This is how a tutorial should look like. Great video.

Thank you very much! This is a very cool video and I got it! I really hope for new lessons. This is the only lesson in which I was able to do this.

Great video man! Would definitely like to see more of this series!

Thanks for another great tutorial! Very clear and concise.

Great video! I had wondered about how to do the coordinates calculations for this in the past but I'm not good at math and wasn't even sure if hex grids would be better than square grids in my project so I gave up on that and just used a simple square grid. There is only one piece of feedback I have: you can combine the nodes into a function that takes the loop indices as inputs and returns the coordinates of the static mesh instance as an output. You could even add a boolean input "WorldCoordinates" to return world coordinates in the output rather than each tile's actor-relative local coordinates to make the function more useful. This does two things: first the graph will look much cleaner and second you can call this function from another event graph to find out where to place something if you want it to appear on top of a specific tile :)

Modulo gives you the remainder of number after dividing it by the number you put in. So every even number divided by 2 has a remainder of 0 and every uneven number will have a remainder of 1. If you would input modulo 3 it would return a 1 every third number as every 3 integers the cycle of what remains after dividing repeats

Works great in C++ as well :) Just have to make sure you load in the Static Mesh you'd like your UInstancedStaticMeshComponent to create instances of

The reason for that being the sqrt(3) *size is simply pythagoras. We know a side=size. if you make a right angle triangle from the middle to a corner and to the middle of a side you get a right angle triangle with sides: 1*side for the long side and 1/2*side for the other side. let's say side=x to make it easy and solve: x^2-(1/2*x)^2= (hight/2)^2 or 3/4*x^2 = (hight/2)^2. This as 1/2^2 is 1/4 and 1 -1/4 =3/4 Then take the sqrt of both and you get sqrt(3)*sqrt(1/4)*x=1/2*hight or sqrt(3)*1/2*x = 1/2*hight. And this finally gives hight = sqrt(3)x

Great tutorial, thanks! Keen to follow this series for a future game.

Imagine that your hexagons are each made of 6 equilateral triangles. Now imagine a grid of equilateral triangles, each alternating its direction either pointing up or down. Now look at your formula for height: Square root of three multiplied by the radius (which is also the length of side of your equilateral triangles). An equilateral triangle can be split into two right angle triangles. Now look at how Pythagoras can be simplified for your use case.

Nice, clear and simple! Thanks. How to interact with the grid now? Like case selection and paths ?

next tutorials when? I was hoping to randomize terrain on the hexes but I noticed that they are all the same material.

i'm using unreal engine 5.3,my project file map are failed to load map problem & i'm try autosave map open but unfortunaly same at this map, please resolve my problem 🤕🤕