В этой схеме отсутствует ограничение тока. Вернее оно есть но только лишь из-за сопротивления проводов и мощности БП. Просто поставь плату защиты на АКБ и подключи напрямую к БП и будет тоже самое, даже лучше, потому как у платы защиты есть хотя бы защита по току.

why? is it because batteries have a capped current limit they can support?

@@ClassyJohn Because rechargeable batteries work by a reversible chemical reaction. Too much current will cause internal heating that can damage the cell's internal structure. In addition, for some chemical reactions, too much current can produce a different non-reversible chemical reaction to occur, thus lowering the cell's capacity.

En estos casos, no necesitas un balanceador extra.

True, but if you keep in mind that there will be 9,1A charging current you have to choose a ≥10A power supply.

за блок питания не переживай переживать надо за акб ,транзистор не может регулировать ток и это не минуемая гибель акб или вовсе взрыв...

Are you sure it's great?

@@tuxede I don't think it's working, however i give it a try. When it work, the energy problem is solved :-)

@@richardnoordhoff4288 it isn't creating more energy, it just allows more current flow. that is possible, and for that this will work, however the schematic also showed a protection diode which is missing here, as well as you need to be sure it won't remove the protection functions of the cirquit. more curent(certainly) does it still protect the batteries(Perhaps, it does to a certain extend, but should still test it anyway).

Betul, tapi kalo speknya memang high drain kyk murata vtc4 vtc5 vtc5a vtc6, samsung 25r, 35e, 20s, lg 26m mungkin aman

@@mr.febrian9248 saya ada baterai bekas leptop test charging dengan 2A langsung rusak baterainya, baterai panas ketika di charging, kalau dibiarkan tanpa dipakai sehari sudah drop di 2,9V. Paling bagus beli baterai yang jelas tipe dan mereknya sehingga tahu datasheet baterai tersebut misal normal charging dischargingnya, fast chargingnya, umurnya berapa kali, resistansi internalnya, dll.

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How do you balance batteries connected in parallel? It doesn't need a resistor, the current regulation depends on the connected power supply.

@@wernerpeter9706 just skipped on some part lol but you can do balance the batteries using a resitor to lower the output from source or like you said just change the supply to 4v 2a

@@tossancuyota7848 That's not balancing, that's charge control. In a parallel circuit, there are no voltage differences between the individual cells that need to be balanced. If you set 4.2V and 2A on the laboratory power supply, why do you need a modified TA4056 module? In this case, 2 cables are enough ;-) So this modification is not only dangerous but also pointless.

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The maximum charging current is limited by the power supply itself. The gate resistor does not affect the charging current.

Bu uygulama sakıncalı mı telefon şarj adaptorlerinin makisimum verebileceği akımı görüyorum kaliteyi öğrenmiş oluyorum 4 pil lityum paralel bağlı 10 - 12 ampere bu şekilde elimdeki kaynağında tabi 10 amper çıkış vermesi gerekiyor

@@burakerisen3979 Lityum şarj işlemi pilin kapasitesi bilerek bilinmiyorsa tespit edildikten sonra sabit volt sabit akım (cc-cv) yöntemi ile yapılır. Lityum piller kapasitesinden fazla şarj olmaya dirençli değildir, piller şarjını tamamladıktan sonra eğer kontrollü bir şekilde şarj işlemi sonlandırılmazsa iyi ihtimalle yıpranak ömründen ve kapasitesinden kayba uğrarlar, kötü ihtimalde ise ısınıp alev saçarak patlayabilir ki bu telefon şarj ederken isteyeceğiniz en son şey olur. Videoda kullanılan mosfet sabit şarj akımını artıracaktır ancak şarjın sonlanması gereken noktayı tp4056 entegresi yine kendi üzerinden geçen akım miktarı ile kontrol edeceği için piller aşırı şarj olabilir. Özet olarak sağlıklı bir çözüm değildir.

@@burakerisen3979 Telefon adaptörlerinin max akım değerini ölçmek için bir direnç kullanabilirsiniz. değerleri 5V, 2A olan bir adaptörü V=I*R, 5v/2A --> 2,5R direnç kullanarak ve direncin iki ucundaki volt farkını ölçerek üzerinden geçen akımı okuyabilirsiniz. dirençin iki ucundaki voltu dirençin değerine bölerseniz üzerinden geçen akım değerini bulursunuz. örneğin 1,8v / 2,5R = 0,72 A

Çok teşekkür ederim bilgiler icin

well i just tried 4 and seen smoking coming from it so its not 4 haha

2000mah x4 . it connects in parallel

@@PhdHung Oh yes, I saw that voltage is 3.6V across. OK, in that case, 9A is fine !!

this is not working, 2000ma x 4 = 8000ma ! en this is not Safe on 9amp ...

@@louisgabriels6333 a little bit over 1C is not an issue

I think the original charge board will turn off the mosfet when the battery reaches 4.2V via the pin with the 10 ohm resistor he added.

Thanks

Unfortunately, it's real. The TP4056 is still only supplying 1A (and has internal current limiting for over-temperature anyway). But the circuit is using the "charge" indicator output to turn on an external MOSFET between the supply and the battery and that is supplying the extra 8A. The IRF9540 has a resistance of around 0.2 ohms when turned on fully, so the current is being limited crudely by whatever the power supply is capable of. Not a safe circuit.

@Andrey Orel чтобы зарядить с большим током

@Andrey Orel разогнал модуль зарядки с 1 до 9А по току, для того чтобы параллельные сборки не заряжались вечность

@@Deemon1 А как теперь модуль понимает какое напряжение на акуме?

@@alexandr_84 , аккумулятор подключен штатным образом к плате зарядки. Плата контролирует напряжение и отключит зарядку когда нужно. Данный товарищ применил лайфхак. Управление дополнительным транзистором зацепил к ноге 7 контроллера - лампочка окончания зарядки. Загорается светодиод, мощный транзистор отключается. Колхоз во всей красе.

@@alexdubovik2119 я уверин на 99% что так только убьёшь акб силшком большой ток и тд.

voltage gradually increase to 4.2V, then it will cut off charging.

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1/4W bro.

@@PhdHung Ok thank you bro 👍🏻

And if not, can it charge an iPhone?

Thanks for watching

~40*C

Somewhat 2V at 10A, "40C" is only if you live on a pole lol. Well, unless (and I guess that is exactly what happens) he overloaded the power supply so it is what defines the current, not the useless charger.

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unfortunately no, you need P-mos

@@PhdHung ohh thank you buddy

Please make using N channel MOSFET and also charger for 120Ah lead acid battery using computer SMPS

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Да это ложь,первое,провода которые он использует при таких токах потекли бы как вода,второе,эти 18650 которые он использует имеют максимальный ток заряда 2 ампера,и третье,плата не выключится при достижении 4,2 вольта,что приведет к печальным последствиям и опасным для жизни

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5V 2A is almost too much. By wiring the MosFET via the LED charge indicator, it gets an enormous current gain. Combined with the low resistance value and the polished, highly efficient copper antenna, it can convert the missing power from the magic around it. Sorry for the joke, but output power can never be greater than input power. If you want 5V 10A at the output you have to provide at least 5V 10A at the input.

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ok bro.

However, this rule of thumb does not apply to all battery types (NiMh/lithium/lead-acid/...). In the case of lithium batteries, it helps to look at the datasheet, where the maximum charging current is given. The rule of thumb for lithium is: charging current = 1C. With lithium, however, the maximum voltage must also be observed. It's also in the datasheet again, the rule of thumb is 4.20 volts.

@@wernerpeter9706 Well, excluding my ~10-12 years doing battery research for my RC hobby, the proper rule of thumb is to use 10% AND using internal battery resistance. That's why 4.20V based on 1C standard is not very good. For example you'll be amazed how many high class 18650 batteries have different characteristics especially in below 0°C temps (even for those with high starting current, oh my)

@@GbpsGbps-vn3jy And because there are so many different characteristics, this rule of thumb (1/10 C = charging current) is not good either. It describes the least common ground, concerning all eventualities and all types. Of course you can charge any 18650 cell with 100 mA, it just takes a correspondingly long time. It is well known that a Li-Ion no longer performs as well in the cold as at +25 degrees, which is why in the RC area, for example, the flight batteries are preheated in winter. But in this case you are right about this used cells, I would no longer charge these cells with 2.5A either. Especially since there is no current limitation here at all.

@@wernerpeter9706 Rule of thumb is called rule of thumb because gives somewhat accurate results based on practice and is easily remembered by people with insufficient knowledge about the given topic Btw in RC during cold days the best is not to preheat them (discharging batteries physically shrunk by low temps even with smallest amps is not good) but to carry them in a bag insulated against cold temps, and use them right before the actual flight

you mean to say ... always give 10 hours to charge ? none of the phones will use fast charger then

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không đâu. pin này sạc đc 1C mà. 4 viên 2000amh song song.

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just add 2 modules on top of another in parallel, you will get 2A

@@JawadAhmadsahibzada I connected two TP4056E modules in parallel: for some reason, the output current did not change. On one of the boards, two diodes are lit at the same time.

@@sddfefr5686 I used 4 tp4056 in parallel to charge my power bank quickly. I tested around 3.8A going to power bank. But make sure you’re using 5v 2A charger minimum for 2 in parallel