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How to control the brightness of LED using Potentiometer| LED Dimmer Circuit on a breadboard
Рет қаралды 20,347
2 жыл бұрынWatch this video to learn how to adjust the brightness of an L.E.D on a breadboard in the most simplest way!
The electronic components you are going to require are listed below👇
COMPONENTS
REQUIRED:- 1k Potentiometer
470 Ohm Resistor
Breadboard
L.E.D
9v Battery with Battery Clip.
Follow the steps in the video!
The potentiometer consists of 3 pins! Make sure you connect a 470 ohm resistor or (any resistor close to this range) to the middle (centre pin) pin of the potentiometer to avoid the L.E.D from burning out!
Then connect the L.E.D in series to this circuit.
Now,
Connect the battery and with the help of a screwdriver adjust the potentiometer to increase or decrease the resistance of the potentiometer.
If you increase the resistance of the potentiometer then the L.E.D will be dimly lit.
If you decrease the resistance of the potentiometer then the L.E.D will be brightly lit.
Hence, you can adjust the brightness of an L.E.D by adjusting the potentiometer!
@mahlonkarpaiya252 Жыл бұрын
Very helpful. Thank u
@anukperera Жыл бұрын
Thank you 🎉❤
@yarianisrivera3422 Жыл бұрын
thank u sm it worked!
@sampratimukherjee1381 Жыл бұрын
The best
@BuckWezr 6 ай бұрын
Is the 103 code 1k or 10k?
@kunalmule2690 Жыл бұрын
Sir can u share Diagram for this project
@newstar01 Жыл бұрын
no bakwas nice tutorial
@CrossedHorizons- 4 ай бұрын
i am confused, why is the other end of the resistor not connected to something?
@hellscooker31 4 ай бұрын
Its actually connected to gnd(Ground) or -
@yousraabdullah3054 11 ай бұрын
When I use the potentiometer the led won't turn off completely
@xpple 9 ай бұрын
i'm pretty sure it depends on the potentiometer your using range
@yousraabdullah3054 9 ай бұрын
@@xpple IDK, i used various types of potentiometer like 50k,10k,100k and same results
@SkillsFx 5 ай бұрын
Yes that's because there is still the other resistor providing a path for power to flow. If you turn the pot to its min (0ohm), it's just bypassing the pot
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