How To Prove Bernoulli's Inequality

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8 ай бұрын

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Пікірлер: 10

@seanfraser3125 8 ай бұрын

Third method: The two sides if the inequality are equal at x=0. The derivative of the RHS is n, and the derivative of the LHS is n(1+x)^(n-1) >= n, since 1+x > 1. So the LHS is increasing at a faster rate than the RHS, so the LHS must always be at least as large as the RHS

@nikos4677 6 ай бұрын

you are not allowed to do that but good try

@jehannabary3872 5 ай бұрын

@@nikos4677why he can’t do that.?

@nikos4677 5 ай бұрын

@@jehannabary3872 You are not allowed to differentiate on an inequality.

@sammyasher 2 ай бұрын

Why set x > 0 here rather than > -1 like the principal seems to originally state? is it just a simpler approach and the full proof would have a separate case for between -1 and 0?

@neuralwarp 8 ай бұрын

You could have taken n=0 as your base case

@yoav613 8 ай бұрын

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@ShortsOfSyber 8 ай бұрын

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