How to Calculate Percent Yield and Theoretical Yield The Best Way

How to Calculate Percent Yield and Theoretical Yield The Best Way - TUTOR HOTLINE

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In this video, I answer these two questions:
1) "The combustion of 0.374 kg of methane in the presence of excess oxygen produces 0.983 kg of carbon dioxide. What is the percent yield?"
2) "The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the theoretical yield?"
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Пікірлер: 129

@melissamaribel 5 жыл бұрын

Hope this video helped! I've also made the perfect set of notes for finding percent yield, theoretical yield, limiting reactants, and more. Get them here melissa.help/limreactnotes

@bchandrax 3 жыл бұрын

May u pls teach how to calculate percentage purity

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Exactly! If it doesn't make sense, it just means you need to learn it a different way. Keep going Jared 👍

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You're welcome! So happy you passed!

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@destinyramos7290 2 жыл бұрын

this!!

@sarahialbornoz1518 4 жыл бұрын

you honestly saved me. I’ve been looking for the right video to help find the percent yield of a reaction where part of the reaction uses an excess. this video was a perfect explanation on how to approach the work. thank you so much!

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@melissamaribel 5 жыл бұрын

Hope it went well!

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@melissamaribel 5 жыл бұрын

You’re welcome 😊

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bruhhh the way you wrote of those steps at the 7 minute mark is genius! I always struggled with conversions but that makes it so much easier.

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@melissamaribel 5 жыл бұрын

You're welcome! 💕

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Thank you so much Giana!

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@melissamaribel 5 жыл бұрын

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@melissamaribel 5 жыл бұрын

You're welcome Brenda!

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@kaleighwenze2142 3 жыл бұрын

Currently doing my chem exam lol thank you so much! 10 hours into the exam I totally blanked on Theo yield 😂

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@melissamaribel 5 жыл бұрын

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@melissamaribel 4 жыл бұрын

Hope it went well!

@robertgargano3726 4 жыл бұрын

i really could use so much help in this. please respond!!!

@alyssaluhr3415 Жыл бұрын

thank you. just, thank you

@ricecum5814 3 жыл бұрын

do we multiply the coefficients with the subscript or add them

@alinabaltazar 3 жыл бұрын

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@akashayaqub7175 4 жыл бұрын

This is a great resource and it's very helpful indeed. I just don't understand why the 0.374kgCH4 wasn't used (12:47) if it was one of the givens. The actual yield, as mentioned in the video, was .983kgCO2 and I am not sure how you knew .983kgCO2 was the actual yield instead of .374kgCH4 being the actual if it makes sense. Thanks for all that you do!

@user-le3xf3hi6u Жыл бұрын

What if the numbers are already grams do you leave it as is and just solve?

@nigiasb8709 4 жыл бұрын

nice explanation!

@muhammadtayyab1276 5 жыл бұрын

Good teacher you are

@AwaisKhan-mh6cd 5 жыл бұрын

U SAVED A CAREER

@MuhammadHassan-mf3vs 3 жыл бұрын

thank you

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@Tyba_Angie 5 жыл бұрын

I love your videos, they are really helpful, can you go through some Aleks problems???

@melissamaribel 5 жыл бұрын

Thank you and I don't have access to Aleks problems so I don't know what is on there.

@jeddaaah 3 жыл бұрын

nice, what software are you using for explanation? what device is it

@rameenfayyaz966 3 жыл бұрын

How do I find the theoretical yield with limiting reagent. My question has the percent yield and I need to find out the actual? Idk if u will see this but I hope

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You are a lifesaver

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@TheUrbandilema 5 жыл бұрын

Thanks again..chem finals Friday for me

@melissamaribel 5 жыл бұрын

You're welcome Ryan!

@loveofaflower5486 2 жыл бұрын

Excuse me but, when calculating theoretical yield, would you not coincided the second component “O2 and 2H2O” since it has a smaller value of 528.211? I’m a bit confused with this topic…please can you take the time to explain?

@studylux3691 4 жыл бұрын

How do you know what the actual yield is?

@cyrussneilmancia4625 3 жыл бұрын

If 5.25 g SO2 reacts with excess of CaCO3 and O2, how many grams of CaSO4 are formed?

@AwaisKhan-mh6cd 5 жыл бұрын

u deserve more subscribe about 1M tbh love ur effort

@melissamaribel 5 жыл бұрын

Thank you so much! I really appreciate you noticing all the effort and time I put into my videos!

@AwaisKhan-mh6cd 5 жыл бұрын

@@melissamaribel welcome

@tagwaali9287 3 жыл бұрын

you honestly are godsent. My professor is great, but i cant seem to understand him.

@bernicelin8045 2 жыл бұрын

Why did u divide by the molar mass

@lump4698 3 жыл бұрын

Ahh I wish all the chemistry teachers would have been like Melissa

@ebenburger111 4 жыл бұрын

If I understand this correctly, there's a very simple way to get an average extraction yield. Weigh the Original dried ingredient you'd like to extract. Infuse your dried substance and filter. Now dehydrate the remainder Fibrous content to get rid of most of the water - comparable to its original state, and Weigh it again. The difference in weight before and after the infusion of the dried matter will show you how much extracted content you now have mixed within your liquid. For example, if the dried coffee was 100g before extraction, and after filtration and dehydration is 60g, the total dissolved/extracted content is 40g.

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Brilliant

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I love lovelovee your channel . It is so perfect! :)

@melissamaribel 4 жыл бұрын

Thank you 😊

@ethenthompson9802 5 жыл бұрын

Thank you for helping me with my final tomorrow

@melissamaribel 5 жыл бұрын

You're welcome! Good luck with your final tomorrow!

@memebeans6094 5 жыл бұрын

god tier youtuber

@someoneclassified774 2 ай бұрын

1 hour before my eoc exam i hope this clutches up

@lizc8489 9 ай бұрын

Wouldn't the theoretical value be 1026? How do we jump from 1025.5 to 1030? Don't we round up to the next number which would be 1026. Please explain.

@jessieamir603 2 жыл бұрын

Please i need a heelp Ticl4+2mg»ti+2mgcl2 3.54x10^7g of Ticl4are treated with 1.13x10^7g of Mg ::calculate the therotical yeild of To in grams!!!

@jessieamir603 2 жыл бұрын

Ti* not To

@naomygonzalez4930 4 жыл бұрын

Hello Meliss! No one is class could figure this out, but thought maybe you could. We did a precipitate lab and we mixed magnesium hydroxide and hydrochloric acid and CO2 was formed. We don’t know why this reaction would happen.

@melissamaribel 4 жыл бұрын

Were you guys testing for carbonate in your sample? If acid reacts with carbonate then CO2 is produced. I'm gonna need a little more info on your lab to know exactly what's going on. What was the purpose of the lab or procedure, what was the initial sample you used etc.

@cforchemistry6197 4 жыл бұрын

Nice

@Ivan-gt4ln 4 жыл бұрын

Is limiting reactant the same as theoretical yield?

@Ivan-gt4ln 4 жыл бұрын

nevermind lol thanks

@olaalmaarufiz5116 4 жыл бұрын

Why did you chose CO2 specially to the theoritical yield?💕

@adilazharhussain3256 3 жыл бұрын

Hello miss how are you thanks for this video

@user-gd7ih5yg9b 17 күн бұрын

Wow❤

@basantkumargupta9194 4 жыл бұрын

Very nice madam

@adt4025 2 жыл бұрын

Is it possible that a question will end up with a % yield higher than 100? Idk how to fix it.

@ibireconditum6466 2 жыл бұрын

late to answer but just in case anyone sees this and is wondering the same thing, the answer is no that is not possible. The law of conservation of mass says matter cannot be created nor destroyed and that would be creating it :)

@Hani-qt6bj 5 жыл бұрын

Thank you so much You just earned yourself a new subscribe Also my marks increase to a 88%

@melissamaribel 5 жыл бұрын

Yay!!! So happy to hear your improving!

@ownwrites Жыл бұрын

Wonna ask u to slove my question how can I send u should I email on KZfaq BTW I'm new here watching your this as my first video nd found helpful?

@doaaalasadi7187 4 жыл бұрын

I love you girl!!!!!!!!!!!!!!!!

@telasbanda5630 2 жыл бұрын

Any tips of how to become an A+ student 🙏🙏

@jonahhamoui8357 4 жыл бұрын

9:30

@Mirrorz_ 4 жыл бұрын

About to take my lab final in 3 hours and I'm not ready at all

@smitak9367 4 жыл бұрын

4:22 you could have used the formula CxHy + (x+y/4)O2 --------> xCO2 + (y/2)H2O

@cachalittlevideos7530 5 жыл бұрын

im the 200th like

@MsSmith-rq9vy 7 ай бұрын

Excellent job, but the girl's paper doesn't match the answer. The guessing teacher made a mistake on her paper. Thanks, Melissa, for all you do to help us Chem students!