You’re very welcome, I’m happy to hear the video answered your questions! :-)

I'm really glad to hear you're enjoying the video lectures, and thank you so much for sharing them with people, that's very much appreciated! :-D

I'm so glad to hear that Shovnik, and you're welcome! :-)

Thank you very much for the encouragement! :-)

Thank you very much Sergio! 🙂

You're welcome David, I'm glad that it made things clear! :-)

You’re welcome! :-)

You're welcome! :-)

You're welcome Arafath! :-)

I'm really glad to hear this video helped you out Mowafk! :-) I'm not sure why that wouldn't work for you, if you post your code here in a comment I could take a look at it (or maybe someone else may be able to help you out too if I can't).

Can you maybe share your code in a comment so I can see what you're trying to do? :-) In general we cannot make something "more public" in a derived class... if it's protected in the base class it should be protected in the derived class too. So I'm just wondering what your code looks like and what you mean by "use it".

@@PortfolioCourses Thank you for your reply, here is the part of the code : ----- header file ---- class Piece : public CObject { private: CString model; // type of the piece protected: CString reference; // reference of the piece Piece(CString); // constructor, the parameter gives the piece type ; the reference will be composed of the three first letters of the type, all defined in cpp file below. public: Piece(); // default constructor, the type of the piece will be "piece" and the reference to "NR" in cpp file. void display(); //function that will display the model and reference }; class Engine : public Piece { private: int cptref; // counter public: Engine(); // default constructor, the type of the piece will be "engine" and the reference will be composed of the 3 first letters of the type followed by a underdash "_" then the number of the piece. void display(); }; ------- cpp file ------- Piece::Piece() { model = _T("piece"); reference = _T("NR"); } Piece::Piece(CString type) { modele = type; reference=modele.Left(3); } void Piece::display() { cout

That should work yes. :-)

@@PortfolioCourses Thank you very much! :D

You’re welcome! :-)

Like when you create the object, you want to provide arguments for both constructors, one in the base class and one in the derived class? The only way to do that, that I'm aware of, is to make a derived class constructor that accepts whatever parameters are needed for itself and whatever the base class constructor would need. And then that construct can "do some work" and then call the base class constructor as well. So you still only use one constructor when making the object, but the derived class constructor uses the base class constructor to have it do work too.

@@PortfolioCourses Thanks!

@@gavinthecrafter You're welcome! 🙂

So in general that is not something we want to do, the idea is that the parent class constructor sets up any member variables that the child class uses too. It may be possible though, there is an answer here for example: stackoverflow.com/questions/4065109/not-calling-base-class-constructor-from-derived-class